Develop Reference

Ajax POST request from JS to PHP does not work correctly

The idea of ​​the code I'm trying to run is this: When a $ _GET [] request arrives on the products.php page, I pass it via an ajax POST request to the get_data_products.php page and get data from there.
PHP
if(isset($_GET['cat'])){
$filter_cat = $_GET['cat'];
echo '<input type="hidden" value="'.$filter_cat.'" class="getcat" />';
}
JS
function filter_data2() {
$('.filter_data').html('<div id="loading" style="" ></div>');
var action = 'fetch_data';
var filter = [];
var category = $('.getcat').val();
filter.push(category);
$.ajax({
url:"<?php echo $g['url']; ?>get_date_products.php",
method:"POST",
data:{action:action,category:filter},
success:function(data){
$('.filter_data').html(data);
}
});
}
The problem is: When I get for example $_GET['category'] = 2 and ajax sends the data to get_data_products.php and then selects another category and $_GET['category'] = 12 sometimes it is not sent.
When I give var_dump ($_GET['category']) it always contains the correct value, but for some reason ajax does not send it.

I can see a typo here url:"get_date_products.php" doesn't it supposed to be data?

Laravel 5 attach with Ajax?

I have this laravel code in my controller detach function.
$input = Input::all();
$product= Products::findOrFail($input['product_id']);
$product->tags()->detach($input['tag_id']);
$product= Products::where('customer_id', Auth::user()->customers_id)->get();
return view('products.tagsdelete', [
'products' => $product,
]);
This works fine, it deletes the tag realation from my pivot table. The only thing that bugs me it that I don't want to reload the page everytime I press the delete button on my view.
( Of course I could make a selection of all tags the user want to delete, but I want to to this live with Ajax )
My problem is, I couldn't find anything that helps me with detachment from laravel + Ajax. I'm quite okay with Javascript and Jquery but Ajax is still a new thing for me..
So can anybody help me there? I'm really stuck.
Thanks for taking your time :)
#Wiriya Rungruang
current controller code:
public function detach()
{
$input = Input::all();
$product= Products::findOrFail($input['product_id']);
$product->tags()->detach($input['tag_id']);
$product= Products::where('customer_id', Auth::user()->customers_id)->get();
}
my button:
<button type="submit" class="delete-tag-btn" data-product_id="{{ $product->id }}" data-tag_id="{{ $tag->id }}"><i class="glyphicon glyphicon-trash"></i></button>
at the bottom of the code the JS:
<script>
$(".delete-tag-btn").on('click', function(){
var url = "{{ route('detach') }}"; // Url to deleteTag function
url += "product_id=" + $(this).data('product_id');
url += "&tag_id=" + $(this).data('tag_id');
// Now url should look like this 'http://localhost/deletetag?product_id=2&tag_id=5
// Send get request with url to your server
$.get(url, function(response){
alert("success");
});
});
</script>

First : You should create function detach tag from product in your controller and return status success or failure(or nothing)
In your controller
function detachTag(){
$input = Input::all();
$product= Products::findOrFail($input['product_id']);
$product->tags()->detach($input['tag_id']);
$product= Products::where('customer_id', Auth::user()->customers_id)->get();
return "Some state for checking it a success or not";
}
Second : Create javascript function for checking when you click on delete button send request with parameter to function that we created in the first step and rerender or remove that tag from your HTML page
**Parameter is mean product_id and tag_id that your want to detach it
In your js
$(".delete-tag-btn").on('click', function(){
var url = "localhost/deletetag?"; // Url to deleteTag function
url += "product_id=" + $(this).data('product_id');
url += "&tag_id=" + $(this).data('tag_id');
// Now url should look like this 'http://localhost/deletetag?product_id=2&tag_id=5
// Send get request with url to your server
$.get(url, function(response){
// Do what you want
});
});
So when you click on .delete-tag-btn It will send request for detach it

While you can right a simple ajax call, send data and return html and replace it with the old html
lets begin :)
first step is to write ajax, and send it when form is submit or any button is clicked (as per your code)
this one is sample ajax, just fill in your data in it.
var BASEURL = window.location.origin + "/your_domain_name/";
$.ajax({
url: BASEURL + "your_route",
type: "POST/GET", //any_one
data: {
// Your data comes here (object)
},
beforeSend: function () {
},
success: function (response) {
console.log(response); // your html in return
},
complete: function (response) {
}
});
now a call will be send with your data to controller respective to specified route you mentioned, processing will be normal.
It will return only html. You can do whatever you want with this html.
One important problem you might face if considering these instructions is, right now the view you are returning is probably of whole page (because the page is been refresh every time), but if you are thinking to replace it with new html, your will only have to return that part of the page may be a single row or something like that. So break your view in many sub views. Php #include(//path) (blade) might come handy. Thats how I use to work. :)

how to fetch data from sql server database in php without refreshing the page

I am trying to get some data from the database. I create a function that is located in functions.php file that return a value. On another page, I create a variable and just get that value. I was trying to use the onkey to check the database but then I realize that i need to know the amount of tickets even if they don't type anything.
Here is the function:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$amount_of_tickets = $row['number_of_tickets'];
}
return $amount_of_tickets;
}
And, I am trying to check the database (without refreshing the page) and get the value on this page:
application.php
$amount_of_tickets = is_ticket_able($conn);
Then, I just check that $amount_of_tickets is not 0 or 1. Because if is one then some stuff have to change.
I am doing this (inside application.php):
if($amount_of_tickets !=0){
//show the form and let them apply for tickets.
//also
if($amount_of_tickets == 1){
//just let them apply for one ticket.
}
}
EDIT: I saw that AJAX would be the right one to use, but I am so confuse using it.
UPDATE:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
return $ticket;
}
application.php
$amount_of_tickets = is_ticket_able($conn);
<script type="text/javascript">
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
alert(global_isTicketAble);
if( global_isTicketAble == 0 ){
window.location.replace("http://www.google.com");
}
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
});
}
</script>
So, now the problem is that when I alert(global_isTicketAble); it doesn't alert the value from the database but it does alert everything that is inside application.php...Help plzzz

Server side
Assuming you need to check $amount_of_tickets periodically and this can be computed into application.php, inside that file you'll have
<?php
// $conn is defined and set somewhere
$amount_of_tickets = is_ticket_able($conn);
echo $amount_of_tickets;
exit(0);
?>
This way when the script is invoked with a simple GET request the value is returned in the response as simple text.
Client Side
ajax is the way to go if you want to update information on page without reloading it.
Below is just a simple example (using jQuery) that may be extended to fit your needs.
The code below is a JavaScript snippet. A global is used to store the value (globals should be avoided but it's just for the purpose of the example)
Then a function is invoked and the updated value is fetched from function.php script.
The function -prior termination- schedules itself (with setTimeout) to be re-invoked after a given amount of milliseconds (to repeat the fetch value process).
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
// eventually do something here
// with the value just fetched
// (ex. update the data displayed)
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
}
}
Note that $.ajax() sends the request but does not wait for the response (as async is set to true). When the request is received the function specified as success is executed.
Complete jQuery ajax function documentation can be found here
http://api.jquery.com/jquery.ajax/

I assume that you have a page (application.php) that displays a table somewhere.
And that you wish to fill that table with the data found in you database.
I'm not sure about WHEN you want these data to be refreshed.
On button click or periodically (like ervery 5 seconds)... But it doesn't matter for what I explain below.
In application.php:
Assemble all your page as you already know how.
But inside it, somewere, just insert an empty div where your table should show:
<div id="dynamicContent"></div>
Also add this script at the bottom of the page:
<script>
function getData(){
PostData="";
$.ajax({
type: "POST",
url: "function.php",
data: PostData,
cache: true,
success: function(html){
$(Destination).html(html);
}
});
}
getData(); // Trigger it on first page load !
</script>
There is 2 variables here... I named it "PostData" and "Destination".
About PostData:
You can pass data collected on the client side to your PHP function if needed.
Suppose you'd need to pass your user's first and last name, You'd define PostData like this:
Fname=$("#Fname").val(); // user inputs
Lname=$("#Lname").val();
PostData="Fname="+Fname+"&Lname="+Lname;
In your function.php, you will retreive it like this (like any normal POST data):
$Fname=$_POST['Fname'];
$Lname=$_POST['Lname'];
If you do not need to pass data from your client side script to you server side PHP... Just define it empty.
PostData="";
Then, about Destination:
This is the place for the empty "dynamic div" id ( I named it "dynamicContent" above).
Don't forget about the hashtag (#) for an id or the dot for a class.
This is a jQuery selector.
So here, PostData would be defined like this:
Destination="#dynamicContent";
The result of the ajax request will land into that "dynamic div".
This WILL be the result of what's defined in function.php..
So, if you follow me, you have to build your table in function.php...
I mean the part where you do your database query and your while fetch.
echo "<table>";
echo "<tr><th>column title 1</th><th>column title 2</th></tr>"
while ($row = sqlsrv_fetch_array($stmt)){
echo "<tr><td>" . $row['data1'] . "</td><td>" . $row['data2'] . "</td></tr>";
}
echo "</table>";
So if you have no data, the table will be empty.
You'll only get the table and table headers... But no row.
There is then no need for a function that checks if there is data or not.
Finally... About the trigger to refresh:
In application.php, you may place a button that fires getData()... Or you may define a setInterval.
It's up to you.
This is how I use ajax to refresh part of a page without reloading it completly.
Since ajax is new to you, I hope this answer will help.
;)
------------------------
EDIT based on Ariel's comment (2016-05-01)
Okay, I understand! Try this:
In application.php:
<div id="dynamicDiv"></div>
<script type="text/javascript">
// timer to trigger the function every seconds
var checkInterval = setInterval(function(){
checkTicket();
},1000);
function checkTicket(){
$.ajax({
type: "POST",
url: "function.php",
data: "",
cache: true,
success: function(html){
$("#dynamicDiv").html(html);
}
});
}
function noMoreTikets(){
clearInterval(checkInterval);
window.location.replace("http://www.google.com");
}
</script>
In function.php:
// Remove the "function is_ticket_able($conn){" function wrapper.
// Define $conn... Or include the file where it is defined.
// I assume that your query lookup works.
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
// Add this instead of a return.
if($ticket>0){
echo "There is still some tickets!"; // Text that will show in "dynamicDiv"
}else{
?>
<script>
$(document).ready(function(){
noMoreTikets();
});
</script>
<?php
}
Remember that your PHP scripts are executed server-side.
That is why your "return $ticket;" wasn't doing anything.
In this ajax way to call function.php, its script is executed alone, like a single page, without any relation with application.php, which was executed long ago.
It produces text (or javascript) to be served to the client.
If you want to pass a PHP variable to the client-side javascript, you have to echo it as javascript.
So here, if the PHP variable $ticket is more than zero, some text saying that there is still tickets available will show in "dynamicDiv" and the application page will not be refreshed. I suppose it shows a button or something that allows students to get a ticket.
Else, it will be the javascript trigger to "noMoreTikets()" that will land in the "dynamicDiv".

Save form data using AJAX to PHP

How can I save the form data in a file or a local db (maybe using AJAX) which send the data via form action to an external db?
The source code for my form is here: http://jsbin.com/ojUjEKa/1/edit
What changes (if any) should I make to the code?
EDIT:
Right. So I'm able to store the data into localStorage using AJAX and want to send the data stored across to a file called backend.php. Here's my html file: http://jsbin.com/iSorEYu/1/edit
and here's my backend.php file: http://jsbin.com/OGIbEDuX/1/edit
The AJAX is working absolutely fine to store the fields in localStorage but things go wrong when it tries to send the data across to backend.php. I receive the following errors:
[24-Jan-2014 08:40:34 America/Chicago] PHP Notice: Undefined index: data in /home4/private/public_html/marketer/backend.php on line 7
[24-Jan-2014 08:40:34 America/Chicago] PHP Warning: Invalid argument supplied for foreach() in /home4/private/public_html/marketer/backend.php on line 10
[24-Jan-2014 08:40:58 America/Chicago] PHP Notice: Undefined index: data in /home4/private/public_html/marketer/backend.php on line 7
[24-Jan-2014 08:40:58 America/Chicago] PHP Warning: Invalid argument supplied for foreach() in /home4/private/public_html/marketer/backend.php on line 10
What's the issue here?

LocalStorage would be your best bet. I would suggest using storejs as their API is straight forward, easy to use, and x-browser.
You could then trigger the form values to be stored on the "blur" event of each field.
$('input').on('blur', function (e) {
var el = e.target;
store.set(el.attr('name'), el.val());
});
When you are ready to submit to the server, you could use something like the following:
$('#formID').on('submit', function (e) {
e.preventDefault();
$.post('/my/save/route', store.getAll(), function () { ... });
});
You of course could do all of this without storejs and use vanilla JS to interact with the native LocalStorage API.

PHP:
<h1>Below is the data retrieved from SERVER</h1>
<?php
date_default_timezone_set('America/Chicago'); // CDT
echo '<h2>Server Timezone : ' . date_default_timezone_get() . '</h2>';
$current_date = date('d/m/Y == H:i:s ');
print "<h2>Server Time : " . $current_date . "</h2>";
$dataObject = $_POST; //Fetching all posts
echo "<pre>"; //making the dump look nice in html.
var_dump($dataObject);
echo "</pre>";
//Writes it as json to the file, you can transform it any way you want
$json = json_encode($dataObject);
file_put_contents('your_data.txt', $json);
?>
JS:
<script type="text/javascript">
$(document).ready(function(){
localStorage.clear();
$("form").on("submit", function() {
if(window.localStorage!==undefined) {
var fields = $(this).serialize();
localStorage.setItem("eloqua-fields", JSON.stringify( fields ));
alert("Stored Succesfully");
$(this).find("input[type=text]").val("");
alert("Now Passing stored data to Server through AJAX jQuery");
$.ajax({
type: "POST",
url: "backend.php",
data: fields,
success: function(data) {
$('#output').html(data);
}
});
} else {
alert("Storage Failed. Try refreshing");
}
});
});
</script>

Ajax POST is not posting onclick to current page

Alright so this has been bugging me for a long time now... I have tried everything but I cant get it to work!
So what I want to have is a link that acts as a button, and once you click it, it POSTs an ID number of the button in the form "{ 'id' : id }"
edit-homepage.php:
<script>
$(function() { // document ready
$('a.inactive').on('click', function(event) {
event.preventDefault(); // instad of return false
var id = $(this).data('id');
// use $.post shorthand instead of $.ajax
$.post('edit-homepage.php', {id: id}, function(response) {
// after you get response from server
editSlide(id);
});
});
});
</script>
The a href button is created using PHP and I want it to call the ajax function postID( id ) which will post the id so that later I can populate a form via PHP using the posted id.
edit-homepage.php:
echo '<li><a class="inactive" id="slide-'.$info["id"].
'" onClick="postID('.$info["id"].'); editSlide('.$info["id"].'); return false;">'
.'<img src="../images/'.$info["img"].'" width="175"/><p>Edit Slide '
. $info["id"] .'</p></a></li>';
Currently, when I click the link, it opens the alert but it is EMPTY or Undefined. It is supposed to display "ID: 1" for example if the link clicked has a ID of 1.
edit-homepage.php:
<script>
function editSlide($id) {
<?PHP
if (isset ($_POST['id'])) {
echo "alert('success!2');";
}$id = !empty($_POST['id']) ? $_POST['id'] : '';
$data = mysql_query("SELECT * FROM slider WHERE id='$id'") or die(mysql_error());
$info = mysql_fetch_array( $data );?>
document.getElementById("edit-slide-id").innerHTML="Edit Slide #"+$id;
document.getElementById("edit-form").style.display = "block";
document.getElementById("short-title").value="<?PHP echo $info['s_title']; ?>";
}
</script>
Thanks!

With jquery, you don't need to use attributes to attach events, like that:
$(function() { // document ready
$('a.inactive').on('click', function(event) {
event.preventDefault(); // instad of return false
var id = $(this).data('id');
// use $.post shorthand instead of $.ajax
$.post('edit-homepage.php', {id: id}, function(response) {
alert('ID:' + response);
// after you get response from server
editSlide(id);
});
});
});
As of server side, try replacing raw
<?PHP echo $_POST['id']; ?>
With
<?php echo !empty($_POST['id']) ? $_POST['id'] : '' ?>
You likely get notice about Undefined index id, which breaks javascript if there is no post data.
UPDATE
edit-homepage.php shold be separated something like that:
if(!empty($_POST)) {
// here you process your post data and return
// only wenever you want to pass to script
// not all the html
} else {
// here you output html and scripts, but don't do request processing
}
You should always remember, that your HTML rendering must always be separated from your logic. It is better to put views in separate files from logic, though it is not required, it is much easier to debug and maintain.

You can not include PHP code that is supposedly to run after the ajax call. The PHP code will be run only to generate the page. Anything you want to include in alert should be provided in the ajax response, in your case the data variable.

You need to use alert('ID: ' + id).
The $_POST['id'] part of the script does not react to the AJAX request. It is whatever the $_POST['id'] value is when the script is output to the browser (i.e. when the page is first loaded).
You will see this if you view the source.

alert ("ID:"+data);
then only you will get response
or
alert("ID"+id);
this will alert the id passes to function

http://jsfiddle.net/U54ME/
$(".checkthisclass").click(function() {
$.ajax({
type: "POST",
url: "edit-homepage.php",
data: { 'id' : $(this).attr("slideid"); },
success: function(data) {
alert(data);
}
});
}
});
--
<ul>
<li><a class="inactive checkthisclass" id="slide-5" slideid = "5" ><img src="http://blog.entelo.com/wp-content/uploads/2013/04/stackoverflow-logo.png" width="175"/><p>Edit Slide 5</p></a></li>
</ul>