Develop Reference

Login slider with jQuery issues

I want to make a login slider with jQuery. You will have a div at the top of your page with a plus image. I want the plus image to be changed into a minus image and the div will slide down. Here is my code but there is a problem.
<script src="_js/jquery-1.7.2.min.js"></script>
<script>
$(document).ready(function() {
$("form").hide();
$(".open").click(function() {
$("form").slideDown("slow");
$(".open").addClass("close");
$(".close").removeClass("open");
$(".close").click(function() {
$("form").slideUp("slow");
$(".close").addClass("open");
$(".open").removeClass("close");
});
});
});
</script>
It works once but if you want to slide it down for the second theme it doesn't work anymore.. Can somebody help my please?
tnx!

Working JSFiddle
Try something different like the following:
$('.open').click(function () {
$('form').slideToggle('slow', function () {
$('.open').toggleClass('form-is-open');
});
});
jQuery offers some toggle functions which supply the desired behaviour. This way you don't need two click handlers or keep track of classes yourself. The above code simply adds a class ('form-is-open') to the button, when the form is shown and removes it, when it is hidden.

whole page moves a bit when a show function is executed

I am trying to build my first website www.angelosmavraidis.com
I have inserted a javascript to show 8 divs of the same class when clicking on the "artwork" div.
The problem is that when the "artwork" is clicked and the rest of the divs show up the whole page moves a bit to the left.
Anyone know why this is happening?
Also can you recommend a better alternative to the following script to do the job?
$(document).ready(function(e) {
$('.mainmenu').each(function(index, element) {
$(this).click(function() {
$('.artwork').eq(index).show();
});
});
});
Thanks

Use preventDefault here like
$(document).ready(function(e) {
$('.mainmenu').each(function(index, element) {
$(this).click(function(ev) {
ev.preventDefault();
$('.artwork').eq(index).show();
});
});
});

Make toggle link only effect box in the same parent

So I currently have two toggle boxes set up and there will be more soon, I'd like to keep the JS pretty simple and not have a new script for each area, but whenever I attempt to toggle in one place it applies the function to both other the toggle-content boxes I have set up.
In order to see both areas, open the first one and close it before opening the second so a product is added to the Recently Viewed box
http://www.coreytegeler.com/bolivares/shop/pablo-ribbed-winter-skully/
http://www.coreytegeler.com/bolivares/shop/salvador-crewneck-sweater-copy/
Here's what I have in place now:
$(window).load(function(){
$('.toggle-link').click(function(e){
$('.toggle-content').slideToggle();
e.preventDefault();
});
$(".toggle-link div").click(function()
{
$(".toggle-link div").toggle();
});
});
I tried using $(this).find('.toggle-content').slideToggle(); but still no luck.
I know this is a pretty easy fix but just can't figure it out.
Any help would be great!

$(document).ready(function(){
$('.toggle-link').click(function(e){
$(this).closest("ul").children('.toggle-content').slideToggle();
$(this).children('div').toggle();
});
});

Unable to show the div on body load

This is my code posted in a jsfiddle Demo.
As you can see when you click on the
Hyderabad.
Visakhapatnam.
Then a Horizontal Image slider is shown ( YOu can slide throgh the Pictures )
Now my requirement is I need to also show the Image slider on body load itself also
I have tried using body onload function to show the div , and also in Jquery ready function , and by commenting all the hide() functions in javascript , but none of them really worked .
Could anybody please tell me what is the way to do this .

I just tested it.. first I thought that you should just do this:
jQuery(document).ready(function() {
$fp_galleries.first().click();
});
but poorly this will only show the first image and not all images.
I don't know why but it looks like you should do this.
$(window).load(function() {
/* your code */
$fp_galleries.first().click();
});
Maybe because you need to wait until the images are loaded.

perhaps use document on ready to call the function: http://api.jquery.com/ready/
$(document).ready(function() {
openGallery(galleryname){
})
;

The problem is not that it is hidden, its rather that the content are only generated by som javascript when the user clicks one of your links.
You could add something like
$("li",$fp_galleries).first().click()
at the bottom of your script.
This will trigger the click event on one of the links.

fadeIn as callback function after fadeOut doenst work as expected

In my HTML a#navInnerMapR and a#navInnerMapL are contained within div#navTwo.
The following code is within a function. When called, I need the function to fadeOut any visible links in div#navTwo, pause for a moment, and then fadeIn a#navInnerMapR.
$('div#navTwo a').fadeOut(200, function() {
$('a#navInnerMapR').delay(100).fadeIn(200);
});
The code fades out the links but doesn't fade anything in. I thought that they delay would only start once the fadeOut finishes, however changing the delay value to 1000 makes it sometimes work but its very buggy. Thanks
UPDATE Here is a fiddle showing that the hidden link starts to be shown before the visible is hidden: http://jsfiddle.net/jamesbrighton/d9QKr/5/
UPDATE Apologies, my question doesnt include the full details of what I need to achieve. I simplified it as I thought I just had some sort of sytax issus that could be easily fixed.
div#navTwo actually contains 3 links. At any point (other than the delay before animations run) only 1 link is visible. I need to be able to call a function that will hide either of the other 2 links that are being shown, and then show a#navInnerMapR.
Different events will call this function, so either of the 2 links that arn't a#navInnerMapR may be visible. Thanks
UPDATE I think this fiddle illustrates the issue. Ive created 2 div.nav's to illustrate different states. Ive hidden different links with inline CSS in each one. JavaScript will be showing and hiding the links in my div repeatedly, so the same div will look like each example at different times.
Ive created 2 triggers to illustrate that different events will need to call the function. When you click on a trigger you can see the issue with both examples. The visible divs are not hidden before the a.one is shown. Thanks for your patience!
http://jsfiddle.net/jamesbrighton/dYvMS/24/
Interesting point, if I change $('.nav a.one').fadeIn(1000); to an alert, the alert fires multiple times! No idea why this would be the case!

Edit: Updated answer based on your below comment,
Yes this works as I need, but im not sure it will work for my actual
page. Sorry for my question not being detailed enough. The code
example I gave is simplified. In the actual page their are 3 links
within div#navTwo, at any time only one of them will be visible. I
need to be able to call a function that hides any links and shows a
specific one, but either one of the other 2 links in div#navTwo may be
visible. Thanks
DEMO
HTML: Added class to all links inside navTwo
<div id="navTwo">
Right
Left
Middle
Upper
Lower
</div>
JS:
$('.links').click(function() {
showHide($(this));
});
function showHide($this) {
$this.fadeOut(1000, function() {
$('#navTwo a').not($this).delay(1000).fadeIn(1000);
});
}
I think I understood what you need. Try below DEMO and let me know if that is what you want,
DEMO
$('#navInnerMapR').click(function() {
runMeR($(this));
});
$('#navInnerMapL').click(function() {
runMeL($(this));
});
function runMeR($this) {
$this.fadeOut(1000, function() {
$('a#navInnerMapL').delay(1000).fadeIn(1000);
});
}
function runMeL($this) {
$this.fadeOut(1000, function() {
$('a#navInnerMapR').delay(1000).fadeIn(1000);
});
}

As you said, You need the function to fadeOut any visible links in div#navTwo, pause for a moment, and then fadeIn a#navInnerMapR (not other links, only a#navInnerMapR).
$('#navTwo a').click(function(e) {
$(this).parent().children().each(function(i){
$(this).fadeOut('slow', function(){
$('a#navInnerMapR').delay(1000).fadeIn(1000);
});
});
});​
A fiddle is here.