I just need some ideas how i get the value from the dropdown
<select id="ins" name="instructor" required>
<?php
//dropdown instructor name
echo "<option value=\"\">"."Select"."</option>";
$qry = "select * from instructor";
$result = mysqli_query($con,$qry);
while ($row = mysqli_fetch_array($result)){
echo "<option value=".$row['insA_I'].">".$row['insname']."</option>";
}
?>
</select>
and put the value in this .php file in $_POST['instructor']
<?php
session_start();
require 'connection.php'; //connection
$qry = "select course from instructor where insA_I = '".$_POST['instructor']."'";
$result = mysqli_query($con,$qry);
$_SESSION['row'] = mysqli_fetch_array($result);
$data = $_SESSION['row']['course'];
echo $data;
?>
am still new in ajax
$(document).ready(function() {
$('#ins').change(function(){
$.ajax({
type: "POST",
url: "json_php.php",
data: '',
datatype: 'json',
success: function(result){
alert(result);
}
});
});
});
i already searched this in internet but didn`t get my answer after some modifcation
just need idea, techniques .etc.
Try this ajax code
$(document).ready(function() {
$('#ins').change(function(){
$.ajax({
type: "POST",
url: "json_php.php",
data: {instructor:$(this).val()},
success: function(result){
alert(result);
}
});
});
});
php code for query
$qry = "select course from instructor where insA_I = '".$_POST['instructor']."'";
$result = mysqli_query($con,$qry);
$fetch = mysqli_fetch_array($result);
$_SESSION['row']['course']=$fetch['course'];
$data = $_SESSION['row']['course'];
echo $data;
Since you're using jQuery, use jQuery:
data: { instructor: $('#ins').val() }
Also, please note that your SQL query is wide open to SQL injection. This is a good place to start reading about that.
Related
I am trying to make some code where a click of a SQL html button can display a different SQL table as a popup. I have already gotten the variable from the table to pass through using this:
echo "<td><a class='btn-floating btn-large waves-effect waves-light black' onclick='partSearch(".$product.")' value='display'><i class='material-icons'>search</i></a></td>";
The 'part search' code is as follows:
<script type="text/javascript">
function partSearch() {
$.ajax({
url: 'serv.php?id=<?php echo $product ?>',
type: 'GET',
success: function(result){
var obj = jQuery.parseJSON(result)
alert(obj)
}
})
}
</script>
Even though the variable is passed through to 'serv.php', I can't manage to get the sql data to be returned as a popup using alert. All I get is either nothing or [object, Object]. This is the SQL/php code:
<?php
include 'includes/dbh.inc.php';
$id = $_GET['id'];
$result = mysqli_query($conn,"SELECT * FROM pr WHERE product_ID='".$id."'");// test this
$rows = array();
while($r = mysqli_fetch_assoc($result)){
$rows[] = $r;
}
echo json_encode($rows);
?>
Any help is appriciated
<script type="text/javascript">
function partSearch() {
var product_id = "<?php echo $product; ?>";
$.ajax({
url: 'serv.php?id=product_id',
type: 'GET',
success: function(result){
alert(result);
}
})
}
</script>
i have to get select option list from my database
and for this my controller is
<?php
require_once 'connexion.php';
$sql = "select * from Motif";
$stmt = sqlsrv_query($conn, $sql);
if ($stmt === false)
{
die(print_r(sqlsrv_errors() , true));
}
$data = array();
while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC))
{
$data["id"] = $row['id'];
$data["libelle"] = utf8_encode($row['libelle']);
echo json_encode($data);
}
echo json_encode($data);
exit;
?>
and my html like this
<select id="rejetselect" class="form-control">
<option value="" selected="selected"></option>
</select>
and to get values from database with ajax i did this code
var $select = $('#rejetselect');
$.ajax({
url: 'motifRejet.php',
dataType: 'json',
data: 'libelle',
success: function() {
alert('good');
},
error: function() {
alert('nooo');
}
});
so after testing all this i can see my alert in good and in my console i can see the information that i got from database but i can't see it in my select option
With this code I can see empty data saving into my db once I click on the link button. But i need to the GET's data in my database. Any solution to this.
<a href="?id=1&pid=238874" id="day" onclick="this.form.submit();><button type="button" class="label label-danger" >Select</button></a>
<script>
$('#day').click(function(e)
{
e.preventDefault();
$.ajax({
type: 'post',
url: "index.php",
data: $("select.day").serialize(),
});
return false;
});
</script>
For PHP Code to save data
<?php
$a = $_GET['id'];
$b = $_GET['pid'];
// query
$sql = "INSERT INTO hos_patient(reg_id,pid) VALUES ('$a','$b')";
mysqli_query($db, $sql);
?>
Thanks
You specified using POST in your ajax function. But then you try to get the data by GET in your PHP-Script. I'd suggest you just use POST for this.
Alter your PHP-Script to use $_POST instead of $_GET
Try with this :
...
$.ajax({
type: 'post',
url: "index.php?id=1&pid=238874",
data: $("select.day").serialize(),
});
...
Use this in script file and in PHP file use below code
<script>
$('#day').click(function(e)
{
e.preventDefault();
$.ajax({
type: 'post',
url: "index.php?id=1&pid=238874",
data: $("select.day").serialize(),
});
return false;
});
</script>
<?php
$a = $_POST['id'];
$b = $_POST['pid'];
// query
$sql = "INSERT INTO hos_patient(reg_id,pid) VALUES ('$a','$b')";
mysqli_query($db, $sql);
?>
<button type="button" class="label label-danger" >Select</button>
<script>
$(function () {
$('.login_form_1').on('click', function (e) {
e.preventDefault();
$.ajax({
type: 'GET',
url: 'show.php?id=22&pid=33',
data: $('.login_form_1').serialize(),
success: function (data) {
$('div.logerrors').html(data);
}
});
});
});
</script>
For PHP output
<?php
$a = $_GET['id'];
$b = $_GET['pid'];
// query
$sql = "INSERT INTO hos_patient(reg_id,pid) VALUES ('$a','$b')";
mysqli_query($db, $sql);
?>
Below is my php file to apply query
$host = "localhost";
$user = "root";
$pass = "abc123";
$databaseName = "class";
$con = mysql_connect($host,$user,$pass);
$dbs = mysql_select_db($databaseName, $con);
$result = mysql_query("SELECT id, name FROM lecturer");
if (mysql_num_rows($result)) {
$data = array();
while ($row = mysql_fetch_assoc($result)) {
$data[] = array(
'id' => $row['id'],
'name' => $row['name']
);
}
header('Content-type: application/json');
echo json_encode( $data );
}
And this is my other file where i am applying javascript. I have searched a lot of same queries but could not find solution. Please help me
<script type="text/javascript">
function lecturer(){
$("#a1_title").empty();
$("#a1_title").append("<option>Default</option>");
$.ajax({
type:'POST',
url : 'get-data.php',
contentType :"application/json; charset-utf8",
dataType:'json',
type:'POST',
success:function(data){
$('#a1_title').empty();
$('#a1_title').append("<option>Default</option>");
$.each(data, function(i, data){
$('#a1_title').append('<option value="'+data[i].id+'">'+data[i].name+'</option>');
});
},
complete: function(){
}
)};
}
$(document).ready(function(){
lecturer();
});
</script>
Please help me I have tried to solve this problem buy i am not able to do it.
Your PHP code had bad syntax since you had your array() was surrounded with curly braces rather than parentheses. You also had some errors in your $.ajax, a misplaced parentheses. In addition, you do not need an iterator ([i]) in your $.each() function - you can just get each item's bit of information by associating this iteration's values. And as #Jay Blanchard said, mysqli would be used best here.
Try the following editions:
PHP:
<?php
$host = "localhost";
$user = "root";
$pass = "";
$databaseName = "test";
$con = mysqli_connect($host, $user, $pass, $databaseName);
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con, "SELECT id, name FROM lecturer");
if (mysqli_num_rows($result)) {
$data = array();
while ($row = mysqli_fetch_assoc($result)) {
$data[] = $row;
}
header('Content-type: application/json');
echo json_encode($data);
}
?>
JS:
<script type="text/javascript">
function lecturer() {
$("#a1_title").empty();
$("#a1_title").append("<option>Default</option>");
$.ajax({
type: 'POST',
url: 'get-data.php',
contentType: "application/json; charset-utf8",
dataType: 'json',
type: 'POST',
success: function (data) {
$('#a1_title').empty();
$('#a1_title').append("<option>Default</option>");
$.each(data, function (k, v) {
$('#a1_title').append('<option value="' + v.id + '">' + v.name + '</option>');
});
},
complete: function () {
}
});
}
$(document).ready(function () {
lecturer();
});
</script>
I have tried removing the JSON.stringify and changing the post to get change cache to false and true. I am at a loss as to what needs to happen. It always goes to the else statement in my php and returns the default JSON. I have allowed crossdomain in my php with the wildcard so that is definitely not the problem.
Code:
$(document).ready(function() {
$('.check').click(function(){
var thisID = $(this).attr('id');
alert(thisID);
$.ajax({
type: "POST",
crossDomain: true,
url: "retrieveColumn.php",
data: JSON.stringify({ ID: thisID}),
cache: true,
async:true,
datatype: "json",
success: function(data)
{
console.log(data);
alert(data);
}
});
});
});
PHP which always goes to the else condition:
if(isset($_POST['ID']))
{
$ID = $_POST['ID'];
{
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = $ID ");
if($stmt->num_rows) //if there is an ID of this name
{
$row = $stmt->fetch_assoc();
echo $row;
print json_encode($row);
}
}
}
else
{
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = 2");
$row = $stmt->fetch_assoc();
print json_encode($row);
}
Unless this is part of a larger document, you have unnecessary brackets which might be causing problems.
if(isset($_POST['ID'])){
$ID = $_POST['ID'];
{ /* <!-- HERE! What is this?? */
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = $ID ");
if($stmt->num_rows) //if there is an ID of this name{
$row = $stmt->fetch_assoc();
echo $row;
print json_encode($row);
}
}
}
else
{
$stmt = $mysqli->query("SELECT * FROM group2.menu WHERE ItemID = 2");
$row = $stmt->fetch_assoc();
print json_encode($row);
}
You don't need to stringify the object you submit as data here:
data: JSON.stringify({ ID: thisID}),
Use:
data: { ID: thisID},