Develop Reference

How to create whitespace inside a JSON

I want to put a line of space or blanks between the values. Because they're all leaving together right now.
My example:
data: JSON.stringify({
"sessionID":xxxxx,
"synchronize":false,
"sourceRequest":{
"numberOrigin":xxxxxx,
"type":"x",
"description":test + "\\n" + test2 "\\n" + test3 "\\n" + test4,
"userID":xxxxxxxx,
"contact":{
"name":"xxxxxxxxxxxxxxxxx",
"phoneNumber":"xxxxxxxxxx",
"email":xxxx,
"department":"xxxxx"
},

The "\\n" says to put a literal \n in the string - 2 chars. You should just use "\n" to say that its a new line - 1 char.
Note if viewing in Windows Notepad, \n is not enough for a new line.

A simple ' ' (space character) is enough to do what is needed, the json key does hold a string after all, if you need something more prominent you can use '\t', refer here for more.

Regex with multiple start and end characters that must be the same

I would like to be able to search for strings inside a special tag in a string in JavaScript. Strings in JavaScript can start with either " or ' character.
Here an example to illustrate what I want to do. My custom tag is called <my-tag. My regex is /('|")*?<my-tag>((.|\n)[^"']*?)<\/my-tag>*?('|")/g. I use this regex pattern on the following strings:
var a = '<my-tag>Hello World</my-tag>'; //is found as expected
var b = "<my-tag>Hello World" + '</my-tag>'; //is NOT found, this is good!
var c = "<my-tag>Hello World</my-tag>"; //is found as expected
var d = '<my-tag>something "special"</my-tag>'; //here the " char causes a problem
var e = "<my-tag>something 'special'</my-tag>"; //here the " char causes a problem
It works well with a and also c where it finds the tag with the containing text. It also does not find the text in b which is what I want. But in case d and e the tag with content is not found due to the occurrence of the " and ' character. What I want is a regex where inside the tag " is allowed if the string is start with ', and vice versa.
Is it possible to achieve this with one regex, or is the only thing I can do is to work with two separate regex expressions like
/(")*?<my-tag>((.|\n)[^']*?)<\/my-tag>*?(")/g and /(')*?<my-tag>((.|\n)[^"]*?)<\/my-tag>*?(')/g ?

It's not pretty, but I think this would work:
/("<my-tag>((.|\n)[^"]*?)<\/my-tag>"|'<my-tag>((.|\n)[^']*?)<\/my-tag>')/g

You should be able to use de match from the first match ('|") and reuse it for the second match. Something like the following:
/('|")<my-tag>.*?<\/my-tag>\1/g
This should make sure to match the same character at the beginning and the end.
But you really shouldn't use regex for parsing HTML.

ASCII character not being recognized in if statement

I am trying to get a string from a html page with jquery and this is what I have.
var text = $(this).text();
var key = text.substring(0,1);
if(key == ' ' || key == ' ')
key = text.substring(1,2);
text is this  Home
And I want to skip the space and or the keycode above It appears this code does not work either. It only gets the text.substring(0,1); instead of text.substring(1,2); because the if statement is not catching.= and I am not sure why. Any help would be super awesome! Thanks!

There are several problems with the code in the question. First,   has no special meaning in JavaScript: it is a string literal with six characters. Second, text.substring(1,2) returns simply the second character of text, not all characters from the second one onwards.
Assuming that you wish to remove one leading SPACE or NO-BREAK SPACE (which is what   means in HTML; it is not an Ascii character, by the way), then the following code would work:
var first = text.substring(0, 1);
if(first === ' ' || first === '\u00A0') {
text = text.substring(1, text.length);
}
The notation \u00A0 is a JavaScript escape notation for NO-BREAK SPACE U+00A0.
Should you wish to remove multiple spaces at the start, and perhaps at the end too, some modifications are needed. In that case, using a replace operation with regular expression is probably best.

If you want remove spaces at the beginning (and end) of a string, you can use the trim function
var myvar = " home"
myVar.trim() // --> "home"
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/Trim

Regular expression for removing whitespaces

I have some text which looks like this -
" tushar is a good boy "
Using javascript I want to remove all the extra white spaces in a string.
The resultant string should have no multiple white spaces instead have only one. Moreover the starting and the end should not have any white spaces at all. So my final output should look like this -
"tushar is a good boy"
I am using the following code at the moment-
str.replace(/(\s\s\s*)/g, ' ')
This obviously fails because it doesn't take care of the white spaces in the beginning and end of the string.

This can be done in a single String#replace call:
var repl = str.replace(/^\s+|\s+$|\s+(?=\s)/g, "");
// gives: "tushar is a good boy"

This works nicely:
function normalizeWS(s) {
s = s.match(/\S+/g);
return s ? s.join(' ') : '';
}
trims leading whitespace
trims trailing whitespace
normalizes tabs, newlines, and multiple spaces to a single regular space

Try this:
str.replace(/\s+/g, ' ').trim()
If you don't have trim add this.
Trim string in JavaScript?

Since everyone is complaining about .trim(), you can use the following:
str.replace(/\s+/g,' ' ).replace(/^\s/,'').replace(/\s$/,'');
JSFiddle

This regex may be useful to remove the whitespaces
/^\s+|\s+$/g

Try:
str.replace(/^\s+|\s+$/, '')
.replace(/\s+/, ' ');

try
var str = " tushar is a good boy ";
str = str.replace(/^\s+|\s+$/g,'').replace(/(\s\s\s*)/g, ' ');
first replace is delete leading and trailing spaces of a string.

Regex that only works on browser tester

I've tested my regex on Regex testers and it worked, but I didn't get it to work on my code.
var mail = "chdelfosse#gmail.com";
var regExp = new RegExp("#(.*?)\.");
document.write(regExp.exec(mail)) ;
I get this result :
#g,
I tried to add a backslash before the dot, and I got this :
#gmail.,gmail
I also wanted to remove the "#" and the "." from the email, so I tried to use " (?:#) ", but I didn't get it to work (on Regex testers).
It's my first time trying to use Regex, and I don't get it.
Why is there a comma ?

You can use this regex to get the domain name:
/#(.+)\./
Live DEMO

Faster than regex:
var emailAddress = "my.email#gmail.com";
var array_email = emailAddress.split("#");​​
alert('Account: ' + array_email[0] +'; Domain: ' + array_email[1]);​​​​​​​​​​​​​​​​​​​​​​​​​​

A couple things to do differently:
You need to double escape your backslash in the string so that one backslash still remains for the RegExp constructor or switch to the /regex here/ syntax.
If you want just the subgroup in the parens, you need to refer to that specific subgroup.
Here's the code:
var mail = "chdelfosse#gmail.com";
console.log(mail.match(/#(.*?)\./)[1]);