Fiddle
I am making a social button, and I want it to look sort of like a custom g+ sign in button:
However, when I put the second div (to hold the right part of the button), It doesn't show:
HTML:
<div id='p' style='display: inline-block'>Testing Testing 123</div>
CSS:
#p {
height: 25px;
width: 50px;
background: #371e41
}
There is no enough space for the letters in the button. If you increase the width of the button, putting for example width: 300px in the button, the letters will show.
#b {
height: 25px;
width: 300px;
...
}
Fiddle
Related
I have a div that after I click an element(button1), expands its height. I then have another button appear which allows you to shrink the div(button2). After I click button1, the div expands and button2 shows at the bottom. I can then click button2 to shrink the div back to normal, but if I expand the div again, button2 is now off the edge of the screen, albeit in the same bottom location, just far left rather than centered.
I had to set the margin on button2 to -25px since the absolute positioning was kicking it off-center. And I need to use absolute positioning since it seemed it was only way to get the button to appear at the bottom of div after it had expanded.
$(".button1").on("click", function(){
$(".button1" ).fadeOut(200);
$("#block3").animate({
height: '800px'
}, 600, function() {
$(".button2").fadeIn(200);
});
});
$(".button2").on("click", function(){
$(".button2").fadeOut(200);
$("#block3").animate({
height: '400px'
}, 600,function(){
$(".button1" ).fadeIn(200);
});
});
.button2{
width: 50px;
height: 50px;
display:none;
position: absolute;
margin-left: 25px;
}
.button1{
width: 50px;
height: 50px;
margin-top: 25px;
image-rendering: auto;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="row">
<div class = "col-md-12" id = "block3">
<img src="https://placehold.it/120x80/00aaaa/fff/?text=scroll.png" class = "button1" />
<img src="https://placehold.it/120x80/00aaaa/fff/?text=scroll1.png" class = "button2" />
</div>
</div>
Uploaded the code.
https://jsfiddle.net/bs9xhe5e/2/
On the second click it changed the inline styling to display:block instead of display:inline, if you just add the display:inline into your jQuery it works;
https://jsfiddle.net/havL1z3m/
Added
$(".button2").css({display:"inline"});
The reason .button2 is showing up all the way to the left is that the absolute positioning gives it a default left of 0px.
Probably the easiest fix would be to remove absolute position, as well as the margin-left. Instead, to get .button2 to the bottom of the section, just set margin-top: 725px.
.button2{
width: 50px;
height: 50px;
display:none;
margin-top: 725px;
}
And then you will no longer need to use .css() to change bottom of .button2.
Check out this working fiddle: https://jsfiddle.net/gkpx7L15/
Change button2 styles like this:
.button2{
width: 50px;
height: 50px;
display:none;
position: absolute;
margin-left: -25px;
left:50%;//added style
}
https://jsfiddle.net/bs9xhe5e/3/
And everything will work fine
NOTE: Element will be positioned to the center of parent like this only when width is fixed like here. Example:
.someItem{
width: someWidth;//here we set some width to element
left: 50%; //Here we set position from the left
margin-left: -(somewidth/2);//here we set -half of the element's width for margin-left
}
In my web page I have an image that has a button positioned over it. I want to show and hide the button as mouse enter and leave the image:
$('#UserImage').mouseenter(function()
{
$('#ButtonChange').show();
}).mouseout(function()
{
$('#ButtonChange').hide();
})
It is working but as the button is contained inside the image when the mouse enters the button it is considered to leave the image so the button is hidden then at tha same moment as the button is hidden the mouseenter event is triggered again and the button is shown causing a flickering effect
any suggestion to solve this?
Edit:
$('#UserImage').mouseenter(function() {
$('#ButtonChange').show();
}).mouseout(function() {
$('#ButtonChange').hide();
})
.imageUser {
width: 150px;
height: 200px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div style="position:relative;width=150px">
<img ID="UserImage" class="imageUser" ImageUrl="~/Images/logo.jpg" />
<input type="button" ID="ButtonChange" Text="Change" style="position: absolute;top: 180px;height:25px;left:0px;width:100px;display:none">
</div>
The whole thing is also possible with pure CSS ! for such simple thing, you don't really need Jquery !
.imageUser {
width: 150px;
height: 200px;
}
.img-wrapper {
position: relative;
width: 150px
}
.img-btn {
position: absolute;
top: 180px;
height: 25px;
left: 0px;
right:0; /* gave right, to align the button in center */
margin:0 auto; /* as button as fixed width, margin aligns in center */
width: 100px;
display: none
}
.img-wrapper:hover .img-btn {display:block} /* whenever mouse hovers the image wrapper, the button is shown, other time, its hidden */
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="img-wrapper">
<img ID="UserImage" class="imageUser" ImageUrl="~/Images/logo.jpg" />
<input type="button" ID="ButtonChange" Text="Change" class="img-btn">
</div>
Try hover?
$("#UserImage").hover(function () {
$('#ButtonChange').show();
}, function () {
$('#ButtonChange').hide();
});
I don't have an image so I make a div instead. See Fiddle below.
Fiddle: https://jsfiddle.net/9koswww1/1
Change mouseenter to mouseover.
https://api.jquery.com/mouseenter/
Check the bottom of the page for an example.
try this
$('#UserImage').mouseenter(function()
{
$('#ButtonChange').show();
}).mouseleave(function()
{
$('#ButtonChange').hide();
})
I have an HTML page and unfortunatly I don't know much about it. In my HTML page there is a simple button that redirect to another website. What I would like to do is to show a popup that advise the user that he is moving to another site. If he accepts so he is redirected, if not then he stays in page.
I've made a graphic for all the process described before and it is a simple gif animated. what I wanna do is this:
The user click on the button
the gif animated pop up (and all the background is unclickable with a dark color if it's possible to do)
after 2 seconds the alert pop up next to the gif.
I've an example of what I wanna do. http://imgur.com/8dAf3Xp
Try this sample i created in js fiddle
fiddle
I use 2 overlapping divs to achieved this, wait 2 seconds and the pop-out will automatically show.
Hope this helps :)
HTML
<div id = "pop-out">
<div id = "message">
Message goes here
<button class = "ok"> Ok </button>
</div>
</div>
<div id = "container">
Content goes here
<button>You can't click me</button>
</div>
CSS
div#pop-out {
position: absolute;
top: 0;
left: 0;
background-color: rgba(255,255,255,.2);
width: 100%;
height: 100%;
z-index: 1;
display: none;
}
div#message {
width: 50%;
height: 100px;
margin: 0 auto;
border: 1px solid red;
text-align: center;
line-height: 100px;
}
jQuery
$(document).ready(function(){
setTimeout(function(){
$("#pop-out").show();
},2000);
$("button.ok").click(function(){
$("#pop-out").hide();
});
});
I am trying to get an information tag to slide out from behind a circular picture. In order to do this I used a block and circle to create the information field and stuck it behind the image.
The problem I am running into is getting it to slide out smoothly. Since there are two div's, the square slides out and then the circle, causing it to look choppy.
I would like to get it to toggle in and out as if it were one object.
$(document).ready(function(){
$('.employeeBlock').hide();
$('.employeeDot').hide();
$('.employee').click(function(){
$('.employeeDot').toggle('slide');
$('.employeeBlock').toggle('slide');
});
I have tried it with the employeeDot inside the employeeBlock which is in the employee div
as well as both the employeeDot and the employeeBlock seperate and in the employee div.
Both methods give similar results
Thanks
EDIT: Thanks for the replies, it's running smoother, but not quite perfect. I think I need to create one item that is shaped like a bullet, and toggle that in and out. Any ideas on how to do that?
The closest I can get is a pill shape, which leaves some of the area uncovered
EDIT: Here is my html:
<body>
<div class = 'employee'>
<div class = 'employeeDot'></div>
<div class = 'employeeBlock'></div>
<img class = 'pic' src = "https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcQfMDb1Qtu7gTDZTfnFR2XcPqrfkn27zeWASTBfczi-GGQAIKG_"/>
</div>
</body>
</html>
And my CSS:
.pic {
height: 150px;
width: 150px;
border-radius: 75px;
position: absolute;
}
>.employeeBlock {
background-color:maroon;
height: 150px;
width: 150px;
position: absolute;
left: 75px;
float: left;
}
>.employeeDot {
background-color: maroon;
height: 150px;
width: 250px;
border-radius: 150px;
position: absolute;
float: left;
left: 75px;
}
You can specify any number of selectors to combine into a single result:
$('.employeeDot, .employeeBlock').toggle('slide');
Multiple Selector
.toggle(); is deprecated, use .slideToggle(); instead.
Slide down:
$(document).ready(function(){
$('.employeeDot','.employeeBlock').hide();
$('.employee').on("click", function(){
$('.employeeDot, .employeeBlock').slideToggle('fast');
});
});
Slide from side:
$(document).ready(function(){
$('.employeeDot','.employeeBlock').hide();
$('.employee').on("click", function(){
$('.employeeDot, .employeeBlock').animate({width: 'toggle'});
});
});
The rest of the answers have covered everything, but to get the element to shape like a bullet use:
border-radius: 10px 10px 0 0;
But match the size and sides to your likings.
try this.
$(document).ready(function(){
$('.employeeBlock,.employeeDot').hide();
$('.employee').click(function(){
$('.employeeDot, .employeeBlock').toggle('slide');});
I have a container (500px width and height 800px). THe container users an image as a background and in the middle I want to add a button that says "sign up." When a user clicks on the sign up button I want a sign up form that pops in the same container.
In other words I need a rollover effect where the background changes color to something else and the same container is used a sign up box. And I need the transformation to stay until the user hits the close button or something like that.
How can I accomplish this? Any ideas will be appreciated. Thanks!
You can place the 2 containers on top of each other and fade in/out the top one - DEMO
HTML
<section>
<div id="lower">
<button> Close </button>
</div>
<div id="upper">
<button> Sign up </button>
</div>
</section>
CSS
div {
position: absolute;
left: 20px;
top: 20px;
height: 300px;
width: 400px;
line-height: 300px;
text-align: center;
}
#lower { background: honeydew; }
#upper { background: beige; }
jQuery
$("#upper button").on("click", function() {
$("#upper").fadeOut(300);
});
$("#lower button").on("click", function() {
$("#upper").fadeIn(300);
});