I am trying to work out how to show more divs when hovering over one div.
I know how to show changes of the same div when hovering over it but how can I show more divs when hovering over one div?
Take this as an example:
http://jsfiddle.net/j4LFD/
How can I make it so when you hover over the box another box appears next to it?
Im not sure if this can be done with css or needs javascript?
Thanks!
James
You can do it with css like this:
.box , .appear{
background: #151515;
height: 100px;
width: 100px;
float:left;
}
.appear{
background:red;
display:none
}
.box:hover{
background: #e6e6e6;
height: 100px;
width: 100px;
}
.box:hover + .appear {
display:block;
}
Check this example http://jsfiddle.net/j4LFD/1/
To my knowledge it's not possible without Javascript, and I'd recommend using jQuery because it will make your life a lot easier. If you just want to show a div then you can do something similar to
<div id="div1">First Div</div>
<div id="div2" style="display:none">Second Div</div>
Then in the javascript
$('#div1').mouseover(function(){
$('#div2').show();
})
$('#div1').mouseout(function(){
$('#div2').hide();
})
If you actually want to add it dive on hover then you can use the jquery .append() function (http://api.jquery.com/append/)
Edit: Ok seeing sandeep's answer it clearly is possible in CSS, but still, this is how you'd do it in JS :-)
CSS solution: Use a parent/container div.
http://jsfiddle.net/samliew/j4LFD/4/
You can also do this with vanilla Javascript (no JQuery) and without having your elements be adjacent siblings. Example fiddle: http://jsfiddle.net/3nxfG/
html/js:
<div id="box1" class="box"></div>
<div id="box2" class="box hidden"></div>
<script type="text/javascript">
var box1 = document.getElementById('box1');
box1.onmouseover = function() {
var box2 = document.getElementById('box2');
box2.style.visibility = 'visible';
};
box1.onmouseout = function() {
var box2 = document.getElementById('box2');
box2.style.visibility = 'hidden';
};
</script>
css:
.box {
background: #151515;
height: 100px;
width: 100px;
float: left;
}
.hidden {
visibility: hidden;
}
You can fake it, use the box to hide the second box and the border to be the box,http://jsfiddle.net/j4LFD/3/
Related
I'm building a responsive page that, when viewed on mobile, includes some popular behaviors.
I have an element that includes text and a link. The text portion needs to cover 100% of the width of the viewport and when clicked/tapped the link should push the text content left and reveal the link.
Fiddle: http://jsfiddle.net/Flignats/0n0fwm20/
HTML:
<div id="container">
<div id="block-one">
I'm a bunch of informational text.
</div>
<div id="block-two">
I'm a link!
</div>
</div>
CSS:
#container {
width: 100%;
height: 100px;
}
#block-one {
float: left;
width: 75%;
height: 100px;
background-color: #626366;
}
#block-two {
float: left;
width: 25%;
height: 100px;
background-color: #969696;
}
#block-two a {
color: blue;
}
How can I have block-one span the full width of the screen, block-two hidden off the screen, and, on click, animate (the margin?) block-two into view with block-one pushed to the left?
My apologies if I missed a clear example on site, most other questions were more complex.
I'd prefer not to build a jquery mobile page, though the push and reveal panels would accomplish this action. I'm also using Angular if nganimate is preferred over javascript.
Here is pure css solution: http://jsfiddle.net/3wcfggmf/
I've used trick with label and checkbox:checked to recognize if element is clicked or not.
input:checked + #block-one {
width: 75%;
}
If I didn't understand you correctly please let me know and I'll modify this PURE css solution for you :)
I forked your fiddle here with a working example: http://jsfiddle.net/90gm224q/
Added CSS to yours:
#container * { transition: width .4s; }
#container.clicked #block-one { width:25%; }
#container.clicked #block-two { width:75%; }
The JS:
var container = document.getElementById('container'),
link = document.getElementById('block-two').getElementsByTagName('a')[0];
link.onclick = function() {
container.className = 'clicked';
return false;
}
Assuming I understood your question correctly, you can play with the CSS values for width to achieve your desired effect.
You could accomplish this via CSS transistions and a JavaScript class toggle.
Demo - http://jsfiddle.net/Leh5t9t6/
In my demo, clicking #block-one toggles a class which fires the CSS transision. I included a pure JavaScript and jQuery version in the demo (you mentioned you'd prefer not use jQuery).
I also edited the styles slightly to accommodate the off-screen link.
Pure Javascript
var element = document.getElementById('block-one');
element.addEventListener('click', function () {
this.classList.toggle('reveal');
}, false);
jQuery
$('#block-one').on('click', function(){
$(this).toggleClass('reveal');
});
I have created an element that is displayed when I am over a particular box.
If I move my mouse over the box I can see my element but then I need to move my mouse in and out twice for the element to disappear. How can I fix it? Shouldn't the element hide itself once I move the mouse out?
How do I make my box only show when mouse is over the box?
<script>
$("#box").on("mouseover",function()
{
$("#my-box").toggle();
});
</script>
I tried to hide it myself, but it didn't work:
$("#box").on("onmouseout", function()
{
$("#my-box").hide();
});
You can use mouseover and mouseout in a same eventlistener like one below:
$("#box").on("mouseover mouseout",function()
{
$("#my-box").toggle();
});
#my-box{
display:none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="box">
Box here
</div>
<div id="my-box">
My Box
</div>
FIDDLE DEMO
The problem with your code is you're using onmouseout instead of use mouseenter and mouseleave method.
You can use hover:
$('#box').hover(function(){
$('#my-box').toggle();
});
You can use combination of both
$("#box").mouseover(function() {
$("#my-box").show();
}).mouseout(function() {
$("#my-box").hide();
});
Example
jQuery Solution
HTML
<div class="box" id="action"></div>
<div class="box" id="hidden"></div>
JS
$("#action").on("mouseover mouseout",function()
{
$("#hidden").toggle();
});
CSS
.box{
width: 30px;
height: 30px;
background: red;
margin: 10px;
}
#hidden{
display: none;
}
JSFiddle
Allthough it would be better doing this by just using CSS.
CSS Only Solution
.box{
width: 30px;
height: 30px;
background: red;
margin: 10px;
}
#action:hover + #hidden{
display: block;
}
#hidden{
display: none;
}
JSFiddle
I have a div that I want to be able to click and shrink to the top ~10% of a page. I have code similar to this where one DIV should cover everything, then the second DIV would have the content for the page:
<div id="cover">Optimized the javascript so that all code is based on jQuery.
</div>
<div id="content" style="height:300px;" class="hide" >Optimized the javascript so that all code is based on jQuery.
</div>
This is a partial example of what I want to do:
JSFiddle
The problem with this is that the slideUp() function seems to completely hide the "cover" DIV rather than shrink it to part of it's size. The other problem I have is that the background doesn't scale with the DIV. I would like the background image to shrink to a reasonable size in the cover DIV. Is this possible? In my example JSFiddle, the white space should have the "cover" DIV, and a smaller version of the background image.
jQuery slideToggle(); is actually supposed to hide or show an element completely due the fact that you're not supposed to hide or show it with the element you're hiding / showing.
So to solve your problem I've created an extra div that will hide or show the element giving it the appearence of only partly hiding the element. You can find the fiddle here:
JSFiddle
I've also scaled the background for you.
I would use jquery's animate() for this and replace background-attachment:fixed with background-size: 8em;
Tweak this part depending on the size of your divs { "height": "30%","background-size": "6em" }
$(function () {
$('#cover').click(function () {
$(this).animate({ "height": "30%","background-size": "6em" }, 400, function () {
$(this).next().show();
});
});
});
* {
margin: 0px;
padding: 0px;
}
html {
width:100%;
height:100%;
}
.hide {
display: none
}
.show {
}
#cover {
background-color: black;
width:100%;
height: 100%;
top:0;
left:0;
position:fixed;
background-size: 8em;
margin: 0 auto;
background-image: url('http://i.stack.imgur.com/JVX13.png');
background-repeat:no-repeat;
background-position:center;
}
#content {
background-color: #CCCCFF;
padding: 5px 10px;
width:100%;
height: 100%;
top:30%;
left:0;
position:absolute;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div id="cover">Optimized the javascript so that all code is based on jQuery.</div>
<div id="content" class="hide">Optimized the javascript so that all code is based on jQuery.</div>
I'm trying to make a div that I have on top of another div show up when you click on something.
This is the code for the two divs, without all the stuff that's within each:
<div id="randomarticle_enlarge">
<h1></h1>
<h4></h4>
<p></p>
<p></p>
</div>
<div class="bodybag">
<h1></h1>
<h4></h4>
<p></p>
<p></p>
</div>
Then I have css for each, of course:
.bodybag {
width:960px;
}
#randomarticle_englarge {
height:750px;
width:960px;
position:absolute;
z-index:2;
margin-top:1px;
padding-left:20px;
padding-right:20px;
display: none;
}
Am I supposed to have the bodybag class have a z-index and a position:relative? Because even though I don't it's working (at this point).
Anyway, I have this script written that's doing exactly what I want it to do:
$(document).ready(function() {
$('.popular').click(function() {
$('#textmask').fadeTo( 'fast', 0.1);
$('#backgroundmask').css('background-color', 'white');
});
});
And all I want to happen next is that as the textmask and the backgroundmask fade in/change as they should and do, is for the randomarticle_enlarge div to show up.
I've tried using .toggle and .toggleClass and .slideToggle and .show but nothing is working.
Absolute positioning must be relative to a container. In order to absolutely position something you need to indicate what it's absolutely positioned to. Something along these lines.
<div id="randomarticle_englargeContainer">
<div id="randomarticle_englarge">
</div>
<div class="bodybag">
</div>
</div>
#randomarticle_englargeContainer {
position: relative;
}
.bodybag {
position: absolute;
left: 0;
top: 0;
}
When copying everything from above I have no issues using $('#randomarticle_englarge').toggle();. Check your browser's console for errors; you might find the answers there.
I'm not exactly sure about what would you like to do with the divs, but I created an example for you, maybe this is what you want:
LIVE DEMO
So there is two divs. The 2nd div covers the 1st one. Clicking on a 'button' hides the 2nd div, so the 1st one reveals. Clicking again the 'button', the 2nd div appears and covers the 1st one again.
HTML:
<div class="popular">Click me!</div>
<div class="container">
<div id="randomarticle_enlarge">
<h1>A</h1>
<h4>B</h4>
<p>C</p>
<p>D</p>
</div>
<div class="bodybag">
<h1>E</h1>
<h4>F</h4>
<p>G</p>
<p>H</p>
</div>
</div>
CSS:
.container {
position: relative;
}
.bodybag {
width: 100px;
height: 200px;
background-color: red;
}
#randomarticle_enlarge {
width: 100px;
height: 200px;
background-color: green;
position: absolute;
top: 0;
left: 0;
}
.hide {
display: none;
}
jQuery:
$(document).ready(function() {
$('.popular').click(function() {
$('#randomarticle_enlarge').toggleClass('hide');
});
});
I'm trying to achieve the effect of a sliding div using the jquery animate option. I'm able to "slide" the parent div up but I'm having issues with showing the div behind the slider.
I've created this jsfiddle to show my issue.
Try uncommenting the photoOptions div. I'm trying to hide this div so it's only revealed when the parent div is slid up.
<div class="photoWrapper">
<!-- <div class="photoOptions"> This is your data. </div>-->
<div class="photoHolder">
Image Here
</div>
<div class="photoMeta">More data here</div>
<div class="photoCredits">
Trigger
</div>
</div>
Code
jQuery.fn.blindToggle = function(speed, easing, callback) {
var h = this.height() + parseInt(this.css('paddingTop')) + parseInt(this.css('paddingBottom'));
return this.animate({
marginTop: parseInt(this.css('marginTop')) < 0 ? 0 : -h
}, speed, easing, callback);
};
$(document).ready(function(){
$(".trigger").click(function(){
$('.photoHolder').blindToggle('slow');
});
});
Current CSS:
.photoWrapper {
width:200px;
border: solid 1px #ddd;
}
.photoHolder {
border: solid 1px #eee;
width:200px;
height:266px;
}
.photoOptions {
padding-top: 50px;
height: 266px;
width: 200px;
background: #eee;
position:absolute;
}
Any thoughts on how I can achieve this?
The browser renders elements based on there place in the DOM, if an element preceeds another element in the dom, it is rendered under it.
To change this default behaviour, you should use the CSS rule z-index, by defining a lower z-index on your .photoOptions div, it will be rendered below it.
as seen in this fiddle
Also be aware that z-index values may be handled differently for elements that are positioned absolute, due to the fact that they are not rendered in the normal flow.
Using the callback on .blindToggle() can achieve that effect but you're going to have to edit your CSS so that .photoCredits is visible and just start off with .photoOptions hidden:
$(document).ready(function () {
$(".trigger").click(function () {
$('.photoHolder').blindToggle('slow', function () {
$(".photoOptions").show();
});
});
});
.photoOptions {
padding-top: 50px;
height: 266px;
width: 200px;
background: #eee;
position:absolute;
display:hidden;
}