This question already has answers here:
How can I get last characters of a string
(25 answers)
Closed 10 years ago.
If I have the following variable in javascript
var myString = "Test3";
what is the fastest way to parse out the "3" from this string that works in all browsers (back to IE6)
Since in Javascript a string is a char array, you can access the last character by the length of the string.
var lastChar = myString[myString.length -1];
It does it:
myString.substr(-1);
This returns a substring of myString starting at one character from the end: the last character.
This also works:
myString.charAt(myString.length-1);
And this too:
myString.slice(-1);
var myString = "Test3";
alert(myString[myString.length-1])
here is a simple fiddle
http://jsfiddle.net/MZEqD/
Javascript strings have a length property that will tell you the length of the string.
Then all you have to do is use the substr() function to get the last character:
var myString = "Test3";
var lastChar = myString.substr(myString.length - 1);
edit: yes, or use the array notation as the other posts before me have done.
Lots of String functions explained here
myString.substring(str.length,str.length-1)
You should be able to do something like the above - which will get the last character
Use the charAt method. This function accepts one argument: The index of the character.
var lastCHar = myString.charAt(myString.length-1);
You should look at charAt function and take length of the string.
var b = 'I am a JavaScript hacker.';
console.log(b.charAt(b.length-1));
Related
This question already has answers here:
Regular Expression to get a string between parentheses in Javascript
(10 answers)
Closed 4 years ago.
How can I modify this string:
"SRID=4326;POINT (-21.93038619999993 64.1444948)"
so it will return
"-21.93038619999993 64.1444948"
(and then I can split that)?
The numbers in the string can be different.
I've tried using .replace & split, but I couldn't get it to work properly. How can I make this happen using Javascript?
You can try with match and regex:
"SRID=4326;POINT (-21.93038619999993 64.1444948)".match(/\(([^)]+)\)/)[1]
// "-21.93038619999993 64.1444948"
I am not good using REGEXP but this could be a solution with pure split.
Hope it helps :>
var str = "SRID=4326;POINT (-21.93038619999993 64.1444948)" ;
var newStr = str.split('(')[1].split(')')[0];
console.log(newStr)
var new_string = string.replace("SRID=4326;POINT (", "");
You can use a regular expression. The first number is put in first, the second number is put in second.
const INPUT = "SRID=4326;POINT (-21.93038619999993 64.1444948)";
const REGEX = /SRID=\d+;POINT \((.+) (.+)\)/
const [_, first, second] = INPUT.match(REGEX);
console.log(first);
console.log(second);
This question already has answers here:
Regular expression greater than and less than
(3 answers)
Closed 8 years ago.
I need a regular expression that replaces the greater than and less than symbol on a string
i already tried
var regEx = "s/</</g;s/>/>/g"
var testString = "<test>"
alert(testString.replace(regEx,"*"))
My first time to use it please go easy on me :)
Thanks
You can use regEx | like
var regEx = /<|>/g;
var testString = "<test>"
alert(testString.replace(regEx,"*"))
Fiddle
For greater than and less than symbol.
var string = '<><>';
string = string.replace(/[\<\>]/g,'*');
alert(string);
For special characters
var string = '<><>';
string = string.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g,'_');
alert(string);
Insert the regular expression in the code before class
using System.Text.RegularExpressions;
below is the code for string replace using regex
string input = "Dot > Not Perls";
// Use Regex.Replace to replace the pattern in the input.
string output = Regex.Replace(input, "some string", ">");
source :
http://www.dotnetperls.com/regex-replace
This question already has answers here:
How do I replace all occurrences of a string in JavaScript?
(78 answers)
Closed 8 years ago.
I have a string as follows:
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f";
How do I remove the '=' character from this? I've tried a couple of different ways but the '=' character seems to be causing a conflict
If it's always the first character then this will work...
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f".substring(1);
If it's not definitely the first character then this will work...
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f".replace("=", "");
If it's in there more than once then this will work...
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f".split("=").join("");
You can use .replace():
The replace() method returns a new string with some or all matches of
a pattern replaced by a replacement
string = string.replace('=','');
Fiddle Demo
Its very simple.
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f";
string=string.replace('=','');
To get rid of the first character:
string = string.substring(1);
Do this:
var string = "=09e8d76c-c54c-32e1-a98e-7e654d32ec1f";
if(string.indexOf('=')>=0){ //check string contains =
string = string.replace("=",'');
}
This question already has answers here:
How do I replace a character at a particular index in JavaScript?
(30 answers)
Closed 9 years ago.
I'm sure this was supposed to work, but I can't get it doing what I want it to:
new_str = old_str.replace(3, "a");
// replace index 3 (4th character) with the letter "a"
So if I had abcdef then above should return abcaef but I must have gotten something wrong. It is changing characters, but not the expected ones.
Either native JS or jQuery solution is fine, whatever is best (I'm using jQuery on that page).
I've tried searching but all tutorials talk of Regex, etc. and not the index replace thing.
You appear to want array-style replacement, so convert the string into an array:
// Split string into an array
var str = "abcdef".split("");
// Replace char at index
str[3] = "a";
// Output new string
console.log( str.join("") );
Here are three other methods-
var old_str= "abcdef",
//1.
new_str1= old_str.substring(0, 3)+'a'+old_str.substring(4),
//2.
new_str2= old_str.replace(/^(.{3}).(.*)$/, '$1a$2'),
//3.
new_str3= old_str.split('');
new_str3.splice(3, 1, 'a');
//return values
new_str1+'\n'+new_str2+'\n'+ new_str3.join('');
abcaef
abcaef
abcaef
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
JavaScript Split without losing character
I have a string:
"<foo>abcdefg</bar><foo>abcdefg</bar><foo>abcdefg</bar><foo>abcdefg</bar>"
I want to separate all instances of "abcdefg" into an array like this:
["<foo>abcdefg</bar>", "<foo>abcdefg</bar>", "<foo>abcdefg</bar>", "<foo>abcdefg</bar>"];
I try:
var str="<foo>abcdefg</bar><foo>abcdefg</bar><foo>abcdefg</bar><foo>abcdefg</bar>";
var Array_Of_FooBars = str.split("</bar>");
alert(Array_Of_FooBars);
But it returns:
["<foo>abcdefg", "<foo>abcdefg", "<foo>abcdefg", "<foo>abcdefg",]
It is removing the separator ''. I don't want that.
How can I use split and not lose the separators from the string?
Thanks.
Ken
Try this. It's not a perfect solution, but it should work in most cases.
str.split(/(?=<foo>)/)
That is, split it in the position before each opening tag.
EDIT: You could also do it with match(), like so:
str.match(/<foo>.*?<\/bar>/g)
It seems that you would most likely want to use match:
var s = "<foo>abcd1efg</bar><foo>abc2defg</bar><foo>abc3defg</bar><foo>abc4defg</bar>"
s.match(/(<foo>.+?<\/bar>)/g)
// =>["<foo>abcd1efg</bar>", "<foo>abc2defg</bar>", "<foo>abc3defg</bar>", "<foo>abc4defg</bar>"]
You could just iterate over a simple regular expression and build the array that way:
var x = new RegExp('<foo>(.*?)</bar>', 'ig'),
s = "<foo>abcdefg</bar><foo>abcdefg</bar><foo>abcdefg</bar><foo>abcdefg</bar>",
matches = [];
while (i = x.exec(s)) {
matches.push(i[0]);
}
Just realized using String.match() would be better; this code would be more useful for matching the contents inside the tags.
Use positive lookahead so that the regular expression asserts that the special character exists, but does not actually match it:
string.split(/<br \/>(?=&#?[a-zA-Z0-9]+;)/g);