My problem is that when onclicktriggers the toggleNew function it's not executing but when I click the div a second time it's executing just as it should...
HTML:
<div id="aside_main">
<div onclick="toggleNew();">click</div>
content
</div>
<div id="aside_new">
content
</div>
JS:
function toggleNew() {
var e = document.getElementById('aside_main');
var se = document.getElementById('aside_new');
if(e.style.display == 'block') {
e.style.display = 'none';
se.style.display = 'block';
} else {
e.style.display = 'block';
se.style.display = 'none';
}
}
CSS:
#aside_main {
display: block;
}
#aside_new {
display: none;
}
What is happening here and how can I make the function work the first time a user clicks the div?
This will not work properly because you are using following line inside 'div#aside_main' which is going to be hidden.
<div onclick="toggleNew();">click</div>
Try keeping it outside like this-
<div onclick="toggleNew();">click</div>
<div id="aside_main">
content
</div>
<div id="aside_new">
content2
</div>
Also in javascript it is not checking for 'e.style.display' first time in if condition.
Try using
if(e.offsetWidth > 0 || e.offsetHeight > 0){
e.style.display = 'none';
se.style.display = 'block';
}
else
{
e.style.display = 'block';
se.style.display = 'none';
}
You need to call the function like onclick="toggleNew();" in the div onclick. I just added your code in fiddle.
May not be the best answer, but the fix was to use inline css by style attribute.
Like this:
<div id="aside_main" style="display: block; border: 2px solid green;">
<div onclick="toggleNew();">click</div>
content
</div>
<div id="aside_new" style="display: none; border: 2px solid red;">
content
</div>
e.style.display represents the style of the element defined by the style attribute, it does not give you the computed style. to get the computed style use
if (window.getComputedStyle(e,null).getPropertyValue("display") == 'block){
I had the same double click required issue. I was using an internal style sheet which was correctly setting the display like this.
When loading the HTML file #YourID was not visible as expected.
#YourID {
display: none;
}
When clicking the button tied to the function I noticed that the first click set the inline display to style="display: none;". The second click set the inline style="display: block;" and of course then it displayed as expected.
I found that I needed to set the element directly inline with style="display: none;" and just removed the intern style sheet entry (Above "#YourID").
I'm doubtful that this is 100% the correct answer in every scenario but it would seem the underlying issue is caused by the element not being set in the appropriate initial state for the function to act on it properly.
https://jsfiddle.net/em05a1kf
<div id="YourID" style="display: none;">
<b>Super Hidden Content</b>
</div>
<button onclick="ToggleID('YourID');">Do Foo</button>
<script type="text/javascript">
function ToggleID(idname) {
var x = document.getElementById(idname);
(x.style.display === "none") ? (x.style.display = "block") : (x.style.display = "none");
return false;
}
</script>
In your condition : Use onclick="toggleNew();" // calling
This is the way to call a function.
And if you want to Pass the function then you use only toggleNew //passing
They are two different activities.
Here is another way of doing that. You just need to add two lines to your javascript code-
document.getElementById('aside_main').style.display='block';
document.getElementById('aside_new').style.display='none';
set initial display property in javascript. This will work fine.
One way (for me the simplest way) to solve this is by counting clicks.
For this purpose you set the new intiger variable click to 0 outside of your function toggleNew() and everytime you call your function you increase variable click for 1 like this:
<script> var click = 0;
function toggleNew() {
click = click +1;
var e = document.getElementById('aside_main');
var se = document.getElementById('aside_new');
if (click > 1) {
if(e.style.display == 'block') {
e.style.display = 'none';
se.style.display = 'block';
} else {
e.style.display = 'block';
se.style.display = 'none';
}
} else {
e.style.display = 'none';
se.style.display = 'block';
}
}
</script>
Related
My goal is to display various divs conditionally, such that:
display "x" div if it's not already
display "y" div but only if "x" div is already being displayed
display "z" div but only if "x" and "y" div are already being displayed.
With this code I can toggle a div to display and then not display:
function myFunction() {
var x = document.getElementById("myDIV");
if (x.style.display === "none") {
x.style.display = "block";
} else {
x.style.display = "none";
}
}
But then when I try do this for more than one div, it doesn’t work.
For example, this is what I tried:
function myFunction() {
var x = document.getElementById("myDIV");
var y = document.getElementById("myDIV2");
if (x.style.display === "none") {
x.style.display = "block";
} else if (y.style.display === "none") {
y.style.display = "block";
} else {
console.log("It worked!");
}
}
I made a couple CodePens showing those snippets:
This is the first snippet that works
This is the second one that doesn't
I would appreciate any help. Thank you!
So let's walk through it in the first myFunction. That will work reliably because there's only two options - "is x set to display: none? if so, do X; otherwise, do Y" will always work as expected because it is simple binary logic (all the cases are handled, it basically just toggles the style.display property). As soon as you bring more complicated logic into the equation and take multiple factors into consideration, it gets a little more slippery, and you need to formulate your approach more carefully.
The logic you basically want is, if X is hidden, show it; if y is hidden AND x is visible, show it; finally, if X is visible AND y is visible AND z is hidden, show it. You can write this in a really readable way by defining some quick isHidden(), isVisible(), and show() helper functions:
EDIT: FZs made a good point about classes not being caught by this logic. To account for that, all we need to do is add an "OR classList contains hidden" expression to the isHidden() check and voila.
// helpers
let isHidden = (el) => el.style.display == "none" || el.classList.contains('hidden'),
isVisible = (el) => !isHidden(el),
show = (el) => el.style.display = "block";
// elements
let x = document.getElementById("div-x"),
y = document.getElementById("div-y"),
z = document.getElementById("div-z");
// click handler
let handleClick = () => {
if (isHidden(x))
show(x);
else if (isHidden(y) && isVisible(x))
show(y);
else if (isHidden(z) && isVisible(y) && isVisible(x))
show(z);
else console.log("It worked!");
}
document.getElementById('btn').addEventListener('click', handleClick);
<div id="div-x" style="display:none">X</div>
<div id="div-y" style="display:none">Y</div>
<div id="div-z" style="display:none">Z</div>
<button id="btn">Click me!</button>
Because elem.style returns the inline style (style="/* styles */") of elem.
As #myDiv and #myDiv2 have only styles applied by stylesheets, x.style.display will return undefined, which isn't "none".
To solve it, I recommend toggling a .hidden class on the elements:
function myFunction() {
var x = document.getElementById("myDIV");
var y = document.getElementById("myDIV2");
if (x.classList.contains("hidden")) {
x.classList.remove("hidden");
} else if (y.classList.contains("hidden")) {
y.classList.remove("hidden");
} else {
console.log("It worked!");
}
}
.hidden{
display: none;
}
<div id="myDiv" class="hidden"></div>
<div id="myDiv2" class="hidden"></div>
Or, to show them alternately (I assume that was the goal):
function myFunction() {
var x = document.getElementById("myDIV");
var y = document.getElementById("myDIV2");
x.classList.toggle("hidden")
y.classList.toggle("hidden")
}
.hidden{
display: none;
}
<div id="myDiv"></div>
<div id="myDiv2" class="hidden"></div>
I have a DIV which has a display set to none, by using javascript I tried showing it by using the onclick of a button. But what happens is the exact opposite. My DIV is already shown and when I click the button it hides the DIV. What am i doing wrong here, please HELP!
This is my button and the div:
<button onclick="myFunction()">SHOW</button>
<div id="how_to_form">
<img src="../images/view.png">
</div>
This is the JS code:
function myFunction() {
var x = document.getElementById("how_to_form").style.display = 'none';
if (x.style.display === "none") {
x.style.display = "block";
} else {
x.style.display = "none";
}
}
Your line there has a double assignment:
var x = document.getElementById("how_to_form").style.display = 'none';
It first assigns the display to none:
document.getElementById("how_to_form").style.display = 'none';
and then takes the result of that expression (which is the string you assigned), and assigns it to x:
var x = 'none';
Which isn't what you want. First declare the variable for the element, then assign its style.
Also, it sounds like you want the element to start out hidden - assign its initial style outside the function:
const form = document.getElementById("how_to_form");
form.style.display = 'none';
function myFunction() {
if (form.style.display === "none") {
form.style.display = "block";
} else {
form.style.display = "none";
}
}
Or, to be more concise, use the conditional operator:
function myFunction() {
form.style.display = form.style.display === "none"
? 'block'
: 'none';
}
Also consider attaching the handler properly using Javascript, rather than using inline HTML attributes, which are generally considered to be pretty poor practice and can be hard to manage:
document.querySelector('button').addEventListener('click', myFunction);
have you checked if you have already set a default style to your div?
you either have to set your div's default style to display:none by inline
<div id="how_to_form" style="display:none">
or by css
<style>
#how_to_form{ display:none }
</style>
Issue is your variable assignment
Chaining the assignment operator is possible in order to assign a single value to multiple variables.
Please refer this link for variable assignment options
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Assignment_Operators
var x = y= 10
Then both x and y values are 10
Similarly in your code var x is none
To achieve expected result , use below option
1. set CSS for html_to_form to display:none
2.In your code change variable x assignment to
var x = document.getElementById("html_to_form")
Javascript newbie here. This is basically what I'm working with.
The function below is intended to hide everything enclosed in the newsDisplay class, but nothing happens when clicking the button that calls it.
function showHide() {
var x = document.getElementsByClassName('newsDisplay');
if (x.style.display === 'none') {
x.style.display = 'block';
} else {
x.style.display = 'none';
}
}
.newsDisplay {
display: block;
}
<h1>News<button onclick="showHide();"><img src="..\Images\showHide.png"></button></h1>
<div class="newsDisplay">
<div class="bodyBox">
<h2>Diablo 3</h2>
TEXT/PARAGRAPHS
</div>
</div>
Manually changing display: block; to display: none; behaves exactly as expected, so either the syntax or logic of the function is incorrect, or something is preventing the function from executing when clicking the button.
Could really use some help, thank you!
Try the first element of this class as follows
var x = document.getElementsByClassName('newsDisplay')[0];
Document document.single getElementsByClassName() will return an array of elements with the same class. It is different from document.getElementById() in so far as the latter returns a DOM object rather than an array of DOM objects.
As stated from it's name getElementsByClassName get elements (and not single element), so result of this function call is a collection of elements.
To access to first element of collection you can:
x = document.getElementsByClassName('newsDisplay')[0];
// or
X = document.getElementsByClassName('newsDisplay').item(0);
You can try a loop if you want multiple of the page. The key is you're grabbing a list of elements with the class, since classes aren't unique identifiers. You can either use my code below or switch it to an id and grab it by document.getElementById. Notice the s in document.getElementsByClassName
var x = document.getElementsByClassName('newsDisplay');
function showHide() {
for (var i = 0; i < x.length; i++){
x[i].style.display === 'none'
? x[i].style.display = 'block'
: x[i].style.display = 'none';
}
}
<h1>News<button onclick="showHide();"><img src="..\Images\showHide.png"></button></h1>
<div class="newsDisplay">
<div class="bodyBox">
<h2>Diablo 3</h2>
TEXT/PARAGRAPHS
</div>
</div>
<h1>News<button onclick="showHide();"><img src="..\Images\showHide.png"></button></h1>
<div class="newsDisplay">
<div class="bodyBox">
<h2>Diablo 3</h2>
TEXT/PARAGRAPHS
</div>
</div>
Try the code below.
Use this
var x = document.getElementsByClassName('newsDisplay')[0];
function showHide() {
var x = document.getElementsByClassName('newsDisplay')[0];
if (x.style.display === 'none') {
x.style.display = 'block';
} else {
x.style.display = 'none';
}
}
.newsDisplay {
display: block;
}
<h1>News<button onclick="showHide();"><img src="..\Images\showHide.png"></button></h1>
<div class="newsDisplay">
<div class="bodyBox">
<h2>Diablo 3</h2>
TEXT/PARAGRAPHS
</div>
</div>
If you hit F12, navigate to the sources tab (on google chrome) you can set a breakpoint on your javascript function, your code is running, but you are getting a
Uncaught TypeError: Cannot read property 'display' of undefined
The reason for this is getElementsByClassName is returning a list of elements with that class selector, not just the one. If you want to just do this to the first element you can simply do:
function showHide() {
var x = document.getElementsByClassName('newsDisplay')[0];
if (x.style.display === 'none') {
x.style.display = 'block';
} else {
x.style.display = 'none';
}
}
I am new to all of this so please excuse any misuse of terms.
I have added a toggle to my wordpress site to hide long sections of text and it seems to work just fine.
I wanted to add an arrow that flips depending on whether the section is open or not. My problem is the arrow flips back and forth no matter what section is toggled and I don't know how to fix that.
JS:
function toggle(id) {
var element = document.getElementById(id);
var text = document.getElementById("arrow");
if (element) {
var display = element.style.display;
if (display == "none") {
element.style.display = "block";
text.innerHTML = "▲";
} else {
element.style.display = "none";
text.innerHTML = "▼";
}
}
}
HTML:
<h4>Procedure</h4>
<h4 onclick="toggle('telnetPrint')">Telnet<a id="arrow">▼</a></h4>
<div id="telnetPrint" style="display: none;">
<ol>
<li>fjkldsaj;lkf</li>
</ol>
<h4 onclick="toggle('telnetPrint')">Hide -</h4>
</div>
<p> </p>
<h4 onclick="toggle('linuxPrint')">Linux Computer▼</h4>
<div id="linuxPrint" style="display: none">
<ol>
<li>fjkldsjfklsa</li>
</ol>
<h4 onclick="toggle('linuxPrint')">Hide -</h4>
</div>
If anyone can help, I'd greatly appreciate it.
p.s. no jQuery please
It looks like you are calling the same "arrow". You only have arrow set for Telnet. You can add an arrow as well to linuxPrint. I would ID them as :
<a id="arrowtelnetPrint"></a>
and
<a id="arrowlinuxPrint"></a>
That way you can use the "id" to change the correct one. Here is the jsfiddle:
https://jsfiddle.net/ezdrhLtr/2/
This will have the full code, with minor adjustments, that toggle both arrows.
var text = document.getElementById("arrow");
you are referencing an element with id 'arrow'. Everytime the toggle function is executed, you will flip the element with id 'arrow'. What you can do is pass a boolean value to know if its to be flipped or not
<h4 onclick="toggle('telnetPrint',true)">Telnet<a id="arrow">▼</a></h4>
and in your script
function toggle(id, flipOrNot) {
var element = document.getElementById(id);
var text = document.getElementById("arrow");
if (element) {
var display = element.style.display;
if (display == "none") {
element.style.display = "block";
if(flipOrNot){
text.innerHTML = "▲";
}
} else {
element.style.display = "none";
if(flipOrNot){
text.innerHTML = "▼";
}
}
}
}
for other elements, you can do
<h4 onclick="toggle('linuxPrint',false)">Hide -</h4>
to prevent flip
So I looked at other questions and I found an answer that was chosen on this link:
Toggle (show/hide) element with javascript
This below was the following function that works in the answer to change the display.
function toggle(id) {
var element = document.getElementById(id);
if (element) {
var display = element.style.display;
if (display == "none") {
element.style.display = "block";
} else {
element.style.display = "none";
}
}
}
I tried that in my code, but it's not working. I've attached a link to the JSFiddle at the end or this post.
I have a parent div with the id of #activities. It contains multiple children, but the important ones are the li,p, and div which has an id as #suggestion_input. Below is the HTML.
HTML
<div id="activities" class="info_container">
<h1>Our Activities</h1>
<div class="contain">
<ul>
<li>Activity 1</li>
<li>Activity 2</li>
<li>Activity 3 </li>
<li>Activity 4 </li>
<li>Activity 5</li>
<li>Activity 6 </li>
<li>Activity 7</li>
<li>Your Suggestions</li>
</ul>
<p>
Bacon ipsum dolor sit amet ribeye tenderloin meatball, chuck andouille beef ribs jerky ...
</p>
<div id="suggestion_input">
<label for="name" >Your Name</label>
<input type="text" id="name" name="name">
<label for="email">Email</label>
<input type="email" id="email" name="email">
<label for="suggestions">Suggestions</label>
<textarea id="suggestions" name="suggestions" rows="39"></textarea>
</div>
When the user clicks the last li in the ul called "Your Suggestions", then the p will have display set to none and the #suggestion_input will have display of inline-block. Currently, their css is set to inline-block and none respectively.
CSS
#activities p{
display:inline-block;
width:500px;
vertical-align:top;
margin-top:20px;
margin-left:20px;
background:#FFFDA1;
}
#suggestion_input{
display:none;
margin-left:150px;
vertical-align:top;
margin-top:20px;
text-align:center;
}
And then this is my javascript which I think reflects the answer in the link except that it isn't a function.
Javascript - This code is part of an addEventListener. Event is a "click".
if(e.target.innerText === 'Your Suggestions'){
var para = document.getElementById('activities').querySelector('p');
var display = para.style.display;
/* if you uncomment this, then the following code will work
outside of the if display == 'inline-block' condition
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
*/
if(display == 'inline-block'){
// This code will not work
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
console.log('works');
}
}else{
if(display == 'none'){
display = "inline-block";
}
}
}
When I click, nothing happens. Is the error because of the condition in the if statement of "display == 'none'" ?
Here is the JSfiddle: http://jsfiddle.net/a4t7w/1/
There is a couple of error in your js , I listed them in the comment , 4 in totoal
document.getElementById('activities').addEventListener("click",function(e){
// SKIP THIS CODE, THE ERROR LIES BELOW
// 1. put the var outside of the if/else
var para = document.getElementById('activities').querySelector('p');
var display = para.style.display;
// THIS WAS WHERE THE ERROR OCCURS
if(e.target.innerText === 'Your Suggestions'){
if(display = 'inline-block'){ // 2. it should be "=" instead of "=="
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
console.log('works');
}
}else{
if(display = 'none'){
suggestion_input.style.display = 'none'; // 3. add in suggestion display none
para.style.display = 'inline-block'; // 4. "para.style.display" instead of "display"
}
}
}
});
A working demo : http://jsfiddle.net/a4t7w/7/
So now when you click suggestion , the from show up, than if you click the activity, the paragraph come back in, from disappear
Okay, so to start, part of your problem is with the understanding that para.style.display equals inline-block like is set in your style sheet. Unfortunately in this usage Javascript is accessing your inline styles as defined with the element itself and not what you are defining with external CSS.
So this statement: if(display == 'inline-block') never returns true because display is actually set to "". If you aren't already, get familiar with Firebug for Firefox. It does wonders for helping debug this kind of stuff.
Another thing is here: if(e.target.innerText === 'Your Suggestions'). Instead of innerText you should use innerHTML or textContent. The innerText property is an IE thing.
Now, to solve your problem! I see you are attaching the click event to the <div> element that holds your <ul> element. If you only need this click event you function on your "Suggestions" <li> then I would recommend you isolate that particular element when attaching your listener.
Change your HTML and JS:
<li id="suggestionToggle">Your Suggestions</li>
...
document.getElementById('suggestionToggle').addEventListener("click",function(e) ...
Next you can rewrite your Javascript to test for the presence of "" or inline-block when setting your styles on the <p> element. Here's an updated version of your code:
document.getElementById('activities').addEventListener("click",function(e)
{
var suggestion_input = document.getElementById('suggestion_input');
var para = document.getElementById('activities').querySelector('p');
var light_green = document.getElementById('activities').querySelector('.light_green');
if(light_green){
light_green.style.backgroundColor="red";
light_green.className = "";
e.target.style.backgroundColor = '#0DFFB9';
e.target.className = 'light_green';
} else {
e.target.style.backgroundColor = '#0DFFB9';
e.target.className = 'light_green';
}
if(e.target.innerHTML == 'Your Suggestions') {
var display = para.style.display;
if(display == 'inline-block' || display == "") {
// This code will not work ** It will now! **
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
} else {
if(display != "inline-block") {
para.style.display = "inline-block";
suggestion_input.style.display = "none";
}
}
} else {
para.style.display = "inline-block";
suggestion_input.style.display = "none";
}
});
JS Fiddle to see the toggle in action is here: http://jsfiddle.net/RyUz5/8/
Hope that helps!
EDIT: Enabled proper toggling that I accidentally stripped out as noted by yancie.
Read this line carefully:
/*
if you uncomment this, then the following code will work
outside of the if display == 'inline-block' condition
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';
*/
now all you have to do is uncomment this line:
para.style.display = 'none';
suggestion_input.style.display = 'inline-block';