This would seem like an easy problem but I am having some trouble figuring this one out. The example given is a SSCCE and I have a larger problem that this attempts to solve. In order for this to work the query must NOT contain any immediate child selectors (>) due to the dom tree being a bit more complex than this example.
My goal here is to select all children whom aren't underneath a parent who contains a class. In this example I am trying to select the 2 div containers hello and world but not foo and bar.
Here is a plunker that has the code in it for your convience. http://plnkr.co/edit/4zsKAFts5X7X2kLADj2V?p=preview
Using this HTML:
<div id="root" class="parent">
<div>
<div class="child">hello</div>
<div class="child">world</div>
</div>
<div class="parent">
<div>
<div class="child">foo</div>
<div class="child">bar</div>
</div>
</div>
</div>
And this Javascript:
var root = $('#root');
$(':not(.parent) .child', root).css('font-weight', 'bold');
I am seeing this result:
hello
world
foo
bar
But what I would like to get is
hello
world
foo
bar
To reiterate I want to get all elements with class child who dont have a parent with class parent starting from a given node (in this example #root).
var root = $('#root');
$('.child', root).not($("#root .parent .child")).css('font-weight', 'bold');
jsFiddle example
It might not be pretty but here you go:
$('#root').find('.child').filter(function(){
if($(this).parents('.parent').first().attr('id') === 'root'){
return 1;
}
else{
return 0;
}
}).css('font-weight', 'bold');
http://jsfiddle.net/PDZL8/
JSFiddle: http://jsfiddle.net/TrueBlueAussie/78G6N/3/
var root = $('#root');
$('#root').find('.child').filter(function(){
return $(this).closest('.parent').is(root);
}).css('font-weight', 'bold');
I also improved j08691's solution so that it uses the root node supplied, rather than duplicating the selector (which is not portable):
http://jsfiddle.net/TrueBlueAussie/78G6N/4/
var root = $('#root');
$('.child', root).not(root.find(".parent .child")).css('font-weight', 'bold');
You can use this :
$('#root').find('.child').filter(function(){
return $(this).parents('.parent').length <= 1;
}).css('font-weight', 'bold');
It check the number of parent the div has and if it is lower or equal than 1, it return the child.
Fiddle : http://jsfiddle.net/akwPb/
$("#root .child:not(#root .parent * .child)")
.css("font-weight", "bold")
jsfiddle http://jsfiddle.net/guest271314/UJJXU/
Related
Is there a way to assign nested div attribute with variable? Like
<div>
<div>
123456
</div>
</div>
Become
<div>
<div sectionid="123">
123456
</div>
</div>
BTW above component will be created by JavaScript.
I've tried something like this, but it didn't work.
var a = $('<div><div>123456</div></div>');
a.eq(":nth-child(2)").attr("sectionid", "123");
Try this snippet.
//FOR DOM HTML
console.log("FOR DOM HTML");
//1st way
$('#input > div').find('div').attr("sectionid","123");
console.log($('#input').html());
//2nd way
$('#input > div > div').attr("sectionid","321");
console.log($('#input').html());
//JS HTML
console.log("FOR JS OBJECT");
var input = $('<div><div>123456</div></div>');
//1st way
input.eq(0).children().attr('sectionid', '456');
console.log(input[0].outerHTML);
var input = $('<div><div>123456</div></div>');
//2nd way
$(input[0]).children().attr('sectionid', '789');
console.log(input[0].outerHTML);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="input">
<div>
<div>
123456
</div>
</div>
</div>
nth-child(2) maches elements that are the second child element of their parent. This is not the case for your div, it is the first element of the parent div.
.eq finds an element at a specific index. It is not the place to pass a selector.
The child selector, >, will find a child element, i.e. div>div will find a div that is an immediate child of a div.
Note that the code you've provided, $('<div></div>123456<div></div>');, doesn't create a DOM tree like the one you've pasted.
Update, now that the code is edited, the value of a is a div with a child div. Since a.find will perform a search within a, you don't have to use a child selector, but can find the div immediately:
a.find('div')
Just apply attribute to children. No complicated 'find', eq(), etc.
var a = $('<div><div>123456</div></div>');
a.children().attr('sectionid', '123');
$('body').append(a);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Why don't you add it in the first place? Not clear if you add it later!
$(document).ready(function() {
var sectionid = "123";
var a = $('<div><div sectionid="' + sectionid + '">123456</div></div>');
$('body').append(a);
});
div[sectionid]{
color: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Try this - I have added comments to the code to explain what is happening.
Inspect the element to see that the attribute is added
var a = $('<div><div>123456</div></div>'); // change this to match the structure you want
a.children() // .children gets the direct descendant (which should be the nested div
.eq(0) // gets the first in the array that is returned (if there are multiple direct descendents) - it is a 0 based index selector
.attr('sectionid', '123');
$('body').append(a)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
More information about .children()
More information about .eq()
try it :
$(document).ready(function(){
$("div").eq(1).attr("sectionid","123");
})
In an attempt to make my answer more flexible on this question:
function invertDivs(parentDiv) {
var first = document.getElementById(parentDiv).firstChild;
console.log(first);
var second = document.getElementById(parentDiv).lastChild;
console.log(second);
document.getElementById(parentDiv).insertBefore(second, first);
}
<div id="parent">
<div id="first">Div 1</div>
<div id="second">Div 2</div>
</div>
<button onclick="invertDivs('parent');">Invert Divs</button>
However, the divs are only inverted sometimes, not always.
An initial click on the button yields this on the console:
A second click:
After a bunch of clicks:
I'm confused as to what's wrong with the code. I select the first child of parent div, and do the same for the last child. Then I just insert the current second div before the first. That's the end of the function. They are also the direct children of the parent div, as required by the insertBefore function.
As mentioned in comments, firstChild and lastChild can return text nodes for the whitespace between elements. You can use firstElementChild and lastElementChild to ignore these.
function invertDivs(parentDiv) {
var first = document.getElementById(parentDiv).firstElementChild;
console.log(first);
var second = document.getElementById(parentDiv).lastElementChild;
console.log(second);
document.getElementById(parentDiv).insertBefore(second, first);
}
<div id="parent">
<div id="first">Div 1</div>
<div id="second">Div 2</div>
</div>
<button onclick="invertDivs('parent');">Invert Divs</button>
For some other workarounds, which you might need for older browsers, see element.firstChild is returning '<TextNode ...' instead of an Object in FF
You're not taking into account text nodes. In your HTML example above, there are 5 nodes.
[0] => TextNode
[1] => #first
[2] => TextNode
[3] => #second
[4] => TextNode
It seems pretty evident that you don't care about the text nodes here. You have quite a few options.
One option would be to filter out all the text nodes. (Can't use Array.prototype.filter method because childNodes is not an array, but a NodeList)
This will give you an array of only DOM elements.
function invertDivs(parentNodeId) {
var childElements = [],
parentNode = document.getElementById(parentNodeId);
//Filter out the child nodes that aren't elements.
//parentNode.childNodes is a NodeList, and not an array (even though it looks like one)
for (var i = 0; i < parentNode.childNodes.length; ++i) {
if (parentNode.childNodes[i].nodeType === 1)
childElements.push(parentNode.childNodes[i]);
}
parentNode.insertBefore(childElements[childElements.length - 1], childElements[0]);
}
<div id="parent">
<div id="first">Div 1</div>
<div id="second">Div 2</div>
</div>
<button onclick="invertDivs('parent');">Invert Divs</button>
Another option would be to use the more modern DOM API properties: See Barmar or GolezTrol's answers. They would be much more performant if you audience has support for IE9+ browsers.
It's not random. If I click 2 times, to add Div 2 to the end of the list, then click 3 times to get Div 1 at the end of the list. This pattern repeats.
The reason is because there are also next nodes inbetween. This is the whitespace inbetween the elements.
To work around this, use the children attribute. This selects the child elements (instead of nodes).
function invertDivs(parentDiv) {
var parent = document.getElementById(parentDiv);
var first = parent.children[0];
console.log(first);
var second = parent.children[parent.children.length-1];
console.log(second);
document.getElementById(parentDiv).insertBefore(second, first);
}
<div id="parent">
<div id="first">Div 1</div>
<div id="second">Div 2</div>
</div>
<button onclick="invertDivs('parent');">Invert Divs</button>
The answer to your question is given in the MDN docs(https://developer.mozilla.org/en-US/docs/Web/API/Node/firstChild) for Node.firstChild. If you refer to docs you will understand why you are getting the #text as the first Node.
i have got this :
<div id="video_pattern">
<div id="des"position:relative;></div>
<div id="mes"position:relative;></div>
</div>
i want to remove the
> <div id="video_pattern">
but the
<div id="des"position:relative;></div>
<div id="mes"position:relative;></div>
should stay, is this possible?
To handle your exact situation you can use this code:
var ToRemoveElement = document.getElementById("video_pattern");
ToRemoveElement.parentNode.appendChild(document.getElementById("des"));
ToRemoveElement.parentNode.appendChild(document.getElementById("mes"));
ToRemoveElement.remove();
This is the way to go if you only want these specific elements removed from the video_pattern div. If you want a more generic solution to remove all child elements then use the following:
var ToRemoveElement = document.getElementById("video_pattern");
var children = ToRemoveElement.children;
while (children.length > 0) {
ToRemoveElement.parentNode.appendChild(children[0]);
}
ToRemoveElement.remove();
JSfiddle example
Using Jquery you can do like this
var inner = $("#video_pattern").contents();
$("#video_pattern").replaceWith(inner);
I want to be able to remove HTML elements if they contain no content.
Let's say we have some markup and are targeting all 'collapse' classes:
<div class='collapse'>[CONTENT?]</div>
If there is some content then don't do anything.
But if there is no content - no string characters or whitespace - then remove the div element completely.
This is easy to implement in the simple cases but with nested content it's slightly more more tricky.
Here is a demo, if you try removing the [CONTENTX?] strings and then seeing what the HTML structure is you'll notice that it doesn't work completely.
If a div only has other divs with no content then that should be treated as no characters or whitespace.
If we remove all [CONTENTX?] strings then we should see no HTML structure.
What ways are there to handle this?
jsFiddle: http://jsfiddle.net/97udq/
HTML:
<div id='container'>
<div class='collapse'>
[CONTENT1?]
</div>
<div class='collapse'>
[CONTENT2?]
<div class='collapse'>
[CONTENT3?]
<div class='collapse'>[CONTENT4?]</div>
<div class='collapse'>[CONTENT5?]</div>
</div>
</div>
</div>
Javascript:
$(function(){
// function
collapse();
// Show HTML structure
alert($('#container').html());
});
function collapse(){
// Loop thru all collapse elements
$('.collapse').each(function(){
// Check for pure whitespace
if($(this).html().replace(/\s+/g, '').length==0){
// Nothing to see, so remove.
$(this).remove();
}
});
}
CSS:
.collapse{
height:20px;
border:1px solid red;
}
I think this does the job;
It just uses text() instead of html();
Here's the documentation.
This one adds the trim(), but I thik that's not what you want.
function collapse(){
$('.collapse').each(function(){
if($(this).text().length==0){
$(this).remove();
}
});
}
Here's another way of accomplishing what you want. It recurses down the DOM pruning nodes from the bottom up. Hope this helps.
function prune(root) {
$.each($(root).children(), function(){
prune($(this));
});
if($(root).html().replace(/\s+/g, '').length==0 && $(root).hasClass("collapse")){
$(root).detach();
}
}
Code integrated into your JSFiddle
You need to recreate the .each() loop, but reversed. Just like that :
function collapse(){
var el = $('.collapse');
for(var i = el.length - 1; i >= 0; i--){
if(el[i].innerHTML.replace(/\s+/g, '').length==0){
$(el[i]).remove();
}
}
}
It will remove the childrens first, then check for parent.
Here a fiddle : http://jsfiddle.net/97udq/5/
EDIT :
I missunderstood your question, here's the right solution :
function collapse(){
$('.collapse').each(function(){
var $this = $(this)
var clone = $this.clone();
clone.children().remove();
if(clone.html().replace(/\s+/g, '').length==0){
$this.children().appendTo($this.parent());
$this.remove()
}
})
}
Basicly, you clone the current div, remove its children and then check if there is some text. If there's none, you append his children to his parent
Fiddle : http://jsfiddle.net/97udq/9/
I am looking for a way to wrap, with jQuery, an element into a comment, like:
<!--
<div class="my_element"></div>
-->
and also a way to remove the comments.
Is this possible?
To wrap an element with comment, or more specifically to replace an element with a comment node having that element's HTML:
my_element_jq = $('.my_element');
comment = document.createComment(my_element_jq.get(0).outerHTML);
my_element_jq.replaceWith(comment);
To switch it back:
$(comment).replaceWith(comment.nodeValue);
If you don't have the reference to the comment node then you need to traverse the DOM tree and check nodeType of each node. If its value is 8 then it is a comment.
For example:
<div id="foo">
<div>bar</div>
<!-- <div>hello world!</div> -->
<div>bar</div>
</div>
JavaScript:
// .contents() returns the children of each element in the set of matched elements,
// including text and comment nodes.
$("#foo").contents().each(function(index, node) {
if (node.nodeType == 8) {
// node is a comment
$(node).replaceWith(node.nodeValue);
}
});
You can comment the element out by doing the following:
function comment(element){
element.wrap(function() {
return '<!--' + this.outerHTML + '"-->';
});
}
DEMO:
http://jsfiddle.net/dirtyd77/THBpD/27/
I'm impresed nobody gave the following solution. The following solution require a container. This container will have inside, the commented / uncommented code.
function comment(element) {
element.html('<!--' + element.html() + '-->')
}
function uncomment(element) {
element.html(element.html().substring(4, element.html().length - 3))
}
function isCommented(element) {
return element.html().substring(0, 4) == '<!--';
}
Example: https://jsfiddle.net/ConsoleTVs/r6bm5nhz/
For wrapping?
function wrap(jQueryElement){
jQueryElement.before("<!--").after("-->");
}
Not sure how successful you'd be finding the comments once wrapped though. A text search on the body element using regular expressions is an option.
Or this - is it possible to remove an html comment from dom using jquery