I want to have a page turn effect like the one seen on this page: jFlip demo except I want to automate the page turning, like make it happen every second, 20 times (or however many images I have). I want to be able to trigger this animation to run either on page load, when a button is clicked, etc.
Unfortunately I don't understand jQuery all that well and the plugin's events seem rather complicated to me, probably mostly due to my inexperience with jQuery. Any help on which direction I should go, methods I should try? I am not limiting myself to jQuery or even Javascript, this is just the example I have found that achieves my desired effect.
You can find the updated code here. replace this with old one.
Usage :
var jFlip = new Flip("#g1",300,300,{background:"green",cornersTop:true,scale:"fit"});
// here #g1 is a jquery selector (make sure it returns only one).
// The structure is Flip(JQselector,width,height,options)
then use the jFlip object to flip slides/pages
jFlip.flipMe() // for next slide
jFlip.flipMe(true) // for prev slide
for binding a function to slide change event you can use
$("#g1").bind("flip.jflip",function(event,index,total){
$("#l1").html("Image "+(index+1)+" of "+total);
});
// here the selector is same as the one passed inside jFlip function.
Try this and let me know the feedback.
Related
I'm aware that this is an 'old question' by now, but I have searched and not yet found an explanation that makes sense to me.
Note: I know just enough html, css, and wordpress to have developed my website: (http://www.gregorygainsborough.com), and am just beginning to learn javascript.
If you visit my site, you'll see the problem - much of the content is revealed when various boxes are hovered on. On tablet, since there is no :hover, I'd like to make it do this:
First tap -> reveal the style that would have been applied on :hover.
Second tap -> follow the link like a mouse click would.
ALSO helpful would be to 'close' the :hover style when a) another element is tapped, or b) ten seconds elapse.
Thanks for any help you can offer. I'm aware that some of this will be above my js knowledge at present, and I'm looking for explanations or references which can help me target my learning and close that gap.
I would in PHP make a IF statement to check if Tablet is used.
You can use this Library for this. Then I would in the IF statement echo this javascript out:
var clicked = 0;
$('a.iftablet').on('click',function(){
var old_clicked = clicked;
var number = $(this).attr('tablet_id'); // Get the tablet ID for this item
var clicked = number;
if (old_clicked != number){ return false;} // This might do the trick, so that on first click, it doesn't link.
});
NOTE: I use jQuery, so you need the jQuery library.
NOTE 2: Add class="iftablet" to the links around the boxes, and add as well tablet_id="X" (Where X is a unique number for that box, so that when click on one box, the others will disapear).
Maybe there is some errors on the code, put then let me know. Good luck
I have created the following image gallery.
http://jsfiddle.net/sfiddle/Nf7yR/7/
I think the thing is, that even though I can get a hand on the paragraphs css, the currentIndex won't update, i.e. an event listener seems to be missing.
var thumb = document.getElementById("thumb");
myParagraphs = thumb.getElementsByTagName("p");
console.log(myParagraphs[1]);
function thumby(){
$(myParagraphs[currentIndex]).css("background-color", "red");
}
thumby();
The thing is that I can not manage to link the image index with the index of the pagination dot (which has a normal p tag).
I want to code it in that way that if the first picture is displayed the first dot is red, if the second image is displayed the second ...
How could I approach this?
Thanks for any good advice as I invested a few hours already but can not get my head around it.
PS: no, I want no plugin or ready made imagegallery, I want my approach to work :-)
You made a function thumby() but you are calling it only once (during script start). You just need to call it when you change currentIndex. Here you have fixed code: http://jsfiddle.net/Nf7yR/10/ (I commented my edits).
BTW your code looks terrible. You should indent it properly to make it easier to read :)
Can't seem to get this one to work...
I have a page that hides certain links. When the DOM is loaded, I'm using jQuery to toggle some of those elements. This is driven by using a data attribute like so:
<div class="d_btn" data-usr='48'>
<div class="hidden_button">
Then, I have the code:
$.each($(".d_btn"), function() {
var btn = $(this).data('usr');
if ( btn == '48' ){
$(this).children('.hidden_button').toggle();
}
The above all works as planned. The problem is that I am trying to remove the data-usr from the class .d_btn once the if statement is evaluated. I've tried the following and nothing works (i.e., after the page is loaded, the source still shows the data-usr attribute:
$(this).removeAttr("data-usr");
$(this).removeData("usr");
I've been working on this for a couple of hours now and...nothing! Help is greatly appreciated!
UPDATE
I've tried the great suggestions of setting the data attribute to an empty string but I'm still not getting the desired result.
To explain a little further, The reason I'm trying to remove the attribute is so when an ajax response adds another item to the page, the previously added items would already have the button either shown or hidden. Upon AJAX response, I'm calling the same function once the DOM is loaded.
Currently, when something is added via AJAX, it toggles all the buttons (showing the ones that were hidden and vice versa.) Ugh...
I'm also fully willing to try alternatives to my approach. Thanks!
UPDATE
Well, the light bulb just flashed and I am able to do what I want to do by just using .show() instead of .toggle()
Anyway, I'd still like to find an answer to this question because the page will be potentially checking hundreds of items whenever something is added - this seems horribly inefficient (even for a computer, hahaha.)
Why don't you set the value to a random value or empty variable instead if removeAttr does not work..
$(this).attr("data-usr" , '');
$(this).prop("data-usr" , '');
Changing the DOM doesn't affect the source. It affects the DOM, which you can view with the Inspector/Developer Tools. Right click => View Source will give you the original source of the page, not the actual current source as modified by JavaScript.
Set it to a blank string:
$(this).attr("data-usr", "");
I second what Kolink said: check the DOM, not the source. (Chrome: Ctrl + Shift + i).
As others have stated. Checking the source will only show the original unedited source for the webpage. What you need to do is check the DOM using developer tools.
I've just checked everything in Chrome's inspector on jsfiddle here and the attribute is definitely being removed as well as the data.
after logging on to facebook, there is a downward arrow symbol after home tab. On clicking it shows a div (?) which just appears on the existing content and on another click it disappears.
How can I make exactly such a thing?
Edit:
I followed this link from TheBlackBenzKid. One thing is clear, on clicking on the button, just 2 divs are toggled.
But AFAIK toggle takes place on mouse click. so the 'click' event should be there in the jquery code.
1) But I didn't find it. where is that?
2)there is some css that makes it possible for the menu to appear on a place without dislocating the existing content there( from the demo this is not visible, but it does happen actually). What is that css code?
There are so many ways to do these things: thefinishedbox.com/files/freebies/dropdown-gui/index.html this is a nice one that already comes with simple clean CSS look and feel
This is how i wouldve done it, but its a pretty basic solution.
div id="arrowid">▼</div>
<div id="dropdownbox" style="display:none;">Dropdownbox</div>
<script type="text/javascript">
$(document).ready(function() {
$('#arrowid').click(){
$('#dropdownbox').toggle();
});
});
</script>
this one does'nt support outside clicks, it just shows and hides when clicking the arrow. Hope it helps!
You can use .slideToggle() to achieve this effect, if you are using jQuery.
Use it to display or hide the matched elements with a sliding motion.
.slideToggle( [duration] [, easing] [, callback] )
duration: A string or number determining how long the animation will run.
easing: A string indicating which easing function to use for the transition.
callback: A function to call once the animation is complete.
Using jquery, I currently append html to a div on a click event. The following code allows me to fade in only the appended portion of the div:
var html = "..";
$('<div></div>').appendTo("#id").hide().append(html).fadeIn('slow');
This portion works perfectly. But how can I later remove (fade out) only the appended portion? I tried hacking this by storing the html prior to the appending, and then simply hiding everything and showing the stored html. But this does not work well when the same procedure is reused for several divs on the same page (and this seems like poor implementation). Is there a good way to do this?
Just to give an idea of why I need this: Think of a blog type page where for every article on the page there are several comments with only x amount showing by default: the click event fetches the remaining comments and displays them, and then toggling the button again removes the appended comments and sends it back to the original state.
empty() is always an option
jQuery('#main').empty();
Give a look at the empty() function.
It might better solve the problem. Here's the link http://api.jquery.com/empty/
I'd just set and clear the html with '.html()' ...
-- edit
to be more clear, have an area layed out specifically for the addition of these comments:
<div id='commentarea1'></div>
etc.
Try:
var html = "..";
$('<div></div>').appendTo("#id").hide().append(html).fadeIn('slow').addClass('appended');
then later
$('#id .appended').fadeOut('slow'); // or whatever you want to do.
It is not that clear from the question but say you show 5 comments by default and then show x more comments. To get back to the original 5 comment default state you can remove all comments with an index greater than 4 (zero based).
The following assumes each comment goes inside its own div that has a class comment.
$('#id>div.comment:gt(4)').remove();