I am a total noob, so please go easy.
I am trying to replace one image with a second image while hovering on a different element. My problem is that only the first image is being replaced by the link images. I've give each image an ID, I just am not sure how to apply it.
Thank you in advance for any help you can provide!
Here is what I have so far:
Script:
<script>
function changeimage(towhat,url){
if (document.images){
document.images.targetimage.src=towhat.src
gotolink=url
}
}
function warp(){
window.location=gotolink
}
</script>
<script language="JavaScript1.1">
var myimages=new Array()
var gotolink="#"
function preloadimages(){
for (i=0;i<preloadimages.arguments.length;i++){
myimages[i]=new Image()
myimages[i].src=preloadimages.arguments[i]
}
}
preloadimages("http://www.dxmgp.com/group/images/color_si.jpg", "http://www.dxmgp.com/group/images/bw_si.jpg","http://www.dxmgp.com/group/images/color_dxm.jpg", "http://www.dxmgp.com/group/images/bw_dxm.jpg","http://www.dxmgp.com/group/images/color_tsg.jpg", "http://www.dxmgp.com/group/images/bw_tsg.jpg","http://www.dxmgp.com/group/images/color_image.jpg", "http://www.dxmgp.com/group/images/bw_image.jpg")
</script>
HTML:
<div id="wrap">
<div id="upper">
<div class="u-top">
<img src="http://www.dxmgp.com/group/images/bw_si.jpg" name="targetimage" id="si" border="0" />
<img class="picright" src="http://www.dxmgp.com/group/images/bw_dxm.jpg" name="targetimage" id="dxm" border="0" />
</div>
<div class="u-mid">
<img src="http://www.dxmgp.com/group/images/bw_owners.png" />
</div>
<div class="u-low">
<img class="picleft" src="http://www.dxmgp.com/group/images/bw_tsg.jpg" id="tsg" />
<img class="dxmlogo" src="http://www.dxmgp.com/group/images/logo_dxm.png" />
<img class="picright" src="http://www.dxmgp.com/group/images/bw_image.jpg" id="img" />
</div>
</div>
<div id="lower">
<div class="dots"><img src="http://www.dxmgp.com/group/images/topdots.png"></div>
<div class="logos">
<a href="http://www.thescoutguide.com">
<img class="picll" src="http://www.dxmgp.com/group/images/logo_tsg.png"></a>
<img class="picmid" src="http://www.dxmgp.com/group/images/logo_si.png">
<a href="http://www.imagebydxm.com">
<img class="piclr" src="http://www.dxmgp.com/group/images/logo_image.png"></a>
</div>
<div class="dots"><img src="http://www.dxmgp.com/group/images/lowdots.png"></div>
</div>
</div>
How about something like this? Consider you have a div containing image1.png. When you mouse over a hyperlink, you want to replace image1.png with image2.png. Then, when you move your mouse away from the hyperlink, image2.png will once again be replaced with image1.png:
This is your div containing the image:
<div id="image">
<img src="image1.png" />
</div>
This is the hyperlink:
Mouse over to change image
Here are the JavaScript functions that will replace the inner HTML of the div with different images:
<script type="text/javascript">
function mouseOver() {
document.getElementById("image").innerHTML = '<img src="image2.png" />';
}
function mouseOut() {
document.getElementById("image").innerHTML = '<img src="image1.png" />';
}
</script>
Let me know if this is what you are looking for.
Related
With this function i want to replace a static image with an animated image (gif) on mouseover. But it's not working only on FIRST mouseover. Is there someone that could help me?
JQuery function:
function mouseListener(imageDiv, image, animated, static)
{
$(function() {
$(imageDiv).hover(
function() {
$(image).attr("src", animated);
},
function() {
$(image).attr("src", static);
}
);
});
}
HTML:
<div onmouseover="mouseListener('#would_youDiv','#would_you','images/would_you.gif','images/would_you.jpg');" id="would_youDiv" class="container">
<a href="work.html">
<img id="would_you" class="img-fluid" src="images/would_you.jpg" width="100%" height="100%" />
<div class="overlay">
<div class="text">WOULD YOU</div>
</div>
</a>
</div>
You could make this much easier by generalizing the logic with classes and data elements.
$(document).ready(function() {
$('.hover-image-container').hover(
function() {
//find the image in the container
var $img = $(this).find('img');
//set the src to the animaged src on it
$img.attr('src', $img.data('animated-src'));
},
function() {
//find the image in the container
var $img = $(this).find('img');
//set the src to the original src
$img.attr('src', $img.data('src'));
}
);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container hover-image-container">
<a href="work.html">
<img src="images/would_you.jpg" data-src="images/would_you.jpg" data-animated-src="images/would_you.gif" width="100%" height="100%" />
<div class="overlay">
<div class="text">WOULD YOU</div>
</div>
</a>
</div>
Your mouseListener method is called when the mouseover event occurs, which is when it creates the listener to the event, instead of acting on the event. You don't need to add the listener, since you've already registered the function to be called on mouse over, you just need to do the action you want for that event.
You need to either put that binding somewhere else, or create two methods that are bound to onmouseover and onmouseout.
For example, if you want to go the two methods route (as that's most similar to your current code):
<div onmouseover="mouseOverListener('#would_youDiv','#would_you','images/would_you.gif','images/would_you.jpg');" onmouseout="mouseOutListener('#would_youDiv','#would_you','images/would_you.gif','images/would_you.jpg');" id="would_youDiv" class="container">
<a href="work.html">
<img id="would_you" class="img-fluid" src="images/would_you.jpg" width="100%" height="100%" />
<div class="overlay">
<div class="text">WOULD YOU</div>
</div>
</a>
</div>
And then in your Javascript:
function mouseOverListener(imageDiv, image, animated, static) {
$(image).attr("src", animated);
}
function mouseOutListener(imageDiv, image, animated, static) {
$(image).attr("src", static);
}
You don't need a js function
HTML
<div class="container">
<a href="work.html">
<img class="img-fluid" src="images/would_you.jpg" width="100%" height="100%" onmouseover="this.src='images/would_you.gif'" onmouseout="this.src='images/would_you.jpg'"/>
<div class="overlay">
<div class="text">WOULD YOU</div>
</div>
</a>
</div>
There is an Image coming from server:
<div class="storyDetail">
<img src="img/photo.jpg" height="180" width="300" style="float:left;">
</div>
Now I want to change this image like this through javascript when page loads:
<div class="storyDetail">
<div class="insta-gallery">
<a href="img/photo.jpg" class="tt-lightbox">
<img src="img/photo.jpg" height="180" width="300" style="float:left;"/>
</a>
</div>
</div>
I have tried through Javascript but got nothing because I am not fimilier with Javascript!
I just got the answer with the help of MR.#sinisake.
<!-- Getting Image 'Src' -->
var storyDetailImageSrc= $('.storyDetail').find('img').attr('src');
<!-- Wrapping image with required div(s) -->
$('.storyDetail img').wrap('<a href="'+storyDetailImageSrc+'" class="tt-lightbox">');
$('.tt-lightbox').wrap('<div class="insta-gallery">');
To change text:
Add an id to your div:
<div class="storyDetail" id="storyDetail01">
Define a function:
function changeText {
document.getElementById("storyDetail01").innerHTML =
' <div class="insta-gallery">
<a href="img/photo.jpg" class="tt-lightbox">
<img src="img/photo.jpg" height="180" width="300" style="float:left;"/>
</a>
</div>';
return false; }
Place that function wherever you execute Javascript when loading your page.
If not sure about what you do to that purpose, but the easiest -and dirtiest-, is to add a scirpt at the bottom of the html
<body> -> that's your html page body
--- code code...
<script type="text/javascript">
changeText();
</script>
</body>
Im curently creating a picture gallery for my project in school. I came across the problem that i don't know how to add a picture description that will only show under the big preview picture and not next to the small pictures at the top. Every small picture will have a different description. I tried some stuff myself but i failed miserably, Im still new to all of this :)
Any solutions to that problem?
<head>
<title>Gallery</title>
<link href="galery.css" rel="stylesheet" type="text/css">
</head>
<body background="cosmic.jpg">
<div class="gallery" align="center">
<div class="smallpics">
<img onclick="getElementById('bigpic').src=this.src" id="picture1" src="images/picture1.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture2" src="images/picture2.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture3" src="images/picture3.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture4" src="images/picture4.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture5" src="images/picture5.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture6" src="images/picture6.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture7" src="images/picture7.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture8" src="images/picture8.png" />
<img onclick="getElementById('bigpic').src=this.src" id="picture9" src="images/picture9.png" />
</div>
<div class="bigpic" align="center">
<img id="bigpic" src="images/picture1.png" alt="" />
</div>
<div class="smallpics">
<img onclick="getElementById('bigpic').src=this.src; getElementById('bigpicDesc').innerHTML(this.alt) " id="picture1" src="images/picture1.png" alt="The Description" />
....
</div>
<div class="bigpic" align="center">
<img id="bigpic" src="images/picture1.png" alt="" />
<div id="bigpicDesc"> </div>
</div>
or
<div class="smallpics">
<img onclick="showInBig(this)" id="picture1" src="images/picture1.png" alt="The Description" />
....
</div>
<div class="bigpic" align="center">
<img id="bigpic" src="images/picture1.png" alt="" />
<div id="bigpicDesc"> </div>
</div>
function showInBig(element){
document.getElementById('bigpic').setAttribute('src',element.getAttribute('src'));
document.getElementById('bigpicDesc').innerHTML(element.element.getAttribute('alt'));
}
Given that alt of the small images are the descriptions.
The first thing is to clean up your HTML and separate out the JavaScript. This has a number of benefits. It keeps your HTML and JS separate without muddying one with the other.
All of your onclick code can be handled thus:
var big_pic = document.querySelector('#bigpic');
document.querySelector('body').addEventListener('click', function(evt) {
if (!/^picture\d+$/.test(evt.target.id)) return;
big_pic.src = evt.target.src;
}, false);
Now, let's consider adding a description. The first question is, how are you going to store these, and in relation to the images?
An obvious solution is to store them in a data attribute on the pictures elements. So just as we read the src from the clicked pic's element, we'll read its description from the same source.
So our elements become:
<img id='picture1' src='some/src.jpg' data-descr='Picture description here' />
Then you're going to need a description placeholder in the big picture area, so add a paragraph.
Finally, change the above JS code to factor in the description also:
var
big_pic = document.querySelector('#bigpic'),
big_pic_descr = document.querySelector('.bigpic p');
document.querySelector('body').addEventListener('click', function(evt) {
if (!/^picture\d+$/.test(evt.target.id)) return;
big_pic.src = evt.target.src;
big_pic_descr.innerHTML = evt.target.getAttribute('data-descr');
}, false);
Could be done in 2 ways, first by making use of data- attribute (1)
jsFiddle 1
var pics = document.querySelectorAll('.smallpics img'),
bigPic = document.getElementById('bigpic'),
descP = document.getElementById('description');
for (var i = 0, ln = pics.length; i < ln; i++) {
// we pass each img with its src and data-desc attributes to the function.
var $this = pics[i];
theClickFunction($this, $this.getAttribute('src'), $this.getAttribute('data-desc'));
}
function theClickFunction($th, $src, $desc) {
$th.addEventListener('click', function() {
//on click we update the bigpic display and thedescription paragraph
bigPic.setAttribute('src', $src);
bigPic.style.display = 'block';
descP.innerHTML = $desc;
});
}
body { margin: 0; padding: 0; }
.smallpics img { width: 19%; cursor: pointer; }
#bigpic { display:none}
<div class="gallery" align="center">
<div class="smallpics">
<img id="pic1" src="//dummyimage.com/300x100?text=pic1" data-desc="description of picture 1" />
<img id="pic2" src="//dummyimage.com/300x100?text=pic2" data-desc="description of picture 2" />
<img id="pic3" src="//dummyimage.com/300x100?text=pic3" data-desc="description of picture 3" />
<img id="pic4" src="//dummyimage.com/300x100?text=pic4" data-desc="description of picture 4" />
<img id="pic5" src="//dummyimage.com/300x100?text=pic5" data-desc="description of picture 5" />
<img id="pic6" src="//dummyimage.com/300x100?text=pic6" data-desc="description of picture 6" />
<img id="pic7" src="//dummyimage.com/300x100?text=pic7" data-desc="description of picture 7" />
<img id="pic8" src="//dummyimage.com/300x100?text=pic8" data-desc="description of picture 8" />
<img id="pic9" src="//dummyimage.com/300x100?text=pic9" data-desc="description of picture 9" />
<img id="pic10" src="//dummyimage.com/300x100?text=pic10" data-desc="description of picture 10" />
</div>
<hr>
<div class="bigpic" align="center">
<img id="bigpic" src="images/picture1.png" alt="" />
<p id="description"></p>
</div>
The other way is by using some hidden element, I used <ul> with its lis here but it could be divs or p etc.., while this way adds extra markup to the page it suits better when you have HTML, styled and/or long descriptions rather than just normal text.
jsFiddle 2
var pics = document.querySelectorAll('.smallpics img'),
DescLis = document.querySelectorAll('#hiddenDescs li'),
bigPic = document.getElementById('bigpic'),
descP = document.getElementById('description');
for (var i = 0, ln = pics.length; i < ln; i++) {
// we pass each img with its src attribute.
var $this = pics[i];
theClickFunction($this, $this.getAttribute('src'), i);
}
function theClickFunction($th, $src, i) {
$th.addEventListener('click', function() {
//on click we update the bigpic display and thedescription paragraph
bigPic.setAttribute('src', $src);
bigPic.style.display = 'block';
// get the inner html of the corresponding li and inject it as innerHTML
// of the descreption p
descP.innerHTML = DescLis[i].innerHTML;
});
}
(1) Using alt attribute, as in #Thuin's answer, rather than data-* is better because: This attribute defines the alternative text describing the image. Users will see this text displayed if the image URL is wrong, the image is not in one of the supported formats, or if the image is not yet downloaded.
I was assigned to do a photo gallery.
A big picture (1000x1000) in the middle, three little thumbnails picture(200x200) below it.
I was given this useful function
getBigImg(thumbnail); // Returns big image
We assume the CSS is already given for us and we do not need to worry.
<div class="big image">
<img src="big picture"/>
</div>
<div class = "thumbnails">
<div id="placement1> img src thumbnail 1 </div>
<div id="placement2> img src thumbnail 2 </div>
<div id="placement3> img src thumbnail 3 </div>
</div>
What I did is simple create 3 copies of the .HTML and do infront of each of the thumbnails. Whenever the user click on the image it will redirects to the .html where the big image is big image of the thumbnail.
I was told I can save all this hassle by using JQuery. What are they referring to?
you can do something like this example:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script>
$(document).ready(function() {
$(".galImg").click(function() {
var image = $(this).attr("rel");
$('#feature').fadeOut('slow');
$('#feature').html('<img src="' + image + '"/>');
$('#feature').fadeIn('slow');
});
});
</script>
use this HTML: little bug fixes
<div class="big image">
<img class="bigImage" src="big picture"/>
</div>
<div class="thumbnails">
<div id="placement1" > <img src="thumbnail1" /> </div>
<div id="placement2" > <img src="thumbnail2" /> </div>
<div id="placement3" > <img src="thumbnail3" /> </div>
</div>
and add this to your HTML:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script type="text/javascript">
$(function(){
$(document).on('click', '.thumbnails > div', function(){
var img = $(this).find('img').attr('src');
$('.bigImage').attr('src', img);
});
});
</script>
how to display some information of image in another div by clicking on image and information should be shown/hidden as clicking on this image.
$(document).ready(function () {
$(".cell").click(function () {
$(this).find("span").toggle("slow");
})
});
<div class="cell">
<div class="inner">
<span style="display:none;"> <img src="Images/sachin.jpg" alt="" width="180" height="180" /></span> <span class="name">Sachin Tendulkar</span>
<input type="hidden" class="friend_id" value="22 " />
</div>
</div>
I want that name displayed in another div when i click on particular image
If I'm understanding correctly, I think what you're asking is for the name to be displayed when you click on its image?
$(document).ready(function () {
$(".inner>img").click(function () {
$(this).parent().find("span").toggle("slow");
})
});
<div class="cell">
<div class="inner">
<img src="Images/sachin.jpg" alt="" width="180" height="180" />
<span class="name" style="display: none;">Sachin Tendulkar</span>
<input type="hidden" class="friend_id" value="22 " />
</div>
</div>
Take notice of the reformatted html that removes the span around the image (it's not necessary) and the style attributes of your image and name span.
Try:
$(.cell).click(function() {
$(this).toggle("slow");
$(otherDiv).html( $(this).find('span.name').html() );
// other processing ...
});
But this is for your current code, which should be cleaned up a bit. So see below.
You shouldn't need a span to wrap your image. I would try something more along the lines of:
<div class="cell">
<div class="inner">
<img src="Images/sachin.jpg" data-name="Sachin Tendulkar" alt="" />
<input type="hidden" name="22" class="friend_id" value="22" />
</div>
</div>
Along with:
$('.cell').click(function() {
var img = $(this).find('img');
$(img).toggle('slow');
$(otherDiv).html( $(img).attr('data-name') );
// other processing ...
});