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Can someone help me with a regex expression for a phone number
it needs to be in this format only
xxx-xxx-xxxx
Try this
^\d{3}\-\d{3}\-\d{4}$
Multiple ways are there. For example:
var regex = /^\d{3}-\d{3}-\d{4}$/;
console.log(regex.test('999-999-9999'));
console.log(regex.test('9999-999-99999'));
//OR
var regex2 = /^[0-9]{3}-[0-9]{3}-[0-9]{4}$/
console.log(regex2.test('999-999-9999'));
console.log(regex2.test('9999-999-99999'));
You can also write specific to a country or area. See this example.
If you are taking it from user input validate it like this:
var val = document.getElementbyId('yourInputId').value;
if(regex2.test(val)){
alert("Success!!");
}
else{
alert("Failure!!");
}
Related
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Clarification - I want to check if str1 and str2 share common substring.
str1 = "and we know that the lion"
str2 = "the lion is big"
by using those two string because the lion happens to show on both string then true will be invoked.
Thanks.
You can use String.includes that will return a boolean value:
console.log("and we know that the lion".includes("the lion is big")); // returns false
console.log("and we know that the lion".includes("the lion")); // returns true
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I'm trying to make something that gives an output based on your input. I would like it to take every letter and produce something with the next letter in the alphabet. So if I entered "Hello" it would produce "Ifmmp". The only way I can think to do this is with a series of ifs and else ifs, but I would like to know if there is a faster way.
You can use the String.fromCharCode feature. For example:
let myChar = 'c';
let nextChar = String.fromCharCode(myChar.charCodeAt(0)+1);
console.log(nextChar) // 'd'
In your case, you would replace 'c' with your character variable.
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Let's say I have a string that looks like this:
Red#Yellow#Blue#Green
How can I use Javascript to remove the last instance of # as well as the text that comes after it, so that the resulting string would look like this:
Red#Yellow#Blue
string=string.split("#");
alert(string.pop());//Green
string=string.join("#");
I dont see a problem? Simply split by #, remove the last one and join again?
you can split the string into arrays and join all the items of the array except the last one
var myString = Red#Yellow#Blue#Green;
var myArrray = myString.split('#');
myArray.splice(myArray.length-1,1);
myArray.join('#');
console.log('Red#Yellow#Blue#Green'.replace(/\#[a-zA-Z]+$/,''));
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I want to validate the textbox as per date & time format like YYYYMMDD.HHMMSS so I required regular expression for date & Time using the javascript.
Please let me know the answer as soon as possible.
Required RE for YYYYMMDD.HHMMSS date Time format.
Dear, Here is your answer :
var r = /^((((19|[2-9]\d)\d{2})[\/\.-](0[13578]|1[02])[\/\.-](0[1-9]|[12]\d|3[01])\s(0[0-9]|1[0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9]))|(((19|[2-9]\d)\d{2})[\/\.-](0[13456789]|1[012])[\/\.-](0[1-9]|[12]\d|30)\s(0[0-9]|1[0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9]))|(((19|[2-9]\d)\d{2})[\/\.-](02)[\/\.-](0[1-9]|1\d|2[0-8])\s(0[0-9]|1[0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9]))|(((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))[\/\.-](02)[\/\.-](29)\s(0[0-9]|1[0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])))$/g;
r.test('2014-06-24 15:49:05'); // true
r.test('2016-02-29 23:19:20'); // true [leap year]
r.test('2015/02/29 23:19:20'); // false
r.test('2010.11.31 10:00:02'); // false
r.test('1956.10.12 24:10:02'); // false
Thanks & Cheers
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I have a phone number like (123) 456-7891. I need number like 1234567891.
How can I do that in Javascript ?
To be on the safe side, I would recommend removing everything except + (for country codes) and digits:
result = subject.replace(/[^+\d]+/g, "");
You can use String.replace() to do this. Pass it a RegExp that matches everything but digits and replace them with ''.
var number = '(123) 456-7891';
number = number.replace(/[^\d]/g, '');
alert("(123) 456-7891".replace(/[\(\)\-\s]+/g, ''));
please check this link.it might help you
http://www.w3resource.com/javascript/form/phone-no-validation.php
there are many examples here.it might be useful for you.