I'm trying to get this panel menu to work. I've been working on it for hours without any success. I have it partially working. See fiddle here.
What I'm trying to do is:
When you click target 1, target 2, target 3 links. The div holding these links should slide out. Right now, it is only being covered and hidden by the next div that is sliding in. I would like it to slide out first to the left, and then have the next div slide in after.
After clicking one of the target links. Then when clicking "main menu" link, make the "target" box below (green, red, yellow boxes) slide out from right to left and have the "target menu" the one that loads initially, slide in from the left. Right now, I can't get that "main menu" link to do anything. It should show the initial target menu when clicked.
I know there is a lot of right and left stuff in there. But I wanted to be as specific as possible. I'm not really concerned about the direction of the slide. I am more concerned just to make it work first.
<div class="main-menu">Main Menu Link
</div>
<div id="right" id="target0">
This is the Target Menu<br />
Target 1<br/>
Target 2<br/>
Target 3<br/>
<div class="panel" id="target1" style="background:green">Target 1</div>
<div class="panel" id="target2" style="background:red">Target 2</div>
<div class="panel" id="target3" style="background:yellow">Target 3</div>
</div>
The #target0 is your entire element (it contains target1 target2 and target3)
You should break it out on its own:
<div class="main-menu">Main Menu Link
</div>
<div id="right" id="main">
<div id="target0" class="panel active">This is the Target Menu<br />
Target 1<br/>
Target 2<br/>
Target 3<br/>
</div>
<div class="panel" id="target1" style="background:green">Target 1</div>
<div class="panel" id="target2" style="background:red">Target 2</div>
<div class="panel" id="target3" style="background:yellow">Target 3</div>
</div>
EDIT:
To make the gray block slide, you should add your Panel class to it (I also added the active class so it displays by default). You'll just need to style it
div.panel.active {
display:block;
}
Related
I am trying to make Bootstrap 4 dropdown have this style: slinky.js.org
This is what I have by now: https://codepen.io/nht910/pen/yLexeEM
Main code:
<div class="dropdown-menu" aria-labelledby="navbarDropdown">
<div class="main-container">
<div class="menu-container">
<div class="menu-1">
<span>Link-1</span>
<button class="button-1">arrow-1</button>
</div>
<div class="menu-2">
<span>Link-2</span>
<button class="button-2">arrow-2</button>
</div>
</div>
<div class="submenu-container">
<div class="submenu-1"> <!-- submenu of .menu-1 -->
<div class="arrow-back">
<button class="button-back-1">Arrow back 1</button>
</div>
<div>
<span>Child 1</span>
</div>
</div>
<div class="submenu-2"> <!-- submenu of .menu-2 -->
<div class="arrow-back">
<button class="button-back-2">Arrow back 2</button>
</div>
<div>
<span>Child 2</span>
</div>
</div>
</div>
</div>
</div>
To make dropdown has slide effect:
I set two classes .submenu-1 and .submenu-2 to display: none, and when user click on arrow button, corresponding submenu will be shown and slide to it.
when user click on arrow back, it will slide back to main menu, and after finish sliding effect, it will hide submenu.
That is what I have for now. But I don't know how to resize dropdown's height to fit content inside it (dynamic height) like slinky.js.org.
Thank you so much.
Try using hide & code when you click.
you can simply do it by using jQuery
$("selector").hide() & $("selector").show()
when user clicks your custom buttons
Solution: https://codepen.io/nht910/pen/OJMobEm
I change height of dropdown using JS with .submenu-1 is the content I want dropdown to fit:
$('.dropdown-menu').height($('.submenu-1').outerHeight());
But it got one problem. At the first time I click on arrow button (it is the first time height of dropdown changed), the transition animation doesn't work. But after that, it work perfectly. So I add another line at global to make the first time that height is changed happen on page load. And now it work perfectly for me.
I have the following html:
<div class="col-sm-12" id='dropdown_menu_group'>
<div id='dropdown_library_menu'>
<div class="row" id='dropdown_menu_row'>
<div class="col-sm-2">
<a class='button-text btn' id='library_button' href="{{pathFor 'library'}}">my library</a>
</div>
<div class='col-sm-2 col-sm-pull-1' id='google_drive_text'>
GOOGLE DRIVE
</div>
<div class="col-sm-2" id='settings_button'></div>
</div>
</div>
<div id='dropdown_library_menu_border'></div>
</div>
my id='dropdown_library_menu' is hidden by default, and the div below it <div id='dropdown_library_menu_border'></div> has opacity of 0, so that when it is scrolled over, it makes the id='dropdown_library_menu' slide down. The issue is, though, that <div id='dropdown_library_menu_border'></div> is still there when the menu slides down, and thus, when I scroll over the opacity 0 div that triggers the slideDown (inside of the menu, at this point), it tricks my jQuery into thinking this condition is met:
'mouseout #dropdown_library_menu': function(ev){
ev.preventDefault();
$('#dropdown_library_menu').slideUp('slow');
}
Because technically, I am mousing out of the dropdown menu and into the dropdown menu trigger.
I want to make the blank div move to the bottom of the menu when the slideDown is triggered, but setting position relative on the parent and position absolute on the children totally messes up my webpage.
You can make it even slower,
'mouseout #dropdown_library_menu': function(ev){
ev.preventDefault();
$('#dropdown_library_menu').slideUp(3000); // Slide up in 3 seconds,
}
I have a main menu. This main menu opens hidden divs that also contain inner menus that show and hide content.
You can see this in action here: http://shirleycollinsmovie.com/collins-html5/index.html#about
The user can select from the main menu and open up one of the hidden divs, and then explore the contents of the inner menu.
However when the user closes the hidden div and then opens a new one, then returns to the previous one again, instead of it displaying the contents from the beginning again it shows them exactly where they were when they left the hidden div previously. I want it to display the contents from the beginning again.
This is the code I have which shows the hidden divs from the main menu (I am using the same code for the inner menus as well):
$('#menu nav a').click(function() {
$('.draggable').hide();
$(this.getAttribute('href')).show()
});
<div id="menu">
<h1>main header</h1>
<nav>
<a id="about-link" href="#about">About</a>
<a id="news-link" href="#news">News</a>
<a id="foundation-link" href="#foundation">Foundation</a>
<a id="contact-link" href="#contact-info">Contact</a>
</nav></div>
<div id="foundation" class="hidden draggable-scroll">
<div id="foundation-nav" class="box-text">
<nav>
The Story so Far
What will the Foundation do?
The Manifesto
Who is the Foundation?
</nav>
</div>
<div id="foundation-opening" class="box-text foundation-info">
<h2>header </h2>
<p>
</p></div>
<div id="the-story" class="box-text foundation-info hidden">
<h2>The Story so far: </h2>
<p>
And she’s not done yet,</p>
</div>
<div id="what" class="box-text foundation-info hidden">
<p>
The Ballad of </p>
</div>
<div id="manifesto" class="box-text foundation-info hidden">
<h2>The proposed Manifesto: </h2>
<p>
The reason for the foundation to exist: </p>
</div>
<div id="who" class="box-text foundation-info hidden">
<h2>Who is the Foundation?</h2>
<p> </p>
</div>
<div class="close-box">
x</div>
</div>
Perhaps there is a way to target the starting content from the href of the main menu?
Or is there a way within the jQuery to re-hide the hidden content when the users selects from the main menu again?
A simple workaround,
The following code finds first/beginning Menu Item - a:first selector and trigger click on it.
$('#menu nav a').click(function() {
$('.draggable').hide();
$(this.getAttribute('href')).show().find('nav a:first').click();
});
This would always open first <a> of <nav>.
It works with your site link. Tried out in console.
I have a markup arranged as follows in my website:
<body>
<div id="wrapper">
<div id="middle">
<div class="red-container">
<div class="row">
Middle. Row 1.
</div>
</div>
</div>
<div id="right">
<div class="green-container">
<div class="row">
Right. Row 1.
</div>
</div>
</div>
</div>
</body>
The right div as would be obvious has to be towards the right of the middle div.
Here's the fiddle (right div here inside my fiddle somehow is not actually to the right of middle div) : http://jsfiddle.net/NNMYS/
I am trying to achieve a sliding effect here:
All the content from the middle div should slide to the left and get removed after the animation. On the other hand, simultaneously, the content from the right div (which in my case will be added by ajax to the right div) should slide from the right div to the middle div (and removed from the right div). How can that be done?
I could have done a content slider directly by having all the content directly placed separated by positions and sliding to the clicked item. But here since I would be adding content by ajax and also have some responsive implementation, in my case that doesn't seem to possible.
Look at this. I think this might help
http://tympanus.net/codrops/2012/04/09/direction-aware-hover-effect-with-css3-and-jquery/
Suppose I have 4 visible divs:
- 2 on top
- 2 on the bottom, wrapped in a container
and 1 hidden div.
When a mouse hover over a bottom div it changes its color and changes color of one of the top divs.
When user clicks on a bottom div the hidden div appears and stays on the screen until mouse leave the container.
I use if statements to change color of divs, but I'm not sure whether I'm doing this right. Maybe there is a more simple and elegant way to do this.
So there are the questions:
- Do I have to use if statement here? Maybe there is a way to somehow "link" pairs of elements to reduce the amount of code?
- What if I want a top div to stay active while hidden div is visible? Do I need to write additional function with if statements again? Wouldn't that be "do not repeat yourself" rule violation?
Code example here: http://jsfiddle.net/Xq9kr
You can create implicit links through structure.
For example with this HTML:
<div class="top">
<div>Div 1</div>
<div>Div 2</div>
</div>
<div class="bottom">
<div>Div 1</div>
<div>Div 2</div>
</div>
You can then select the respective div in the top via indices:
$('div.bottom > div').hover(function () {
var index = $(this).toggleClass('highlight').index();
$('div.top > div').eq(index).toggleClass('highlight');
});
Or you can create explicit links through data attributes and IDs.
<div class="top">
<div id="div1">Div 1</div>
<div id="div2">Div 2</div>
</div>
<div class="bottom">
<div data-for="div2">Div 2</div>
<div data-for="div1">Div 1</div>
</div>
Then select like this:
$('#' + $(this).attr('data-for')).toggleClass('highlight');
// Or, even better if you're using jquery-1.4.3+
$('#' + $(this).data('for')).toggleClass('highlight');