I have an array of arbitrary values. I Wrote a function that transforms the array to an array of functions that return the original values, so instead of calling a[3], I will call a3.
Here is my code which does not work? code. It gives this error Cannot call method '1' of undefined.
var numToFun = [1, 2, { foo: "bar" }];
var numToFunLength = numToFun.length;
function transform(numTo) {
for (var i = 0; i < numToFunLength; i++) {
(function(num){
numTo.unshift(function() {
return num;
});
}(numTo.pop()))
}
}
var b = transform(numToFun);
console.log(numToFun);
console.log(b[1]());
Others have already answered your question while I was writing mine but I will post it anyway - this may be somewhat easier to follow without all of those popping and unshifting:
function transform(numTo) {
var r = [];
for (var i = 0; i < numTo.length; i++) {
r[i] = (function (v) {
return function() {
return v;
}
}(numTo[i]));
}
return r;
}
(I have also changed the hard-coded length from numToFunLength to numTo.length so the transform() function would work for other inputs than only the global numToFun variable.)
See DEMO.
UPDATE: even more elegant way to do it using the Sugar library:
function transform(array) {
return array.map(function (v) {
return function() {
return v;
}
});
}
I like this syntax because it makes it more explicit that you want to map an array of values to an array of functions that return those values.
See DEMO.
Your function transform does not return anything. That is why b is undefined.
return numTo;
jsFiddle Demo
On the other hand, the array will be passed to the function as a reference anyways, so the original array will be changed. It is not a problem if you don't return anything, just omit the var b = transform(numToFun); line and simply write transform(numToFun).
Your transform function isn't returning anything. So b is undefined
Related
Why is m "undefined" in this code:
currentViewModel = ko.mapping.fromJS(viewModel);
currentViewModel.getReport = function(reportId) {
for(var i=0;i<currentViewModel.availableReports().length;i++) {
if(currentViewModel.availableReports()[i].id == reportId) {
var m = currentViewModel.availableReports()[i];
return currentViewModel.availableReports()[i];
}
}
}
I call getReport() as an onclick event and I want to send the report object to a view (modal) I can do a foreach on the availableReports and it's all there. When I run through the debugger, it loops through the array and finds the right one. But why can't I pull it out of the array? "m" remains undefined the the function returns undefined.
What am I missing here?
EDIT: there is a follow up question here:
Can knockout.js wait to bind until an onClick?
You just need to change if(currentViewModel.availableReports()[i].id ... to if(currentViewModel.availableReports()[i].id() ... because after mapping id will become an observable, i.e. function.
Updated code:
currentViewModel = ko.mapping.fromJS(viewModel);
currentViewModel.getReport = function(reportId) {
for (var i = 0; i < currentViewModel.availableReports().length; i++) {
if (currentViewModel.availableReports()[i].id() == reportId) {
var m = currentViewModel.availableReports()[i];
return currentViewModel.availableReports()[i];
}
}
}
Demo - Fiddle.
I'll repeat the solution from #NikolayErmakov's answer here, but want to add two things to get a more complete answer. You end with:
...m remains undefined and the function returns undefined.
What am I missing here?
You're missing two things:
The var m bit of the first statement inside the if is hoisted to the top of the current scope (the top of the function). This is why the debugger can tell you what m is, even if you never reach the line of code it's on.
If a function invocation reaches the end of a function (as is the case for you, since you never go inside the if) without seeing an explicit return statement, it will return undefined.
To better understand this, you should interpret your function like this:
currentViewModel.getReport = function(reportId) {
var m;
for (var i = 0; i < currentViewModel.availableReports().length; i++) {
if (currentViewModel.availableReports()[i].id == reportId) {
m = currentViewModel.availableReports()[i];
return currentViewModel.availableReports()[i];
}
}
return undefined;
}
Some people (e.g. Douglas Crockford) do recommend placing var statements at the top of a function, though it's a matter of style to some degree. I don't think many people explicitly return undefined at the end of a function, though in your case I might be explicit about that scenario and return null (or throw an Error even).
As promised, I'll repeat the actual solution, as I concur with the other answer:
you need to invoke id as a function to get its value (because the mapping plugin will map to observable()s.
In addition:
I'd retrieve the array only once
I'd suggest using === instead of ==
Here's my v0.5 version:
currentViewModel.getReport = function(reportId) {
var m = null, reports = currentViewModel.availableReports();
for (var i = 0; i < reports.length; i++) {
if (reports[i].id() === reportId) {
m = reports[i];
return m;
}
}
return m;
}
But I'd optimize it to this v1.0:
currentViewModel.getReport = function(reportId) {
var reports = currentViewModel.availableReports();
for (var i = 0; i < reports.length; i++) {
if (reports[i].id() === reportId) {
return reports[i];
}
}
return null;
}
For completeness, here's another version that utilizes filter on arrays:
currentViewModel.getReport = function(reportId) {
var reports = currentViewModel.availableReports().filter(function(r) { return r.id() === reportId; });
return reports.length >= 1 ? reports[0] : null;
}
Just for fun, I'm looking for a way to create a function, array, with the following behavior:
array() // []
array(2) // ugly function thing
array(2)() // [2]
array(2)(3)() // [2,3] etc
The closest I can come is
function array(x) {
if (x == null)
return []
return function() {
// same as above?!
// I don't want some inelegant solution involving a lot of additional parameters
}
}
Is there a way to do this in ECMA5? If not, prove that the syntax can't accomodate such a function.
Yes, "same as above". This is solved by a "recursive"1 call:
function makeArrayAppender(arr) {
return function array() {
var args = Array.prototype.slice.call(arguments);
if (!args.length)
return arr;
else
return makeArrayAppender(arr.concat(args));
};
}
var array = makeArrayAppender([]);
1: As the function is called from the returned "thunk" function, not from the call itself, it's not really recursive. It's more like a tail-call-optimised function, being invoked manually in-a-row without filling the stack
I think this should do exactly what you are looking for. The self-executing function scopes off r and rr, which are basically static variables using this implementation. Of course, you need to reset r after assigning it to rr, so you can return the Array when ra has an undefined argument, which then stops the recursive behavior.
var array = (function(){
var r = [], rr;
function ra(a){
if(a === undefined){
rr = r; r = []
return rr;
}
else{
r.push(a);
return ra;
}
}
return ra;
})();
console.log(array()); console.log(array(5)()); console.log(array());
console.log(array(7)(2)());
This question already has answers here:
How do JavaScript closures work?
(86 answers)
Closed 8 years ago.
I'm learning JS and I need help with the following task:
I need to create a function compile_csv_search(text, key_name) that parses text in
the CSV format. (not required to handle quoting and escaping in values;
assume field values never contain commas or other special characters.)
A function must return a function that looks up a record by a value of the
field specified as the second argument to compile_csv_search. Assume that all
values in the key field are unique.
Sample usage:
var csv_by_name = compile_csv_search(
"ip,name,desc\n"+
"1.94.0.2,server1,Main Server\n"+
"1.53.8.1,server2,Backup Server\n",
"name");
console.log(csv_by_name("server2"));
console.log(csv_by_name("server9"));
...will print:
{ip: "10.52.5.1", name: "server2", desc: "Backup Server"}
undefined
** I didn't understand what does it mean "function that return function". How can function return another function?
Thank you!
P.S.
attaching my solution for your review
function compile_csv_search(csvServerData){
var header = csvServerData.split('\n')[0].split(",");
var spleatedServerData = csvServerData.split('\n');
return function(serverName)
{
for(var i = 1; i < spleatedServerData.length; i++){
var singleServer = spleatedServerData[i].split(',')
var result = {};
var exist = false;
for (var j = 0; j < header.length; j++) {
if(singleServer.indexOf(serverName) == -1)
break;
exist = true;
result[header[j]] = singleServer[j];
}
if(exist){
return(result);
break;
}
}
}
}
var csv_by_name = compile_csv_search(
"ip,name,desc\n"+
"10.49.1.4,server1,Main Server\n"+
"10.52.5.1,server2,Backup Server\n");
Functions in JavaScript are objects; they can be referred to by variables, passed as arguments and returned from functions like any other object.
Here's a function that returns an object:
function returnObject() {
var result = { a: 1, b: 2, c: 3 };
return result;
}
And here's a function that returns another function:
function returnFunction() {
var result = function() {
console.log('another function!');
}
return result;
}
Notice how they're really similar - object returned by the first function is a plain Object created using object literal syntax ({}), and the object returned by the second happens to be a function.
You could call the inner, returned function like this:
var out = returnFunction();
out();
Or even returnFunction()();
However, you can't just call result() - result is only defined inside of returnFunction. The only way to access it from outside is to retrieve it by calling the outer function.
Something like this would be fine:
function compile_csv_search(text, key_name) {
var lines = text.split('\n');
var keys = lines[0].split(',');
var key_index = keys.indexOf(key_name);
return function(value) {
for(var i = 1; i<lines.length; i++) {
current_line_values = lines[i].split(',');
if(current_line_values[key_index] === value) {
var result = {};
for(var j = 0; j<keys.length; j++) {
result[keys[j]] = current_line_values[j];
}
return result;
}
}
}
}
Also see this fiddle: http://jsfiddle.net/efha0drq/
You can always treat a function the same as any other js objects. Assign to a variable, pass to a function, store in an array... all are fine.
The magic in this example is that, you can read/write the variables defined in the compile_csv_search() function within the returned function. So it's possible to store something in the local variables of the defining function, and later retrieve from the returned one, even when the defining function has finished execution long time ago. You may have heard of "closure", right?
This question already has an answer here:
Double-Queue Code needs to be reduced
(1 answer)
Closed 9 years ago.
Is there any way for me to shorten this code by using pointers?
I need to make a class that has mostly the same function as a given array class unshift,shift,push and pop but with different names.
var makeDeque = function()
{
var a= [], r=new Array(a);
length = r.length=0;
pushHead=function(v)
{
r.unshift(v);
}
popHead=function()
{
return r.shift();
}
pushTail=function(v)
{
r.push(v);
}
popTail=function()
{
return r.pop();
}
isEmpty=function()
{
return r.length===0;
}
return this;
};
(function() {
var dq = makeDeque();
dq.pushTail(4);
dq.pushHead(3);
dq.pushHead(2);
dq.pushHead("one");
dq.pushTail("five");
print("length " + dq.length + "last item: " + dq.popTail());
while (!dq.isEmpty())
print(dq.popHead());
})();
Output should be
length 5last item: five
one
2
3
4
Thanks!
Maybe I'm oversimplifying, but why not just add the extra methods you need to the Array prototype and call it directly?
I need to make a class that has mostly the same function as a given array class unshift,shift,push and pop but with different names.
I suppose you could add these "new" methods to Array.prototype.
Like this perhaps?
var makeDeque = (function (ap) {
var Deque = {
length: 0,
pushHead: ap.unshift,
popHead: ap.shift,
pushTail: ap.push,
popTail: ap.pop,
isEmpty: function () {
return !this.length;
}
};
return function () {
return Object.create(Deque);
};
})(Array.prototype);
DEMO
If it's still too long, you can always directly augment Array.prototype like others already mentionned. We agree that it's all experimental here and the only goal is to save characters.
!function (ap) {
ap.pushHead = ap.unshift;
ap.popHead = ap.shift;
ap.pushTail = ap.push;
ap.popTail = ap.pop;
ap.isEmpty = function () {
return !this.length;
};
}(Array.prototype);
function makeDeque() {
return [];
}
This can be compressed to 174 chars:
function makeDeque(){return[]}!function(e){e.pushHead=e.unshift;e.popHead=e.shift;e.pushTail=e.push;e.popTail=e.pop;e.isEmpty=function(){return!this.length}}(Array.prototype)
DEMO
Not sure why you need this, but my suggestions per best practice are:
Don't override the Array.prototype. The reason for this is because other libraries might try to do the same, and if you include these libraries into yours, there will be conflicts.
This code is not needed. var a= [], r=new Array(a);. You only need ...a = [];.
Ensure you are creating a real class. In your code, makeDeque is not doing what you want. It is returning this which when a function is not called with the new keyword will be the same as the window object (or undefined if you are using what is called as "strict mode"). In other words, you have made a lot of globals (which are usually a no-no, as they can conflict with other code too).
When you build a class, it is good to add to the prototype of your custom class. This is because the methods will only be built into memory one time and will be shared by all such objects.
So I would first refactor into something like this:
var makeDeque = (function() { // We don't need this wrapper in this case, as we don't have static properties, but I've kept it here since we do want to encapsulate variables in my example below this one (and sometimes you do need static properties).
function makeDeque () {
if (!(this instanceof makeDeque)) { // This block allows you to call makeDeque without using the "new" keyword (we will do it for the person using makeDeque)
return new makeDeque();
}
this.r = [];
this.length = 0;
}
makeDeque.prototype.setLength = function () {
return this.length = this.r.length;
};
makeDeque.prototype.pushHead=function(v) {
this.r.unshift(v);
this.setLength();
};
makeDeque.prototype.popHead=function() {
return this.r.shift();
this.setLength();
};
makeDeque.prototype.pushTail=function(v){
this.r.push(v);
this.setLength();
};
makeDeque.prototype.popTail=function() {
return this.r.pop();
this.setLength();
};
makeDeque.prototype.isEmpty=function() {
return this.r.length === 0;
};
return makeDeque;
}());
Now you could shorten this as follows, but I wouldn't recommend doing this, since, as it was well said by Donald Knuth, "premature optimization is the root of all evil". If you try to shorten your code, it may make it inflexible.
var makeDeque = (function() {
function makeDeque () {
if (!(this instanceof makeDeque)) {
return new makeDeque();
}
this.r = [];
this.length = 0;
}
makeDeque.prototype.setLength = function () {
return this.length = this.r.length;
};
for (var i=0, methodArray = [
['pushHead', 'unshift'], ['popHead', 'shift'], ['pushTail', 'push'], ['popTail', 'pop']
]; i < methodArray.length; i++) {
makeDeque.prototype[methodArray[i][0]] = (function (i) { // We need to make a function and immediately pass in 'i' here because otherwise, the 'i' inside this function will end up being set to the value of 'i' after it ends this loop as opposed to the 'i' which varies with each loop. This is a common "gotcha" of JavaScript
return function () {
var ret = this.r[methodArray[i][1]].apply(this.r, arguments);
this.setLength();
return ret;
};
}(i));
}
makeDeque.prototype.isEmpty=function() {
return this.r.length === 0;
};
return makeDeque;
}());
If you need to get the length by a length property, as opposed to a method like setLength() which sets it manually after each update, either of the above code samples could be shortened by avoiding the setLength() method, but you'd need to use the Object.defineProperty which does not work (or does not work fully) in older browsers like IE < 9.
I'm trying to extend the Array.push method so that using push will trigger a callback method and then perform the normal array function.
I'm not quite sure how to do this, but here's some code I've been playing with unsuccessfully.
arr = [];
arr.push = function(data){
//callback method goes here
this = Array.push(data);
return this.length;
}
arr.push('test');
Since push allows more than one element to be pushed, I use the arguments variable below to let the real push method have all arguments.
This solution only affects the arr variable:
arr.push = function () {
//Do what you want here...
return Array.prototype.push.apply(this, arguments);
}
This solution affects all arrays. I do not recommend that you do that.
Array.prototype.push = (function() {
var original = Array.prototype.push;
return function() {
//Do what you want here.
return original.apply(this, arguments);
};
})();
First you need subclass Array:
ES6 (https://kangax.github.io/compat-table/es6/):
class SortedArray extends Array {
constructor(...args) {
super(...args);
}
push() {
return super.push(arguments);
}
}
ES5 (proto is almost deprecated, but it is the only solution for now):
function SortedArray() {
var arr = [];
arr.push.apply(arr, arguments);
arr.__proto__ = SortedArray.prototype;
return arr;
}
SortedArray.prototype = Object.create(Array.prototype);
SortedArray.prototype.push = function() {
this.arr.push(arguments);
};
Array.prototype.push was introduced in JavaScript 1.2. It is really as simple as this:
Array.prototype.push = function() {
for( var i = 0, l = arguments.length; i < l; i++ ) this[this.length] = arguments[i];
return this.length;
};
You could always add something in the front of that.
You could do it this way:
arr = []
arr.push = function(data) {
alert(data); //callback
return Array.prototype.push.call(this, data);
}
If you're in a situation without call, you could also go for this solution:
arr.push = function(data) {
alert(data); //callback
//While unlikely, someone may be using "psh" to store something important
//So we save it.
var saved = this.psh;
this.psh = Array.prototype.push;
var ret = this.psh(data);
this.psh = saved;
return ret;
}
While I'm telling you how to do it, you might be better served with using a different method that performs the callback and then just calls push on the array rather than overriding push. You may end up with some unexpected side effects. For instance, push appears to be varadic (takes a variable number of arguments, like printf), and using the above would break that.
You'd need to do mess with _Arguments() and _ArgumentsLength() to properly override this function. I highly suggest against this route.
Or you could use "arguments", and that'd work too. I still advise against taking this route though.
There's another, more native method to achieve this: Proxy
const target = [];
const handler = {
set: function(array, index, value) {
// Call callback function here
// The default behavior to store the value
array[index] = value;
// Indicate success
return true;
}
};
const proxyArray = new Proxy(target, handler);
I wanted to call a function after the object has been pushed to the array, so I did the following:
myArray.push = function() {
Array.prototype.push.apply(this, arguments);
myFunction();
return myArray.length;
};
function myFunction() {
for (var i = 0; i < myArray.length; i++) {
//doSomething;
}
}