I have a string of url encoded characters.
wondering if there is a javascript function that can replace all the url encoded characters with normal string characters.
i know i can use the replace function, but it only replaces one certain character an not all at once
for example, I am looking for one function that will replace all the url encoded characters in this string:
string urlEncoded = '1%20day%20%40work!%20Where%20are%20you%3F'
and give me this string:
string replaced = '1 day # work! Where are you?'
thanks a lot
Use decodeURIComponent(string) for that purpose.
string urlEncoded = '1%20day%20%40work!%20Where%20are%20you%3F';
string replaced = decodeURIComponent(urlEncoded);
alert(replaced);
More info here: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/decodeURIComponent
string replaced = decodeURIComponent(urlEncoded);
There is also just decodeURI but this does not cope with "special" characters, such as & ? ! # etc
Use decodeURIComponent(urlEncoded)
You are looking for unescape
var decoded = unescape(urlEncoded);
Related
If a string contains character from interval U+D800..U+DFFF then encodeURIComponent() throws a malformed URI sequence error. I would like to eliminate those characters from a given string before passing it to encodeURIComponent(). How to do that?
Example:
I have a textfile encoded in UTF-16BE which contains the following hexa chars:
D7FF D800 D801 ... DFFE DFFF E000
I'm searching for a function which returns this string from the string above:
D7FF E000
So only valid Unicode characters remain.
You can use a replace/encodeURIComponent combo to achieve the desired result. You first need to match all the characters that do not fall in the unicode range [0xD800..0xDFFF] using this regex: /[^\uD800-\uDFFF]+/g then replace them with their encoded versions:
let result = string.replace(/[^\uD800-\uDFFF]+/g, match => encodeURIComponent(match));
Example:
let string = "/foo/\uD7FF\uD800\uD801/bar";
let result = string.replace(/[^\uD800-\uDFFF]+/g, match => encodeURIComponent(match));
console.log(result);
I'm trying to fix a string which has some encoding characters in it.
I thought I should be able to match the hex characters of the special characters and convert them back to a normal character.
Here is my example code:
let str = "url('https\3a //');";
str = str.replace(/\x5C\x33\x61\x20/g,":"); // equivalent to '\3a '
console.log(str);
I expected the output to be url('https://'); but I actually got url('https a //');
What am I missing? jsfiddle here. Is this some sort of multi byte character issue? I looked at the resulting string in a hex editor and the replaced characters seem to be \x03\x61\x20 rather than the expected \x3A.
EDIT: why has this been down voted? It is a fair question isn't it?
Is the code that you use really needs to be in this form?
I got the desired result using "3a".
str = "url('https\3a //');";
str = str.replace(/\3a /g,":"); // equivalent to '\3a '
console.log(str);
//result: url('https://');
I need a certain type of regular expression where I need list of special type of strings from a string. Example input:
str = 'this is extra data which i do not need /type/123456/weqweqweqweqw/ these are more extra data which i dont need /'
Result needed:
/type/123456/weqweqweqweqw/
Here the /type/ string will be constant and the remaining will be dynamic i.e. 123456/weqweqweqweqw and the last string will be /.
I tried:
var myRe = /\/type\/(.*)\//g
But this matches everything from /type/ to the end of the string.
Instead of repeating ., which will match anything, repeat anything but a space via \S+, so that only the URL part of the string will be matched:
const str = 'this is extra data which i do not need /type/123456/weqweqweqweqw/ these are more extra data which i dont need /';
console.log(str.match(/\/type\S+/));
It's tagged Python, so here is a solution:
import re
re.search(r"/type/[^/]*/[^/]*/",str)
Out: <_sre.SRE_Match object; span=(39, 66), match='/type/123456/weqweqweqweqw/'>
i have this text:
this is a sample
text
Apparently, after "sample" there is a Line feed character (ENTER). How can i encode JUST those characters and not the whole string. When i use encodeURI the whole string gets encoded
What i want to do is to get a string like "this is a sample%0Atext"
Thanks
So double url encoding - where the API requires raw input of %250A for a \n ?
str = str.replace(/[\r\n]/g, function(m) { return escape(m); });
I'm trying to do something which seems fairly basic, but can't seem to get it working.
I'm trying to strip the characters after the last instance of an underscore.
I have this long Query String:
json_data=demo_title=Demo+title&proc1_script=script.sh+parameters&proc1_chk_make=on&outputp2_value=&demo_input_description=hola+mundo&outputp4_visible=on&outputp4_info=&inputdata1_max_pixels=1024000&tag=&outputp1_id=nanana&proc1_src_compresion=zip&proc1_chk_cmake=off&outputp3_description=&outputp3_value=&inputdata1_description=input+data+description&inputp2_description=bien%3F&inputp3_description=funciona&proc1_cmake=-D+CMAKE_BUILD_TYPE%3Astring%3DRelease+&outputp2_visible=on&outputp3_visible=on&outputp1_type=header&inputp1_type=text&demo_params_description=va+bien&outputp1_description=&inputdata1_type=image2d&proc1_chk_script=off&demo_result_description=win%3F&outputp2_id=nanfdsvfa&inputp1_description=funciona&demo_wait_description=boh&outputp4_description=&inputp2_type=integer&inputp2_id=papapa&outputp1_value=&outputp3_id=nananartrtrt&inputp3_id=pepepe&outputp3_type=header&inputp3_visible=+off&outputp1_visible=on&inputdata1_id=id_lsd&outputp4_value=&inputp2_visible=on&proc1_source=lsd-1.5.zip&inputp3_value=si&proc1_make=-j4+-C+&images_config_file=cfgmydemo.cfg&outputp2_type=header&proc1_subdir=xxx-1.5&proc1_url=http%3A%2F%2Fwww.ipol.im%2Fpub%2Falgo%2F...&inputdata1_image_depth=1x8i&inputp1_id=popopo&inputp1_value=si&inputp2_value=no&demo_data_filename=data_saved.cfg&inputdata1_info=info_lsd&outputp3_info=&inputdata1_image_format=.pgm&outputp1_info=&inputdata1_compress=False&inputp1_visible=on&proc1_id=lsd&outputp4_id=nana&outputp2_description=&outputp4_type=header&outputp2_info=&inputp3_type=float&&tag&inputp4_iddcksmdclk&inputp4_typetext&inputp4_descriptionkldmsclk&inputp4_valueklcdmkl&inputp4_infoclkdmscdl
Now I replace the separator = in separator %24+ and & in +%23+ using fr=fr.replace(/\&/g,"+%23+");
Separator
javascript Mako
= %24+
& +%23+
But the result is:
json_data%24+demo_title%24+Demo+title+%23+proc1_script%24+script.sh+parameters+%23+proc1_chk_make%24+on+%23+outputp2_value%24++%23+demo_input_description%24+hola+mundo+%23+outputp4_visible%24+on+%23+outputp4_info%24++%23+inputdata1_max_pixels%24+1024000+%23+tag%24++%23+outputp1_id%24+nanana+%23+proc1_src_compresion%24+zip+%23+proc1_chk_cmake%24+off+%23+outputp3_description%24++%23+outputp3_value%24++%23+inputdata1_description%24+input+data+description+%23+inputp2_description%24+bien%3F+%23+inputp3_description%24+funciona+%23+proc1_cmake%24+-D+CMAKE_BUILD_TYPE%3Astring%3DRelease++%23+outputp2_visible%24+on+%23+outputp3_visible%24+on+%23+outputp1_type%24+header+%23+inputp1_type%24+text+%23+demo_params_description%24+va+bien+%23+outputp1_description%24++%23+inputdata1_type%24+image2d+%23+proc1_chk_script%24+off+%23+demo_result_description%24+win%3F+%23+outputp2_id%24+nanfdsvfa+%23+inputp1_description%24+funciona+%23+demo_wait_description%24+boh+%23+outputp4_description%24++%23+inputp2_type%24+integer+%23+inputp2_id%24+papapa+%23+outputp1_value%24++%23+outputp3_id%24+nananartrtrt+%23+inputp3_id%24+pepepe+%23+outputp3_type%24+header+%23+inputp3_visible%24++off+%23+outputp1_visible%24+on+%23+inputdata1_id%24+id_lsd+%23+outputp4_value%24++%23+inputp2_visible%24+on+%23+proc1_source%24+lsd-1.5.zip+%23+inputp3_value%24+si+%23+proc1_make%24+-j4+-C++%23+images_config_file%24+cfgmydemo.cfg+%23+outputp2_type%24+header+%23+proc1_subdir%24+xxx-1.5+%23+proc1_url%24+http%3A%2F%2Fwww.ipol.im%2Fpub%2Falgo%2F...+%23+inputdata1_image_depth%24+1x8i+%23+inputp1_id%24+popopo+%23+inputp1_value%24+si+%23+inputp2_value%24+no+%23+demo_data_filename%24+data_saved.cfg+%23+inputdata1_info%24+info_lsd+%23+outputp3_info%24++%23+inputdata1_image_format%24+.pgm+%23+outputp1_info%24++%23+inputdata1_compress%24+False+%23+inputp1_visible%24+on+%23+proc1_id%24+lsd+%23+outputp4_id%24+nana+%23+outputp2_description%24++%23+outputp4_type%24+header+%23+outputp2_info%24++%23+inputp3_type%24+float+%23++%23+tag+%23+inputp4_iddcksmdclk+%23+inputp4_typetext+%23+inputp4_descriptionkldmsclk+%23+inputp4_valueklcdmkl+%23+inputp4_infoclkdmscdl
Now I am interested how to replace this = after the value jsondata.
Explain:
In the Query string there is the string json_data+%23+ and this +%23+ I want replace to =
How?
Strip the characters after the last instance of an underscore:
json_data.substring(0, json_data.lastIndexOf("_"));
Replace +%23+ with =
json_data.replace("+%23+", "=");
However, if you're trying to turn all the %xx into what they're supposed to be, you should url decode the string instead.
Which would probably have to be something like:
decodeURIComponent((json_data).replace('+', '%20'));