#&q=car&category=Car%20Audio%2CAccessories&brand=
I borrowed a this function from a previous question asked on SO:
function insertParam(key, value)
{
key = escape(key); value = escape(value);
var kvp = document.location.hash.substr(1).split('&');
var i=kvp.length; var x; while(i--)
{
x = kvp[i].split('=');
if (x[0]==key)
{
x[1] = value;
kvp[i] = x.join('=');
break;
}
}
if(i<0) {kvp[kvp.length] = [key,value].join('=');}
//this will reload the page, it's likely better to store this until finished
document.location.hash = kvp.join('&');
}
I use it like this:
insertParam("category",xy);
insertParam("brand",zy);
My problem is it is decoding comma's to %2C. I know I can handle the characters on the server side, but how can I make it look pretty with javascript? By pretty I mean replace %2c with a comma.
I do not know why in the previous answer that was striked out, but the answer was correct.
alert(decodeURIComponent('%2C'));
So, you break your query strings into elements, splitting by & symbol. Than you split the results by = symbol and apply decodeURIComponent on both name and the value.
ps: key = escape(key); value = escape(value); you should not use escape here (it is different for different browsers. and by 'different' I meant IE). Use encodeURIComponent.
pps: because they either encode commas or don't encode &=???
alert(encodeURIComponent('&=,'));
outputs %26%3D%2C
This worked for me for undoing encodeURIComponent() on URIs that contain commas:
.replace(/%2C/g,",")
decodeURIComponent(foo) is the thing you are looking for.
Edit: Misread your question.
Use replace(/&/g, "%26").replace(/=/g, "%3D") instead of escape on key and value to do this.
None of the 3 functions encodeURI, encodeURIComponent or encode work for this task, because they either encode commas or don't encode &=.
Related
I want to replace the smart quotes like ‘, ’, “ and ” to regular quotes. Also, I wanted to replace the ©, ® and ™. I used the following code. But it doesn't help.
Kindly help me to resolve this issue.
str.replace(/[“”]/g, '"');
str.replace(/[‘’]/g, "'");
Use:
str = str.replace(/[“”]/g, '"');
str = str.replace(/[‘’]/g, "'");
or to do it in one statement:
str = str.replace(/[“”]/g, '"').replace(/[‘’]/g,"'");
In JavaScript (as in many other languages) strings are immutable - string "replacement" methods actually just return the new string instead of modifying the string in place.
The MDN JavaScript reference entry for replace states:
Returns a new string with some or all matches of a pattern replaced by a replacement.
…
This method does not change the String object it is called on. It simply returns a new string.
replace return the resulting string
str = str.replace(/["']/, '');
The OP doesn't say why it isn't working, but there seems to be problems related to the encoding of the file. If I have an ANSI encoded file and I do:
var s = "“This is a test” ‘Another test’";
s = s.replace(/[“”]/g, '"').replace(/[‘’]/g,"'");
document.writeln(s);
I get:
"This is a test" "Another test"
I converted the encoding to UTF-8, fixed the smart quotes (which broke when I changed encoding), then converted back to ANSI and the problem went away.
Note that when I copied and pasted the double and single smart quotes off this page into my test document (ANSI encoded) and ran this code:
var s = "“This is a test” ‘Another test’";
for (var i = 0; i < s.length; i++) {
document.writeln(s.charAt(i) + '=' + s.charCodeAt(i));
}
I discovered that all the smart quotes showed up as ? = 63.
So, to the OP, determine where the smart quotes are originating and make sure they are the character codes you expect them to be. If they are not, consider changing the encoding of the source so they arrive as “ = 8220, ” = 8221, ‘ = 8216 and ’ = 8217. Use my loop to examine the source, if the smart quotes are showing up with any charCodeAt() values other than those I've listed, replace() will not work as written.
To replace all regular quotes with smart quotes, I am using a similar function. You must specify the CharCode as some different computers/browsers default settings may identify the plain characters differently ("",",',').
Using the CharCode with call the ASCII character, which will eliminate the room for error across different browsers, and operating systems. This is also helpful for bilingual use (accents, etc.).
To replace smart quotes with SINGLE QUOTES
function unSmartQuotify(n){
var name = n;
var apos = String.fromCharCode(39);
while (n.indexOf("'") > -1)
name = name.replace("'" , apos);
return name;
}
To find the other ASCII values you may need. Check here.
I want to replace the smart quotes like ‘, ’, “ and ” to regular quotes. Also, I wanted to replace the ©, ® and ™. I used the following code. But it doesn't help.
Kindly help me to resolve this issue.
str.replace(/[“”]/g, '"');
str.replace(/[‘’]/g, "'");
Use:
str = str.replace(/[“”]/g, '"');
str = str.replace(/[‘’]/g, "'");
or to do it in one statement:
str = str.replace(/[“”]/g, '"').replace(/[‘’]/g,"'");
In JavaScript (as in many other languages) strings are immutable - string "replacement" methods actually just return the new string instead of modifying the string in place.
The MDN JavaScript reference entry for replace states:
Returns a new string with some or all matches of a pattern replaced by a replacement.
…
This method does not change the String object it is called on. It simply returns a new string.
replace return the resulting string
str = str.replace(/["']/, '');
The OP doesn't say why it isn't working, but there seems to be problems related to the encoding of the file. If I have an ANSI encoded file and I do:
var s = "“This is a test” ‘Another test’";
s = s.replace(/[“”]/g, '"').replace(/[‘’]/g,"'");
document.writeln(s);
I get:
"This is a test" "Another test"
I converted the encoding to UTF-8, fixed the smart quotes (which broke when I changed encoding), then converted back to ANSI and the problem went away.
Note that when I copied and pasted the double and single smart quotes off this page into my test document (ANSI encoded) and ran this code:
var s = "“This is a test” ‘Another test’";
for (var i = 0; i < s.length; i++) {
document.writeln(s.charAt(i) + '=' + s.charCodeAt(i));
}
I discovered that all the smart quotes showed up as ? = 63.
So, to the OP, determine where the smart quotes are originating and make sure they are the character codes you expect them to be. If they are not, consider changing the encoding of the source so they arrive as “ = 8220, ” = 8221, ‘ = 8216 and ’ = 8217. Use my loop to examine the source, if the smart quotes are showing up with any charCodeAt() values other than those I've listed, replace() will not work as written.
To replace all regular quotes with smart quotes, I am using a similar function. You must specify the CharCode as some different computers/browsers default settings may identify the plain characters differently ("",",',').
Using the CharCode with call the ASCII character, which will eliminate the room for error across different browsers, and operating systems. This is also helpful for bilingual use (accents, etc.).
To replace smart quotes with SINGLE QUOTES
function unSmartQuotify(n){
var name = n;
var apos = String.fromCharCode(39);
while (n.indexOf("'") > -1)
name = name.replace("'" , apos);
return name;
}
To find the other ASCII values you may need. Check here.
With the code below, I have converted the following names into URL such as
Love & Relationships to http://domain.org/love-relationships
Career & Guidance to http://domain.org/career-guidance
filter('ampToDash', function(){
return function(text){
return text ? String(text).replace(/ & /g,'-'): '';
};
}).filter('dashToAmp', function(){
return function(text){
return text ? String(text).replace(/-/g,' & '): '';
};
})
However, I have a new set of names and I can't figure out how to do both at the same time.
Being Human to http://domain.org/being-human
Competitive Exams to http://domain.org/competitive-exams
filter('ampToDash', function(){
return function(text){
return text ? String(text).replace(/ /g,'-'): '';
};
}).filter('dashToAmp', function(){
return function(text){
return text ? String(text).replace(/-/g,' '): '';
};
})
How do I combine both the regex codes so it can work hand in hand?
You may also want to extend your replacement criteria to cover all "non-word" characters, instead of just accounting for the ones you're currently aware of (& and space). This would be more future-proof, and perhaps easier to reason with:
String(text).replace(/\W+/g, '-')
(\W+ means any sequence of non-word characters.)
Example:
'Jack & Jill went up the #$%#! hill'.replace(/\W+/g, '-')
Yields:
Jack-Jill-went-up-the-hill
And because there's loss of information (i.e. you don't know what exactly leads to a '-' by looking at the transformed string), a way you can find the original string is to simply store it and look up by the transformed string. To elaborate: You're probably going to be looking up some document from this new string (a "slug", as others pointed out). Store the slug along with the document and just look up the document (and its original title) from your database.
It looks like you simply want to change any instances of an ampersand with leading or trailing white-space or just white-space to a single hyphen. If so, you could just use the following expression :
// Replace any strings that have leading and trailing spaces or just a series of spaces
String(text).replace(/(\s+&\s+|\s+)/g,'-'): '';
Example
var input = ['Love & Relationships', 'Career & Guidance', 'Being Human', 'Competitive Exams'];
for (var i in input) {
var phrase = input[i];
console.log(phrase + ' -> ' + phrase.replace(/(\s+&\s+|\s+)/g, '-'));
}
I think you are looking for a lib that converts a string into a slug.
You can do this manually, but you'll probably have hard time covering other edge cases.
I would suggest you to use something like :
https://github.com/dodo/node-slug
Or check out this gist if you really want to stay with the regex way : https://gist.github.com/mathewbyrne/1280286
You have two separate problems:
how to 'slugify' a string
how to undo / reverse the slugify.
To answer 1: A generic slugify method would be something like: text.replace(/\W+/g, '-')
To answer 2: you can't. You have a function (ampToDash) that can produce the same output given different inputs. i.e. there is NO equivalent of dashToAmp any more.
So, I recently found this example on trimming whitespace, but I've found that it also affects strings in code. For instance, say I'm doing a lesson on string comparison, and to demonstrate that "Hello World!" and "Hello World!" are different, I need the code compression to not have any effect on those two strings.
I'm using the whitespace compression so that people with different formatting styles won't be punished for using something that I don't use. For instance, I like to format my functions like this:
function foo(){
return 0;
};
While others may format it like this:
function foo()
{
return 0;
};
So I use whitespace compression around punctuation to make sure it always comes out the same, but I don't want it to affect anything within a string. Is there a way to add exceptions in JavaScript's replace() function?
UPDATE:
check this jsfiddle
var str='dfgdfg fdgfd fd gfd g print("Hello World!"); sadfds dsfgsgdf'
var regex=/(?:(".*"))|(\s+)/g;
var newStr=str.replace(regex, '$1 ');
console.log(newStr);
console.log(str);
In this code it will process everything except the quoted strings
to play with the code more comfortably you can see how the regex is working :
https://regex101.com/r/tG5qH2/1
I made a jsfiddle here: https://jsfiddle.net/cuywha8t/2/
var stringSplitRegExp = /(".+?"|'.+?')/g;
var whitespaceRegExp = /\s+\{/g;
var whitespaceReplacement = "{"
var exampleCode = `var str = "test test test" + 'asdasd "sd"';\n`+
`var test2 = function()\n{\nconsole.log("This is a string with 'single quotes'")\n}\n`+
`console.log('this is a string with "double quotes"')`;
console.log(exampleCode)
var separatedStrings =(exampleCode.split(stringSplitRegExp))
for(var i = 0; i < separatedStrings.length; i++){
if (i%2 === 1){
continue;
}
var oldString = separatedStrings[i];
separatedStrings[i] = oldString.replace(whitespaceRegExp, whitespaceReplacement)
}
console.log(separatedStrings.join(""))
I believe this is what you are looking for. it handles cases where a string contains the double quotes, etc. without modifying. This example just does the formatting of the curly-braces as you mentioned in your post.
Basically, the behavior of split allows the inclusion of the splitter in the array. And since you know the split is always between two non-string elements you can leverage this by looping over and modifying only every even-indexed array element.
If you want to do general whitespace replacement you can of course modify the regexp or do multiple passes, etc.
How can I split the following string?
var str = "test":"abc","test1":"hello,hi","test2":"hello,hi,there";
If I use str.split(",") then I won't be able to get strings which contain commas.
Whats the best way to split the above string?
I assume it's actually:
var str = '"test":"abc","test1":"hello,hi","test2":"hello,hi,there"';
because otherwise it wouldn't even be valid JavaScript.
If I had a string like this I would parse it as an incomplete JSON which it seems to be:
var obj = JSON.parse('{'+str+'}');
and then use is as a plain object:
alert(obj.test1); // says: hello,hi
See DEMO
Update 1: Looking at other answers I wonder whether it's only me who sees it as invalid JavaScript?
Update 2: Also, is it only me who sees it as a JSON without curly braces?
Though not clear with your input. Here is what I can suggest.
str.split('","');
and then append the double quotes to each string
str.split('","'); Difficult to say given the formatting
if Zed is right though you can do this (assuming the opening and closing {)
str = eval(str);
var test = str.test; // Returns abc
var test1 = str.test1; // returns hello,hi
//etc
That's a general problem in all languages: if the items you need contain the delimiter, it gets complicated.
The simplest way would be to make sure the delimiter is unique. If you can't do that, you will probably have to iterate over the quoted Strings manually, something like this:
var arr = [];
var result = text.match(/"([^"]*"/g);
for (i in result) {
arr.push(i);
}
Iterate once over the string and replace commas(,) following a (") and followed by a (") with a (%) or something not likely to find in your little strings. Then split by (%) or whatever you chose.