for a button if i need a background image i would use background like below
#statusButton span {
color: #445058;
font-size: 14px;
font-weight: bold;
text-shadow: 1px 1px #fff;
padding: 7px 29px 9px 10px;
background: url('../images/Arrow.png') no-repeat 53px 7px;
display: block;
}
similar to here http://www.soundendeavors.com/clients/index.html
now How do i add this type of image as a foreground for a image. when i use same background attr for image th regular image will overlap is what i need is something of foreground type of css.
an image over a image.
So you want to put another image on top of one, right? You can do it this way:
div{ /*You can use whatever element you prefer*/
width: 400px;
height: 400px;
background-image: url('link1.jpg'), url('link2.png'); /*URLs*/
background-position: left top, right bottom; /*position*/
background-repeat: no-repeat; /*repeat or not*/
}
Fast and easy. The first image in the list will show up on the very top.
Demo: http://jsfiddle.net/DerekL/Pdxpe/
The good thing about this method is that you still has one solid element, instead of wrappers floating around.
if i understand You right, You want to overlay another image over an image?
to overlay another image over an existing image You can work with position in CSS:
CSS:
#wrapper {
position: relative;
}
#img1 {
position: absolute;
top: 0;
left: 0;
z-index:0;
}
#img2 {
position: absolute;
top: 0;
left: 0;
z-index:100;
}
HTML:
<div id="wrapper">
<img src="img1.jpg" id="img1" />
<img src="img2.jpg" id="img2" />
</div>
now the image with the id #img1 is under the image #img2, because of the lower z-index value...
Related
I have a square with a logo inside. On hover in the square, I want the background color to change as well as the color of the logo.
I have the following code:
<div class="pure-u-1 pure-u-md-1-3">
<div class="project", id="project1">
</div>
</div>
.project {
background-color: #f5f4f4;
margin: 0 0.5em 2em;
padding: 4em 4em;
}
#project1:hover {
background-color: red;
}
I can get the logo to change on hover and I can get the square to change, but I can't get them to both change at the same time, i.e. when the mouse touches the square.
I'm assuming this needs javascript, which I do not know. Any tips/help is greatly appreciated.
No JavaScript required, just CSS. No need for an <img> either.
<div class="logo">Brand Name</div>
.logo {
width: 80px;
height: 78px;
text-indent: -9999em;
background-image: url('http://s17.postimg.org/7hltqe5e3/sprite.png');
background-repeat: no-repeat;
background-position: 0 0;
background-color: blue;
}
.logo:hover {
background-color: red;
background-position: -80px 0;
}
http://jsfiddle.net/12u7ma2q/
Create a sprite with both versions of the logo side-by-side. When you hover you will change the background color and shift the position of the sprite image (left, right, up, down - depends on how you created your sprite).
The benefits to this answer over sailens is that you're not using invalid markup (<img> without a src attribute) and you're only making a single request for an image instead of two. Oh, and less markup - a single <div> (which could be an <a>, <span> etc).
You could also shorten .logo by using background instead of individual background properties. I listed them out at first for clarity.
.logo {
width: 80px;
height: 78px;
text-indent: -9999em;
background: blue url('http://s17.postimg.org/7hltqe5e3/sprite.png') no-repeat 0 0;
}
http://jsfiddle.net/12u7ma2q/1/
Cleaner HTML (since img tag needs a source, you can change it for a div):
<div class="pure-u-1 pure-u-md-1-3">
<div class="project", id="project1">
<div class="pure-img">
</div>
</div>
And the CSS:
.project {
background-color: #f5f4f4;
margin: 0 0.5em 2em;
padding: 4em 4em;
}
#project1:hover {
background-color: red;
}
.pure-img{
background-image: url(http://dummyimage.com/600x400/000/fff);
width: 80px;
height: 78px;
}
#project1:hover .pure-img {
background-image: url(http://dummyimage.com/600x400/666/0011fc);
}
and the fiddle
http://jsfiddle.net/h6gwwox6/1/
Relative newbie here. I have two different mouseover/hover functions I can get to work just fine: one, an inline mouseover that 'darkens' an image/box by making it lose opacity; and the second, text that appears over this image/box on hover (jumping up from a hidden position).
The problem is, I want to get them working together without this text losing opacity, which it does when part of the same div class as the image/box. But when I try two separate div classes and position them on top of each other (using z-index), whichever one I put on top seems to block the other one. Is there any way to have it so the image/box loses opacity, but the text that appears doesn't, all in the same mouseover/hover action?
These are the relevant bits in my stylesheet, mostly covering the text part:
.rightbox {
background: rgb(140, 183, 98);
width: 290px;
height: 160px;
margin-bottom: 18px;
padding: 2px;}
.rightboxtext {
display: table-cell;
height: 160px;
width: 290px;
vertical-align: bottom;
text-align: center;
font-weight: bold;
font-size: 20px;
color: #8CB762;
}
.rightboxtext span {
display: block;
height: 0px;
overflow: hidden;
}
.rightboxtext:hover span {
height: 80px;
}
This is the inline stuff that I used where everything, including text, gets the opacity treatment. (In this case the image is attached to the rightboxtext div class, but I also tried it attached to the rightbox div class.)
<div class="rightbox"
onmouseout="this.style.opacity=1;this.filters.alpha.opacity=100"
onmouseover="this.style.opacity=0.6;this.filters.alpha.opacity=60">
<div class="rightboxtext"
style="background-image: url(image.jpg); height: 160px; width: 290px;">
<span>Hello text.</span></div>
</div>
Otherwise I achieved this mangled bit of code, where one seems to block the other:
<div class="rightboxcontainer">
<div class="rightboxtext"
style="position: absolute; z-index: 100; height: 160px; width: 290px;">
<span>Hello text.</span></div>
<div class="rightbox"
style="position: absolute; z-index: 50; height: 160px; width: 290px;"
onmouseout="this.style.opacity=1;this.filters.alpha.opacity=100"
onmouseover="this.style.opacity=0.6;this.filters.alpha.opacity=60"><img
src="image.jpg">
</div>
</div>
With this extra bit in the stylesheet:
.rightboxcontainer { width: 290px; height: 160px; margin-bottom: 18px;}
Thanks in advance!
As a commenter pointed out above, you can do this entirely with CSS:
<style>
* {
padding: 0;
margin: 0;
}
.box {
width: 250px;
height: 250px;
overflow: hidden;
}
.box img {
width: 250px;
height: 250px;
}
.box .message {
background: rgba(0, 0, 0, 0.5);
opacity: 0;
width: 250px;
height: 250px;
position: relative;
top: -256px;
color: #fff;
font-size: 32px;
line-height: 250px;
text-align: center;
font-weight: bold;
font-family: arial;
}
.box .message:hover {
opacity: 1;
}
</style>
<div class="box">
<img src="http://www2.le.ac.uk/departments/geology/people/clark-n/personal/copy_of_images/Satellite-map-of-Antarctica/image">
<div class="message">Antarctica</div>
</div>
.message is positioned on top of the container, .box. When you hover over .message, it fades in from 0 opacity. Its background is semi-opaque (using RGBA, where the fourth value is the opacity), so it dims the image. You could make the image the background-image of the .box if you wanted to.
http://jsfiddle.net/dgGG3/4/
Fist of all, try to avoid inline event handling as you can achieve the desired result with css :hover.
The problem as you can see here http://jsfiddle.net/UjY5Q/ is with opacity on a parent element all child elements also get that opacity.
.rightbox:hover {
opacity:0.5;
}
You can cheat on that one by setting positions to the elements and overlap one to the other one. That's kind a tricky and may also need browser support.
so the easyest way to get what you want is on :hover show a transparent background image example here: http://jsfiddle.net/UjY5Q/1/
I would say that's the way to go
I'm trying to do what many have asked before, but even after trying everything I still can't get the results I want.
I have an image 600px by 1600px, 4 images of 600px by 400px in a vertical line. I want to show 600px by 400px of the image at any one time. Ideally I would be able to hover over an element somewhere on my page and move the image upwards to reveal the other portions of the 600px by 400px image. In effect, I'd have 4 images viewable by hovering over 4 the elements.
I've tried various css3 and jquery solution but none have worked. I would appreciate any help with this.
HTML
<div class="mainimage">
<div class="buttonsection">
<div class="button1">Button 1</div>
<div class="button2">Button 2</div>
<div class="button3">Button 3</div>
<div class="button4">Button 4</div>
</div><!--end of buttonsection-->
<div class="rollingimage">
<img src="IMG/four-pics.png">
</div><!--end of rollingimage-->
</div><!--end of mainimage-->
</div><!--end of main content-->
CSS
.mainimage {
position: relative;
top: 0px;
left: 0px;
width: 900px;
height: 400px;
border: 2px solid #E78F25;
margin: 0 10px 20px 0;
}
.buttonsection {
width: 290px;
height: 400px;
position: relative;
float: left;
}
.button1,
.button2,
.button3,
.button4 {
display: inline;
height: 98px;
width: 290px;
border: 1px solid #E78F24;
text-align: center;
float: left;
}
.rollingimage {
width: 598px;
height: 400px;
position: relative;
overflow: hidden;
top: 0px;
left: 0px;
float: right;
}
jquery
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage').stop().animate({'top': '-200px'}, 1500);
});
});
Here is the jsfidle: http://jsfiddle.net/dirtyd77/jCvYm/1/
Thanks yet again
Gary
Just for fun, no JS:
http://jsfiddle.net/coma/MTWdb/5/
HTML
<div id="foo">
Button 1
Button 2
Button 3
Button 4
<div></div>
</div>
CSS
#foo {
width: 400px;
border: 2px solid #E78F25;
position: relative;
}
#foo > div {
position: absolute;
top: 0;
right: 0;
bottom: 0;
width: 200px;
background: #fff url(http://placekitten.com/600/1600) no-repeat 0 0;
transition: background-position .5s;
}
#foo > a {
display: block;
width: 200px;
line-height: 100px;
text-align: center;
text-decoration: none;
}
#foo > a + a {
border-top: 1px solid #E78F25;
}
#foo > a:nth-child(1):hover ~ div {
background-position: 0 0;
}
#foo > a:nth-child(2):hover ~ div {
background-position: 0 -400px;
}
#foo > a:nth-child(3):hover ~ div {
background-position: 0 -800px;
}
#foo > a:nth-child(4):hover ~ div {
background-position: 0 -1200px;
}
You need to change the positioning of the image inside the div, not the div itself. To animate my example, you could add CSS transitions for better performance than JS animations.
http://jsfiddle.net/jCvYm/8/
$('.rollingimage').find('img')
As Dom mentioned, the jsFiddle you provided didn't reference the jQuery library. It also didn't included any actual images, and only contained code for one of the three buttons. I doubt those were the original problems you were having, though. (The missing reference to jQuery might have been.)
Once I had those straightened out, I noticed that hovering the button caused the picture to slide out of the screen, instead of scrolling. The simplest way to fix that is to move the img element, instead of moving the div. (The more natural way would be to change the scroll position of the div, but I don't recall how to do that off the top of my head.)
Added CSS:
.rollingimage img {
position: relative;
}
New JS:
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage img').stop().animate({'top': '0px'}, 1500);
});
$(".button2").hover(function(){
$('.rollingimage img').stop().animate({'top': '-400px'}, 1500);
});
$(".button3").hover(function(){
$('.rollingimage img').stop().animate({'top': '-800px'}, 1500);
});
$(".button4").hover(function(){
$('.rollingimage img').stop().animate({'top': '-1200px'}, 1500);
});
});
jsFiddle: http://jsfiddle.net/jCvYm/6/
I'm trying to change one image to another on mouseover. Specifically, when the visitor hovers over this:
The image will change to this:
The Current Code
I'd like to do this as lightweight as possible. But the image-background CSS thing doesn't work for me. My code is as follows:
<div id="featured-box-right"><a href="/videos/"
target="_self"><img src="../images/box-featured-home-right.png" title="videos"
alt="videos" width="300" height="150"></a></div>
But when I do this to the CSS:
#featured-box-right a:hover
{
background-image: url(../images/box-featured-home-right-hover.png);
}
The effect doesn't turn out right; it's not a background. It's an actual image. Any guidance as to how I can achieve this as lightweight as possible would be greatly appreciated!
The lightweight method is to use CSS, and use the property background-image of the div:
jsFiddle
<div id="featured-box-right"></div>
CSS:
#featured-box-right {
width: 300px;
height: 150px;
background-image: url('http://i.stack.imgur.com/OywDf.png');
}
#featured-box-right:hover {
background-image: url('http://i.stack.imgur.com/aRJOk.png');
}
You should use css image sprites techniques and do not use img tag here use css background property. You should try something below. you can use cllass or id or parent child relationship that is totally up to you.
<div id="featured-box-right">
</div>
css:
#img1
{
background: url(../images/box-featured-home-right.png);
}
#img1:hover
{
background: url(../images/box-featured-home-right-hover.png);
}
Remove the <img/> tag altogether and try this css.
#featured-box-right a {
background-image: url(../images/box-featured-home-right.png);
}
#featured-box-right a:hover {
background-image: url(../images/box-featured-home-right-hover.png);
}
CSS Sprites is a technique where you use a background-image, a set width and height, and adjust the background-position to display only the portion you need to show. This way you can use a single image and display lots of different graphics with it, saving server requests and speeding up page load times:
HTML:
<img src="images/arrow-sprite.png" alt="arrow" class="clip pos-1" />
CSS:
.clip { position: absolute; top: 0; left: 0; }
.pos-1 { clip:rect(0 48px 48px 0); }
.pos-2 { clip:rect(0 96px 48px 48px); left: -48px; }
.pos-3 { clip:rect(48px 48px 96px 0); top: -48px; }
.pos-4 { clip:rect(48px 96px 96px 48px); top: -48px;
left: -48px; }
Took from here
You can delete the <img> tag and use CSS background iamge method, but you need to combine the 2 pic into one (one on top and one on bottom)
next, you need to use this code:
#featured-box-right {
width: 300px;
height: 150px;
background-image: url(image url here) center top;
}
#featured-box-right:hover {
background-image: url(image url here) center bottom;
}
Using this method makes you need only 1 image
No images (background or otherwise) are required.
This comes out to only 3.84% the size of your two images combined:http://fiddle.jshell.net/gWytK/show/:
<!doctype html>
<html>
<head>
<title></title>
<style>
body {
margin: 8px;
}
#links {
list-style: none;
margin: 0;
padding: 0;
display: block !important;
display: inline-block;
overflow: hidden;
}
#links li {
float: left;
width: 300px;
height: 150px;
overflow: hidden;
background: #000000;
border-radius: 20px;
}
#links a {
display: block;
font: bold 30px/30px 'comic sans ms', sans-serif;
padding: 40px 66px 100px;
color: #5496ff;
text-decoration: none;
text-transform: capitalize;
text-shadow: 0 0 100px #ffffff, 0 0 100px #ffffff;
}
#links a:after {
content: ' >>';
}
#links a:hover,
#links a:focus {
color: #1b1b1b;
background: #5496ff;
text-shadow: none;
}
</style>
</head>
<body>
<ul id="links">
<li>
Our video collection
</li>
</ul>
</body>
</html>
No image property in CSS. In order to get the desired effect you should replace it with background-image and delete the img tag from your HTML code.
#featured-box-right
{
background-image: url(../images/box-featured-home-right.png);
}
#featured-box-right:hover
{
background-image: url(../images/box-featured-home-right-hover.png);
}
I have a menu button. The main blue outline is meant to sit above the image but right now the blue border is behind the image.
Can you help me figure out what I need to do to get the image behind the blue border?
I cut the blue border into 2 sections, the top & the bottom. The bottom is a tall image, so that the border can grow/be large for tall images.
This is how the buttom is meant to look:
This is how it currently looks:
My Code:
<div class="buttonTop">
<div class="buttonBottom">
<img class="buttomImg" src="images/ButtonImages/sweets2.jpg" width="150px" height="105px" alt=""/>
</div>
</div>
.buttonTop {
background: url(../images/dinnersButton.png) 0 top no-repeat;
padding-top: 73px;
display: block;
width: 153px;
height: 113px;
margin: 0px auto;
}
.buttonBottom {
background: url(../images/buttonBottomLite.png) 0 bottom no-repeat;
padding: 0px 2px 5px 2px;
display: block;
height: 109px;
z-index: 2;
}
.buttomImg {
z-index: 0;
}
<div class="round_border">
<img src="" alt="" />
</div>
--- CSS
.round_border {
padding: 5px;
border: 5px solid blue;
-moz-border-radius: 10px;
-webkit-border-radius: 10px;
-khtml-border-radius: 10px;
border-radius: 10px;
}
That should work in most modern browsers.
The methodology is flawed. You cannot put something inside a div while at the same time expect it to appear behind that div. Your div has a background image and anything you put inside it will cover the background, period.
You need to re-think the whole thing... each of the three items in their own div all within another div used as a container. Then you can put the image div behind (under) the border div.
EDIT:
The following jsFiddle shows how to put three div's in a container, while having the second two cover the first. The two div's are transparent to simulate your transparent border PNG which also allows you to see the div behind. The red div behind is supposed to represent your photo and it's set to position: absolute and bottom: 0.
http://jsfiddle.net/sparky672/a9cX8/