This question already has answers here:
Regular expression greater than and less than
(3 answers)
Closed 8 years ago.
I need a regular expression that replaces the greater than and less than symbol on a string
i already tried
var regEx = "s/</</g;s/>/>/g"
var testString = "<test>"
alert(testString.replace(regEx,"*"))
My first time to use it please go easy on me :)
Thanks
You can use regEx | like
var regEx = /<|>/g;
var testString = "<test>"
alert(testString.replace(regEx,"*"))
Fiddle
For greater than and less than symbol.
var string = '<><>';
string = string.replace(/[\<\>]/g,'*');
alert(string);
For special characters
var string = '<><>';
string = string.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g,'_');
alert(string);
Insert the regular expression in the code before class
using System.Text.RegularExpressions;
below is the code for string replace using regex
string input = "Dot > Not Perls";
// Use Regex.Replace to replace the pattern in the input.
string output = Regex.Replace(input, "some string", ">");
source :
http://www.dotnetperls.com/regex-replace
Related
This question already has answers here:
Regular Expression to get a string between parentheses in Javascript
(10 answers)
Closed 4 years ago.
How can I modify this string:
"SRID=4326;POINT (-21.93038619999993 64.1444948)"
so it will return
"-21.93038619999993 64.1444948"
(and then I can split that)?
The numbers in the string can be different.
I've tried using .replace & split, but I couldn't get it to work properly. How can I make this happen using Javascript?
You can try with match and regex:
"SRID=4326;POINT (-21.93038619999993 64.1444948)".match(/\(([^)]+)\)/)[1]
// "-21.93038619999993 64.1444948"
I am not good using REGEXP but this could be a solution with pure split.
Hope it helps :>
var str = "SRID=4326;POINT (-21.93038619999993 64.1444948)" ;
var newStr = str.split('(')[1].split(')')[0];
console.log(newStr)
var new_string = string.replace("SRID=4326;POINT (", "");
You can use a regular expression. The first number is put in first, the second number is put in second.
const INPUT = "SRID=4326;POINT (-21.93038619999993 64.1444948)";
const REGEX = /SRID=\d+;POINT \((.+) (.+)\)/
const [_, first, second] = INPUT.match(REGEX);
console.log(first);
console.log(second);
This question already has answers here:
How to tell if a string contains a certain character in JavaScript?
(21 answers)
Closed 4 years ago.
I'm a beginner in node.js so please do excuse me if my question is foolish. As we know we can use
var regex = /[ !##$%^&*()_+\-=\[\]{};':"\\|,.<>\/?]/g;
regex.test(str);
to check whether a string contains special charecters or not .But what I'm asking is how to check for only a particular charecter means how can I check only presence of #.
I tried to do
var regex = /[#]/g; regex.test(str).
Although it's not working but are there any other method of doing this?
You don't need a regex to find a single character in a string. You can use indexOf, like this:
var hasHashtag = str.indexOf('#') >= 0;
This returns true if the character is in the string.
Use includes to check the existence of # in your string. You don't actually require regex to do that.
var str = 'someSt#ring';
var res = str.includes('#');
console.log(res);
str = 'someSt#ri#ng';
res = str.includes('#');
console.log(res);
str = 'someString';
res = str.includes('#');
console.log(res);
Use indexOf
str.indexOf('#') >= 0;
This question already has answers here:
JavaScript Regex, where to use escape characters?
(3 answers)
Closed 8 years ago.
I'm unable to parse a regex. I've tested it from regexpal.com and regex101.com (by setting the expression as "(?:^csrf-token|;\s*csrf-token)=(.*?)(?:;|$)" and the test string as "__ngDebug=false; csrf-token=b2ssOJ4jNOlPdmXAHn4CORPvFoO4Ngsupej25tdj") where it works.
The example is jsfiddle.
function getCookie(name) {
var s = "__ngDebug=false; csrf-token=b2ssOJ4jNOlPdmXAHn4CORPvFoO4Ngsupej25tdj";
var regexp = new RegExp("(?:^" + name + "|;\s*"+ name + ")=(.*?)(?:;|$)", "g");
var result = regexp.exec(s);
return (result === null) ? null : result[1];
}
alert(getCookie("csrf-token"));
If however s is "csrf-token=b2ssOJ4jNOlPdmXAHn4CORPvFoO4Ngsupej25tdj", then it works fine. Please tell me what's wrong.
The expected output is "b2ssOJ4jNOlPdmXAHn4CORPvFoO4Ngsupej25tdj", and there is no input (the string to be tested is 's').
Change
"|;\s*"
to
"|;\\s*"
^
The thing is, you are constructing the RegExp by passing in a string via the constructor, so you need to follow the rule of escaping in string literal. In JavaScript, "\s" is recognized as a single character string, with lowercase s. To specify \, you need to escape it.
You should escape \s
var regexp = new RegExp("(?:^" + "csrf-token" + "|;\\s*"+ "csrf-token" + ")=(.*?)(?:;|$)", "g");
^
This question already has answers here:
How do I replace all occurrences of a string in JavaScript?
(78 answers)
Closed 8 years ago.
I have a string as follows:
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f";
How do I remove the '=' character from this? I've tried a couple of different ways but the '=' character seems to be causing a conflict
If it's always the first character then this will work...
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f".substring(1);
If it's not definitely the first character then this will work...
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f".replace("=", "");
If it's in there more than once then this will work...
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f".split("=").join("");
You can use .replace():
The replace() method returns a new string with some or all matches of
a pattern replaced by a replacement
string = string.replace('=','');
Fiddle Demo
Its very simple.
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f";
string=string.replace('=','');
To get rid of the first character:
string = string.substring(1);
Do this:
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f";
if(string.indexOf('=')>=0){ //check string contains =
string = string.replace("=",'');
}
This question already has answers here:
How can I get last characters of a string
(25 answers)
Closed 10 years ago.
If I have the following variable in javascript
var myString = "Test3";
what is the fastest way to parse out the "3" from this string that works in all browsers (back to IE6)
Since in Javascript a string is a char array, you can access the last character by the length of the string.
var lastChar = myString[myString.length -1];
It does it:
myString.substr(-1);
This returns a substring of myString starting at one character from the end: the last character.
This also works:
myString.charAt(myString.length-1);
And this too:
myString.slice(-1);
var myString = "Test3";
alert(myString[myString.length-1])
here is a simple fiddle
http://jsfiddle.net/MZEqD/
Javascript strings have a length property that will tell you the length of the string.
Then all you have to do is use the substr() function to get the last character:
var myString = "Test3";
var lastChar = myString.substr(myString.length - 1);
edit: yes, or use the array notation as the other posts before me have done.
Lots of String functions explained here
myString.substring(str.length,str.length-1)
You should be able to do something like the above - which will get the last character
Use the charAt method. This function accepts one argument: The index of the character.
var lastCHar = myString.charAt(myString.length-1);
You should look at charAt function and take length of the string.
var b = 'I am a JavaScript hacker.';
console.log(b.charAt(b.length-1));