I need to rotate an image with javascript in 90-degree intervals. I have tried a few libraries like jQuery rotate and Raphaël, but they have the same problem - The image is rotated around its center. I have a bunch of content on all sides of the image, and if the image isn't perfectly square, parts of it will end up on top of that content. I want the image to stay inside its parent div, which has max-with and max-height set.
Using jQuery rotate like this (http://jsfiddle.net/s6zSn/1073/):
var angle = 0;
$('#button').on('click', function() {
angle += 90;
$("#image").rotate(angle);
});
Results in this:
And this is the result i would like instead:
Anyone have an idea on how to accomplish this?
You use a combination of CSS's transform (with vendor prefixes as necessary) and transform-origin, like this: (also on jsFiddle)
var angle = 0,
img = document.getElementById('container');
document.getElementById('button').onclick = function() {
angle = (angle + 90) % 360;
img.className = "rotate" + angle;
}
#container {
width: 820px;
height: 100px;
overflow: hidden;
}
#container.rotate90,
#container.rotate270 {
width: 100px;
height: 820px
}
#image {
transform-origin: top left;
/* IE 10+, Firefox, etc. */
-webkit-transform-origin: top left;
/* Chrome */
-ms-transform-origin: top left;
/* IE 9 */
}
#container.rotate90 #image {
transform: rotate(90deg) translateY(-100%);
-webkit-transform: rotate(90deg) translateY(-100%);
-ms-transform: rotate(90deg) translateY(-100%);
}
#container.rotate180 #image {
transform: rotate(180deg) translate(-100%, -100%);
-webkit-transform: rotate(180deg) translate(-100%, -100%);
-ms-transform: rotate(180deg) translateX(-100%, -100%);
}
#container.rotate270 #image {
transform: rotate(270deg) translateX(-100%);
-webkit-transform: rotate(270deg) translateX(-100%);
-ms-transform: rotate(270deg) translateX(-100%);
}
<button id="button">Click me!</button>
<div id="container">
<img src="http://i.stack.imgur.com/zbLrE.png" id="image" />
</div>
var angle = 0;
$('#button').on('click', function() {
angle += 90;
$('#image').css('transform','rotate(' + angle + 'deg)');
});
Try this code.
No need for jQuery and lot's of CSS anymore (Note that some browsers need extra CSS)
Kind of what #Abinthaha posted, but pure JS, without the need of jQuery.
let rotateAngle = 90;
function rotate(image) {
image.setAttribute("style", "transform: rotate(" + rotateAngle + "deg)");
rotateAngle = rotateAngle + 90;
}
#rotater {
transition: all 0.3s ease;
border: 0.0625em solid black;
border-radius: 3.75em;
}
<img id="rotater" onclick="rotate(this)" src="https://upload.wikimedia.org/wikipedia/en/e/e0/Iron_Man_bleeding_edge.jpg"/>
CSS can be applied and you will have to set transform-origin correctly to get the applied transformation in the way you want
See the fiddle:
http://jsfiddle.net/OMS_/gkrsz/
Main code:
/* assuming that the image's height is 70px */
img.rotated {
transform: rotate(90deg);
-webkit-transform: rotate(90deg);
-moz-transform: rotate(90deg);
-ms-transform: rotate(90deg);
transform-origin: 35px 35px;
-webkit-transform-origin: 35px 35px;
-moz-transform-origin: 35px 35px;
-ms-transform-origin: 35px 35px;
}
jQuery and JS:
$(img)
.css('transform-origin-x', imgWidth / 2)
.css('transform-origin-y', imgHeight / 2);
// By calculating the height and width of the image in the load function
// $(img).css('transform-origin', (imgWidth / 2) + ' ' + (imgHeight / 2) );
Logic:
Divide the image's height by 2. The transform-x and transform-y values should be this value
Link:
transform-origin at CSS | MDN
Hope this can help you!
<input type="button" id="left" value="left" />
<input type="button" id="right" value="right" />
<img src="https://www.google.com/images/srpr/logo3w.png" id="image">
<script>
var angle = 0;
$('#left').on('click', function () {
angle -= 90;
$("#image").rotate(angle);
});
$('#right').on('click', function () {
angle += 90;
$("#image").rotate(angle);
});
</script>
Try it
i have seen your running code .There is one line correction in your code.
Write:
$("#wrapper").rotate(angle);
instead of:
$("#image").rotate(angle);
and you will get your desired output,hope this is what you want.
I think this will work.
document.getElementById('#image').style.transform = "rotate(90deg)";
Hope this helps. It's work with me.
You can always apply CCS class with rotate property - http://css-tricks.com/snippets/css/text-rotation/
To keep rotated image within your div dimensions you need to adjust CSS as well, there is no needs to use JavaScript except of adding class.
Based on Anuga answer I have extended it to multiple images.
Keep track of the rotation angle of the image as an attribute of the image.
function rotate(image) {
let rotateAngle = Number(image.getAttribute("rotangle")) + 90;
image.setAttribute("style", "transform: rotate(" + rotateAngle + "deg)");
image.setAttribute("rotangle", "" + rotateAngle);
}
.rotater {
transition: all 0.3s ease;
border: 0.0625em solid black;
border-radius: 3.75em;
}
<img class="rotater" onclick="rotate(this)" src="https://upload.wikimedia.org/wikipedia/en/e/e0/Iron_Man_bleeding_edge.jpg"/>
<img class="rotater" onclick="rotate(this)" src="https://upload.wikimedia.org/wikipedia/en/e/e0/Iron_Man_bleeding_edge.jpg"/>
<img class="rotater" onclick="rotate(this)" src="https://upload.wikimedia.org/wikipedia/en/e/e0/Iron_Man_bleeding_edge.jpg"/>
Edit
Removed the modulo, looks strange.
Related
I need help regarding the translate-animate property.
There's an image I want to translate in the upward direction when I scroll down on the page.
Now I know I can use the property translateY(px) to move it but then I don't know how to translateY while scrolling.
I want to make my webpage look like this
https://www.apple.com/uk/iphone/
As you can see when you scroll down the image translates upwards with a smooth flow.
I need a code such that I can translate my image upward smoothly on scrolling down.
P.s- This is my first question, sorry if I am not clear.
This is rather cheap parallax effect that I made myself but does not require any special magic to work... Link to my original demo page
let $scrollPrev = 0;
const $viewBottom = () => $(window).scrollTop() + $(window).innerHeight(),
$parallaxIllusion = () => {
const $pxTop = $(".parallaxTop"),
$pxMid = $(".parallaxMiddle"),
$pxBottom = $(".parallaxBottom"),
$scrollCurr = $viewBottom(),
$bodyTop = $("body").offset().top,
$bodyBottom = $bodyTop + $("body").outerHeight(true),
$pxspeed = $scrollCurr - $bodyTop;
if ($bodyTop > 0 && $viewBottom() > $bodyTop && $(window).scrollTop() <= $bodyBottom) {
$pxTop.css({
"top": 40 + -$pxspeed / 4
});
$pxMid.css({
"top": $pxspeed / 2
});
$pxBottom.css({
"top": ($pxspeed / 4)
});
$scrollPrev = $scrollCurr;
};
};
$(document).ready(() => {
$(window).scroll(() => {
$parallaxIllusion();
});
});
body{
height:700px;
}
.parallaxTop {
background: url('https://raw.githubusercontent.com/NightKn8/pure/master/img/demo1/pxHand.png') center center / cover no-repeat;
position: absolute;
left: 50%;
-ms-transform: translate(-100%, 0);
-webkit-transform: translate(-100%, 0);
transform: translate(-100%, 0);
width: 403px;
height: 298px;
z-index: 2;
}
.parallaxMiddle {
background: url('https://raw.githubusercontent.com/NightKn8/pure/master/img/demo1/pxCaps.png') center center / cover no-repeat;
position: absolute;
right: 50%;
-ms-transform: translate(50%, 0);
-webkit-transform: translate(50%, 0);
transform: translate(50%, 0);
width: 109px;
height: 117px;
z-index: 4;
}
.parallaxBottom {
background: url('https://raw.githubusercontent.com/NightKn8/pure/master/img/demo1/pxBeer.png') center center / cover no-repeat;
position: absolute;
right: 50%;
-ms-transform: translate(100%, 0);
-webkit-transform: translate(100%, 0);
transform: translate(100%, 0);
width: 406px;
height: 443px;
z-index: 2;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<div class="parallaxTop"></div>
<div class="parallaxMiddle"></div>
<div class="parallaxBottom"></div>
</body>
Note that you can edit the code to peak 1 image. Speed or direction is controlled at if level.
I am writing a webapp which loads the image and display on canvas (more exact, I am writing a Tizen app which uses HTML5/JavaScript).
I can load the image properly:
function loadImage(file) {
var img = new Image();
img.src = file;
return img;
}
Everything works fine until I started to get images which display in wrong orientation. I figure out how to get the EXIF and orientation, and I was wondering how do I change the above function to return a proper image?
function loadImage(file) {
var img = new Image();
img.src = file;
// Retrieve EXIF orientation (works fine)
...
// What should I do here to rotate the img?
return img;
}
I have been looking around and others are suggesting drawing the image rotated in canvas, but that causes a lot of problems in my calculation (where the x, y are not in 0, 0, width and height are not the same size as the canvas).
Try this
<!DOCTYPE html>
<html>
<body>
<button id="button" value="click here!">Click Here!</button>
<div id="parentdiv">
<img id="image"
src="https://d13yacurqjgara.cloudfront.net/users/71134/screenshots/1020838/save-icon.png" />
</div>
<style>
#parentdiv {width:820px;height:100px;}
#parentdiv.rotate90,#container.rotate270 {width:100px;height:820px}
#image {
transform-origin: top left; /* IE 10+, Firefox, etc. */
-webkit-transform-origin: top left; /* Chrome */
-ms-transform-origin: top left; /* IE 9 */
}
#parentdiv.rotate90 #image {
transform: rotate(90deg) translateY(-100%);
-webkit-transform: rotate(90deg) translateY(-100%);
-ms-transform: rotate(90deg) translateY(-100%);
}
#parentdiv.rotate180 #image {
transform: rotate(180deg) translate(-100%,-100%);
-webkit-transform: rotate(180deg) translate(-100%,-100%);
-ms-transform: rotate(180deg) translateX(-100%,-100%);
}
#parentdiv.rotate270 #image {
transform: rotate(270deg) translateX(-100%);
-webkit-transform: rotate(270deg) translateX(-100%);
-ms-transform: rotate(270deg) translateX(-100%);
}
</style>
<script>
var angle = 0, img = document.getElementById('parentdiv');
document.getElementById('button').onclick = function() {
angle = (angle+90)%360;
img.className = "rotate"+angle;
}
</script>
</body>
</html>
Try:
img.style.transform = 'rotate(30deg)';
I have a slider that I've been trying to get working. It's demo was 3 slides, but I am trying to add 4. When I add it in, the 4 item is either
In the back permanently
Under the right-sides image
I'm not quite sure how I can fix this, if there is a way.
To help describe what I'm looking for, imagine the below is my diagram:
[back img]
[left img] [right img]
[front img]
I am trying to make it so it revolves. Currently, you can see the front/left/right images, which is what I need, but you can also see the back image.
I essentially need the back image to be hidden, so whichever image is in that spot, hide it.
Here is the set up in HTML
<div class='p_slider'>
<div class='p_slider__item'>
<img src='https://s3-us-west-2.amazonaws.com/s.cdpn.io/217233/iwatch1.png'>
</div>
<div class='p_slider__item'>
<img src='https://s3-us-west-2.amazonaws.com/s.cdpn.io/217233/iwatch2.png'>
</div>
<div class='p_slider__item'>
<img src='https://s3-us-west-2.amazonaws.com/s.cdpn.io/217233/iwatch3.png'>
</div>
<div class='p_slider__item'>
<img src='https://s3-us-west-2.amazonaws.com/s.cdpn.io/217233/iwatch3.png'>
</div>
</div>
The positioning in CSS
.p_slider__item:nth-of-type(1) {
-webkit-transform: scale(0.6);
-ms-transform: scale(0.6);
transform: scale(0.6);
left: -200px;
-webkit-filter: blur(2px);
opacity: 0.8;
z-index: 1;
}
.p_slider__item:nth-of-type(2) {
-webkit-transform: scale(1);
-ms-transform: scale(1);
transform: scale(1);
left: 0px;
z-index: 2;
}
.p_slider__item:nth-of-type(3) {
-webkit-transform: scale(0.6);
-ms-transform: scale(0.6);
transform: scale(0.6);
left: 200px;
z-index: 1;
-webkit-filter: blur(2px);
opacity: 0.8;
}
.p_slider__item:nth-of-type(4) {
-webkit-transform: scale(1);
-ms-transform: scale(1);
transform: scale(1);
left: 0px;
z-index: 2;
}
I have quite a bit more code invested in this, but to keep it short, I also have this JS Fiddle Link. I know this is pretty custom work so I appreciate all the help I get! Thanks!
What I've Tried
updated fiddle with 4 items all moving here: DEMO
So I now have 4 items in rotation, but the slider wants to do this.
Slide front image to right
Slide left image to center
Slide (new center) img to Left and swap with that left
Slide (new center) to right, Slide Left to center
You can simplify the code for rotating by defining classes like left,right,front and back for the positions respectively and add and remove them to elements based on rotateLeft() or rotateRight() functions.
CSS:
.back
{
-webkit-transform: scale(0.4);
-ms-transform: scale(0.4);
transform: scale(0.4);
left:0px;
z-index: 1;
-webkit-filter: blur(2px);
}
.front
{
-webkit-transform: scale(1);
-ms-transform: scale(1);
transform: scale(1);
left: 0px;
z-index: 3;
}
.left
{
-webkit-transform: scale(0.6);
-ms-transform: scale(0.6);
transform: scale(0.6);
left: -200px;
opacity: 0.8;
z-index: 2;
-webkit-filter: blur(2px);
}
.right
{
-webkit-transform: scale(0.6);
-ms-transform: scale(0.6);
transform: scale(0.6);
left: 200px;
z-index: 2;
-webkit-filter: blur(2px);
opacity: 0.8;
}
JS:
// 3D Slider for Reece
on = 0; // Init
time = 500; // Set the delay before the next click is accepted to 1 second
// Right
$('.right').click(function () {
rotateRight(); // Call
on = 1; // Set delay on
});
// Left
$('.left').click(function () {
rotateLeft(); // Call
on = 1; // Set delay on
});
play = setInterval(function () {
rotateLeft()
}, 3000)
// Rotate left
function rotateLeft() {
if (on == 0) {
var frontElem = $('.p_slider__item.front');
var leftElem = $('.p_slider__item.left');
var backElem = $('.p_slider__item.back');
var rightElem = $('.p_slider__item.right');
frontElem.removeClass('front').addClass('left');
leftElem.removeClass('left').addClass('back');
backElem.removeClass('back').addClass('right');
rightElem.removeClass('right').addClass('front');
setTimeout(function () {
on = 0; // Accept clicks again
}, time)
}
}
// Rotate right
function rotateRight() {
if (on == 0) {
var frontElem = $('.p_slider__item.front');
var leftElem = $('.p_slider__item.left');
var backElem = $('.p_slider__item.back');
var rightElem = $('.p_slider__item.right');
frontElem.removeClass('front').addClass('right');
leftElem.removeClass('left').addClass('front');
backElem.removeClass('back').addClass('left');
rightElem.removeClass('right').addClass('back');
setTimeout(function () {
on = 0; // Accept clicks again
}, time)
}
}
$('.p_slider__item img').hover(function () {
clearInterval(play)
})
$('.p_slider__item img').mouseenter(function () {
$(this).animate({ 'top': '-14px' }, 300);
})
$('.p_slider__item img').mouseout(function () {
$(this).stop(true, false).animate({ 'top': '0px' }, 300)
play = setInterval(function () {
rotateLeft()
}, 3000)
})
JSFiddle: http://jsfiddle.net/pL03g26f/2/
Is there any way to rotate or spin below image in jQuery. If user swipe up or touch up it rotate clockwise .Or if user swipe down it rotate anticlockwise. In other word is there any way to spin the tyre image clockwise or anticlockwise using mouse over up and mouse down event .so that it look we type is scrolling ? Can I use animation function?
thanks
here is my fiddle
http://jsfiddle.net/wemsbtwj/
function scrolling() {
$("img").css({
'transform': 'rotate(' + ($("main").scrollTop() / mainHeight * 360) + 'deg)'
});
}
var mainHeight = $("main").height();
window.addEventListener("scroll", scrolling, false);
You can use reel or threesixty jQuery plugin for 360 Degrees Image Display.
Here is a list of 360-degrees-image-display-plugins.
If you are thinking of using this as a product image. usually it is done using multiple images of the product taken from different angles slightly different from each other, and then they are changed based on the mouse movement.
If you just want to rotate this image there are many ways, you can take advantage of CSS3 animate and change the image animation property. A good library to look at is
Animate.css http://daneden.github.io/animate.css/
and you can use the Flipper classes, but change the speed so it rotate slower. you can change this using JQuery .CSS function.
fiddle to rotate image with 360deg - http://jsfiddle.net/invincibleJai/wemsbtwj/1/
this what can be done with just jquery.
http://jsfiddle.net/invincibleJai/u62YD/5/
$("img").click(function(){
if($(this).attr("class") == $(this).attr("id")){
$(this).removeClass();
}
else{
$(this).addClass($(this).attr("id"));
}
});
body {
font: 13px/16px "Lucida Sans Unicode","Lucida Grande",sans-serif;
}
.pic_translate {
/*Firefox*/
-moz-transform: translate(200px, 50px);
/*WebKit - Chrome and Safari*/
-webkit-transform: translate(200px, 50px);
/*Internet Explorer 9*/
-ms-transform: translate(200px, 50px);
/*Opera*/
-o-transform: translate(200px, 50px);
/*general*/
transform: translate(200px, 50px);
/*other properties*/
margin-bottom: 70px;
}
.pic_rotate {
/*Firefox*/
-moz-transform: rotate(360deg);
/*WebKit - Chrome and Safari*/
-webkit-transform: rotate(360deg);
/*Internet Explorer 9*/
-ms-transform: rotate(360deg);
/*Opera*/
-o-transform: rotate(360deg);
/*general syntax*/
transform: rotate(360deg);
}
.pic_scale {
/*Firefox*/
-moz-transform: scale(2, 0.5);
-moz-transform-origin: top left;
/*WebKit - Chrome and Safari*/
-webkit-transform: scale(2, 0.5);
-webkit-transform-origin: top left;
/*Internet Explorer 9*/
-ms-transform: scale(2, 0.5);
-ms-transform-origin: top left;
/*Opera*/
-o-transform: scale(2, 0.5);
-o-transform-origin: top left;
/*general syntax*/
transform: scale(2, 0.5);
transform-origin: top left;
}
.pic_skew {
/*Firefox*/
-moz-transform: skew(20deg, -10deg);
/*WebKit - Chrome and Safari*/
-webkit-transform: skew(20deg, -10deg);
/*Internet Explorer 9*/
-ms-transform: skew(20deg, -10deg);
/*Opera*/
-o-transform: skew(20deg, -10deg);
/*general syntax*/
transform: skew(20deg, -10deg);
/*other properties*/
margin-top:50px;
margin-left:100px;
}
img {
/*Firefox*/
-moz-transition: all 3s;
/*WebKit - Chrome and Safari*/
-webkit-transition: all 3s;
/*Opera*/
-o-transition: all 3s;
/*general syntax*/
transition: all 3s;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<p>
Translate 200 X and 50 Y, adding a margin at the bottom to prevent overlapping:
</p>
<img src="data:image/gif;base64,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" alt="nice_picture" id="pic_translate" />
<p>
Rotate 360 degrees clockwise:
</p>
<img src="data:image/gif;base64,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" alt="nice_picture" id="pic_rotate" />
<p>
Scale by 2 times on the X axis and 0.5 on the Y, using the top left point as origin:
</p>
<img src="data:image/gif;base64,R0lGODlhPQBEAPeoAJosM//AwO/AwHVYZ/z595kzAP/s7P+goOXMv8+fhw/v739/f+8PD98fH/8mJl+fn/9ZWb8/PzWlwv///6wWGbImAPgTEMImIN9gUFCEm/gDALULDN8PAD6atYdCTX9gUNKlj8wZAKUsAOzZz+UMAOsJAP/Z2ccMDA8PD/95eX5NWvsJCOVNQPtfX/8zM8+QePLl38MGBr8JCP+zs9myn/8GBqwpAP/GxgwJCPny78lzYLgjAJ8vAP9fX/+MjMUcAN8zM/9wcM8ZGcATEL+QePdZWf/29uc/P9cmJu9MTDImIN+/r7+/vz8/P8VNQGNugV8AAF9fX8swMNgTAFlDOICAgPNSUnNWSMQ5MBAQEJE3QPIGAM9AQMqGcG9vb6MhJsEdGM8vLx8fH98AANIWAMuQeL8fABkTEPPQ0OM5OSYdGFl5jo+Pj/+pqcsTE78wMFNGQLYmID4dGPvd3UBAQJmTkP+8vH9QUK+vr8ZWSHpzcJMmILdwcLOGcHRQUHxwcK9PT9DQ0O/v70w5MLypoG8wKOuwsP/g4P/Q0IcwKEswKMl8aJ9fX2xjdOtGRs/Pz+Dg4GImIP8gIH0sKEAwKKmTiKZ8aB/f39Wsl+LFt8dgUE9PT5x5aHBwcP+AgP+WltdgYMyZfyywz78AAAAAAAD///8AAP9mZv///wAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACH5BAEAAKgALAAAAAA9AEQAAAj/AFEJHEiwoMGDCBMqXMiwocAbBww4nEhxoYkUpzJGrMixogkfGUNqlNixJEIDB0SqHGmyJSojM1bKZOmyop0gM3Oe2liTISKMOoPy7GnwY9CjIYcSRYm0aVKSLmE6nfq05QycVLPuhDrxBlCtYJUqNAq2bNWEBj6ZXRuyxZyDRtqwnXvkhACDV+euTeJm1Ki7A73qNWtFiF+/gA95Gly2CJLDhwEHMOUAAuOpLYDEgBxZ4GRTlC1fDnpkM+fOqD6DDj1aZpITp0dtGCDhr+fVuCu3zlg49ijaokTZTo27uG7Gjn2P+hI8+PDPERoUB318bWbfAJ5sUNFcuGRTYUqV/3ogfXp1rWlMc6awJjiAAd2fm4ogXjz56aypOoIde4OE5u/F9x199dlXnnGiHZWEYbGpsAEA3QXYnHwEFliKAgswgJ8LPeiUXGwedCAKABACCN+EA1pYIIYaFlcDhytd51sGAJbo3onOpajiihlO92KHGaUXGwWjUBChjSPiWJuOO/LYIm4v1tXfE6J4gCSJEZ7YgRYUNrkji9P55sF/ogxw5ZkSqIDaZBV6aSGYq/lGZplndkckZ98xoICbTcIJGQAZcNmdmUc210hs35nCyJ58fgmIKX5RQGOZowxaZwYA+JaoKQwswGijBV4C6SiTUmpphMspJx9unX4KaimjDv9aaXOEBteBqmuuxgEHoLX6Kqx+yXqqBANsgCtit4FWQAEkrNbpq7HSOmtwag5w57GrmlJBASEU18ADjUYb3ADTinIttsgSB1oJFfA63bduimuqKB1keqwUhoCSK374wbujvOSu4QG6UvxBRydcpKsav++Ca6G8A6Pr1x2kVMyHwsVxUALDq/krnrhPSOzXG1lUTIoffqGR7Goi2MAxbv6O2kEG56I7CSlRsEFKFVyovDJoIRTg7sugNRDGqCJzJgcKE0ywc0ELm6KBCCJo8DIPFeCWNGcyqNFE06ToAfV0HBRgxsvLThHn1oddQMrXj5DyAQgjEHSAJMWZwS3HPxT/QMbabI/iBCliMLEJKX2EEkomBAUCxRi42VDADxyTYDVogV+wSChqmKxEKCDAYFDFj4OmwbY7bDGdBhtrnTQYOigeChUmc1K3QTnAUfEgGFgAWt88hKA6aCRIXhxnQ1yg3BCayK44EWdkUQcBByEQChFXfCB776aQsG0BIlQgQgE8qO26X1h8cEUep8ngRBnOy74E9QgRgEAC8SvOfQkh7FDBDmS43PmGoIiKUUEGkMEC/PJHgxw0xH74yx/3XnaYRJgMB8obxQW6kL9QYEJ0FIFgByfIL7/IQAlvQwEpnAC7DtLNJCKUoO/w45c44GwCXiAFB/OXAATQryUxdN4LfFiwgjCNYg+kYMIEFkCKDs6PKAIJouyGWMS1FSKJOMRB/BoIxYJIUXFUxNwoIkEKPAgCBZSQHQ1A2EWDfDEUVLyADj5AChSIQW6gu10bE/JG2VnCZGfo4R4d0sdQoBAHhPjhIB94v/wRoRKQWGRHgrhGSQJxCS+0pCZbEhAAOw==" alt="nice_picture" id="pic_scale" />
<p>
Skew 20 degrees X and -10 degrees Y, adding top and left margins to keep the picture within the visible page:
</p>
<img src="data:image/gif;base64,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" alt="nice_picture" id="pic_skew" />
I'm attempting to achieve a CSS 3 effect where when you click on an image in a bank of images, it expands to all the available area and flips over at the same time.
The way I was able to accomplish this was to clone the element and absolutely position it on top of the original then transform that. In the code below the cloned image is assigned the classes clone and activated.
All is well.
However, if I pre-flip all of the images in the series of images, activated using the flip all button (adding origflipped class, which has rotateY(180deg) so now the backs are showing) and then try the same effect (expand and now rotateY(0deg) to the front side), the animation somehow has unintended side effects.
It looks like when the rotateY transition is executing, half of the image in the rotation effect dips below the page in 3d space, behind the other images and out of view.
So how can I rotateY(0) from rotateY(180deg) without having half of the image floating underneath other things?
$(document).ready(function() {
var ALL_CARDS = [
['http://twitpic.com/show/thumb/26n3ms', 'http://twitpic.com/show/thumb/26n3mr'],
['http://twitpic.com/show/thumb/26n3ma', 'http://twitpic.com/show/thumb/26n3mq'],
['http://twitpic.com/show/thumb/26n3mb', 'http://twitpic.com/show/thumb/26n3mt'],
['http://twitpic.com/show/thumb/26n3mc', 'http://twitpic.com/show/thumb/26n3mu'],
['http://twitpic.com/show/thumb/26n3md', 'http://twitpic.com/show/thumb/26n3mv'],
];
var width = 100;
for (var i = 0; i < ALL_CARDS.length; i++) {
$(document.createElement('div'))
.addClass("card")
.append(
$('<img src="' + ALL_CARDS[i][0] + '" />')
.addClass("face front")
)
.append(
$('<img src="' + ALL_CARDS[i][1] + '" />')
.addClass("face back")
)
.width(width)
.height(width + 10)
.appendTo($('#target_area'))
.find('img').width('100%').height('100%');
}
$('#target_area .card')
.click(function(e) {
e.preventDefault();
var original = $(this);
var proxy = $(this).clone();
var body = $('body');
original.addClass("origshown");
proxy
.css({
'position': 'absolute',
'top': this.offsetTop,
'left': this.offsetLeft - 5
})
.click(function() {
original.removeClass("origshown");
$(this).remove();
})
.addClass("clone")
.appendTo($('#target_area'));
var border_width = 10;
proxy
.css({
'background-color': 'white',
'top': border_width,
'left': border_width,
'height': body.height() - (2 * border_width),
'width': body.width() - (2 * border_width),
})
.addClass('activated');
});
$('#flip_all').click(function(e) {
e.preventDefault();
$('.card').toggleClass('origflipped');
});
});
#target_area .face {
-webkit-backface-visibility: hidden;
position: absolute;
}
#target_area .face img {
vertical-align: middle;
height: 100%;
}
#target_area .face.back {
-webkit-transform: rotateY(180deg);
}
#target_area .card {
float: left;
margin-left: 5px;
-webkit-transform-style: preserve-3d;
-webkit-transition-property: all;
-webkit-transition-duration: 1s;
-webkit-transition-timing-function: ease-in;
}
#target_area .card.origshown {
-webkit-transition-property: none;
visibility: hidden;
}
#target_area .card.origflipped {
-webkit-transform: rotateY(180deg);
}
#target_area .card.clone {
float: none;
-webkit-box-shadow: 0px 2px 6px rgba(0, 0, 0, 0.5);
}
#target_area .card.clone.activated {
-webkit-transform: rotateY(180deg);
}
#target_area .card.clone.origflipped {
-webkit-transform: rotateY(180deg);
}
#target_area .card.clone.origflipped.activated {
-webkit-transform: rotateY(0deg);
}
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.js"></script>
</head>
<body>
<div id="target_area"></div>
<input type="button" value="flip all" id="flip_all" />
</body>
</html>
Hmm, Testing this works fine for me in chrome 5.0.375.99,
http://jsfiddle.net/Fhxb3/
so im not sure what you issue is, what browser are you using?
also, although im sure you know this, it is completly broken in firefox/ie (but thats cause your using -webkit styles