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Using javascript or python regular expressions I want to determine if the number is 1-99 how to make it?

var category = prompt("where do you go? (1~99)", "");
hello
Using regular expressions I want to determine if the category is 1-99.
How can I solve it?
Thank you if you let me know.

You can use character classes to match digits, like this [0-9]. If you put two of them together you'll match 00 - 99. If you put a ? after one of them, then it's optional, so you'll match 0 - 99. To enforce 1-99, make the non-optional one like this [1-9]. Finally, you need to make sure there's nothing before or after the one or two digits using ^, which matches the beginning of the string, and $ which matches the end.
if (category.match(/^[1-9][0-9]?$/)){
console.log("ok")
} else {
console.log("not ok")
}

In JavaScript you can use test() method with RE for 1-99 as shown below:
var one_to_ninetynine = /^[1-9][0-9]?$/i;
if(one_to_ninetynine.test(category)) {
console.log("The number is between 1-99");
} else {
console.log("The number is NOT between 1-99");
}

Form validation to check repetition in string

I want to check the entered string in text-box for repetition. i.e. I want to accept only those String which have no repetition and can have all alphabets (CAPS ON & off) + special characters and all digits?
I tried this regexp for checking repetition
var pattern = /(\d).*\1/;
and as everything is allowed when it comes to range so i did not make any check for the same but it is not working.
Can anyone help me out with something that can make my Spin. :-)
Example - vCc##^k->Valid VbhUiu->Valid mnkOOp->Invalid fgty^^m->Invalid

var pattern = /(.).*\1/;
if (pattern.test(str)) {
alert("No repetition allowed");
} else {
alert("Looks good!");
}
DEMO

Javascript regexp using val().match() method

I'm trying to validate a field named phone_number with this rules:
the first digit should be 3 then another 9 digits so in total 10 number example: 3216549874
or can be 7 numbers 1234567
here i have my code:
if (!($("#" + val["htmlId"]).val().match(/^3\d{9}|\d{7}/)))
missing = true;
Why doesnt work :( when i put that into an online regexp checker shows good.

You should be using test instead of match and here's the proper code:
.test(/^(3\d{9}|\d{7})$/)
Match will find all the occurrences, while test will only check to see if at least one is available (thus validating your number).

Don't get confused by pipe. Must end each expression
if (!($("#" + val["htmlId"]).val().match(/^3\d{9}/|/\d{7}/)))
missing = true;
http://jsfiddle.net/alfabravoteam/e6jKs/

I had similar problem and my solution was to write it like:
if (/^(3\d{9}|\d{7})$/.test($("#" + val["htmlId"]).val()) == false) {
missing = true;
}

Try this, it's a little more strict.
.match(/^(3\d{9}|\d{7})$/)

Form validation of numeric characters in JavaScript

I would like to perform form validation using JavaScript to check for input field only to contain numeric characters.So far, the validation checks for the field not being empty - which works fine.However, numeric characters validation is not working.I would be grateful for any help.Many thanks.
<script type="text/javascript">
//form validation
function validateForm()
{
var x=document.forms["cdp_form"]["univer_number"].value
if (x==null || x=="")
{
alert("University number (URN) field must be filled in");
cdp_form.univer_number.focus();
return false;
}
else if (is_valid = /^[0-9]+$/.test(x))
{
alert("University number (URN) field must have numeric characters");
cdp_form.univer_number.focus();
return false;
}
}
</script>
<input type ="text" id="univer_number" maxlength="7" size="25" name="univer_number" />

Rather than using Regex, if it must only be numerals you can simply use IsNumeric in Javascript.
IsNumeric('1') => true;
IsNumeric('145266') => true;
IsNumeric('abc5423856') => false;

You need invert your regular expression (add ^ inside [0-9]):
/^[^0-9]+$/

Your test condition is a bit strange:
else if (is_valid = /^[0-9]+$/.test(x))
Why have the redundant comparison to is_valid? Just do:
else if (/^[0-9]+$/.test(x))
Though the regex you are using will match numerals and only numerals - you need to change it to match anything that is not a numeral - like this /^[^0-9]+$/.
Better yet, get rid of the regex altogether and use IsNumeric:
else if (!IsNumeric(x))

On your line that says else if (is_valid = /^[0-9]+$/.test(x)), you're doing a simple assignment instead of testing that it is actually matching the regex.

Your pattern will still accept this input <b>##$##123 or ad!##12<b>. Use this pattern I created:
/[a-zA-Z-!##$%^&*()_+\=\[\]{};':"\\|,.<>\/?]/
This pattern will check if it is alphabetic and special characters.

You need to test for the negation of the RegExp because you want the validation to alert upon failure, so just add ! in front of it:
else if (is_valid = !/^[0-9]+$/.test(x))
See example →

I know this is an old post but I thought I'd post what worked for me. I don't require the field to be filled at all but if it is it has to be numerical:
function validateForm()
{
var x=document.forms["myformName"]["myformField"].value;
if (/[^0-9]+$/.test(x))
{
alert("Please enter a numerical amount without a decimal point");
myformName.myformField.focus();
return false;
}
}

Regular Expression for Phone Number

I need a Javascript RegEx through which I can validate phone number. RegEx should handle following criteria
It should only consist of numbers ( ) + and -
Count of + should not exceed 1
Count of - should not exceed 4
There must be only one pair of ()
If '(' is present in phone number then ')' must be present.
Thanks for the help!
Hussain.

Try this:
function valid_phone_number(ph) {
var regex = /^(?!([^-]*-){5})(\+\d+)?\s*(\(\d+\))?[- \d]+$/gi;
return regex.test(ph);
}
I'm new to regular expressions, so please be nice. :-)