I have question that I feel should be simple but I am having issues getting the result I need. I can not change the HTML. Any help would be great!
I have a set up like this.
<div class="container">
<div class='mydiv'>this is text1</div>
</div>
<div class="container">
<div class='mydiv'>this is text2</div>
</div>
I am trying to get the text from each of those divs, set it to a var that I can then use to add a data attribute to the above it.
var DivText = $('mydiv').text();
$('.myAtag').attr('data', 'DivTest');
The problem I run into this that the data attribute is then filled with the text from both divs.
<div class="container">
<div class='mydiv'>this is text1</div>
</div>
<div class="container">
<div class='mydiv'>this is text2</div>
</div>
What can I use/how can I modifiy my jquery to achieve this outcome?
<div class="container">
<div class='mydiv'>this is text1</div>
</div>
<div class="container">
<div class='mydiv'>this is text2</div>
</div>
Use a callback to set each data attribute differently
$('.myAtag').attr('data-text', function() {
return $(this).next('.mydiv').text();
});
FIDDLE
It's usually a good idea to use a key, as in data-whatever
You could also use data(), but that sets the data internally in jQuery and does not add an attribute
Related
Is there any way I can remove the element in JS and to move inside another class. I have tried multiple ways but its throwing an error.
<div class="posts container">
<div class="row">
<div class="posts-item col-md-7 col-xs-12 p-0">
Abc
</div>
<ul>
</ul>
</div>
</div>
<div class="blog">
XYZ
</div>
I am trying to get output like using Javascript
<div class="posts container">
<div class="row">
<div class="posts-item col-md-7 col-xs-12 p-0">
Abc
</div>
<div class="blog">
XYZ
</div>
<ul>
</ul>
</div>
</div>
Iam trying to move the class name "blog" inside "posts-item".
Use insertBefore for moved your item:
const referenceNode = document.querySelector('.posts-item')
referenceNode.parentNode.insertBefore(document.querySelector('.blog'), referenceNode.nextSibling);
Try something like this, which works in Chrome for me, for the result you describe in the text:
document.querySelector('.posts-item').append(document.querySelector('.blog'))
...or to get the result you've illustrated, perhaps this:
document.querySelector('.posts-item').after(document.querySelector('.blog'))
You may need to modify the selectors if there are more elements sharing the classes used.
See docs at https://developer.mozilla.org/en-US/docs/Web/API/ChildNode/after and https://developer.mozilla.org/en-US/docs/Web/API/ParentNode/append
New to js.
I want to be able to say if there are 2 classes on that page then insert another class but if there is 3 classes then insert a different class.
sometimes the page will be like...
<div class="wrapper">
<div class="compare"></div>
<div class="compare"></div>
</div>
and sometimes the page might be
<div class="wrapper">
<div class="compare"></div>
<div class="compare"></div>
<div class="compare"></div>
</div>
and sometimes like
<div class="wrapper">
<div class="compare"></div>
<div class="compare"></div>
<div class="compare"></div>
<div class="compare"></div>
</div>
I need to add a class to compare if the page display 2 classes of compare or add a different class if the page has 3 classes of compare
Thanks in advance
Ollie
Using jQuery you can do like this ( Assuming you are using it)
$(document).ready(function() {
if($('.compare').length >=2 ) {
//$('yourContainer').addClass('your-new-class');
//add your code as per your need.
}
});
How do I move the contents of a div to the contents of another div?
I want to move .sidebar from .post to .carousel. How to do it by using javascript?
I want to go from this:
<div class="container">
<div class="carousel">
<div class="row">
<div class="post">
<div class="sidebar"></div>
</div>
</div>
</div>
</div>
to this:
<div class="container">
<div class="carousel">
<div class="row">
<div class="post"></div>
<div class="sidebar"></div>
</div>
</div>
</div>
document.getElementsByClassName('row')[0].appendChild(document.getElementsByClassName('sidebar')[0]);
I'd suggest, on the off-chance you've more than one element with that class (and assuming that in all instances they should be inserted after their parentNode):
$('.sidebar').each(function(){
$(this).insertAfter(this.parentNode);
});
JS Fiddle demo.
References:
each().
insertAfter().
Assuming you only have only one such occurrence, you can use plain JavaScript:
var sidebar = document.getElementsByClassName('sidebar')[0];
// move after parent node
sidebar.parentNode.parentNode.appendChild(sidebar);
The appendChild() function moves rather than copies existing elements from their previous location in the tree. To perform a copy you would need to clone the respective elements first.
Try to use JQuery Draggable() and Droppable() functions.
See the Demo...
Droppable | JQuery UI
I'm working on a responsive tumblr-theme based on the 1140GRID. To make the static videos fit the column, I used the jquery fitvids plugin.
My setup code looks like this:
$(document).ready(function(){
$("#post_{PostID}").fitVids();
});
and the accompanying html like this:
<div class="container">
<div class="row">
<div class="ninecol"> //grid I want it to fit into
{Block:Video}
<div id="post_{PostID}">
{Video-500}
</div>
{/Block:Video}
</div>
</div>
</div>
How do I trigger fitVids for multiple, dynamically generated ids on a page?
Thank you!
You may want to put that closing DIV inside the video block.
<div class="container">
<div class="row">
<div class="ninecol"> //grid I want it to fit into
{Block:Video}
<div id="post_{PostID}">
{Video-500}
</div>
{/Block:Video}
</div>
</div>
</div>
Then, you could target all the subdivs of ninecol.
<script>
$(document).ready(function(){
$('.ninecol > div').fitVids();
});
</script>
Can someone please explain the structure of this line of a script for me? Another user on here has written it as part of a function that I know want to edit and change to use elsewhere on my site.
$('#main_content .img-wrapper').empty().append($(this).find('img').clone());
This one takes an image from one div and copies it to another with the class="img-wrapper"
I want to do exactly the same but with text. I tried this
$('#main_content .text-wrapper').empty().append($(this).find('.info').clone());
where ('.info') is the class name of the div I want to copy. Its not working.
I don't fully understand the syntax as this is my first day using javascript. Please can someone explain where I'm going wrong?
This is the HTML - There are four different images and when the user clicks on each of the image I want it to load the same image and associated text in the main content div
<div class="row">
<div class="card-container">
<div class="card">
<div class="back">
<img src="images1.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#cc99cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images2.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#9966cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images3.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#6666cc;"></div>
</div>
</div>
<div class="card-container">
<div class="card">
<div class="back">
<img src="images4.png" />
<div class="info" style="display: none;">This is a test for image one</div>
</div>
<div class="front" style="background-color:#3366cc;"></div>
</div>
</div>
This is the main content div
<div id="main_content">
<!-- main content -->
<div class="img-wrapper">
</div>
<div class="text-wrapper">
</div>
</div>
The javascript in question is using jQuery.
$('#main_content .img-wrapper')
returns the element(s) with class 'img-wrapper' inside the element with id 'main_content'
.empty()
empties this element (removes all it's HTML contents)
.append(
inserts the argument (the bit that comes next) into this element
$(this).find('img')
finds all 'img' tags within the element referred to by this (i.e. if this was triggered from a .click() handler then the element that was clicked)
.clone()
clones these elements so that there are two versions - one in their original location and one being inserted into the #main_content img-wrapper element.
);
Do you definitely have a #main_content .text-wrapper element?
Without seeing the html structure, my guess would be the context in which you're trying to find .info is incorrect.
I'm assuming this block of code is within an event handler like a click or mouseover or something. In that case the $(this) is referring to the element that triggered that event. So the following snippet:
$(this).find('.info')
is looking for elements with a classname of info within the element referred to by $(this).
Make sure the context is correct - change $(this) to the element that you need to search within.
Try this:
$('#main_content .text-wrapper').empty().append($(this).find('.info').html());