using javascript to change display - javascript

So I looked at other questions and I found an answer that was chosen on this link:
Toggle (show/hide) element with javascript
This below was the following function that works in the answer to change the display.
function toggle(id) {
var element = document.getElementById(id);
if (element) {
var display = element.style.display;
if (display == "none") {
element.style.display = "block";
} else {
element.style.display = "none";
}
}
}
I tried that in my code, but it's not working. I've attached a link to the JSFiddle at the end or this post.
I have a parent div with the id of #activities. It contains multiple children, but the important ones are the li,p, and div which has an id as #suggestion_input. Below is the HTML.
HTML
<div id="activities" class="info_container">
<h1>Our Activities</h1>
<div class="contain">
<ul>
<li>Activity 1</li>
<li>Activity 2</li>
<li>Activity 3 </li>
<li>Activity 4 </li>
<li>Activity 5</li>
<li>Activity 6 </li>
<li>Activity 7</li>
<li>Your Suggestions</li>
</ul>
<p>
Bacon ipsum dolor sit amet ribeye tenderloin meatball, chuck andouille beef ribs jerky ...
</p>
<div id="suggestion_input">
<label for="name" >Your Name</label>
<input type="text" id="name" name="name">
<label for="email">Email</label>
<input type="email" id="email" name="email">
<label for="suggestions">Suggestions</label>
<textarea id="suggestions" name="suggestions" rows="39"></textarea>
</div>
When the user clicks the last li in the ul called "Your Suggestions", then the p will have display set to none and the #suggestion_input will have display of inline-block. Currently, their css is set to inline-block and none respectively.
CSS
#activities p{
display:inline-block;
width:500px;
vertical-align:top;
margin-top:20px;
margin-left:20px;
background:#FFFDA1;
}
#suggestion_input{
display:none;
margin-left:150px;
vertical-align:top;
margin-top:20px;
text-align:center;
}
And then this is my javascript which I think reflects the answer in the link except that it isn't a function.
Javascript - This code is part of an addEventListener. Event is a "click".
if(e.target.innerText === 'Your Suggestions'){
var para = document.getElementById('activities').querySelector('p');
var display = para.style.display;
/* if you uncomment this, then the following code will work
outside of the if display == 'inline-block' condition
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
*/
if(display == 'inline-block'){
// This code will not work
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
console.log('works');
}
}else{
if(display == 'none'){
display = "inline-block";
}
}
}
When I click, nothing happens. Is the error because of the condition in the if statement of "display == 'none'" ?
Here is the JSfiddle: http://jsfiddle.net/a4t7w/1/

There is a couple of error in your js , I listed them in the comment , 4 in totoal
document.getElementById('activities').addEventListener("click",function(e){
// SKIP THIS CODE, THE ERROR LIES BELOW
// 1. put the var outside of the if/else
var para = document.getElementById('activities').querySelector('p');
var display = para.style.display;
// THIS WAS WHERE THE ERROR OCCURS
if(e.target.innerText === 'Your Suggestions'){
if(display = 'inline-block'){ // 2. it should be "=" instead of "=="
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
console.log('works');
}
}else{
if(display = 'none'){
suggestion_input.style.display = 'none'; // 3. add in suggestion display none
para.style.display = 'inline-block'; // 4. "para.style.display" instead of "display"
}
}
}
});
A working demo : http://jsfiddle.net/a4t7w/7/
So now when you click suggestion , the from show up, than if you click the activity, the paragraph come back in, from disappear

Okay, so to start, part of your problem is with the understanding that para.style.display equals inline-block like is set in your style sheet. Unfortunately in this usage Javascript is accessing your inline styles as defined with the element itself and not what you are defining with external CSS.
So this statement: if(display == 'inline-block') never returns true because display is actually set to "". If you aren't already, get familiar with Firebug for Firefox. It does wonders for helping debug this kind of stuff.
Another thing is here: if(e.target.innerText === 'Your Suggestions'). Instead of innerText you should use innerHTML or textContent. The innerText property is an IE thing.
Now, to solve your problem! I see you are attaching the click event to the <div> element that holds your <ul> element. If you only need this click event you function on your "Suggestions" <li> then I would recommend you isolate that particular element when attaching your listener.
Change your HTML and JS:
<li id="suggestionToggle">Your Suggestions</li>
...
document.getElementById('suggestionToggle').addEventListener("click",function(e) ...
Next you can rewrite your Javascript to test for the presence of "" or inline-block when setting your styles on the <p> element. Here's an updated version of your code:
document.getElementById('activities').addEventListener("click",function(e)
{
var suggestion_input = document.getElementById('suggestion_input');
var para = document.getElementById('activities').querySelector('p');
var light_green = document.getElementById('activities').querySelector('.light_green');
if(light_green){
light_green.style.backgroundColor="red";
light_green.className = "";
e.target.style.backgroundColor = '#0DFFB9';
e.target.className = 'light_green';
} else {
e.target.style.backgroundColor = '#0DFFB9';
e.target.className = 'light_green';
}
if(e.target.innerHTML == 'Your Suggestions') {
var display = para.style.display;
if(display == 'inline-block' || display == "") {
// This code will not work ** It will now! **
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
} else {
if(display != "inline-block") {
para.style.display = "inline-block";
suggestion_input.style.display = "none";
}
}
} else {
para.style.display = "inline-block";
suggestion_input.style.display = "none";
}
});
JS Fiddle to see the toggle in action is here: http://jsfiddle.net/RyUz5/8/
Hope that helps!
EDIT: Enabled proper toggling that I accidentally stripped out as noted by yancie.

Read this line carefully:
/*
if you uncomment this, then the following code will work
outside of the if display == 'inline-block' condition
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
*/
now all you have to do is uncomment this line:
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';

Related

How to show/hide multiple divs using if/else statement?

My goal is to display various divs conditionally, such that:
display "x" div if it's not already
display "y" div but only if "x" div is already being displayed
display "z" div but only if "x" and "y" div are already being displayed.
With this code I can toggle a div to display and then not display:
function myFunction() {
var x = document.getElementById("myDIV");
if (x.style.display === "none") {
x.style.display = "block";
} else {
x.style.display = "none";
}
}
But then when I try do this for more than one div, it doesn’t work.
For example, this is what I tried:
function myFunction() {
var x = document.getElementById("myDIV");
var y = document.getElementById("myDIV2");
if (x.style.display === "none") {
x.style.display = "block";
} else if (y.style.display === "none") {
y.style.display = "block";
} else {
console.log("It worked!");
}
}
I made a couple CodePens showing those snippets:
This is the first snippet that works
This is the second one that doesn't
I would appreciate any help. Thank you!
So let's walk through it in the first myFunction. That will work reliably because there's only two options - "is x set to display: none? if so, do X; otherwise, do Y" will always work as expected because it is simple binary logic (all the cases are handled, it basically just toggles the style.display property). As soon as you bring more complicated logic into the equation and take multiple factors into consideration, it gets a little more slippery, and you need to formulate your approach more carefully.
The logic you basically want is, if X is hidden, show it; if y is hidden AND x is visible, show it; finally, if X is visible AND y is visible AND z is hidden, show it. You can write this in a really readable way by defining some quick isHidden(), isVisible(), and show() helper functions:
EDIT: FZs made a good point about classes not being caught by this logic. To account for that, all we need to do is add an "OR classList contains hidden" expression to the isHidden() check and voila.
// helpers
let isHidden = (el) => el.style.display == "none" || el.classList.contains('hidden'),
isVisible = (el) => !isHidden(el),
show = (el) => el.style.display = "block";
// elements
let x = document.getElementById("div-x"),
y = document.getElementById("div-y"),
z = document.getElementById("div-z");
// click handler
let handleClick = () => {
if (isHidden(x))
show(x);
else if (isHidden(y) && isVisible(x))
show(y);
else if (isHidden(z) && isVisible(y) && isVisible(x))
show(z);
else console.log("It worked!");
}
document.getElementById('btn').addEventListener('click', handleClick);
<div id="div-x" style="display:none">X</div>
<div id="div-y" style="display:none">Y</div>
<div id="div-z" style="display:none">Z</div>
<button id="btn">Click me!</button>
Because elem.style returns the inline style (style="/* styles */") of elem.
As #myDiv and #myDiv2 have only styles applied by stylesheets, x.style.display will return undefined, which isn't "none".
To solve it, I recommend toggling a .hidden class on the elements:
function myFunction() {
var x = document.getElementById("myDIV");
var y = document.getElementById("myDIV2");
if (x.classList.contains("hidden")) {
x.classList.remove("hidden");
} else if (y.classList.contains("hidden")) {
y.classList.remove("hidden");
} else {
console.log("It worked!");
}
}
.hidden{
display: none;
}
<div id="myDiv" class="hidden"></div>
<div id="myDiv2" class="hidden"></div>
Or, to show them alternately (I assume that was the goal):
function myFunction() {
var x = document.getElementById("myDIV");
var y = document.getElementById("myDIV2");
x.classList.toggle("hidden")
y.classList.toggle("hidden")
}
.hidden{
display: none;
}
<div id="myDiv"></div>
<div id="myDiv2" class="hidden"></div>

Displaying 3 different tables with 3 different buttons

I am trying to have 3 buttons and when the user clicks on one of them it displays the corresponding table and hides the other two.
I have tried using getting element by id and then setting the display to none or block based on what the current state of the table is.
<div onclick="myFunction()" id="u362" class="ax_default">
</div>
<div onclick="myFunction2()" id="u317" class="ax_default">
</div>
<script>
function myFunction() {
var a = document.getElementById("tbl");
var b = document.getElementById("tbl2");
if (a.style.display === "none") {
a.style.display = "block";
b.style.display = "block";
} else {
a.style.display = "none";
b.style.display = "none";
}
}
function myFunction2() {
var a = document.getElementById("tbl");
var b = document.getElementById("tbl2");
if (b.style.display === "none") {
a.style.display = "block";
b.style.display = "block";
} else {
a.style.display = "none";
b.style.display = "none";
}
}
</script>
The actual results are just really weird and have no resemblance to what I am trying to do.
You have not shown all of your code and are not explaining what you are wanting to do. Right now both of your functions are acting the same way, because you are operating on both tables each time.
If I can "guess" as to what you might want, it would be that when you click on button 1, then it will show table 1 and hide table 2. If you click on button 2 then it will show table 2 and hide table 1. If you look at your code below this is not what you are doing. You are showing both tables or hiding both tables in both instances.
To fix this you can do something like this:
<div onclick="myFunction()" id="u362" class="ax_default">
</div>
<div onclick="myFunction2()" id="u317" class="ax_default">
</div>
<script>
var a = document.getElementById("tbl");
var b = document.getElementById("tbl2");
function myFunction() {
a.style.display = "block";
b.style.display = "none";
}
function myFunction2() {
a.style.display = "none";
b.style.display = "block";
}
</script>
Notice you do not need an if/else in each function unless you are wanting the buttons to toggle on and off, in which case you may only need one button.
Here is a snippet of your code cleaned up. As #kojow7 noted above they basically do the same thing just based off 1 table or the other.
Things to note:
1) use slightly more descriptive variable names in your functions
2) create a css class that does your hiding so that you can simply test for that. when possible try to keep your js from handling styling
3) i replaced your if else with ternary if's. but in reality if all you are doing is toggling the class hidden then you could replace the if with a toggle.
4) instead of adding the onclick listener in your html it should be added via your js. try not to muddy your html with js concerns.
document.getElementById('u362').addEventListener('click', function () {
const tbl1 = document.getElementById("tbl1"),
tbl2 = document.getElementById("tbl2");
tbl1.classList.contains('hidden') ?
(tbl1.classList.remove('hidden'), tbl2.classList.remove('hidden')) :
(tbl1.classList.add('hidden'), tbl2.classList.add('hidden'));
});
document.getElementById('u317').addEventListener('click', function () {
const tbl1 = document.getElementById("tbl1"),
tbl2 = document.getElementById("tbl2");
tbl2.classList.contains('hidden') ?
(tbl1.classList.remove('hidden'), tbl2.classList.remove('hidden')) :
(tbl1.classList.add('hidden'), tbl2.classList.add('hidden'));
});
.hidden {
display: none;
}
<div id="u362" class="ax_default">u362</div>
<span id="tbl1" class="hidden">Table 1</span>
<span id="tbl2" class="hidden">Table 2</span>
<div id="u317" class="ax_default">u317</div>
With the information provided in your question, I suppose that your error comes when hiding or showing your tables. I think you have to change your code at those lines:
if (a.style.display === "none") {
a.style.display = "block";
b.style.display = "block";
} else {
a.style.display = "none";
b.style.display = "none";
}
for something like this:
b.style.display = "none";
if (a.style.display === "none") {
a.style.display = "block";
}
The new code will always hide table b when hitting button a. It doesn't matter the display status of table a because it doesn't really matter for hiding the rest of the tables. And only changes the display status of table a in case of being hidden.
You should do these changes also for each function of each button. I've also recommended to refactor all functions into a unique function and using it for all of the buttons you need.
I assume that the tables are invisible only after clicking the button, the appropriate table appears.
For future reference, please describe exactly what you want to use and you can use JsFiddle to show your code. Sometimes it is difficult to deduce from the descriptions what the writer had in mind :)
const buttons = document.querySelectorAll('button');
buttons.forEach(button => {
button.addEventListener('click', e => {
showTable(e.target.dataset.table);
});
});
function showTable(idTable) {
const tables = document.querySelectorAll('table');
tables.forEach(table => {
table.id === idTable ? table.style.display = 'block' : table.style.display = 'none';
});
}
table {
display: none;
}
<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/skeleton/2.0.4/skeleton.min.css">
<button id="one" data-table="tb1">One</button>
<button id="two" data-table="tb2">Two</button>
<button id="tree" data-table="tb3">three</button>
<table id="tb1">
<tr>
<td>One</td>
</tr>
</table>
<table id="tb2">
<tr>
<td>Two</td>
</tr>
</table>
<table id="tb3">
<tr>
<td>Three</td>
</tr>
</table>

Toggle icon flips no matter what section is opened

I am new to all of this so please excuse any misuse of terms.
I have added a toggle to my wordpress site to hide long sections of text and it seems to work just fine.
I wanted to add an arrow that flips depending on whether the section is open or not. My problem is the arrow flips back and forth no matter what section is toggled and I don't know how to fix that.
JS:
function toggle(id) {
var element = document.getElementById(id);
var text = document.getElementById("arrow");
if (element) {
var display = element.style.display;
if (display == "none") {
element.style.display = "block";
text.innerHTML = "▲";
} else {
element.style.display = "none";
text.innerHTML = "▼";
}
}
}
HTML:
<h4>Procedure</h4>
<h4 onclick="toggle('telnetPrint')">Telnet<a id="arrow">▼</a></h4>
<div id="telnetPrint" style="display: none;">
<ol>
<li>fjkldsaj;lkf</li>
</ol>
<h4 onclick="toggle('telnetPrint')">Hide -</h4>
</div>
<p> </p>
<h4 onclick="toggle('linuxPrint')">Linux Computer▼</h4>
<div id="linuxPrint" style="display: none">
<ol>
<li>fjkldsjfklsa</li>
</ol>
<h4 onclick="toggle('linuxPrint')">Hide -</h4>
</div>
If anyone can help, I'd greatly appreciate it.
p.s. no jQuery please
It looks like you are calling the same "arrow". You only have arrow set for Telnet. You can add an arrow as well to linuxPrint. I would ID them as :
<a id="arrowtelnetPrint"></a>
and
<a id="arrowlinuxPrint"></a>
That way you can use the "id" to change the correct one. Here is the jsfiddle:
https://jsfiddle.net/ezdrhLtr/2/
This will have the full code, with minor adjustments, that toggle both arrows.
var text = document.getElementById("arrow");
you are referencing an element with id 'arrow'. Everytime the toggle function is executed, you will flip the element with id 'arrow'. What you can do is pass a boolean value to know if its to be flipped or not
<h4 onclick="toggle('telnetPrint',true)">Telnet<a id="arrow">▼</a></h4>
and in your script
function toggle(id, flipOrNot) {
var element = document.getElementById(id);
var text = document.getElementById("arrow");
if (element) {
var display = element.style.display;
if (display == "none") {
element.style.display = "block";
if(flipOrNot){
text.innerHTML = "▲";
}
} else {
element.style.display = "none";
if(flipOrNot){
text.innerHTML = "▼";
}
}
}
}
for other elements, you can do
<h4 onclick="toggle('linuxPrint',false)">Hide -</h4>
to prevent flip

How make multiple javascript hide/show work on one single page

Please can you tell me how to change this code so that the user can click on the first read me to see just the sugar text and separately click on the second read me to see the toast text.
It is driving me mad - the display texts have different names but using this code, both read me clicks show the toast comment.
I'm a non-techie with no code knowledge so please reply in simple language!
<p><script language="javascript">
function toggle() {
var ele = document.getElementById("sugar");
var text = document.getElementById("displayTextsugar");
if(ele.style.display == "block") {
ele.style.display = "none";
text.innerHTML = "read more";
}
else {
ele.style.display = "block";
text.innerHTML = "hide";
}
}
</script> read sugar more <== click Here</p>
<p> </p>
<div style="display: none" id="sugar">
<h1>Sugar in my tea but none in coffee please</h1>
</div>
<script language="javascript">
function toggle() {
var ele = document.getElementById("toast");
var text = document.getElementById("displayTexttoast");
if(ele.style.display == "block") {
ele.style.display = "none";
text.innerHTML = "read more";
}
else {
ele.style.display = "block";
text.innerHTML = "hide";
}
}
</script>
<p>read toast more <== click Here</p>
<div style="display: none" id="toast">
<h1>brown toast with marmite please</h1>
</div>
Since your 2 different codes, shared the same name, only the second one is being called (the first one gets overwritten).
It could be easier to use parameters to make this work, i added a sender and a target to your toggle function, that you can then use with sender (the element that is being clicked) and the target (the element that should hide, or show)
The only changes in your toggle method, is that i am using the parameter to get the elements, so you are now using 1 "code" for both clicks ;)
function toggle(sender, target) {
var ele = document.getElementById(target);
var text = sender;
if (ele.style.display == "block") {
ele.style.display = "none";
text.innerHTML = "read more";
} else {
ele.style.display = "block";
text.innerHTML = "hide";
}
}
<p>read sugar more <== click Here</p>
<p> </p>
<div style="display: none" id="sugar">
<h1>Sugar in my tea but none in coffee please</h1>
</div>
<p>read toast more <== click Here</p>
<div style="display: none" id="toast">
<h1>brown toast with marmite please</h1>
</div>

JavaScript onclick requires two clicks

My problem is that when onclicktriggers the toggleNew function it's not executing but when I click the div a second time it's executing just as it should...
HTML:
<div id="aside_main">
<div onclick="toggleNew();">click</div>
content
</div>
<div id="aside_new">
content
</div>
JS:
function toggleNew() {
var e = document.getElementById('aside_main');
var se = document.getElementById('aside_new');
if(e.style.display == 'block') {
e.style.display = 'none';
se.style.display = 'block';
} else {
e.style.display = 'block';
se.style.display = 'none';
}
}
CSS:
#aside_main {
display: block;
}
#aside_new {
display: none;
}
What is happening here and how can I make the function work the first time a user clicks the div?
This will not work properly because you are using following line inside 'div#aside_main' which is going to be hidden.
<div onclick="toggleNew();">click</div>
Try keeping it outside like this-
<div onclick="toggleNew();">click</div>
<div id="aside_main">
content
</div>
<div id="aside_new">
content2
</div>
Also in javascript it is not checking for 'e.style.display' first time in if condition.
Try using
if(e.offsetWidth > 0 || e.offsetHeight > 0){
e.style.display = 'none';
se.style.display = 'block';
}
else
{
e.style.display = 'block';
se.style.display = 'none';
}
You need to call the function like onclick="toggleNew();" in the div onclick. I just added your code in fiddle.
May not be the best answer, but the fix was to use inline css by style attribute.
Like this:
<div id="aside_main" style="display: block; border: 2px solid green;">
<div onclick="toggleNew();">click</div>
content
</div>
<div id="aside_new" style="display: none; border: 2px solid red;">
content
</div>
e.style.display represents the style of the element defined by the style attribute, it does not give you the computed style. to get the computed style use
if (window.getComputedStyle(e,null).getPropertyValue("display") == 'block){
I had the same double click required issue. I was using an internal style sheet which was correctly setting the display like this.
When loading the HTML file #YourID was not visible as expected.
#YourID {
display: none;
}
When clicking the button tied to the function I noticed that the first click set the inline display to style="display: none;". The second click set the inline style="display: block;" and of course then it displayed as expected.
I found that I needed to set the element directly inline with style="display: none;" and just removed the intern style sheet entry (Above "#YourID").
I'm doubtful that this is 100% the correct answer in every scenario but it would seem the underlying issue is caused by the element not being set in the appropriate initial state for the function to act on it properly.
https://jsfiddle.net/em05a1kf
<div id="YourID" style="display: none;">
<b>Super Hidden Content</b>
</div>
<button onclick="ToggleID('YourID');">Do Foo</button>
<script type="text/javascript">
function ToggleID(idname) {
var x = document.getElementById(idname);
(x.style.display === "none") ? (x.style.display = "block") : (x.style.display = "none");
return false;
}
</script>
In your condition : Use onclick="toggleNew();" // calling
This is the way to call a function.
And if you want to Pass the function then you use only toggleNew //passing
They are two different activities.
Here is another way of doing that. You just need to add two lines to your javascript code-
document.getElementById('aside_main').style.display='block';
document.getElementById('aside_new').style.display='none';
set initial display property in javascript. This will work fine.
One way (for me the simplest way) to solve this is by counting clicks.
For this purpose you set the new intiger variable click to 0 outside of your function toggleNew() and everytime you call your function you increase variable click for 1 like this:
<script> var click = 0;
function toggleNew() {
click = click +1;
var e = document.getElementById('aside_main');
var se = document.getElementById('aside_new');
if (click > 1) {
if(e.style.display == 'block') {
e.style.display = 'none';
se.style.display = 'block';
} else {
e.style.display = 'block';
se.style.display = 'none';
}
} else {
e.style.display = 'none';
se.style.display = 'block';
}
}
</script>

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