I am new at creating websites in HTML. I use free for all SeaMonkey software. So, I want to create several image buttons which would change when user moves the mouse over the image. I already have created 3 images for the different stages of each button (normal, active and clicked). I wrote this code for the first button:
<body>
<a href="first.html" onmouseover="return changeImage(jsbutton)" onmouseout="return changeImageBack(jsbutton)">
<img name="jsbutton" src="first normal.png" alt="first">
<script type="text/javascript">
function changeImage() {
document.images["jsbutton"].src= "first active.png";
return true;
}
function changeImageBack() {
document.images["jsbutton"].src = "first normal.png";
return true;
}
</script>
</a>
</body>
And it works. But when I did the same for second button, it didn't work and in addition to that, the first one has stopped working too. What do I have to change to make it work properly?
Update:
For second button I wrote:
<a href="second.html" onmouseover="return changeImage(jsbutton)"
onmouseout="return changeImageBack(jsbutton)">
<img name="jsbutton" src="second normal.png" alt="second">
<script type="text/javascript">
function changeImage()
{
document.images["jsbutton"].src= "second active.png";
return true;
}
function changeImageBack()
{
document.images["jsbutton"].src = "second normal.png";
return true;
}
</script> </a>
</body>
You are using the same "name" attribute i.e. jsbutton for the both the images. Use different name attributes. Also css :hover is a better way to do this problem.
Your JavaScript is failing because you are using the same name attribute for both images. Each element must have a unique name.
That being said, the functionality you are after is already built in to CSS, so unless you have a specific requirement for this to be JavaScript, this is a problem far better solved in CSS, using :hover.
So in your html:
In your CSS:
#firstButton {
background-image: url('first normal.png');
display:block;
height: [height of img];
width: [width of img];
}
#firstButton:visited {background-image: url('first visited.png'); }
#firstButton:hover { background-image: url('first active.png'); }
And you are done! No use recreating functionality already built in to CSS!
Well you can also use inline javascript for this purpose as it is pretty simple:
<a href="first.html" >
<img onmouseover="this.src = 'second active.png'; " src="second normal.png" onmouseout="this.src = 'second normal.png'; " alt="first" />
</a>
Here is the Demo , in which I used some random images urls
Hope this helps.
Related
Could you help me with this one please?
If you click on my hosting http://www.gosu.cz and select first image from top|left then it's gonna expand on top of the page with a additional info.
Header
Description
link
Now I need to set hidden value for each image which is defined as:
<li class="item col-xs-12 col-sm-6 col-md-4">
<a href="http://placehold.it/857x712" data-caption="description">
<img src="http://placehold.it/857x712" class="img-responsive" alt="alt" />
</a>
</li>
and when is selected then it's gonna show up at this div which is right below header:
<a href="LINK+KEYWORD">
<div class="least-preview"></div>
</a>
Any ideas how could I do that please? My poor skills in programing includes some basic of html, php but not scripting.
This is how it looks like: http://imgur.com/a/CU30N
Cheers,
Martin
So as David Arce suggested it might be done through alt value.
What I have done is using script at the start and also creating link for search queue:
<script>
$(document).ready(function() {
$('img').click(function () {
var alt = $(this).attr("alt")
var strLink = "link&Key=" + alt;
document.getElementById("link").setAttribute("href",strLink);
});
});
</script>
Thanks to document.ElementById... I was able to set a href value via id to generated link.
<a id="link">
<div class="least-preview"></div>
</a>
I think you can use an tag like this inside the li tag
<input type="hidden" name="Image_details" value="Additional details offf that image">
And then on img onclick="getDetails();"
in js:
function getDetails()
{
div.innerHTML = document.getElementById("Img_details").value;
}
//The code is conceptual, so the idea is to assign the hidden input value to the when an image is clicked or selected
I am not quite sure what you are trying to hide, or what you want your code to do. If you want something to be hidden or visible you can use the visibility property in the css for the element you want to hide.
/* Hides h2 element */
h2 {
visibility: hidden;
}
/* Shows h2 element (default value)*/
h2 {
visibility: visible;
}
Here is the reference here...
http://www.w3schools.com/cssref/pr_class_visibility.asp
In enlightenment to what the question is, you can have an onClick="function()" attribute to your image which will grab whichever value, id, class, etc you have in your new which can be put into a search query by variable. All can be done through a function.
$(document).ready(function() {
$('img').click(function () {
var alt = $(this).attr("alt")
var strLink = "link&Key=" + alt;
document.getElementById("link").setAttribute("href",strLink);
});
});
Hello I would like to disable all other links except the clicked one after I click one of the links.
Here is my code so far:
JavaScript
$(".link-chart").click(function($e) {
if($(this).find(".link-selector-two").hasClass('red')) {
$('.link-selector-two', this).addClass('cssclass');
$('.link-selector-one', this).addClass('cssclass');
} else {
$('.link-selector-two', this).removeClass('cssclass');
}
});
HTML
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<a href="#" class="link-chart lx-link-chart">
<div class="link-selector-one">
<div class="link-selector-two red">One</div>
</div>
</a>
<a href="#" class="link-chart lx-link-chart">
<div class="link-selector-one">
<div class="link-selector-two red">Two</div>
</div>
</a>
So the idea is for example if I click the first link to disable the second one, if I click again the first link it will deselect the first link in the way it is working now so the second link will be available for selection again. The same option is for the second link if I click the second to disable the first one.
Any help will be welcome to let me know in which approach have to go.
You could do something like this:
JS
var $linkChart = $('.link-chart');
$linkChart.click(function(e) {
$linkChart.each(function() {
if (e.currentTarget !== this) {
$(this).toggleClass('disabled');
}
});
});
SCSS
.link-chart {
&.disabled {
pointer-events: none;
opacity: 0.25;
}
}
Here's a fiddle to show it in action. FYI, I added a third link so that you could see it'll work exactly the same for as many links as you want to add.
I've been attempting to create an effect where a user clicks on an image, that image is replaced by another image which also acts as a link.
However my problem is that whenever I click the replaced image, the link doesn't work.
Fiddle: http://jsfiddle.net/ha6qp7w4/321/
$('.btnClick').on('click',function(){
$(this).attr('src','https://placekitten.com/g/200/300')
$(this).attr('href','google.com')
});
img tags don't have href properties. You need to wrap the image in an anchor and assign the url to that, or do a custom redirect.
Notice your image html on inspection of element:
<img src="https://placekitten.com/g/200/300" id="1" class="btnClick" href="google.com"> <!-- not valid! -->
This isn't valid because imgs aren't anchors!
function first() {
this.src = 'https://placekitten.com/g/200/300';
$(this).unbind("click");
$(this).on("click", second);
}
function second() {
window.location.href = "https://www.google.com";
$(this).unbind("click");
$(this).on("click", first);
}
$('.btnClick').on('click', first);
(I tried to make a fiddle but it wouldn't save, but this should work)
You need to store your actions in functions so you can revert if need be. First action is the change the source, then change the event to redirect you like a link.
here is an example.
example
html part
<img src="http://i.imgur.com/o46X87d.png" data-new="http://i.imgur.com/9lf2Mjk.png" id="1" class="btnClick" />
add data-new attribute on image with new url of image
and replace it with js
$('.btnClick').on('click',function(){
var url = $(this).attr("data-new");
$(this).attr("src", url);
});
I would use a totally different approach, but here's how to do that with the code you already have:
<div class="btnClick">
<img src="http://i.imgur.com/o46X87d.png" id="1" />
<a href="javascript:check()" id="2" style="display:none;">
<img src="http://i.imgur.com/9lf2Mjk.png" id="static" />
</a>
</div>
<script type="text/javascript">
$('.btnClick').on('click',function(){
if($('#1').is(':visible')) {
$('#1').hide();
$('#2').show();
} else {
$('#1').show();
$('#2').hide();
}
});
</script>
I purposely didn't use toggle() to better show the technique, in case you'd want to turn the click event off when the clicking image appears etc.
I have two images which I'm toggling and a zoom on those images is supposed to be displayed according to the selected image. On the first page load everything works fine (image appears, zoom appears). After I click the image, the image swaps and the zoom works fine as well. However, if I click again, I'm getting the image toggled correctly, but the zoom image does not refresh even for further clicks (keep displaying the zoom for the 2nd loaded image).
I'm trying to change the attributes of data-zoom-image but no luck. Any suggestions?
function pageLoad(sender, args) {
zooming();
}
function chngimg(x) {
if ($("#zoom_mw").attr("src") == x) {
var rimage;
rimage = $("#zoom_mw").attr('rearimage');
$("#zoom_mw").attr("src", rimage);
$("#zoom_mw").removeAttr("data-zoom-image");
$("#zoom_mw").attr("data-zoom-image", rimage);
$("#zoom_mw").elevateZoom({ scrollZoom: true });
} else {
var fimage;
fimage = $("#zoom_mw").attr('frontimage');
$("#zoom_mw").attr("src", fimage);
$("#zoom_mw").attr("data-zoom-image", fimage);
$("#zoom_mw").elevateZoom({ scrollZoom: true });
}
}
<img style="border:1px solid #e8e8e6;" id="zoom_mw"
onclick="chngimg('<%= Session("ImagePathFront")%>')"
frontimage='<%= Session("ImagePathFront")%>'
rearimage='<%= Session("ImagePathRear")%>'
src='<%= Session("ImagePathFront")%>'
width="500" height="250" />
I assume that you are using this library. Is this the case?
In my demo i copied your code and currently
it toggles the images.
Your function pageLoad() calls a function zooming() but the code you provided does not execute pageLoad and the function zooming() is missing.
The call to elevateZoom is not working for me. Are you missing a reference?
If you are using elevateZoom than you have to provide the URL for the larger Image
<img id="zoom_01" src="small/image1.png" data-zoom-image="large/image1.jpg"/>
Their exsample Gallery & Lightbox seems to me that it comes close what you are looking for:
<img id="img_01" src="small/image1.jpg" data-zoom-image="large/image1.jpg"/>
<div id="gal1">
<a href="#" data-image="small/image1.jpg" data-zoom-image="large/image1.jpg">
<img id="img_01" src="thumb/image1.jpg" />
</a>
<a href="#" data-image="small/image2.jpg" data-zoom-image="large/image2.jpg">
<img id="img_01" src="thumb/image2.jpg" />
</a>
</div>
And the matching javascript
//initiate the plugin and pass the id of the div containing gallery images
$("#zoom_03").elevateZoom({gallery:'gallery_01',
cursor: 'pointer', galleryActiveClass: 'active'
, imageCrossfade: true
, loadingIcon: 'http://www.elevateweb.co.uk/spinner.gif'});
//pass the images to Fancybox
$("#zoom_03").bind("click", function(e) {
var ez = $('#zoom_03').data('elevateZoom');
$.fancybox(ez.getGalleryList());
return false;
});
Please ask additional questions or comment if i misunderstood you.
I have a Q&A list with "Open All/Close All" at the top with individual open and close image buttons that toggle when clicked. That works fine.
Then follow individual Q&As, and each has its own open and close image.
If you click on "Open All/Close All" first, as soon as the page loads, and then click on the individual Q&A open/close images, all works fine. But if after page load you click on the individual Q&A open/close images, bypassing "Open All/Close All," they display the inappropriate open or close image.
Here is page code:
<div class="answersee"><span>Open All</span><img src="assets/open.gif" border="0" alt="" /></div>
<div class="answerhide"><span>Close All</span><img src="assets/close.gif" border="0" alt="" /></div>
<div class="qa">
<div><img src="open.gif" border="0" alt="" /><span class="question">Question.</span></div>
<div class="answer"><p>Answer.</p></div>
</div>
Here's the script (also uses Jquery):
$(function () {
$(".qa").click(function () {
$(this).find("div").next().slideToggle("fast");
if ($(this).find("div:eq(0)").find("img").attr("src") == "open.gif") {
$(this).find("div:eq(0)").find("img").attr("src", "close.gif");
}
else {
$(this).find("div:eq(0)").find("img").attr("src", "open.gif");
}
});
$(".answersee").click(function () {
$(".answer").show("fast");
$(".qa > div > img").attr("src", "close.gif");
$(".answerhide").show();
$(".answersee").hide();
})
$(".answerhide").click(function () {
$(".answer").hide("fast");
$(".qa > div > img").attr("src", "open.gif");
$(".answersee").show();
$(".answerhide").hide();
})
});
I don't think it's a CSS problem, or I'd include that code here. Do I need to initialize the script in some way? Or did I make a mistake in the above script?
Here's how I would do it.
Working Demo →
EDIT:
Update the code to have simple open/close link.
Code with comments which explains my approach:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<style>
body
{
font-family: "Verdana";
font-size: 12px;
}
.question
{
background-color: #ccc;
cursor: pointer;
padding: 5px;
margin-bottom: 10px;
border-bottom: 1px solid #000;
}
.answer {
padding: 5px;
}
</style>
<script>
$(document).ready(
function()
{
//Hide all the answers on page load.
$('.answer').hide();
//For all questions, add 'open'/'close' text.
//You can replace it with an image if you like.
//This way, you don't need to specify img tag in your HTML for each question.
$('.question')
.append(' <span>[ open ]</span>');
//Now there are two ways to toggle the visibility of answer.
//Either click on the question OR click on Open All / Close All link.
//To use the same code for both instances, we will create
//a function which will take the 'question' div and toggle the answer for it.
//Advantage of this approach is that the code to toggle the answer is in
//one place.
//By default, this function will try to toggle the status of the answer
//i.e. if it's visible, hide it otherwise show it.
//This function will take a second argument called 'showAnswer'.
//If this argument is passed, it overrides the toggle behavior.
//If 'showAnswer' is true, answer is shown.
//If it's false, answer is hidden.
//This second parameter will be used by the 'openAll', 'closeAll' links.
var toggleAnswer = function toggleAnswer(question, showAnswer)
{
//The way I have structured the HTML, answer DIV is right after
//question DIV.
var $answer = $(question).next('div');
//Animation callback, after the animation is done, we want to
//switch the 'text' to display what could the user do with the question.
//Once again, you can change this code to show open/close image.
var updateText = function()
{
var text = $answer.is(':visible') ? ' [close] ' : ' [open] ';
$(question).find('span').html(text);
}
var method = null;
if(arguments.length > 1)
{
//If the function was called with two arguments, use the second
//argument to decide whether to show or hide.
method = showAnswer === true ? 'show' : 'hide';
}
else
{
//Second argument was not passed, simply toggle the answer.
method = $answer.is(':visible') ? 'hide' : 'show';
}
$answer[method]('fast', updateText);
};
//On each question click, toggle the answer.
//If you have noticed, I didn't enclose both Q&A inside one DIV.
//The way you have done if user clicks on the answer, answer will collapse.
//This may not be desirable as user may want to copy the answer
//and he won't be able to.
$('.question').click(function(){ toggleAnswer(this);});
//We will reuse the same toggleAnswer method in openAll, closeAll
//handling. This way, if you want to change behavior of how the question/answers
//are toggled, you can do it in one place.
$('#openClose').click(
function()
{
var showAnswer = $(this).html().toLowerCase().indexOf('open') != -1 ? true : false;
$('.question').each(function() { toggleAnswer(this, showAnswer); });
$(this).html(showAnswer ? 'Close All' : 'Open All');
return false;
}
);
}
);
</script>
<html>
<head>
<title>simple document</title>
</head>
<body>
<a id='openClose' href='#'>Open All</a>
<br /><br />
<div class='question'>Question 1</div>
<div class='answer'>Answer 1</div>
<div class='question'>Question 2</div>
<div class='answer'>Answer 2</div>
<div class='question'>Question 3</div>
<div class='answer'>Answer 3</div>
</body>
</html>
You need to use the callbacks because your animation will not have finished by the time to check for which image is being shown.
$(".qa").click(function() {
$(this).find("div").next().slideToggle("fast", toggleImage);
}
function toggleImage(){
var $img = $(this).find("img");
$img.attr('src') == "open.gif" ? $img.attr('src', "close.gif") : $img.attr('src', "open.gif");
}
N.B There are better ways to do this but lets get you working first and then see if you want to refactor it some more.
Thank you for taking the time to provide this. I will try this later today and report back. In my version, I toggle the Open All/Close All feature. It's a cleaner look and easier to use, since you don't have to move your mouse.
Redsquare and Solution Yogi:
Thanks. I will reply again later and also post a working demo so you can see the problem more clearly. Sorry, I should have done that before.
Liz