So I want to have one login, but I have 2 different forms to distinguish different functions. How do I pass the login forms between the other 2 functions.
I know javascript and vbs, not jquery.
Example:
I want the same user and pass to appy to both forms without having to make 2 seperate inputs
<%
username = Request.Form("username")
password = Request.Form("password")
%>
<input name="username" />
<input name="password" type="password" />
<form action="test.asp?f=test1" method="post">
text inputs with a submit button
</form>
<form action="test.asp?f=test2" method="post">
different inputs with another submit button
</form>
I haven't used ASP Classic for ages so I am not sure if this is a correct answer, but you can give it try. Since you have two buttons and you want to know which button is being clicked. Why don't you give value to each submit button and then give it the same name? For example.
<form action="test.asp" method="post">
<input name="username" />
<input name="password" type="password" />
<input name='action' type="button" value="Submit One" />
<input name='action' type="button" value="Submit Two" />
</form>
The ASP part
If Request.Form("action") = "Submit One" Then
'' First button is clicked
Else
'' Second button is clicked
End If
I think you're possibly over-thinking this.
I'd put the username and password inputs into a single form and have both submit buttons displayed as follows:
<form action="test.asp?f=test1" method="post">
<input name="username" />
<input name="password" type="password" />
<input id="submit-1" type="button" value="Submit One" />
<input id="submit-2" type="button" value="Submit Two" />
</form>
Then, using JavaScript I'd wire up click event handlers on each button such that when the user click either one, the form action URL querystring would be updated before submitting the form.
var button1 = document.getElementById("submit-1");
var button2 = document.getElementById("submit-2");
b1.onclick = function() {
document.form.action = "test.asp?f=test1";
document.form.submit();
}
b2.onclick = function() {
document.form.action = "test.asp?f=test2";
document.form.submit();
}
Related
If I have a simple html form with two submit buttons:
<form method="POST" class="submit_form main_form" action="myaction">
<input type="submit" name="goback" value="Go Back" />
<input type="submit" name="confirm" value="Confirm">
<input type="hidden" name="secret" value="hello"/>
</form>
It is possible to only post the hidden input if the "confirm" submit is clicked?
If the "goback" submit is clicked the hidden input should be ignored. I know how to accomplish this with JavaScript but was wondering if it can be done with just html.
For anyone wondering, this is how you do this in JavaScript:
<script>
var elements = document.getElementsByClassName('submit_form');
elements[0].addEventListener(
'submit',
function(event) {
if(event.explicitOriginalTarget.name === 'goback'){
var hiddenInput = document.querySelector("input[name='step']");
hiddenInput.setAttribute("disabled", "disabled");
}
}
);
</script>
You could put the buttons in 2 separate forms:
<form method="POST" class="submit_form main_form" action="myaction">
<input type="submit" name="goback" value="Go Back" />
</form>
<form method="POST" class="submit_form main_form" action="myaction">
<input type="submit" name="confirm" value="Confirm">
<input type="hidden" name="secret" value="hello"/>
</form>
That way the secret field will only be posted if the confirm button is clicked.
If you want to do it in the php code you can leave your form as is
and check if isset($_POST["confirm"]) to check if the confirm button was the one clicked.
I'm trying to make a login page and have the following:
<div id="loginField">
<input id="username" type="text" name="user" required></input>
<input id="password" type="password" name="password" required></input>
<input id="submit" type="submit" name="submit" value="Login"></input>
</div>
I made sure that the username and password fields are required. When the login is successful (for this sake, let's just say that both fields are not empty) a login disappears and another view appears. Anyway, I checked to see if the login button is pressed with JQuery:
$(function(){
$('#submit').on('click', function(){
$('#loginField').hide();
$('#differentView').show();});
The problem is that when the login button is clicked, the required attributes gets ignore and the next view is shown. How do I make sure that the required attributes are not ignored when the login button is clicked?
A crude way of doing it...
<div id="loginField">
<input id="username" type="text" name="user" class="required">
<input id="password" type="password" name="password" class="required">
<input id="submit" type="submit" name="submit" value="Login">
</div>
$('#submit').on('click', function(e){
e.preventDefault();
var isReady = true;
$('.required').each(function(){
if (this.value === '') {
isReady = false;
return;
};
});
if (isReady) {
// submit form
};
});
You can use this library: Parsley. It is a javascript form validation library and it is very easy to use and you can customize it for your own means. Good luck!
Instead of handling onclick on button, you can put input fields into the form...
<form action="post" method="post" id="loginField">
<input id="username" type="text" name="user" required></input>
<input id="password" type="password" name="password" required></input>
<input id="submit" type="submit" name="submit" value="Login"></input>
</form>
... and in jQuery you can handle on submit action like this:
$(document).ready(function(){
$('#loginField').on('submit', function(event){
event.preventDefault();
var [username password] = $(this).serializeArray(),
username = username.value,
password = password.value;
/* some validations */
});
});
event.PreventDefault prevents browser from subbmiting so your page won't be refresh. serializeArray returns an array of objects (key-value) that's why you have to use .value
The required attributes are ignored because the input elements are not inside an html form element
To use the HTML5 input valuation attributes (required, minlength... etc)
The inputs should be grouped inside a form element, and you can listen for the form submit event, that is triggered by default when the user press enter (while focus is on a field inside the form) or clicks the submit button (input or button with type="submit") that is also wrapped inside the form
HTML
<form id="loginForm">
<input id="username" type="text" name="user" required />
<input id="password" type="password" name="password" required />
<input id="submit" type="submit" name="submit" value="Login" />
</form>
Javascript
$(function(){
$('#loginForm').on('submit', function (event) {
event.preventDefault(); // prevent default form submit page reload
console.log('I will enter this handler only on valid form')
$('#loginForm').hide();
$('#differentView').show();
})();
Here is a basic plunker with 2 examples https://plnkr.co/edit/I0vUMSeOlrjlYYu4VofU?p=preview
using the default html5 validation
using Parsley
I have a form with ,
In the form after user clicks on Submit , he will be taken to another page which would show all the data entered, Which would allow the user to verify the content.(User will have a look at the content , to see what he entered is correct).
Once user verifies he would submit the data and Insert to DB should be done.
I want to know a method in which i could carry on the approach, to do this.
How can i implement this
EDIT MORE EXPLAIN
addemp.php
The Main Div With Form
<div class="panel-body">
<form>
Employee : <input Type="text" id="name">
<input type="submit" value="check">
</div>
The Second Div in the same form should show once submit is clicked
<div class="submit panel-body">
<form>
Employee : <Employee Name asin main div>
<input type="submit" > <--! this submit would post data
</form>
</div>
how to pass the value from 1st div to the second , and from the second INSERT to db.how can i do without page refresh ?
Use following script on location file
$action='';
if(isset($_POST['submit'])){
//create form here
//Change the action of form
$action = 'save.php';
}
echo '<form method="POST" action="'.$action.'">
<input type="text" name="nric" value="'.isset($_POST['nric'])?$_POST['nric'].'" />
<input type="text" name="empName" value="'.isset($_POST['empName'])?$_POST['empName'].'" />
<input type="text" name="location" value="'.isset($_POST['location'])?$_POST['location'].'" />
<input type="submit" value="Submit"/>
</form>';
EDIT: You don't need to use a form in this case. You can simply use JQuery to show the data from text boxes in a DIV and a button that will POST the data for you on the server.
<input type="text" name="nric" id="nric" />
<input type="text" name="empName" id="empName" />
<input type="text" name="location" id="location" />
<input id="sndData" type="button" value="Submit" />
<div id="showData"></div>
JQuery:
$('#sndData').click(function(){
var makeData = "<p>NRIC: "+$('#nric').val()+"</p><p>Employee Name: "+$('#empName').val()+"</p><p>Location: "+$('#location').val()+"</p>";
$('#showData').html(makeData);
});
When you've done that, just create/show a HTML button that will POST the data for you.
If this answers your question, please mark it as an answer.
I have many forms like the following on the page. Now I want change the form action based on which submit button the user clicked (and of course submit the form)
<form action="/shop/products.php" data-ajax="false" method="post">
<div data-role="fieldcontain">
<input name="submit" class="obutn" type="submit" value="Order" />
<input name="submit" class="oEbutn" type="submit" value="Extras" />
</div>
</form>
I tried with
$(".obtn").click(function() {
$(this).parent().parent().attr("action", "/shop/products.php");
});
$(".oEbtn").click(function() {
$(this).parent().parent().attr("action", "/shop/extras.php");
});
but the form is always submited to products.php. Can you tell me what's wrong?
Instead of setting the action attribute on the form itself, consider setting formaction attribute on each individual input element.
Docs: http://www.w3.org/TR/html-markup/input.submit.html#input.submit.attrs.formaction
<form data-ajax="false" method="post">
<div data-role="fieldcontain">
<input formaction="/shop/products.php"
name="submit" class="obutn" type="submit" value="Order" />
<input formaction="/shop/extras.php"
name="submit" class="oEbutn" type="submit" value="Extras" />
</div>
</form>
There are two typos:
obtn instead of obutn
oEbtn instead of oEbutn
Another suggestion is to use closest("form") to get the form that contains the clicked button.
$(".obutn").click(function() {
$(this).closest("form").attr("action", "/shop/products.php");
});
$(".oEbutn").click(function() {
$(this).closest("form").attr("action", "/shop/extras.php");
});
$("form").on("submit", function () {
alert($(this).attr("action"));
});
JSFIDDLE
Capture the submit event and determine which button was clicked. From that, you can change the action of the form.
Here's a link on how to do that.
How can I get the button that caused the submit from the form submit event?
Also, don't give the form the action until the click happens at all, it is superfluous.
<form data-ajax="false" method="post">
<div data-role="fieldcontain">
<input name="submit" class="obutn" type="submit" value="Order" />
<input name="submit" class="oEbutn" type="submit" value="Extras" />
</div>
</form>
What if you try it out with a switch instead? Something like:
<input name="submit" id = "1" class="obutn" type="submit" value="Order" />
<input name="submit" id = "2" class="oEbutn" type="submit" value="Extras" />
And then in JavaScript we have:
//param: The Id attr of the button that was clicked
function postTo(id){
switch(id){
case 1: postProducts();
break;
case 2: postExtras();
break;
default: //Do something else
}
}
Just an idea. Haven´t tested that yet, but maybe it could be helpful. I hope so.
I am new to forms, and Javascript, so please be forgiving.
I have a form that looks like this:
<form method="post" action="control" name="myform">
<input type="submit" name="Name" value="Do A"/>
<input type="submit" name="Name" value="Do B" />
<input type="submit" name="Name" value="Do C" />
<input type="submit" name="Name" value="Close" />
</form>
I need to change this so that there are two buttons, and the form is submitted using javascript dependent on some external conditions, so I want it to look something like this:
<form method="post" action="control" name="myform">
<script>
function submitForm(form){
if(someConditionA){
submit the form so that the script performs same action as if the button Do A had been clicked
} if (someConditionB){
submit the form so that the script performs same action as if the button Do B had been clicked
} if (someConditionC){
submit the form so that the script performs same action as if the button Do C had been clicked
}
}
function closeForm(form){
window.close();
}
</script>
<button name="doAction" onClick="SubmitForm(this.form)">Do Action<\button>
<button name="close" onClick="SubmitForm(this.form)">Close<\button>
</form>
How can I implement the function submitForm?
Thanks
Add a hidden field with the same name as the original submit buttons:
<input type="HIDDEN" name="Name" value=""/>
Set the value of that field based on your conditions:
function submitForm(form){
if(someConditionA){
form.Name.value = "Do A";
} if (someConditionB){
form.Name.value = "Do B";
} if (someConditionC){
form.Name.value = "Do C";
}
form.submit();
}
Change the new Close button to this:
<button name="close" onClick="this.form.Name.value='Close';this.form.submit();">Close<\button>
I haven't tested this, so it may contain a mistake or two, but that's the general idea. (+1 for 'this.form', not many folks know about that, nice.)
Have just figured out the answer to my question:
The way to do it is to have a hidden field:
<input type="hidden" name="Name" value=""/>
Then in the function, set this hidden field to have the same value as the respective button.
Well, you should simply name your submit buttons differently.
<form method="post" action="control" name="myform">
<input type="submit" name="SubmitA" value="Do A"/>
<input type="submit" name="SubmitB" value="Do B" />
</form>
This way, when submitted, the server will be able to distinguish which submit was clicked.
not sure if I got your Problem right, but why dont you just make a click event on those submit buttons?
like
$('#mysendbtn').click(function(){ ...do A });