What javascript command is this? - javascript

I remember a command that checks that a given condition is true, otherwise it stops the script. It was one word, starting with a, i think starting with att.. and it was just that word, the condition in parentheses, and the semicolon. I've googled everything I can think of and cannot find it!

if(!condition) return; //for a single assertion statement
Furthermore, you might mean "assert." Google it with javascript for a couple of reads on the subject.

You are looking for a function with the semantics of assert(condition), i.e., throw an exception if condition is false. javascript does not contain a native assert like function, but you could certainly implement it yourself. A bit of searching will yield some good results.
function assert(condition) {
condition || throw "assert failed"
}
You can spruce it up a bit as needed, but that's the basic idea.

I don't know if there's something built in natively to JavaScript but have you tried looking at this?
http://aymanh.com/9-javascript-tips-you-may-not-know#assertion

Related

Why does this error- and warning-free statement not complete?

I'm making a simple JavaScript for opening a dialog with a hypothetical recruiter. When I run the script it does not complete, but neither throws any errors or warnings. At least (!) it doesn't seem like it completes, but it might be me not thinking straight about how to use Firebug.
Here's the code:
var str = prompt("How are you today?", "I'm quite alright, thank you")
if (str.search(/\+alright\i|\+good\i|\+fine\i|\+alright\i/) != -1) {
alert("I'm very glad to hear that! Me, I'm feeling freaky today!");
} else if (str.search(/\+not/&&(/\+well|\+good/)||(/\+sad|\+down|\+blue/)) != -1) {
if (confirm("I'm sorry to hear that! Perhaps you'd like to get together and talk sometime?")) {
var sadNumber = prompt("What's your phone number? (The one entered is mine, feel free to call me!)", "072-");
if (sadNumber.search(/\D/) != -1) {
alert("Sorry, I think there's something wrong with your number. Try entering it with just numbers please!");
sadNumber = prompt("What's your phone number? (The one entered is mine, feel free to call me!)", "072-");
} else {
alert("That's fine! Let's move on with our job questions, shall we?");
}
} else if (alert("Wow! I didn't expect that answer! Truly interesting"));
}
Tried methods
This is what it looks like in Firebug:
After running, this is where the statement stops for some reason. Pressing continue breaks and steps out of the statement:
Stepping through, the statement continues to run, but skips all the (I conbsider) important parts. As you can see here, the alert is being skipped, and statements continues at the else if line:
My guess it that my regexp search (either the method, pattern, or modifiers) is wrong and that's why the statement breaks. I'm still finding it odd, though, since regexp errors usually throw errors or warnings, but this script returns none.
Anyone knows why this particular script breaks? Anyone having a good methodology for debugging errors that do not throw errors or warnings?
Your regular expressions are wrong.
This one, for instance: /\+alright\i|\+good\i|\+fine\i|\+alright\i/ searches for +alrighti (literally) or +goodi or +finei or +alrighti, because \+ means a literal + and \i means a literal i.
You probably meant /alright|good|fine/i, which searches for alright, good, or fine, case-insensitve. Or perhaps /\b(?:alright|good|fine)\b/i, which does the same but is expecting word boundaries on either side of the word.
You can test out your regex at various sites, including regex101.com.

Please explain this usage of a colon in javascript

I'm making a library, and I often inspect the result of Closure Compiler's output to see how it's doing things (I do have unit tests, but I still like to see the compiled code for hints of how it could compress better).
So, I found this very weird piece of code, which I never seen before.
variable : {
some();
code()
}
Note: this is not an object literal! Also, there is no ? anywhere that would make it a ?: conditional.
That code is in a regular function block (an IIFE).
variable, in this case, is an undefined variable. There's no code making it true, false, or whatever, and just to make sure, I put a console.log in there and indeed, I get a ReferenceError.
Please do note that I test my code in IE8 too, so this isn't just in modern browsers. It seems to be standard, plain old javascript.
So let's experiment with it. Firing up Chrome's console, I get this:
undeclaredVariable:{console.log('does this get logged?')} // yes it does.
trueValue:{console.log('what about this?')} // same thing.
falseValue:{console.log('and this?')} // same thing.
but then...
(true):{console.log('does this work too?')} // SyntaxError: Unexpected token :
...and...
so?{console.log('is this a conditional?')}:{alert(123)} // Unexpected token .
So what does it do?
thisThing:{console.log('is used to declare a variable?')}
thisThing // ReferenceError: thisThing is not defined
Please, I'd love it if someone could explain to me what this code is meant to do, or at least what it does.
It is a label
Provides a statement with an identifier that you can refer to using a
break or continue statement.
For example, you can use a label to identify a loop, and then use the
break or continue statements to indicate whether a program should
interrupt the loop or continue its execution.
Another common place you see it is when people stick the wonderful and useless javascript: on event handlers.
This is a label (the bit ending with a colon) followed by a block (the code surrounded by the curly brackets).
Blocks usually follow control statements, like if(...) { /*block*/ }, but they can also simply stand on their own, as in your example.
Labels allow jumping up several loops at a time with a continue or break; see the linked MDN page for several examples, such as:
var itemsPassed = 0;
var i, j;
top:
for (i = 0; i < items.length; i++){
for (j = 0; j < tests.length; j++)
if (!tests[j].pass(items[i]))
continue top;
itemsPassed++;
}
Here, top: is a label that code inside the inner loop can jump to, in order to escape to the outer loop.
For the sake of anyone who doesn't know what JSON is, and sees a colon in what might actually be an object, and is trying to figure out what it is, and finds this discussion, a colon is also used in JSON. There is a practice of embedding functions in a JSON object. Which might be confusing (As it was to me) for anyone who happens to see this for the first time. (Everyone isn't born with the knowledge of JSON and JavaScript programmed into their brains.) So if you find yourself at this discussion, and you think that every time you see a colon in JavaScript, that it's a label, it might not be. It might be that it's a colon after a label, OR it might be part of JSON. In fact, a colon in JSON being shown as a string, is a lot more common than a label. JSON in the form of an object, will be displayed as [object Object], with all the content hidden. So, unless the JSON is in the form of a string, and you display an object to the console (console.log(object)) all you will see is [object Object]. It is common practice to write JavaScript code, wrapped in an object. In that case you will see the JSON in the form of code. That's when you'll ask yourself, "What is this? and what is that colon for?" Then you'll find yourself at this discussion, and be told that it's a label, when it's really part of JSON. The topic of this discussion is worded: "Please explain this usage of a colon in javascript", and then the "correct answer" is marked as having to do with a label. The correct answer is that a colon can be used in more than one way. So, if you don't know what JSON is, or think you know (like I did, but didn't really understand) read about it here:
JSON.org
That is just a label.
you can use continue [label name] (or break) in a loop to go to a label.
More explanations of what they are can be seen throughout the interwebs.
it is used for labeling an statement in jsvascript.check more detail here.
the labeled statement can be used with break and continue later.

javascript leaving an empty if statement

I would like to know if leaving an empty if statement for certain situations as:
else if(typeof console === 'undefined'){}
Just to have the code bypass the rest of the function It is an accepted and safe way to work or there are other recommendation practices for these cases?. Thank you.
It's fine and safe to leave if branches empty, the only thing I would add is a comment:
else if(typeof console === 'undefined')
{
//explanation why nothing has to go here
}
Without seeing the rest of the code I'm unsure how you're using this to "bypass the rest of the function", there may be a better way to do this.
From what information you've provided me, I can glean that the answer is "no". It will work, but it's bad style. If you would like to bypass the rest of the function, why not return; or put most of the logic in the if statement that pertains to it so that there is no bypassing at all?
I just had a case in which I chose to use an empty if-statement (professional context). I must agree though, there definitely is a technically cleaner solution. Still, since in a professional context time is important too, I chose to use the empty if-statement in my case, so I wanted to share my train of thought with you.
In my case I'm patching existing code with a variable that is used to skip already existing nested if-statements. The main function keeps running before and after the statement.
Original Code:
if(bValidateA){
}elseif(bValidateB){
}elseif(bValidateC){
}
// ... code continues with variables set inside the statements.
Now we want to add a global Parameter to not validate anything. What are my options and why do they suck?
Solution A sucks because much work and less easy to read:
if(!bValidateNothing && bValidateA){
}elseif(!bValidateNothing && bValidateB){
}elseif(!bValidateNothing && bValidateC){
}
Solution B sucks because empty if-statement:
if(bValidateNothing){
// empty
}elseif(bValidateA){
}elseif(bValidateB){
}elseif(bValidateC){
}
Solution C sucks because it becomes too nested (in my case there have been some additional ifs in the original code):
if(!bValidateNothing){
if(bValidateA){
if(xx){
}elseif(xy){}
}elseif(bValidateB){
}elseif(bValidateC){
}
}
Solution D, the technically cleanest solution by adding additional functions, sucks because you need to split your code, which needs a lot of time, and may result in new errors.
(no pseudocode)
So, to answer the question "accepted and safe": it works, it's readable, safe and quick. Sometimes that has to be enough, considering the alternatives. If you have the time to avoid using it, I'd probably still recommend that instead.
Funny enough, the time I saved by using this quick way to implement my logic, has now been successfully spent adding my cents to this ten year old already answered question.
Just don't write a block for a case you don't want to handle.
If you only want to do something when console exists, then do that:
if(typeof console !== 'undefined'){
// your code
}
// else if(typeof console === 'undefined'){}
// you don't need that second part
Or maybe I didn't quite get your issue?
Same as Pioul's answer, but I'd add that imo checking existence in javascript looks much tidier with the !! (notnot) operator.
if(!!console){
// your code
}
// else if(!console){}
// you don't need that second part
Sometimes it is useful to have debugging information printed out:-
if(typeof console !== 'undefined'){
console.log("debug info");
}
Then, before releasing the code, simply comment out all the console.log's
// console.log("debug info");
This can be done with a macro.
It will leave an empty if statement. But this is not a compilation error so that's OK.
Note, that if you're going to comment out the line it is important that braces are used. Otherwise you'd have the next line dependent on the if statement which would be a bleeding shame.
Using an empty if statement can be a valid and accepted practice in certain situations.
For example, when working with a try-catch block, you may use an empty if statement to handle specific errors without disrupting the rest of the function. Additionally, it can be used for performance optimization by short-circuiting the evaluation of certain conditions.
Make sure that when using an empty if statement, it is properly commented to provide context and explanation for its use.
Example:
try {
// code that may throw an error
} catch (error) {
if(error instanceof SpecificError) {
// handle specific error without disrupting the rest of the function
}
}
Another example:
if(isFirstConditionTrue && isSecondConditionTrue && isThirdConditionTrue) {
// Do something
} else if(isFirstConditionTrue && isSecondConditionTrue) {
// Do nothing, because third condition is false
} else {
// handle other conditions
}
It's always a good practice to add comments explaining the purpose of each empty if statement and why you chose to use it in a certain scenario. It's not generally considered bad style as long as it serves a specific purpose and is well documented.

JSLint, else and Expected exactly one space between '}' and 'else' error

Why JSLint report in code:
function cos(a) {
var b = 0;
if (a) {
b = 1;
}
else {
b = 2;
}
return b;
}
error:
Problem at line 6 character 5: Expected exactly one space between '}' and 'else'.
This error can be turned off by disabling Tolerate messy white space option of JSLint.
Or in other words -- why syntax:
} else { is better then
...
}
else {
...
Google also uses syntax with } else { form.
But I don't understand why. Google mentioned ''implicit semicolon insertion'', but in context of opening {, not closing one.
Can Javascript insert semicolon after closing } of if block even if next token is else instruction?
Sorry that my question is a bit chaotic -- I tried to think loud.
JSLint is based on Crockford's preferences (which I share in this case).
It's a matter of opinion which is "better".
(Although clearly his opinion is right ;)
It's not a matter of style. It's how ECMAScript works.
For better or for worse, it will automatically insert semicolons at the end of statements where it feels necessary.
JavaScript would interpret this:
function someFunc {
return
{
something: 'My Value'
};
}
As this:
function someFunc {
return;
{
something: 'My Value'
};
}
Which is certainly what you don't want.
If you always put the bracket on the same line as the if and if else statement, you won't run into a problem like this.
As with any coding language, the coding style chosen should be the one that minimizes potential risk the most.
Mozilla Developer Network also promotes same line bracketing: https://developer.mozilla.org/en-US/docs/User:GavinSharp_JS_Style_Guidelines#Brackets
JSLint is being very picky here, just enforcing a style that you might not share.
Try JSHint instead:
The project originally started as an effort to make a more configurable version of JSLint—the one that doesn't enforce one particular coding style on its users [...]
JSLint is just being picky here. The guy who wrote it also baked in many stylistic suggestions in order to keep his own code more consistent.
As for semicolon insertion, you shouldn't need to worry here. Inserting a semicolon before the else clause would lead to a syntax error and automatic semicolon insertion only occurs in situations where the resulting code would still be syntactically valid.
If you want to read more on semicolon insertion, I recommend this nice reference
Basically if you insert semicolons everywhere you only need be careful about putting the argument to "return" or "throw" (or the label for "break" and "continue") on the same line.
And when you accidentally forget a semicolon, the only common cases that are likely to bite you are if you start the next line with an array literal (it might parsed as the subscript operator) or a parenthsised expression (it might be parsed as a function call)
Conclusion
Should you omit optional semicolons or not? The answer is a matter of
personal preference, but should be made on the basis of informed
choice rather than nebulous fears of unknown syntactical traps or
nonexistent browser bugs. If you remember the rules given here, you
are equipped to make your own choices, and to read any JavaScript
easily.
If you choose to omit semicolons where possible, my advice is to
insert them immediately before the opening parenthesis or square
bracket in any statement that begins with one of those tokens, or any
which begins with one of the arithmetic operator tokens "/", "+", or
"-" if you should happen to write such a statement.
Whether you omit semicolons or not, you must remember the restricted
productions (return, break, continue, throw, and the postfix increment
and decrement operators), and you should feel free to use linebreaks
everywhere else to improve the readability of your code.
By the way, I personally think that the } else { version is prettier. Stop insisting in your evil ways and joins us on the light side of the force :P
I have just finished reading a book titled Mastering JavaScript High Performance. I speak under correction here, but from what I can gather is that "white space" does in fact matter.
It has to do with the way the interpreter fetches the next function. By keeping white space to a minimum (i.e.) using a minifier when your code is ready for deployment, you actually speed up the process.
If the interpreter has to search through the white space to find the next statement this takes time. Perhaps you want to test this with a piece of code that runs a loop say 10,000 times with white space in it and then the same code minified.
The statement to put before the start of the loop would be console.time and finally console.timeEnd at the end of the loop. This will then tell you how many milliseconds the loop took to compute.
The JSLint error/warning is suggesting to alter code to
// naming convention winner? it's subjective
} else if{
b = 2;
}
from:
}
else if{
b = 2;
}
It prevents insert semicolons; considered more standard & conventional.
most people could agree a tab between the
}tabelse if{
is not the most popular method. Interesting how the opening bracket { is placed (space or not) obviously both ar subjected

Strange Javascript statement

if (1) {
google_conversion_value = 1;
}
What is the meaning of the above statement? I mean, this looks like it will always execute so why bother with the if statement?
updated: one reason might be remnants of scripting on the server side. Any other ideas?
updated2: could as easily change the value of the assignment without bothering with the if statement, no?
There are two likely explanations:
It's a leftover from debugging.
The file containing this code is generated dynamically and the original sourcecode contains something like if(<?php echo $some_stuff_enabled; ?>)
However, in the latter case it would have been cleaner to output that code block only if the condition is met - but maybe it's used in some crappy template engine that just allows replacements but no conditionals...
I've seen this before, and I've always assumed it was a remnant of some old condition that was no longer needed, but never removed. I can't see any actual reason to do something like that otherwise.
Potentially because the person writing the code wanted an easy way to turn it off and on again, this is especially useful if there is a lot of code inside the block (not the case here).
Another possibility is that the original programmer couldn't be bothered writing the logic or, more likely, it hadn't been specified so the "if" was left as a placeholder.
More than likely left in from a debug release or something similar. You're right, it will always execute. It could also have been done like this so that it can be easily enabled / disabled by setting the if to 0. Perhaps the developer intended to use it as a flag somewhere else in the code?
actually, this happens when the "if" condition is driven from server, so instead of doing the right thing and not produce the script when the condition is false, they do something like this:
if (<% if (my_server_condition) then Response.Write("1") else Response.Write("0") %>){
// code goes here
}
Perhaps the if statement used to check for a legitimate conditional, and then someone replaced it with a truthy value for testing/debugging/etc.
You're right, it will always execute because 1 is truthy. I would go through your source control history and investigate that line to see if it used to contain a real conditional. If the conditional was always 1, then it's likely a debugging statement. Otherwise someone might have meant for it to be a temporary change, and may not have meant to check that in (which could be bad).
I'm not sure where this code is from, but as you indicated it will always execute. As for why you'd do this, there are times where you want to see what the result of branch code would be, without having to setup an environment. In this case you can comment out the actual value and replace it with if(1) instead for testing:
// if( ... some hard to achieve condition )
if (1) {
// Now you can see what happens if this value is set quickly
google_conversion_value = 1;
}
Of course the problem with this is that it's sometimes easy to forget to remove the if(1) and uncomment the proper condition.
This is actually the javascript recommended by Google on http://support.google.com/adwords/bin/answer.py?hl=en&answer=1722054#nocomments (click on Step 2 for the sample HTML)

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