Develop Reference

How to fix split property, to give not undefined

I need to have the right function to test, which is giving me string from a fullName and which I have to split and using for loop change the letters to a char "*". I want to keep the first upperCase visible: here is my code:
var fullName = "Jozko Baci";
function testSamoUloha(fullName) {
var splitString=fullName.split("");
for (var i=1;i<splitString[1].length;i++) {
splitString[1].replace(splitString[1][i],"*");
}
var anonymName =splitString[0]+" "+splitString[1];
console.log(anonymName);
}
testSamoUloha();
I'm really new to it, this problem took me two hours to have at least some solution.
I expect that from the string above will become string saved in variable anonymName as "Jozko B***";

You can use the following regex if you'd like to make your code shorter:
(?<=^.+\s\S+)\w
it will match any letter \w that is preceded (?<= by start of string ^, any number of chars .+, a whitespace \s and one or more non-whitespace characters \S+
const fullName = "Jozko Baci";
const censored = fullName.replace(/(?<=^.+\s\S+)\w/g, '*');
console.log(censored);

Strings are immutable (you can't change them) so this code:
splitString[1].replace(splitString[1][i],"*");
won't work in any situation.
What I suggest is you create a temporary string, then loop over the whole of your second word. If the index of the loop is 0 add the letter to the temporary string, otherwise add a *:
var fullName = "Jozko Baci";
function testSamoUloha(fullName) {
var splitString = fullName.split(' ');
// Create a temporary string
var tempString = '';
// Loop over the whole second word
for (var i = 0; i < splitString[1].length; i++) {
// If the index is greater than zero (not the first letter)
// add a * to the temporary string
if (i > 0) {
tempString += '*';
// otherwise, if the index is 0, add the letter
// to the temporary string instead
} else {
tempString += splitString[1][i];
}
}
// Return your string from your function
return splitString[0] + ' ' + tempString;
}
// Make sure you pass in the fullName as an argument
console.log(testSamoUloha(fullName));

The above code looks fine, just added a fix in this line
splitString[1].replace(splitString[1][i],"*")
Also added fix to var splitString=fullName.split(" ");
replaced
fullName.split(""); // ['J', 'o', 'z', 'k', 'o', ' ', 'B', 'a', 'c', 'i']
with
fullName.split(" "); // ['Jozko', 'Baci']
if you use replace on a string it returns the new string after replace
, its is not rewriting the existing string
for eg:
var a = "hello";
a.replace('o', '*') // returns hell*
a // has hello
but if you do
a = a.replace('o', '*') // returns hell* and rewrites a
a // hell*
similarly after adding this fix the existing code works fine
var fullName = "Jozko Baci";
function testSamoUloha(fullName) {
var splitString=fullName.split(" ");
for (var i=1;i<splitString[1].length;i++) {
splitString[1] = splitString[1].replace(splitString[1][i],"*");
}
var anonymName =splitString[0]+" "+splitString[1];
console.log(anonymName);
}
testSamoUloha(fullName);

Could do it with something like this;
const fullName = "Jozko Baci";
// Break name into words (firstName, lastName)
let res = fullName.split(' ').map((word, wordIndex) =>
// If after firstName
wordIndex > 0
// Hide all but first character in word
? word.split('').map((char, charIndex) => (charIndex > 0 ? '*' : char)).join('')
// Else, show entire word
: word
).join(' '); // Join words back together (firstName, lastName)
console.log(res);
Hope this helps,

Recombine capture groups in single regexp?

I am trying to handle input groups similar to:
'...A.B.' and want to output '.....AB'.
Another example:
'.C..Z..B.' ==> '......CZB'
I have been working with the following:
'...A.B.'.replace(/(\.*)([A-Z]*)/g, "$1")
returns:
"....."
and
'...A.B.'.replace(/(\.*)([A-Z]*)/g, "$2")
returns:
"AB"
but
'...A.B.'.replace(/(\.*)([A-Z]*)/g, "$1$2")
returns
"...A.B."
Is there a way to return
"....AB"
with a single regexp?
I have only been able to accomplish this with:
'...A.B.'.replace(/(\.*)([A-Z]*)/g, "$1") + '...A.B.'.replace(/(\.*)([A-Z]*)/g, "$2")
==> ".....AB"

If the goal is to move all of the . to the beginning and all of the A-Z to the end, then I believe the answer to
with a single regexp?
is "no."
Separately, I don't think there's a simpler, more efficient way than two replace calls — but not the two you've shown. Instead:
var str = "...A..B...C.";
var result = str.replace(/[A-Z]/g, "") + str.replace(/\./g, "");
console.log(result);
(I don't know what you want to do with non-., non-A-Z characters, so I've ignored them.)
If you really want to do it with a single call to replace (e.g., a single pass through the string matters), you can, but I'm fairly sure you'd have to use the function callback and state variables:
var str = "...A..B...C.";
var dots = "";
var nondots = "";
var result = str.replace(/\.|[A-Z]|$/g, function(m) {
if (!m) {
// Matched the end of input; return the
// strings we've been building up
return dots + nondots;
}
// Matched a dot or letter, add to relevant
// string and return nothing
if (m === ".") {
dots += m;
} else {
nondots += m;
}
return "";
});
console.log(result);
That is, of course, incredibly ugly. :-)

Make translation function not translate result again

I have made this very simplified version of a translation tool similar to Google Translate. The idea is to build this simple tool for a minority language in sweden called "jamska". The app is built up with a function that takes the string from a textarea with the ID #svenska and replaces words in the string using RegExp.
I've made an array called arr that's used in a for loop of the function as a dictionary. Each array item looks like this: var arr = [["eldröd", "eillrau"], ["oväder", "over"] ...]. The first word in each array item is in swedish, and the second word is in jamska. If the RegExp finds a matching word in the loop it replaces that word using this code:
function translate() {
var str = $("#svenska").val();
var newStr = "";
for (var i = 0; i < arr.length; i++) {
var replace = arr[i][0];
var replaceWith = arr[i][1];
var re = new RegExp('(^|[^a-z0-9åäö])' + replace + '([^a-z0-9åäö]|$)', 'ig');
str = str.replace(re, "$1" + replaceWith + '$2');
}
$("#jamska").val(str);
}
The translate() is then called in an event handler for when the #svenska textarea gets a keyup, like this: $("#svenska").keyup(function() { translate(); });
The translated string is then assigned as the value of another textarea with the ID #jamska. So far, so good.
I have a problem though: if the translated word in jamska also is a word in swedish, the function translates that word too. This problem is occurring because I'm assigning the variable str to the translated version of the same variable, using: str = str.replace(re, "$1" + replaceWith + '$2');. The function is using the same variable over and over again to perform the translation.
Example:
The swedish word "brydd" is "fel" in jamska. "Fel" is also a word in swedish, so the word that I get after the translation is "felht", since the swedish word "fel" is "felht" in jamska.
Does anyone have any idea for how to work around this problem?

Instead of looking for each Jamska word in the input and replacing them with the respective translation, I would recommend to find any word ([a-z0-9åäö]+) in your text and replace this word either with its translation if one is found in the dictionary or with itself otherwise:
//var arr = [["eldröd", "eillrau"], ["oväder", "over"] ...]
// I'd better use dictionary instead of array to define your dictionary
var dict = {
eldröd: "oväder",
eillrau: "over"
// ...
};
var str = "eldröd test eillrau eillrau oväder over";
var translated = str.replace(/[a-z0-9åäö]+/ig, function(m) {
var word = m.toLowerCase();
var trans = dict[word];
return trans === undefined ? word : trans;
});
console.log(translated);
Update:
If dictionary keys may be represented by phrases (i.e. technically appear as strings with spaces), the regex should be extended to include all these phrases explicitly. So the final regex would look like
(?:phrase 1|phrase 2|etc...)(?![a-z0-9åäö])|[a-z0-9åäö]+
It will try to match one of the phrases explicitly first and only then single words. The (?![a-z0-9åäö]) lookbehind helps to filter out phrases immediately followed by letters (e.g. varken bättre eller sämreåäö).
Phrases immediately preceded by letters are implicitly filtered out by the fact that a match is either the fist one (and therefore is not preceded by any letter) or it's not the first and therefore the previous one is separated from the current by some spaces.
//var arr = [["eldröd", "eillrau"], ["oväder", "over"] ...]
// I'd better use dictionary instead of array to define your dictionary
var dict = {
eldröd: "oväder",
eillrau: "over",
bättre: "better",
"varken bättre eller sämre": "vär å int viller",
"test test": "double test"
// ...
};
var str = "eldröd test eillrau eillrau oväder over test test ";
str += "varken bättre eller sämre ";
str += "don't trans: varken bättre eller sämreåäö";
str += "don't trans again: åäövarken bättre eller sämre";
var phrases = Object.keys(dict)
.filter(function(k) { return /\s/.test(k); })
.sort(function(a, b) { return b.length - a.length; })
.join('|');
var re = new RegExp('(?:' + phrases + ')(?![a-z0-9åäö])|[a-z0-9åäö]+', 'ig');
var translated = str.replace(re, function(m) {
var word = m.toLowerCase();
var trans = dict[word];
return trans === undefined ? word : trans;
});
console.log(translated);

Split sentence by space mixed up my index

I'm facing some problem while trying to send text to some spelling API.
The API return the corrections based on the words index, for example:
sentence:
"hello hoow are youu"
So the API index the words by numbers like that and return the correction based on that index:
0 1 2 3
hello hoow are youu
API Response that tell me which words to correct:
1: how
3: you
On the code I using split command to break the sentence into words array so I will be able to replace the misspelled words by their index.
string.split(" ");
My problem is that the API trim multiple spaces between words into one space, and by doing that the API words index not match my index. (I would like to preserve the spaces on the final output)
Example of the problem, sentence with 4 spaces between words:
Hello howw are youu?
0 1 2 3 4 5 6 7
hello hoow are youu
I thought about looping the words array and determine if the element is word or space and then create something new array like that:
indexed_words[0] = hello
indexed_words[0_1] = space
indexed_words[0_2] = space
indexed_words[0_3] = space
indexed_words[0_4] = space
indexed_words[0_5] = space
indexed_words[0_6] = space
indexed_words[0_7] = space
indexed_words[1] = how
indexed_words[2] = are
indexed_words[3] = you?
That way I could replace the misspelled words easily and than rebuild the sentence back with join command but the problem but the problem that I cannot use non-numeric indexes (its mixed up the order of the array)
Any idea how I can keep the formatting (spaces) but still correct the words?
Thanks

in that case you have very simple solution:L
$(document).ready(function(){
var OriginalSentence="howw are you?"
var ModifiedSentence="";
var splitstring=OriginalSentence.split(' ')
$.each(splitstring,function(i,v){
if(v!="")
{
//pass this word to your api and appedn it to sentance
ModifiedSentence+=APIRETURNVALUE//api return corrected value;
}
else{
ModifiedSentence+=v;
}
});
alert(ModifiedSentence);
});

Please review this one:
For string manipulation like this, I would highly recommend you to use Regex
Use online regex editor for faster try and error like here https://regex101.com/.
here I use /\w+/g to match every words if you want to ignore 1 or two words we can use /\w{2,}/g or something like that.
var str = "Hello howw are youu?";
var re = /\w+/g
var words = str.match(re);
console.log("Returning valus")
words.forEach(function(word, index) {
console.log(index + " -> " + word);
})
Correction
Just realize that you need to keep spacing as it is, please try this one:
I used your approach to change all to space. create array for its modified version then send to your API (I dunno that part). Then get returned data from API, reconvert it back to its original formating string.
var ori = `asdkhaskd asdkjaskdjaksjd askdjaksdjalsd a ksjdhaksjdhasd asdjkhaskdas`;
function replaceMeArr(str, match, replace) {
var s = str,
reg = match || /\s/g,
rep = replace || ` space `;
return s.replace(reg, rep).split(/\s/g);
}
function replaceMeStr(arr, match, replace) {
var a = arr.join(" "),
reg = match || /\sspace\s/g,
rep = replace || " ";
return a.replace(reg, rep);
}
console.log(`ori1: ${ori}`);
//can use it like this
var modified = replaceMeArr(ori);
console.log(`modi: ${modified.join(' ')}`);
//put it back
var original = replaceMeStr(modified);
console.log(`ori2: ${original}`);

Updated
var str = "Hello howw are youu?";
var words = str.split(" ");
// Getting an array without spaces/empty values
// send it to your API call
var requestArray = words.filter(function(word){
if (word) {
return word;
}
});
console.log("\nAPI Response that tell me which words to correct:");
console.log("6: how\n8: you");
var response = {
"1": "how",
"3": "you"
}
//As you have corrected words index, Replace those words in your "requestArray"
for (var key in response) {
requestArray[key] = response[key];
}
//now we have array of non-empty & correct spelled words. we need to put back empty (space's) value back in between this array
var count = 0;
words.forEach(function(word, index){
if (word) {
words[index] = requestArray[count];
count++;
}
})
console.log(words);
Correct me, if i was wrong.
Hope this helps :)

Try this JSFiddle
, Happy coding :)
//
// ReplaceMisspelledWords
//
// Created by Hilal Baig on 21/11/16.
// Copyright © 2016 Baigapps. All rights reserved.
//
var preservedArray = new Array();
var splitArray = new Array();
/*Word Object to preserve my misspeled words indexes*/
function preservedObject(pIndex, nIndex, title) {
this.originalIndex = pIndex;
this.apiIndex = nIndex;
this.title = title;
}
/*Preserving misspeled words indexes in preservedArray*/
function savePreserveIndexes(str) {
splitArray = str.split(" ");
//console.log(splitArray);
var x = 0;
for (var i = 0; i < splitArray.length; i++) {
if (splitArray[i].length > 0) {
var word = new preservedObject(i, x, splitArray[i]);
preservedArray.push(word);
x++;
}
}
};
function replaceMisspelled(resp) {
for (var key in resp) {
for (var i = 0; i < preservedArray.length; i++) {
wObj = preservedArray[i];
if (wObj.apiIndex == key) {
wObj.title = resp[key];
splitArray[wObj.originalIndex] = resp[key];
}
}
}
//console.log(preservedArray);
return correctedSentence = splitArray.join(" ");
}
/*Your input string to be corrected*/
str = "Hello howw are youu";
console.log(str);
savePreserveIndexes(str);
/*API Response in json of corrected words*/
var apiResponse = '{"1":"how","3":"you" }';
resp = JSON.parse(apiResponse);
//console.log(resp);
/*Replace misspelled words by corrected*/
console.log(replaceMisspelled(resp)); //Your solution

How to remove the extra spaces in a string?

What function will turn this contains spaces into this contains spaces using javascript?
I've tried the following, using similar SO questions, but could not get this to work.
var string = " this contains spaces ";
newString = string.replace(/\s+/g,''); // "thiscontainsspaces"
newString = string.replace(/ +/g,''); //"thiscontainsspaces"
Is there a simple pure javascript way to accomplish this?

You're close.
Remember that replace replaces the found text with the second argument. So:
newString = string.replace(/\s+/g,''); // "thiscontainsspaces"
Finds any number of sequential spaces and removes them. Try replacing them with a single space instead!
newString = string.replace(/\s+/g,' ').trim();

string.replace(/\s+/g, ' ').trim()

Try this one, this will replace 2 or 2+ white spaces from string.
const string = " this contains spaces ";
string.replace(/\s{2,}/g, ' ').trim()
Output
this contains spaces

I figured out one way, but am curious if there is a better way...
string.replace(/\s+/g,' ').trim()

I got the same problem and I fixed like this
Text = Text.replace(/ {1,}/g," ");
Text = Text.trim();

I think images always explain it's good, basically what you see that the regex \s meaning in regex is whitespace. the + says it's can be multiply times. /g symbol that it's looks globally (replace by default looks for the first occur without the /g added). and the trim will remove the last and first whitespaces if exists.
Finally, To remove extra whitespaces you will need this code:
newString = string.replace(/\s+/g,' ').trim();

We can use the below approach to remove extra space in a sentence/word.
sentence.split(' ').filter(word => word).join(' ')

Raw Javascript Solution:
var str = ' k g alok deshwal';
function removeMoreThanOneSpace() {
String.prototype.removeSpaceByLength=function(index, length) {
console.log("in remove", this.substr(0, index));
return this.substr(0, index) + this.substr(length);
}
for(let i = 0; i < str.length-1; i++) {
if(str[i] === " " && str[i+1] === " ") {
str = str.removeSpaceByLength(i, i+1);
i = i-1;
}
}
return str;
}
console.log(removeMoreThanOneSpace(str));

var s=" i am a student "
var r='';
console.log(s);
var i,j;
j=0;
for(k=0; s[k]!=undefined; k++);// to calculate the length of a string
for(i=0;i<k;i++){
if(s[i]!==' '){
for(;s[i]!==' ';i++){
r+=s[i];
}
r+=' ';
}
}
console.log(r);

// Here my solution
const trimString = value => {
const allStringElementsToArray = value.split('');
// transform "abcd efgh" to ['a', 'b', 'c', 'd',' ','e', 'f','g','h']
const allElementsSanitized = allStringElementsToArray.map(e => e.trim());
// Remove all blank spaces from array
const finalValue = allElementsSanitized.join('');
// Transform the sanitized array ['a','b','c','d','e','f','g','h'] to 'abcdefgh'
return finalValue;
}

I have tried regex to solve this problem :
let temp=text.replace(/\s{2,}/g, ' ').trim()
console.log(temp);
input="Plese complete your work on Time"
output="Please complete your work on Time"

//This code remove extra spaces with out using "string objectives"
s=" This Is Working On Functions "
console.log(s)
final="";
res='';
function result(s) {
for(var i=0;i<s.length;i++)
{
if(!(final==""&&s[i]==" ")&&!(s[i]===" "&& s[i+1] ===" ")){
final+=s[i];
}
}
console.log(final);
}
result(s);