Develop Reference

Removing just position attribute in jQuery

I set up a code that have this traits:
the navigation Items-texts- are hidden behind the some Divs I'll call them Navigation Divs
when the mouse move over the some of pixels-navigation Divs-, the text that they are behind this, slide right and left and in some cases, some of them move top and bottom about 15 px with animate() method...
when the mouse move to another Div, other text will be reset to first position
for next action and I did this with:
$(document).on('mouseover', '.pixel#p18', function(){
$('.submenus').not("this Div's TEXT").fadeOut('fast').removeAttr('style');
});/* this Div's Text is for Example*/
and I wrote this kind for all of my navigation texts..
Now my problem is:
When I hover mouse on one of navigation Divs, some of the texts that they did not animated, become to visible because of removeAttr('style')!!! But I don't want that...
is there any alternative way that I can slide the texts or other elements to left, right, top and down with optional values of move...??? for example 23px to left or 17px to top... etc???- I'm familiyar with slideUp and Down and toggle but not sure that they are good enough for my code...
Do you have some better Idea for this---that actualy you'll have because I think this is very bad
and the last Question is that why my codes are very slow in running? the animations that I wrote have lak some times and I'm not Sure that the problem is my selector or other stuff.

For this you need something like .animate which has a callback. So something like:
$('.submenus').not("this Div's TEXT").animate({opacity:0},500,'linear', function() {
$(this).removeAttr('style');
});
This will only remove the attribute when the animation is complete.

CSS3 transitions animation

I'm very new to CSS/HTML/JS so I don't have lots of experience with CSS transitions.
I'm trying to animate a div elements on my page, but I can't achieve a desired result so far.
Here is my problem:
In my HTML I have a div container element that has 5 div elements inside of it. They look like simple boxes positioned in the middle of the screen and aren't visible for now. I also have 5 buttons in the corner of the screen.
What I'm trying to do is:
when I click a button (for example button 3) 3 of the divs on the left should disappear and be moved to the left behind the margin of the screen and 2 of the divs should do the same, but move to the right. After that I want 3 divs that are on the right slide back to the screen and 2 divs on the right should slide back as well. So it looks like they sliding towards each other to the positions they started from initially.
I'm trying to do this effect using CSS transitions (transform: translateX(Npx);). So in my JS file I have something like this:
$(document).ready(function() {
$(".button").click(function(){
// PART 1
// move 3 divs to the left using transform: translateX(Npx) (no animation)
// move 2 divs to the left using transform: translateX(Npx) (no animation)
// PART 2
// slide 3 divs to the left using transform: translateX(Npx) (with animation)
// slide 2 divs to the left using transform: translateX(Npx) (with animation)
});
So the problem is that in this case only the part one works and part two seems to be not working.....if I attach the part on code to a different event...like another click button...it works just fine.
So my question is if these two transitions can be done under one event?!?!

I have done this, and this kind of effect can look great. If I understand your question correctly, your issue is that you run the animation AFTER you moved the divs, so your animation function uses the wrong starting point.
What you need is:
Be sure you have a CSS position:relative; set on your divs so the animation can work.
Run your animation function moving your divs relative to their current position (i.e. top, left), and include a success callback. You may need to first use offset() and some math to figure out the distance traveled.
On the completion of your animation (success callback), change the relative position of your divs back to 0px (or whatever they were before) and simultaneously perform the function where you actually move the divs to their new position in the DOM using insertBefore(). I've never seen a flicker since these functions are near-instant, but if you see an issue you can set visibility to hidden while you reset the position and move the divs, and then reset the visibility afterward
You can even set custom z-indexes for your divs during the animation that you reset on the success callback, allowing you to determine which elements the divs pass over/under or specifying which is on top if they cross each other.

HTML/CSS/JAVASCRIPT : How to move an element and not show scrollbars

i'm trying to slide a div element from outside the page to within the page. However as soon as the element is shown outside the page, horizontal scrollbars appear!
How can I achieve this without the scrollbars appearing?
Any help appreciated very muchly, thanks :)

Briefly, using overflow-x:
function moveStuff() {
$('body').css('overflow-x', 'hidden');
$('#iteminmotion').show().animate(..., function() {
$('body').css('overflow-x', 'auto');
});
}

move the element off the page to the left, moving it off to the right increases the width of the page

You could temporarily turn off side scrolling by applying this css to the body:
body {overflow-x:hidden;}
http://jsfiddle.net/pxfunc/YYUZJ/

Do you really need to construct the element off page, or just make it look like it slides onto the screen? Ive done similar things in the past to emulate a graphic that slides across a page, but instead of starting outside the view area I've created it as far to the side as possible and then animated the slide to the middle. The user experience at that point can be a graphic that slides onto a page from outside the view area.

animating div elements left to right and back

I have a menu system made up of divs and i want to animate the left property to slide each time the user mouses over a menu item but i need the outer div(which is black) element to expand as the menu items move left to right also I want the div element(.container) to slide back and contract the outer div element(this black div which is 0 width) I have a basic example done in jsFiddle it olny moves the elements to the left

Having a little trouble fully understanding, but is this sort of what you mean?
http://jsfiddle.net/V3RHr/2/

If I could rewrite your html a bit, I would put make each .menu-item into an unordered list.
When you mouseenter the unordered list, you expand the second container. Inside that mouseenter function, I would have a second event when you mouseenter a list item, you populate the second container and stopPropogation.
You could probably still do it with a mouseenter on the first container, and another mouseenter on the div.menu-item, but your first container has extra height and width.

You should be able to fix the left is null issue by having the code not execute on the last .content, like this:
$('.container').not(':last').find('.menu-item').mouseenter(function () {
This will not apply to the menu-items within the green box.
For the re-show issue, I would change the way you are showing. Instead of sliding the box out from behind the other, you can position it where you want it to end up and hide it, then you can use:
.animate({width: 'show'})
Which will give a similar sliding effect.
That, or do it similar to my response to your other question, only without the collapsing I had previously:
http://jsfiddle.net/V3RHr/3/

How can I make a DIV slide in and out?

I am currently learning jQuery. I'd like to know how to make an image slide in when you click on its edge, then click again and it slides away. Similar to this:
http://www.karenmillen.com/
If you see the right hand side and click, there is the effect that i'm looking for. I assume this will involve making a div and giving it a background image then using some jquery to make the div slide into view. Of course the div could have other content such as html. Any ideas?
Would the .slideDown() method work?

if you want a div to slideDown() first it has to hidden.
so use $("#div_Id").hide();
after that use $("#div_Id").slideDown('slow');
this will work

Check out slideToggle

Here's what i have so far:
$(document).ready(function() {
$('.inner').hide();
$("button").click(function() {
$("#static_image").hide();
$('.inner').slideToggle(300);
});
});
So basically the animated div begins hidden. There's another div with a background image that is lined up to look as if the animated div is still sticking out a bit. Then clicking a button makes the static div dissapear and the animated div slide into view. However i'm not sure how to make the timing perfect so it's smooth and people won't know there are two divs. The animated div takes a fraction of a second to move up to where the div with the static image was, however the static images disappears immediately leaving a non-smooth animation.
One other thing, how do i get the static image div to return at the moment that the animated div moves back down after a user click? It can't be at the exact moment the user clicks 'retract' button else it'd definitely appear before it's supposed to.

In order to use the animate() function add a CSS class to the <div> tag that has a height attribute, it can either be in pixels or %, this will be the initial height. After that then you can use the animate().
$('#mydiv').animate({
height: 500px
}, 5000, function() {
// Animation complete.
});
This will slide the div to 500px, which will take 5 seconds.