Develop Reference

Regular expression not capturing multiple characters [duplicate]

I have a string in JavaScript (e.g., #box2), and I just want the 2 from it.
I tried:
var thestring = $(this).attr('href');
var thenum = thestring.replace(/(^.+)(\w\d+\w)(.+$)/i, '$2');
alert(thenum);
It still returns #box2 in the alert. How can I get it to work?
It needs to accommodate for any length number attached on the end.

For this specific example,
var thenum = thestring.replace(/^\D+/g, ''); // Replace all leading non-digits with nothing
In the general case:
thenum = "foo3bar5".match(/\d+/)[0] // "3"
Here's a bonus: regex generator.
function getre(str, num) {
if(str === num)
return 'nice try';
var res = [/^\D+/g,/\D+$/g,/^\D+|\D+$/g,/\D+/g,/\D.*/g, /.*\D/g,/^\D+|\D.*$/g,/.*\D(?=\d)|\D+$/g];
for(var i = 0; i < res.length; i++)
if(str.replace(res[i], '') === num)
return 'num = str.replace(/' + res[i].source + '/g, "")';
return 'no idea';
};
function update() {
$ = function(x) { return document.getElementById(x) };
var re = getre($('str').value, $('num').value);
$('re').innerHTML = 'Numex speaks: <code>' + re + '</code>';
}
<p>Hi, I'm Numex, the Number Extractor Oracle.
<p>What is your string? <input id="str" value="42abc"></p>
<p>What number do you want to extract? <input id="num" value="42"></p>
<p><button onclick="update()">Insert Coin</button></p>
<p id="re"></p>

You should try the following:
var txt = "#div-name-1234-characteristic:561613213213";
var numb = txt.match(/\d/g);
numb = numb.join("");
alert (numb);​
Result
1234561613213213

I think this regular expression will serve your purpose:
var num = txt.replace(/[^0-9]/g, '');
Where txt is your string.
It basically rips off anything that is not a digit.
I think you can achieve the same thing by using this as well:
var num = txt.replace(/\D/g, '');

Try the following: string.replace(/[^0-9]/g, ''); This will delete all non-digit characters, leaving only digits in the string
function retnum(str) {
var num = str.replace(/[^0-9]/g, '');
return parseInt(num,10);
}
console.log('abca12bc45qw'.replace(/[^0-9]/g, ''));
console.log('#box2'.replace(/[^0-9]/g, ''));

Using the match function.
var thenum = "0a1bbb2".match(/\d+$/)[0];
console.log(thenum);

And this is a snippet which extracts prices with currency and formatting:
var price = "£1,739.12";
parseFloat(price.replace(/[^\d\.]*/g, '')); // 1739.12

I tried all the combinations cited in the previous answer with this code and got it working. It was the only one that worked on that string → (12) 3456-7890
var str = "(12) 3456-7890";
str.replace(/\D+/g, '');
Result: "1234567890"
Obs: I know that a string like that will not be on the attribute, but whatever, the solution is better, because it’s more complete.

You may use the great parseInt() method.
It will convert the leading digits to a number:
parseInt("-10px");
// Will give you -10

You can extract numbers from a string using a regex expression:
let string = "xxfdx25y93.34xxd73";
let res = string.replace(/\D/g, "");
console.log(res);
Output: 25933473
Wrap it into a vanilla JavaScript function:
function onlyNumbers(text){
return text.replace(/\D/g, "");
}

For a string such as #box2, this should work:
var thenum = thestring.replace(/^.*?(\d+).*/,'$1');
jsFiddle:
http://jsfiddle.net/dmeku/

function justNumbers(string)
{
var numsStr = string.replace(/[^0-9]/g, '');
return parseInt(numsStr);
}
console.log(justNumbers('abcdefg12hijklmnop'));
You can do a function like this
function justNumbers(string)
{
var numsStr = string.replace(/[^0-9]/g, '');
return parseInt(numsStr);
}
Remember: if the number has a zero in front of it, the int won’t have it

If you want to parse a number from a price like $6,694.20, it can be done this way:
parseFloat('$6,694.20'.replace(/^\D|,+/g, ''))
Or via a function:
function parsePrice(value) {
return parseFloat(value.replace(/^\D|,+/g, ''))
}
parsePrice('$6,694.20') // 6694.2

To return an int from the string, you can do the following code. It removes all not number characters and returns an integer.
Number("strin[g]3".replace(/\D+/g, ""))

You can use a regular expression.
var txt="some text 2";
var numb = txt.match(/\d/g);
alert (numb);
That will alert 2.

let str = "Total Work Duration: 189.56 Hrs.Present: 23.5 Absent: 2";
/* The provided regex globally matches the character
"." and a digit from the string */
let numArr = str.match(/[\d\.]+/g)
/* It returns an array [189.56, ., 23.5, 2], and
uses the filter function to remove the '.' */
numArr = numArr.filter(n => n != '.')
console.log(numArr)

If someone need to preserve dots in extracted numbers:
var some = '65,87 EUR';
var number = some.replace(",",".").replace(/[^0-9&.]/g,'');
console.log(number); // returns 65.87

You can use Underscore.js' string library as follows:
var common = "#box"
var href = "#box1"
_(href).strRight(common)
The result will be: 1
See: Underscore.string
Demo:
http://jsfiddle.net/abdennour/Vyqtt/
HTML code:
<p>
<a href="#box1" >img1</a>
<a href="#box2" >img2</a>
<a href="#box3" >img3</a>
<a href="#box4" >img4</a>
</p>
<div style="font-size:30px"></div>
JavaScript code:
var comm = "#box"
$('a').click(function() {
$('div').html(_($(this).attr('href')).strRight(comm))})
If you have a suffix as follows:
href="box1az"
You can use the following demo:
http://jsfiddle.net/abdennour/Vyqtt/1/
function retrieveNumber(all, prefix, suffix) {
var left = _(all).strRight(prefix);
return _(left).strLeft(suffix);
}

Here's a solution that checks for no data:
var someStr = 'abc'; // Add 123 to string to see the inverse
var thenum = someStr.match(/\d+/);
if (thenum != null)
{
console.log(thenum[0]);
}
else
{
console.log('Not a number');
}

var elValue = "-12,erer3 4,-990.234sdsd";
var isNegetive = false;
if(elValue.indexOf("-") == 0)
isNegetive = true;
elValue = elValue.replace( /[^\d\.]*/g, '');
elValue = isNaN(Number(elValue)) ? 0 : Number(elValue);
if(isNegetive)
elValue = 0 - elValue;
alert(elValue); // -1234990.234

With regular expressions, how to get numbers from a string, for example:
String myString = "my 2 first gifts were made by my 4 brothers";
myString = myString.replaceAll("\\D+", "");
System.out.println("myString: " + myString);
The result of myString is "24".
You can see an example of this running code at http://ideone.com/iOCf5G.

Use this one-line code to get the first number in a string without getting errors:
var myInt = parseInt(myString.replace(/^[^0-9]+/, ''), 10);

Please check the below JavaScript code. There you can get only a number.
var txt = "abc1234char5678#!9";
var str = txt.match(/\d+/g, "") + '';
var s = str.split(',').join('');
alert(Number(s));
Output: 1234567789

You need to add "(/\d+/g)" which will remove all non-number text, but it will still be a string at this point. If you create a variable and "parseInt" through the match, you can set the new variables to the array values. Here is an example of how I got it to work:
var color = $( this ).css( "background-color" );
var r = parseInt(color.match(/\d+/g)[0]);
var g = parseInt(color.match(/\d+/g)[1]);
var b = parseInt(color.match(/\d+/g)[2]);

This answer will cover most of the scenarios. I came across this situation when a user tried to copy paste the phone number.
$('#help_number').keyup(function() {
$(this).val().match(/\d+/g).join("")
});
Explanation:
str = "34%^gd 5-67 6-6ds"
str.match(/\d+/g)
It will give an array of strings as output:
["34", "56766"]
 
str.match(/\d+/g).join("")
join() will convert and concatenate that array data into a single string.
Output:
"3456766"
In my example, I needed the output as 209-356-6788, so I used replace():
$('#help_number').keyup(function() {
$(this).val($(this).val().match(/\d+/g).join("").replace(/(\d{3})\-?(\d{3})\-?(\d{4})/, '$1-$2-$3'))
});

Written without a regular expression:
// Without Regex
function extractNumber(string) {
let numArray = string.split('').map(item => {
if (typeof +item === 'number' && !isNaN(+item))
return +item
})
return +numArray.join('')
}
extractNumber('#1200milion$') // 1200

In one of my projects I had to take a rating value from a string. This is what I used:
let text = '#xbox2'
let num = text.trim().
split('').
map(num => Number(num)).
filter(x => Number.isInteger(x))

Use:
changeStrangeDate(dateString: string) {
var sum = 0;
var numbers = dateString.match(/\d+/g);
if (numbers.length > 1) {
numbers.forEach(element => {
sum += parseInt(element);
}
);
}
console.log(new Date(sum).toDateString());
return new Date(sum).toUTCString();
}
You can do it like that and then call a function where you need it, with a parameter.
this.changeStrangeDate('/Date(1551401820000-0100)/');

Check string starting with substring using regex

Trying to check if randomString starting with just. (including the dot).
This should give me false but it's not the case:
var randomString = 'justanother.string';
var a = randomString.match('^just\.');
console.log(a);
I probably missed something in the regex argument.

You need to use create a Regular Expression and the use .test() method.
var randomString = 'justanother.string';
var a = /^just\./.test(randomString)
console.log(a);

The answer is simple, you didn't create regex propertly.
'this is not regex'
/this is regex/
new RexExp('this is also regex')
var randomString = 'justanother.string';
var a = randomString.match(/^just\./);
console.log(a);
// I sugest dooing something like this
const startsWithJust = (string) => /^just\./.test(string)

var randomString = 'justanother.string';
var another = 'just.....................';
console.log( randomString.match('^(just[.]).*') );
console.log( another.match('^just[.].*') );

If you wish to keep your lines the same only one change is needed.
var a = randomString.match('^just\\.');
you need to escape the first backslash.

Separate by comma (,) and check if any of the values is = "something"

How can I somehow split/separate my JavaScript variable by comma (,).
And then check if value-of-any-of-the-separated-strings = "something"
For example, my variable has the value 1,2,3,4,5,6,7,8,9,10,2212312, and I want to check if any of the numbers are = 7 in a IF-Statement.
Does anyone have any ideas how this can be done?

First, split the string by ",". Then, use indexOf on the split-string array to see if the target string is found (-1 means it wasn't found in the array). For example:
var str = "1,2,3,4,5,6,7,8,9,10,10,2212312";
var split_str = str.split(",");
if (split_str.indexOf("7") !== -1) {
// Original string contains 7
}
References:
String.prototype.split - https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split
Array.prototype.indexOf - https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/indexOf

This is a simple application of Array.prototype.some:
var yourVar = '1,2,3,4,5,6,7,8,9,10,2212312';
function isSeven(val) {
return val === '7';
}
if (yourVar.split(',').some(isSeven)) {
//do stuff
}
Another common way this could be written is:
if (~yourVar.split(',').indexOf('7')) {
//do stuff
}
Or if Array.prototype.contains has been defined:
if (yourVar.split(',').contains('7')) {
//do stuff
}
Or if you want to use a regular expression:
if (/(?:^|,)7(?:,|$)/.test(yourVar)) {
//do stuff
}
Note: Array.prototype.some, Array.prototype.indexOf and Array.prototype.contains all require polyfills to work correctly cross browser.

Split it into an Array, then use indexOf to see if it's there. If it returns -1, it isn't.
"1,2,3,4,5,6,7,8,9,10,2212312".split(",").indexOf("7")

man i hope it will help you.
var yourValues = '1,2,3,4,5,6,7,8,9,10,2212312';
var array = yourValues.split(",");
boolean isValue = false;
for(i in array)
{
if(array[i]=='7')
{
isValue=true;
}
}
if(isValue)
alert("your number is in the string");
else
alert("your number is in the string");

You could use Array.filter, something like:
var values = '1,2,3,4,5,6,7,8,9,10,2212312'.split(','), find = 7;
if ( values.filter(function(a){return +a === find;}).length ) { /* ... */ }

Use split and Array.indexOf()
var str = "1,2,3,4,5,6,7,8,9,10,2212312";
var num = 7;
var pieces = str.split(",");
var index = pieces.indexOf(num.toString());
It can be done with regular expressions too
var str = "1,2,3,4,5,6,7,8,9,10,2212312";
var num = 7;
var re = new RegExp("(^|,)" + num + "($|,)");
alert(re.test(str));
jsFiddle example

use split along with indexOf:
var someString = '1,2,3,4,5,6,7,8,9,10,2212312';
var splitArray = someString.split(',');
var sevenPosition = splitArray.indexOf('7');
http://jsfiddle.net/jbabey/f4NLY/

Are you looking for the "contains" function. You can use jQuery for this.
if ($.inArray(7, value-of-any-of-the-seperated-strings))
{
console.log("there is a 7!")
}

javascript - get two numbers from a string

I have a string like:
text-345-3535
The numbers can change.
How can I get the two numbers from it and store that into two variables?

var str = "text-345-3535"
var arr = str.split(/-/g).slice(1);
Try it out: http://jsfiddle.net/BZgUt/
This will give you an array with the last two number sets.
If you want them in separate variables add this.
var first = arr[0];
var second = arr[1];
Try it out: http://jsfiddle.net/BZgUt/1/
EDIT:
Just for fun, here's another way.
Try it out: http://jsfiddle.net/BZgUt/2/
var str = "text-345-3535",first,second;
str.replace(/(\d+)-(\d+)$/,function(str,p1,p2) {first = p1;second = p2});

var m = "text-345-3535".match(/.*?-(\d+)-(\d+)/);
m[1] will hold "345" and m[2] will have "3535"

If you're not accustomed to regular expressions, #patrick dw's answer is probably better for you, but this should work as well:
var strSource = "text-123-4567";
var rxNumbers = /\b(\d{3})-(\d{4})\b/
var arrMatches = rxNumbers.exec(strSource);
var strFirstCluster, strSecondCluster;
if (arrMatches) {
strFirstCluster = arrMatches[1];
strSecondCluster = arrMatches[2];
}
This will extract the numbers if it is exactly three digits followed by a dash followed by four digits. The expression can be modified in many ways to retrieve exactly the string you are after.

Try this,
var text = "text-123-4567";
if(text.match(/-([0-9]+)-([0-9]+)/)) {
var x = Text.match(/([0-9]+)-([0-9]+)/);
alert(x[0]);
alert(x[1]);
alert(x[2]);
}
Thanks.

Another way to do this (using String tokenizer).
int idx=0; int tokenCount;
String words[]=new String [500];
String message="text-345-3535";
StringTokenizer st=new StringTokenizer(message,"-");
tokenCount=st.countTokens();
System.out.println("Number of tokens = " + tokenCount);
while (st.hasMoreTokens()) // is there stuff to get?
{words[idx]=st.nextToken(); idx++;}
for (idx=0;idx<tokenCount; idx++)
{System.out.println(words[idx]);}
}
output
words[0] =>text
words[1] => 345
words[2] => 3535

Quick Problem - Extracting numbers from a string

I need to extract a single variable number from a string. The string always looks like this:
javascript:change(5);
with the variable being 5.
How can I isolate it? Many thanks in advance.

Here is one way, assuming the number is always surrounded by parentheses:
var str = 'javascript:change(5);';
var lastBit = str.split('(')[1];
var num = lastBit.split(')')[0];

Use regular expressions:-
var test = "javascript:change(5);"
var number = new RegExp("\\d+", "g")
var match = test.match(number);
alert(match);

A simple RegExp can solve this one:
var inputString = 'javascript:change(5);';
var results = /javascript:change\((\d+)\)/.exec(inputString);
if (results)
{
alert(results[1]); // 5
}
Using the javascript:change part in the match as well ensures that if the string isn't in the proper format, you wont get a value from the matches.

var str = 'javascript:change(5);', result = str.match(/\((\d+)\)/);
if ( result ) {
alert( result[1] )
}