I have a regex that accepts payments and amounts below. Allows for formats with "$" "," and two decimal spaces. I need this regex to allow trailing spaces after the decimal places like so '$50.00 '
/^\$?[0-9 ][0-9\, ]*(\.\d{1,2})?$|^\$?[\.]([\d][\d])$/
Thoughts?
\s* will capture any whitespace, including tabs and newlines:
/^\$?[0-9 ][0-9\, ]*(\.\d{1,2})?$|^\$?[\.]([\d][\d])\s*$/
If you're just trying to validate dollar values, I would make it a little simpler (although I don't know your exact use case):
/^\$?[0-9,]+(\.\d{2})?\s*$/
Just adding a [ ]* to the end should do the trick:
/^\$?[0-9 ][0-9\, ]*(\.\d{1,2})?[ ]*$|^\$?[\.]([\d][\d])[ ]*$/
But you can simplify this by wrapping your alternatives in a group. Also note that you don't need to escape , or . inside a character class, and you don't need a character class at all if there is only character you want to match.
/^\$?(?:[0-9 ][0-9, ]*(\.\d{1,2})?|\.([\d][\d]))[ ]*$/
Related
I am trying to build a Regex to replace commas used as a separator in between normal text.
Different ways I can replace that is valid:
Space before comma
Comma is between text and/or numbers, without any space
Several commas after each other
Example:
"This is a text separated with comma, that I try to fix. , It can be split in several ways.,1234321 , I try to make all the examples in one string,,4321,"
Results:
This is a text separated with comma, that I try to fix.
It can be split in several ways.
1234321
I try to make all the examples in one string
4321
This is the code I have so far using Node.js / Javascript:
data.replace(/(\S,\S)|( ,)|(,,)|(,([a-z0-9]))/ig,';')
The answer from #torazaburo work best, except for several commas with space in-between (, , , ,)
console.log(str.split(/ +, *|,(?=\w|,|$)/));
var str = "This is a text separated with comma, that I try to fix. , It can be split in several ways.,1234321 , I try to make all the examples in one string,,4321,";
console.log(str.split(/ +, *|,(?=\w|,|$)/));
This will split on any comma preceded by one or more spaces, no matter what follows (and eat the preceding spaces, and following spaces if any); or, any comma followed by an alphanumeric or comma or end-of-string.
There is no easy way with the regexp to get rid of the final empty string in the result, caused by the comma at the very end of the input. You can get rid of that yourself if you don't want it.
To rejoin with semi-colon, add .join(';').
data.replace(/\s*,+\s*/g, ';');
This will yield:
This is a text separated with comma;that I try to fix.;It can be split in several ways.;1234321;I try to make all the examples in one string;4321;
There are three parts to this:
\s*: Match zero or more whitespace characters.
,+: Match one or more commas.
\s*: Match zero or more whitespace characters.
If, instead, you want to replace any number of consecutive commas with a single semi-colon:
data.replace(/,+/g, ';');
Honestly, I'm not sure I understood your requirements. If I did misunderstand, please provide the output string you're expecting.
I am trying to create a regEx that will have an optional '+' as the first character and then after accept all digits, making sure no spaces are allowed.
I have tried the following, but it does not seem to work :
new RegExp(/^\+?\d $/);
Seems like you want something like this,
new RegExp(/^\+?\d+$/);
Replace space in your regex with +. \d+ matches one or more digits.
I need a regex that will allow alphabets, hyphen (-), quote ('), dot (.), comma(,) and space. this is what i have now
^[A-Za-z\s\-]$
Thanks
I removed \s from your regex since you said space, and not white space. Feel free to put it back by replacing the space at the end with \s Otherwise pretty simple:
^[A-Za-z\-'., ]+$
It matches start of the string. Any character in the set 1 or more times, and end of the string. You don't have to escape . in a set, in case you were wondering.
You probably tried new RegExp("^[A-Za-z\s\-\.\'\"\,]$"). Yet, you have a string literal there, and the backslashes just escape the following characters - necessary only for the delimiting quote (and for backslashes).
"^[A-Za-z\s\-\.\'\"\,]$" === "^[A-Za-zs-.'\",]$" === '^[A-Za-zs-.\'",]$'
Yet, the range s-. is invalid. So you would need to escape the backslash to pass a string with a backslash in the RegExp constructor:
new RegExp("^[A-Za-z\\s\\-\\.\\'\\\"\\,]$")
Instead, regex literals are easier to read and write as you do not need to string-escape regex escape characters. Also, they are parsed only once during script "compilation" - nothing needs to be executed each time you the line is evaluated. The RegExp constructor only needs to be used if you want to build regexes dynamically. So use
/^[A-Za-z\s\-\.\'\"\,]$/
and it will work. Also, you don't need to escape any of these chars in a character class - so it's just
/^[A-Za-z\s\-.'",]$/
You are pretty close, try the following:
^[A-Za-z\s\-'.,]+$
Note that I assumed that you want to match strings that contain one or more of any of these characters, so I added + after the character class which mean "repeat the previous element one or more times".
Note that this will currently also allow tabs and line breaks in addition to spaces because \s will match any whitespace character. If you only want to allow spaces, change it to ^[A-Za-z \-'.,]+$ (just replaced \s with a space).
Having the following regex: ([a-zA-Z0-9//._-]{3,12}[^//._-]) used like pattern="([a-zA-Z0-9/._-]{3,12}[^/._-])" to validate an HTML text input for username, I wonder if is there anyway of telling it to check that the string has only one of the following: ., -, _
By that I mean, that I'm in need of regex that would accomplish the following (if possible)
alex-how => Valid
alex-how. => Not valid, because finishing in .
alex.how => Valid
alex.how-ha => Not valid, contains already a .
alex-how_da => Not valid, contains already a -
The problem with my current regex, is that for some reason, accepts any character at the end of the string that is not ._-, and can't figure it out why.
The other problem, is that it doesn't check to see that it contains only of the allowed special characters.
Any ideas?
Try this one out:
^(?!(.*[.|_|-].*){2})(?!.*[.|_|-]$)[a-zA-Z0-9//._-]{3,12}$
Regexpal link. The regex above allow at max one of ., _ or -.
What you want is one or more strings containing all upper, lower and digit characters
followed by either one or none of the characters in "-", ".", or "_", followed by at least one character:
^[a-zA-Z0-9]+[-|_|\.]{0,1}[a-zA-Z0-9]+$
Hope this will work for you:-
It says starts with characters followed by (-,.,_) and followed and end with characters
^[\w\d]*[-_\.\w\d]*[\w\d]$
Seems to me you want:
^[A-Za-z0-9]+(?:[\._-][A-Za-z0-9]+)?$
Breaking it down:
^: beginning of line
[A-Za-z0-9]+: one or more alphanumeric characters
(?:[\._-][A-Za-z0-9]+)?: (optional, non-captured) one of your allowed special characters followed by one or more alphanumeric characters
$: end of line
It's unclear from your question if you wanted one of your special characters (., -, and _) to be optional or required (e.g., zero-or-one versus exactly-one). If you actually wanted to require one such special character, you would just get rid of the ? at the very end.
Here's a demonstration of this regular expression on your example inputs:
http://rubular.com/r/SQ4aKTIEF6
As for the length requirement (between 3 and 12 characters): This might be a cop-out, but personally I would argue that it would make more sense to validate this by just checking the length property directly in JavaScript, rather than over-complicating the regular expression.
^(?=[a-zA-Z0-9/._-]{3,12}$)[a-zA-Z0-9]+(?:[/._-][a-zA-Z0-9]+)?$
or, as a JavaScript regex literal:
/^(?=[a-zA-Z0-9\/._-]{3,12})[a-zA-Z0-9]+(?:[\/._-][a-zA-Z0-9]+)?$/
The lookahead, (?=[a-zA-Z0-9/._-]{3,12}$), does the overall-length validation.
Then [a-zA-Z0-9]+ ensures that the name starts with at least one non-separator character.
If there is a separator, (?:[/._-][a-zA-Z0-9]+)? ensures that there's at least one non-separator following it.
Note that / has no special meaning in a regex. You only have to escape it if you're using a regex literal (because / is the regex delimiter), and you escape it by prefixing with a backslash, not another forward-slash. And inside a character class, you don't need to escape the dot (.) to make it match a literal dot.
The dot in regex has a special meaning: "any character here".
If you mean a literal dot, you should escape it to tell the regex parser so.
Escape dot in a regex range
Am i doing sth wrong or there is a problem with JS replace ?
<input type="text" id="a" value="(55) 55-55-55" />
document.write($("#a").val().replace(/()-/g,''));
prints (55) 555555
http://jsfiddle.net/Yb2yV/
how can i replace () and spaces too?
In a JavaScript regular expression, the ( and ) characters have special meaning. If you want to list them literally, put a backslash (\) in front of them.
If your goal is to get rid of all the (, ), -, and space characters, you could do it with a character class combined with an alternation (e.g., either-or) on \s, which stands for "whitespace":
document.write($("#a").val().replace(/[()\-]|\s/g,''));
(I didn't put backslashes in front of the () because you don't need to within a character class. I did put one in front of the - because within a character class, - has special meaning.)
Alternately, if you want to get rid of anything that isn't a digit, you can use \D:
document.write($("#a").val().replace(/\D/g,''));
\D means "not a digit" (note that it's a capital, \d in lower case is the opposite [any digit]).
More info on the MDN page on regular expressions.
You need to use a character class
/[-() ]/
Using "-" as the first character solves the ambiguity because a dash is normally used for ranges (e.g. [a-zA-Z0-9]).
document.write($("#a").val().replace(/[\s()-]/g,''));
That will remove all whitespace (\s), parens, and dashes
Use this
.replace(/\(|\)|-| /g,'')
You have to escape the parenthesis (i.e. \( instead of (). In your regexp, you want to list the four items: \(, \), '-' and (space) and as you want to replace any of them, not just a string of them four together, you have to use OR | between them.
May be very bad but a very basic approach would be,
document.write($("#a").val().replace(/(\()|(\))|-| |/g,''));
| means OR,
\ is used for escaping reserved symbols
You want to match any character in the set, so you should use square brackets to make a character set:
document.write($("#a").val().replace(/[()\- ]/g,''));
Normally, parentheses have a special meaning in regular expressions, so they were being ignored in your regex, leaving just the dash. Normally, to get literal parentheses, you need to escape them with \ (but in a square bracket block, as above, you don't).
The dash above is escaped because it has normally indicates range in a character set, e.g., [a-z].
The brackets indicate a capturing group in the regexp. You'd need to escape them (/\(\)-/) to match the sequence "()-". Yet I guess you want to use a character class, i.e. a expression that matches "(", ")" or "-"; for whitespaces include the \s shorthand:
value.replace(/[()-\s]/g, "");
You might want to read some documentation or tutorial.