Related
I want to know how to get the X and Y position of HTML elements such as img and div in JavaScript.
The correct approach is to use element.getBoundingClientRect():
var rect = element.getBoundingClientRect();
console.log(rect.top, rect.right, rect.bottom, rect.left);
Internet Explorer has supported this since as long as you are likely to care about and it was finally standardized in CSSOM Views. All other browsers adopted it a long time ago.
Some browsers also return height and width properties, though this is non-standard. If you're worried about older browser compatibility, check this answer's revisions for an optimised degrading implementation.
The values returned by element.getBoundingClientRect() are relative to the viewport. If you need it relative to another element, simply subtract one rectangle from the other:
var bodyRect = document.body.getBoundingClientRect(),
elemRect = element.getBoundingClientRect(),
offset = elemRect.top - bodyRect.top;
alert('Element is ' + offset + ' vertical pixels from <body>');
This function returns an element's position relative to the whole document (page):
function getOffset(el) {
const rect = el.getBoundingClientRect();
return {
left: rect.left + window.scrollX,
top: rect.top + window.scrollY
};
}
Using this we can get the X position:
getOffset(element).left
... or the Y position:
getOffset(element).top
The libraries go to some lengths to get accurate offsets for an element.
here's a simple function that does the job in every circumstances that I've tried.
function getOffset( el ) {
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) ) {
_x += el.offsetLeft - el.scrollLeft;
_y += el.offsetTop - el.scrollTop;
el = el.offsetParent;
}
return { top: _y, left: _x };
}
var x = getOffset( document.getElementById('yourElId') ).left;
If you want it done only in javascript, here are some one liners using getBoundingClientRect()
window.scrollY + document.querySelector('#elementId').getBoundingClientRect().top // Y
window.scrollX + document.querySelector('#elementId').getBoundingClientRect().left // X
The first line will return offsetTop say Y relative to document.
The second line will return offsetLeft say X relative to document.
getBoundingClientRect() is a javascript function that returns the position of the element relative to viewport of window.
HTML elements on most browsers will have:-
offsetLeft
offsetTop
These specifiy the position of the element relative its nearest parent that has layout. This parent can often be accessed bif the offsetParent property.
IE and FF3 have
clientLeft
clientTop
These properties are less common, they specify an elements position with its parents client area (padded area is part of the client area but border and margin is not).
If page includes - at least- any "DIV", the function given by meouw throws the "Y" value beyond current page limits. In order to find the exact position, you need to handle both offsetParent's and parentNode's.
Try the code given below (it is checked for FF2):
var getAbsPosition = function(el){
var el2 = el;
var curtop = 0;
var curleft = 0;
if (document.getElementById || document.all) {
do {
curleft += el.offsetLeft-el.scrollLeft;
curtop += el.offsetTop-el.scrollTop;
el = el.offsetParent;
el2 = el2.parentNode;
while (el2 != el) {
curleft -= el2.scrollLeft;
curtop -= el2.scrollTop;
el2 = el2.parentNode;
}
} while (el.offsetParent);
} else if (document.layers) {
curtop += el.y;
curleft += el.x;
}
return [curtop, curleft];
};
You can add two properties to Element.prototype to get the top/left of any element.
Object.defineProperty( Element.prototype, 'documentOffsetTop', {
get: function () {
return this.offsetTop + ( this.offsetParent ? this.offsetParent.documentOffsetTop : 0 );
}
} );
Object.defineProperty( Element.prototype, 'documentOffsetLeft', {
get: function () {
return this.offsetLeft + ( this.offsetParent ? this.offsetParent.documentOffsetLeft : 0 );
}
} );
This is called like this:
var x = document.getElementById( 'myDiv' ).documentOffsetLeft;
Here's a demo comparing the results to jQuery's offset().top and .left: http://jsfiddle.net/ThinkingStiff/3G7EZ/
To retrieve the position relative to the page efficiently, and without using a recursive function: (includes IE also)
var element = document.getElementById('elementId'); //replace elementId with your element's Id.
var rect = element.getBoundingClientRect();
var elementLeft,elementTop; //x and y
var scrollTop = document.documentElement.scrollTop?
document.documentElement.scrollTop:document.body.scrollTop;
var scrollLeft = document.documentElement.scrollLeft?
document.documentElement.scrollLeft:document.body.scrollLeft;
elementTop = rect.top+scrollTop;
elementLeft = rect.left+scrollLeft;
How about something like this, by passing ID of the element and it will return the left or top, we can also combine them:
1) find left
function findLeft(element) {
var rec = document.getElementById(element).getBoundingClientRect();
return rec.left + window.scrollX;
} //call it like findLeft('#header');
2) find top
function findTop(element) {
var rec = document.getElementById(element).getBoundingClientRect();
return rec.top + window.scrollY;
} //call it like findTop('#header');
or 3) find left and top together
function findTopLeft(element) {
var rec = document.getElementById(element).getBoundingClientRect();
return {top: rec.top + window.scrollY, left: rec.left + window.scrollX};
} //call it like findTopLeft('#header');
Here's a modern 1-liner using vanilla JS to recursively iterate over element.offsetTop and element.offsetParent:
Function:
getTop = el => el.offsetTop + (el.offsetParent && getTop(el.offsetParent))
Usage:
const el = document.querySelector('#div_id');
const elTop = getTop(el)
Advantage:
Always returns the absolute vertical offset, regardless of the current scroll position.
Traditional syntax:
function getTop(el) {
return el.offsetTop + (el.offsetParent && getTop(el.offsetParent));
}
jQuery .offset() will get the current coordinates of the first element, or set the coordinates of every element, in the set of matched elements, relative to the document.
Update:
The recursion approach (in my old answer) creates many call stacks. We can use a while loop to avoid recursion in this case:
/**
*
* #param {HTMLElement} el
* #return {{top: number, left: number}}
*/
function getDocumentOffsetPosition(el) {
let top = 0, left = 0;
while (el !== null) {
top += el.offsetTop;
left += el.offsetLeft;
el = el.offsetParent;
}
return {top, left};
}
Old answer:
/**
*
* #param {HTMLElement} el
* #return {{top: number, left: number}}
*/
function getDocumentOffsetPosition(el) {
var position = {
top: el.offsetTop,
left: el.offsetLeft
};
if (el.offsetParent) {
var parentPosition = getDocumentOffsetPosition(el.offsetParent);
position.top += parentPosition.top;
position.left += parentPosition.left;
}
return position;
}
Thank ThinkingStiff for the answer, this is only another version.
You might be better served by using a JavaScript framework, that has functions to return such information (and so much more!) in a browser-independant fashion. Here are a few:
Prototype
jQuery
MooTools
YUI (yahoo)
With these frameworks, you could do something like:
$('id-of-img').top
to get the y-pixel coordinate of the image.
I've taken #meouw's answer, added in the clientLeft that allows for the border, and then created three versions:
getAbsoluteOffsetFromBody - similar to #meouw's, this gets the absolute position relative to the body or html element of the document (depending on quirks mode)
getAbsoluteOffsetFromGivenElement - returns the absolute position relative to the given element (relativeEl). Note that the given element must contain the element el, or this will behave the same as getAbsoluteOffsetFromBody. This is useful if you have two elements contained within another (known) element (optionally several nodes up the node tree) and want to make them the same position.
getAbsoluteOffsetFromRelative - returns the absolute position relative to the first parent element with position: relative. This is similar to getAbsoluteOffsetFromGivenElement, for the same reason but will only go as far as the first matching element.
getAbsoluteOffsetFromBody = function( el )
{ // finds the offset of el from the body or html element
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) )
{
_x += el.offsetLeft - el.scrollLeft + el.clientLeft;
_y += el.offsetTop - el.scrollTop + el.clientTop;
el = el.offsetParent;
}
return { top: _y, left: _x };
}
getAbsoluteOffsetFromGivenElement = function( el, relativeEl )
{ // finds the offset of el from relativeEl
var _x = 0;
var _y = 0;
while( el && el != relativeEl && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) )
{
_x += el.offsetLeft - el.scrollLeft + el.clientLeft;
_y += el.offsetTop - el.scrollTop + el.clientTop;
el = el.offsetParent;
}
return { top: _y, left: _x };
}
getAbsoluteOffsetFromRelative = function( el )
{ // finds the offset of el from the first parent with position: relative
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) )
{
_x += el.offsetLeft - el.scrollLeft + el.clientLeft;
_y += el.offsetTop - el.scrollTop + el.clientTop;
el = el.offsetParent;
if (el != null)
{
if (getComputedStyle !== 'undefined')
valString = getComputedStyle(el, null).getPropertyValue('position');
else
valString = el.currentStyle['position'];
if (valString === "relative")
el = null;
}
}
return { top: _y, left: _x };
}
If you are still having problems, particularly relating to scrolling, you could try looking at http://www.greywyvern.com/?post=331 - I noticed at least one piece of questionable code in getStyle which should be fine assuming browsers behave, but haven't tested the rest at all.
Difference between small and little
function getPosition( el ) {
var x = 0;
var y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) ) {
x += el.offsetLeft - el.scrollLeft;
y += el.offsetTop - el.scrollTop;
el = el.offsetParent;
}
return { top: y, left: x };
}
Look a example coordinates:
http://javascript.info/tutorial/coordinates
If you are using jQuery, this could be a simple solution:
<script>
var el = $("#element");
var position = el.position();
console.log( "left: " + position.left + ", top: " + position.top );
</script>
if using jQuery, the dimensions plugin is excellent and allows you specify exactly what you want.
e.g.
Relative position, absolute position, absolute position without padding, with padding...
It goes on, let's just say there is a lot you can do with it.
Plus the bonus of using jQuery is it's lightweight file size and easy use, you won't go back to JavaScript without it afterwards.
The cleanest approach I have found is a simplified version of the technique used by jQuery's offset. Similar to some of the other answers it starts with getBoundingClientRect; it then uses the window and the documentElement to adjust for scroll position as well as things like the margin on the body (often the default).
var rect = el.getBoundingClientRect();
var docEl = document.documentElement;
var rectTop = rect.top + window.pageYOffset - docEl.clientTop;
var rectLeft = rect.left + window.pageXOffset - docEl.clientLeft;
var els = document.getElementsByTagName("div");
var docEl = document.documentElement;
for (var i = 0; i < els.length; i++) {
var rect = els[i].getBoundingClientRect();
var rectTop = rect.top + window.pageYOffset - docEl.clientTop;
var rectLeft = rect.left + window.pageXOffset - docEl.clientLeft;
els[i].innerHTML = "<b>" + rectLeft + ", " + rectTop + "</b>";
}
div {
width: 100px;
height: 100px;
background-color: red;
border: 1px solid black;
}
#rel {
position: relative;
left: 10px;
top: 10px;
}
#abs {
position: absolute;
top: 250px;
left: 250px;
}
<div id="rel"></div>
<div id="abs"></div>
<div></div>
To get the total offset of an element, you could recursively sum up all parent offsets:
function getParentOffset(el): number {
if (el.offsetParent) {
return el.offsetParent.offsetTop + getParentOffset(el.offsetParent);
} else {
return 0;
}
}
with this utility function the total top offset of a dom element is:
el.offsetTop + getParentOffset(el);
This is the best code I've managed to create (works in iframes as well, unlike jQuery's offset()). Seems webkit has a bit of a different behavior.
Based on meouw's comment:
function getOffset( el ) {
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) ) {
_x += el.offsetLeft - el.scrollLeft;
_y += el.offsetTop - el.scrollTop;
// chrome/safari
if ($.browser.webkit) {
el = el.parentNode;
} else {
// firefox/IE
el = el.offsetParent;
}
}
return { top: _y, left: _x };
}
While this is very likely to be lost at the bottom of so many answers, the top solutions here were not working for me.
As far as I could tell neither would any of the other answers have helped.
Situation:
In an HTML5 page I had a menu that was a nav element inside a header (not THE header but a header in another element).
I wanted the navigation to stick to the top once a user scrolled to it, but previous to this the header was absolute positioned (so I could have it overlay something else slightly).
The solutions above never triggered a change because .offsetTop was not going to change as this was an absolute positioned element. Additionally the .scrollTop property was simply the top of the top most element... that is to say 0 and always would be 0.
Any tests I performed utilizing these two (and same with getBoundingClientRect results) would not tell me if the top of the navigation bar ever scrolled to the top of the viewable page (again, as reported in console, they simply stayed the same numbers while scrolling occurred).
Solution
The solution for me was utilizing
window.visualViewport.pageTop
The value of the pageTop property reflects the viewable section of the screen, therefore allowing me to track where an element is in reference to the boundaries of the viewable area.
Probably unnecessary to say, anytime I am dealing with scrolling I expect to use this solution to programatically respond to movement of elements being scrolled.
Hope it helps someone else.
IMPORTANT NOTE: This appears to work in Chrome and Opera currently & definitely not in Firefox (6-2018)... until Firefox supports visualViewport I recommend NOT using this method, (and I hope they do soon... it makes a lot more sense than the rest).
UPDATE:
Just a note regarding this solution. While I still find what I discovered to be very valuable for situations in which "...programmatically respond to movement of elements being scrolled." is applicable. The better solution for the problem that I had was to use CSS to set position: sticky on the element. Using sticky you can have an element stay at the top without using javascript (NOTE: there are times this will not work as effectively as changing the element to fixed but for most uses the sticky approach will likely be superior)
UPDATE01:
So I realized that for a different page I had a requirement where I needed to detect the position of an element in a mildly complex scrolling setup (parallax plus elements that scroll past as part of a message).
I realized in that scenario that the following provided the value I utilized to determine when to do something:
let bodyElement = document.getElementsByTagName('body')[0];
let elementToTrack = bodyElement.querySelector('.trackme');
trackedObjPos = elementToTrack.getBoundingClientRect().top;
if(trackedObjPos > 264)
{
bodyElement.style.cssText = '';
}
Hope this answer is more widely useful now.
I did it like this so it was cross-compatible with old browsers.
// For really old browser's or incompatible ones
function getOffsetSum(elem) {
var top = 0,
left = 0,
bottom = 0,
right = 0
var width = elem.offsetWidth;
var height = elem.offsetHeight;
while (elem) {
top += elem.offsetTop;
left += elem.offsetLeft;
elem = elem.offsetParent;
}
right = left + width;
bottom = top + height;
return {
top: top,
left: left,
bottom: bottom,
right: right,
}
}
function getOffsetRect(elem) {
var box = elem.getBoundingClientRect();
var body = document.body;
var docElem = document.documentElement;
var scrollTop = window.pageYOffset || docElem.scrollTop || body.scrollTop;
var scrollLeft = window.pageXOffset || docElem.scrollLeft || body.scrollLeft;
var clientTop = docElem.clientTop;
var clientLeft = docElem.clientLeft;
var top = box.top + scrollTop - clientTop;
var left = box.left + scrollLeft - clientLeft;
var bottom = top + (box.bottom - box.top);
var right = left + (box.right - box.left);
return {
top: Math.round(top),
left: Math.round(left),
bottom: Math.round(bottom),
right: Math.round(right),
}
}
function getOffset(elem) {
if (elem) {
if (elem.getBoundingClientRect) {
return getOffsetRect(elem);
} else { // old browser
return getOffsetSum(elem);
}
} else
return null;
}
More about coordinates in JavaScript here: http://javascript.info/tutorial/coordinates
HTML program to show (x, y) of an
element by dragging mouse over it you just copied it and use it on your own
<!DOCTYPE html>
<html>
<head>
<title>
position of an element
</title>
<!-- scropt to get position -->
<script type = "text/javascript">
function getPositionXY(element) {
var rect = element.getBoundingClientRect();
document.getElementById('text').innerHTML
= 'X: ' + rect.x + '<br>' + 'Y: ' + rect.y;
}
</script>
</head>
<body>
<p>Move the mouse over the text</p>
<div onmouseover = "getPositionXY(this)">
Position:
<p id = 'text'></p>
</div>
</body>
</html>
i could just like element.offsetLeft or element.offsetTop. Example :
document.getElementById('profileImg').offsetLeft
I successfully used Andy E's solution to position a bootstrap 2 modal depending on what link in a table row a user clicks on. The page is a Tapestry 5 page and javascript below is imported in the java page class.
javascript:
function setLinkPosition(clientId){
var bodyRect = document.body.getBoundingClientRect(),
elemRect = clientId.getBoundingClientRect(),
offset = elemRect.top - bodyRect.top;
offset = offset + 20;
$('#serviceLineModal').css("top", offset);
}
My modal code:
<div id="serviceLineModal" class="modal hide fade add-absolute-position" data-backdrop="static"
tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true" style="top:50%;">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">x</button>
<h3 id="myModalLabel">Modal header</h3>
</div>
<div class="modal-body">
<t:zone t:id="modalZone" id="modalZone">
<p>You selected service line number: ${serviceLineNumberSelected}</p>
</t:zone>
</div>
<div class="modal-footer">
<button class="btn" data-dismiss="modal" aria-hidden="true">Close</button>
<!-- <button class="btn btn-primary">Save changes</button> -->
</div>
The link in the loop:
<t:loop source="servicesToDisplay" value="service" encoder="encoder">
<tr style="border-right: 1px solid black;">
<td style="white-space:nowrap;" class="add-padding-left-and-right no-border">
<a t:type="eventLink" t:event="serviceLineNumberSelected" t:context="service.serviceLineNumber"
t:zone="pageZone" t:clientId="modalLink${service.serviceLineNumber}"
onmouseover="setLinkPosition(this);">
<i class="icon-chevron-down"></i> <!-- ${service.serviceLineNumber} -->
</a>
</td>
And the java code in the page class:
void onServiceLineNumberSelected(String number){
checkForNullSession();
serviceLineNumberSelected = number;
addOpenServiceLineDialogCommand();
ajaxResponseRenderer.addRender(modalZone);
}
protected void addOpenServiceLineDialogCommand() {
ajaxResponseRenderer.addCallback(new JavaScriptCallback() {
#Override
public void run(JavaScriptSupport javascriptSupport) {
javascriptSupport.addScript("$('#serviceLineModal').modal('show');");
}
});
}
Hope this helps someone, this post helped out.
After much research and testing this seems to work
function getPosition(e) {
var isNotFirefox = (navigator.userAgent.toLowerCase().indexOf('firefox') == -1);
var x = 0, y = 0;
while (e) {
x += e.offsetLeft - e.scrollLeft + (isNotFirefox ? e.clientLeft : 0);
y += e.offsetTop - e.scrollTop + (isNotFirefox ? e.clientTop : 0);
e = e.offsetParent;
}
return { x: x + window.scrollX, y: y + window.scrollY };
}
see http://jsbin.com/xuvovalifo/edit?html,js,output
Just thought I'd throw this out there as well.
I haven't been able to test it in older browsers, but it works in the latest of the top 3. :)
Element.prototype.getOffsetTop = function() {
return ( this.parentElement )? this.offsetTop + this.parentElement.getOffsetTop(): this.offsetTop;
};
Element.prototype.getOffsetLeft = function() {
return ( this.parentElement )? this.offsetLeft + this.parentElement.getOffsetLeft(): this.offsetLeft;
};
Element.prototype.getOffset = function() {
return {'left':this.getOffsetLeft(),'top':this.getOffsetTop()};
};
This is easy as two lines in JS :
var elem = document.getElementById("id");
alert(elem.getBoundingClientRect());
Since different browsers are rendering border, padding, margin and etc in different way. I wrote a little function to retrieve top and left positions of specific element in every root element that you want in precise dimension:
function getTop(root, offset) {
var rootRect = root.getBoundingClientRect();
var offsetRect = offset.getBoundingClientRect();
return offsetRect.top - rootRect.top;
}
For retrieve left position you must return:
return offsetRect.left - rootRect.left;
Get position of div in respect to left and Top
var elm = $('#div_id'); //get the div
var posY_top = elm.offset().top; //get the position from top
var posX_left = elm.offset().left; //get the position from left
I want to know how to get the X and Y position of HTML elements such as img and div in JavaScript.
The correct approach is to use element.getBoundingClientRect():
var rect = element.getBoundingClientRect();
console.log(rect.top, rect.right, rect.bottom, rect.left);
Internet Explorer has supported this since as long as you are likely to care about and it was finally standardized in CSSOM Views. All other browsers adopted it a long time ago.
Some browsers also return height and width properties, though this is non-standard. If you're worried about older browser compatibility, check this answer's revisions for an optimised degrading implementation.
The values returned by element.getBoundingClientRect() are relative to the viewport. If you need it relative to another element, simply subtract one rectangle from the other:
var bodyRect = document.body.getBoundingClientRect(),
elemRect = element.getBoundingClientRect(),
offset = elemRect.top - bodyRect.top;
alert('Element is ' + offset + ' vertical pixels from <body>');
This function returns an element's position relative to the whole document (page):
function getOffset(el) {
const rect = el.getBoundingClientRect();
return {
left: rect.left + window.scrollX,
top: rect.top + window.scrollY
};
}
Using this we can get the X position:
getOffset(element).left
... or the Y position:
getOffset(element).top
The libraries go to some lengths to get accurate offsets for an element.
here's a simple function that does the job in every circumstances that I've tried.
function getOffset( el ) {
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) ) {
_x += el.offsetLeft - el.scrollLeft;
_y += el.offsetTop - el.scrollTop;
el = el.offsetParent;
}
return { top: _y, left: _x };
}
var x = getOffset( document.getElementById('yourElId') ).left;
If you want it done only in javascript, here are some one liners using getBoundingClientRect()
window.scrollY + document.querySelector('#elementId').getBoundingClientRect().top // Y
window.scrollX + document.querySelector('#elementId').getBoundingClientRect().left // X
The first line will return offsetTop say Y relative to document.
The second line will return offsetLeft say X relative to document.
getBoundingClientRect() is a javascript function that returns the position of the element relative to viewport of window.
HTML elements on most browsers will have:-
offsetLeft
offsetTop
These specifiy the position of the element relative its nearest parent that has layout. This parent can often be accessed bif the offsetParent property.
IE and FF3 have
clientLeft
clientTop
These properties are less common, they specify an elements position with its parents client area (padded area is part of the client area but border and margin is not).
If page includes - at least- any "DIV", the function given by meouw throws the "Y" value beyond current page limits. In order to find the exact position, you need to handle both offsetParent's and parentNode's.
Try the code given below (it is checked for FF2):
var getAbsPosition = function(el){
var el2 = el;
var curtop = 0;
var curleft = 0;
if (document.getElementById || document.all) {
do {
curleft += el.offsetLeft-el.scrollLeft;
curtop += el.offsetTop-el.scrollTop;
el = el.offsetParent;
el2 = el2.parentNode;
while (el2 != el) {
curleft -= el2.scrollLeft;
curtop -= el2.scrollTop;
el2 = el2.parentNode;
}
} while (el.offsetParent);
} else if (document.layers) {
curtop += el.y;
curleft += el.x;
}
return [curtop, curleft];
};
You can add two properties to Element.prototype to get the top/left of any element.
Object.defineProperty( Element.prototype, 'documentOffsetTop', {
get: function () {
return this.offsetTop + ( this.offsetParent ? this.offsetParent.documentOffsetTop : 0 );
}
} );
Object.defineProperty( Element.prototype, 'documentOffsetLeft', {
get: function () {
return this.offsetLeft + ( this.offsetParent ? this.offsetParent.documentOffsetLeft : 0 );
}
} );
This is called like this:
var x = document.getElementById( 'myDiv' ).documentOffsetLeft;
Here's a demo comparing the results to jQuery's offset().top and .left: http://jsfiddle.net/ThinkingStiff/3G7EZ/
To retrieve the position relative to the page efficiently, and without using a recursive function: (includes IE also)
var element = document.getElementById('elementId'); //replace elementId with your element's Id.
var rect = element.getBoundingClientRect();
var elementLeft,elementTop; //x and y
var scrollTop = document.documentElement.scrollTop?
document.documentElement.scrollTop:document.body.scrollTop;
var scrollLeft = document.documentElement.scrollLeft?
document.documentElement.scrollLeft:document.body.scrollLeft;
elementTop = rect.top+scrollTop;
elementLeft = rect.left+scrollLeft;
How about something like this, by passing ID of the element and it will return the left or top, we can also combine them:
1) find left
function findLeft(element) {
var rec = document.getElementById(element).getBoundingClientRect();
return rec.left + window.scrollX;
} //call it like findLeft('#header');
2) find top
function findTop(element) {
var rec = document.getElementById(element).getBoundingClientRect();
return rec.top + window.scrollY;
} //call it like findTop('#header');
or 3) find left and top together
function findTopLeft(element) {
var rec = document.getElementById(element).getBoundingClientRect();
return {top: rec.top + window.scrollY, left: rec.left + window.scrollX};
} //call it like findTopLeft('#header');
Here's a modern 1-liner using vanilla JS to recursively iterate over element.offsetTop and element.offsetParent:
Function:
getTop = el => el.offsetTop + (el.offsetParent && getTop(el.offsetParent))
Usage:
const el = document.querySelector('#div_id');
const elTop = getTop(el)
Advantage:
Always returns the absolute vertical offset, regardless of the current scroll position.
Traditional syntax:
function getTop(el) {
return el.offsetTop + (el.offsetParent && getTop(el.offsetParent));
}
jQuery .offset() will get the current coordinates of the first element, or set the coordinates of every element, in the set of matched elements, relative to the document.
Update:
The recursion approach (in my old answer) creates many call stacks. We can use a while loop to avoid recursion in this case:
/**
*
* #param {HTMLElement} el
* #return {{top: number, left: number}}
*/
function getDocumentOffsetPosition(el) {
let top = 0, left = 0;
while (el !== null) {
top += el.offsetTop;
left += el.offsetLeft;
el = el.offsetParent;
}
return {top, left};
}
Old answer:
/**
*
* #param {HTMLElement} el
* #return {{top: number, left: number}}
*/
function getDocumentOffsetPosition(el) {
var position = {
top: el.offsetTop,
left: el.offsetLeft
};
if (el.offsetParent) {
var parentPosition = getDocumentOffsetPosition(el.offsetParent);
position.top += parentPosition.top;
position.left += parentPosition.left;
}
return position;
}
Thank ThinkingStiff for the answer, this is only another version.
You might be better served by using a JavaScript framework, that has functions to return such information (and so much more!) in a browser-independant fashion. Here are a few:
Prototype
jQuery
MooTools
YUI (yahoo)
With these frameworks, you could do something like:
$('id-of-img').top
to get the y-pixel coordinate of the image.
I've taken #meouw's answer, added in the clientLeft that allows for the border, and then created three versions:
getAbsoluteOffsetFromBody - similar to #meouw's, this gets the absolute position relative to the body or html element of the document (depending on quirks mode)
getAbsoluteOffsetFromGivenElement - returns the absolute position relative to the given element (relativeEl). Note that the given element must contain the element el, or this will behave the same as getAbsoluteOffsetFromBody. This is useful if you have two elements contained within another (known) element (optionally several nodes up the node tree) and want to make them the same position.
getAbsoluteOffsetFromRelative - returns the absolute position relative to the first parent element with position: relative. This is similar to getAbsoluteOffsetFromGivenElement, for the same reason but will only go as far as the first matching element.
getAbsoluteOffsetFromBody = function( el )
{ // finds the offset of el from the body or html element
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) )
{
_x += el.offsetLeft - el.scrollLeft + el.clientLeft;
_y += el.offsetTop - el.scrollTop + el.clientTop;
el = el.offsetParent;
}
return { top: _y, left: _x };
}
getAbsoluteOffsetFromGivenElement = function( el, relativeEl )
{ // finds the offset of el from relativeEl
var _x = 0;
var _y = 0;
while( el && el != relativeEl && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) )
{
_x += el.offsetLeft - el.scrollLeft + el.clientLeft;
_y += el.offsetTop - el.scrollTop + el.clientTop;
el = el.offsetParent;
}
return { top: _y, left: _x };
}
getAbsoluteOffsetFromRelative = function( el )
{ // finds the offset of el from the first parent with position: relative
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) )
{
_x += el.offsetLeft - el.scrollLeft + el.clientLeft;
_y += el.offsetTop - el.scrollTop + el.clientTop;
el = el.offsetParent;
if (el != null)
{
if (getComputedStyle !== 'undefined')
valString = getComputedStyle(el, null).getPropertyValue('position');
else
valString = el.currentStyle['position'];
if (valString === "relative")
el = null;
}
}
return { top: _y, left: _x };
}
If you are still having problems, particularly relating to scrolling, you could try looking at http://www.greywyvern.com/?post=331 - I noticed at least one piece of questionable code in getStyle which should be fine assuming browsers behave, but haven't tested the rest at all.
Difference between small and little
function getPosition( el ) {
var x = 0;
var y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) ) {
x += el.offsetLeft - el.scrollLeft;
y += el.offsetTop - el.scrollTop;
el = el.offsetParent;
}
return { top: y, left: x };
}
Look a example coordinates:
http://javascript.info/tutorial/coordinates
If you are using jQuery, this could be a simple solution:
<script>
var el = $("#element");
var position = el.position();
console.log( "left: " + position.left + ", top: " + position.top );
</script>
if using jQuery, the dimensions plugin is excellent and allows you specify exactly what you want.
e.g.
Relative position, absolute position, absolute position without padding, with padding...
It goes on, let's just say there is a lot you can do with it.
Plus the bonus of using jQuery is it's lightweight file size and easy use, you won't go back to JavaScript without it afterwards.
The cleanest approach I have found is a simplified version of the technique used by jQuery's offset. Similar to some of the other answers it starts with getBoundingClientRect; it then uses the window and the documentElement to adjust for scroll position as well as things like the margin on the body (often the default).
var rect = el.getBoundingClientRect();
var docEl = document.documentElement;
var rectTop = rect.top + window.pageYOffset - docEl.clientTop;
var rectLeft = rect.left + window.pageXOffset - docEl.clientLeft;
var els = document.getElementsByTagName("div");
var docEl = document.documentElement;
for (var i = 0; i < els.length; i++) {
var rect = els[i].getBoundingClientRect();
var rectTop = rect.top + window.pageYOffset - docEl.clientTop;
var rectLeft = rect.left + window.pageXOffset - docEl.clientLeft;
els[i].innerHTML = "<b>" + rectLeft + ", " + rectTop + "</b>";
}
div {
width: 100px;
height: 100px;
background-color: red;
border: 1px solid black;
}
#rel {
position: relative;
left: 10px;
top: 10px;
}
#abs {
position: absolute;
top: 250px;
left: 250px;
}
<div id="rel"></div>
<div id="abs"></div>
<div></div>
To get the total offset of an element, you could recursively sum up all parent offsets:
function getParentOffset(el): number {
if (el.offsetParent) {
return el.offsetParent.offsetTop + getParentOffset(el.offsetParent);
} else {
return 0;
}
}
with this utility function the total top offset of a dom element is:
el.offsetTop + getParentOffset(el);
This is the best code I've managed to create (works in iframes as well, unlike jQuery's offset()). Seems webkit has a bit of a different behavior.
Based on meouw's comment:
function getOffset( el ) {
var _x = 0;
var _y = 0;
while( el && !isNaN( el.offsetLeft ) && !isNaN( el.offsetTop ) ) {
_x += el.offsetLeft - el.scrollLeft;
_y += el.offsetTop - el.scrollTop;
// chrome/safari
if ($.browser.webkit) {
el = el.parentNode;
} else {
// firefox/IE
el = el.offsetParent;
}
}
return { top: _y, left: _x };
}
While this is very likely to be lost at the bottom of so many answers, the top solutions here were not working for me.
As far as I could tell neither would any of the other answers have helped.
Situation:
In an HTML5 page I had a menu that was a nav element inside a header (not THE header but a header in another element).
I wanted the navigation to stick to the top once a user scrolled to it, but previous to this the header was absolute positioned (so I could have it overlay something else slightly).
The solutions above never triggered a change because .offsetTop was not going to change as this was an absolute positioned element. Additionally the .scrollTop property was simply the top of the top most element... that is to say 0 and always would be 0.
Any tests I performed utilizing these two (and same with getBoundingClientRect results) would not tell me if the top of the navigation bar ever scrolled to the top of the viewable page (again, as reported in console, they simply stayed the same numbers while scrolling occurred).
Solution
The solution for me was utilizing
window.visualViewport.pageTop
The value of the pageTop property reflects the viewable section of the screen, therefore allowing me to track where an element is in reference to the boundaries of the viewable area.
Probably unnecessary to say, anytime I am dealing with scrolling I expect to use this solution to programatically respond to movement of elements being scrolled.
Hope it helps someone else.
IMPORTANT NOTE: This appears to work in Chrome and Opera currently & definitely not in Firefox (6-2018)... until Firefox supports visualViewport I recommend NOT using this method, (and I hope they do soon... it makes a lot more sense than the rest).
UPDATE:
Just a note regarding this solution. While I still find what I discovered to be very valuable for situations in which "...programmatically respond to movement of elements being scrolled." is applicable. The better solution for the problem that I had was to use CSS to set position: sticky on the element. Using sticky you can have an element stay at the top without using javascript (NOTE: there are times this will not work as effectively as changing the element to fixed but for most uses the sticky approach will likely be superior)
UPDATE01:
So I realized that for a different page I had a requirement where I needed to detect the position of an element in a mildly complex scrolling setup (parallax plus elements that scroll past as part of a message).
I realized in that scenario that the following provided the value I utilized to determine when to do something:
let bodyElement = document.getElementsByTagName('body')[0];
let elementToTrack = bodyElement.querySelector('.trackme');
trackedObjPos = elementToTrack.getBoundingClientRect().top;
if(trackedObjPos > 264)
{
bodyElement.style.cssText = '';
}
Hope this answer is more widely useful now.
I did it like this so it was cross-compatible with old browsers.
// For really old browser's or incompatible ones
function getOffsetSum(elem) {
var top = 0,
left = 0,
bottom = 0,
right = 0
var width = elem.offsetWidth;
var height = elem.offsetHeight;
while (elem) {
top += elem.offsetTop;
left += elem.offsetLeft;
elem = elem.offsetParent;
}
right = left + width;
bottom = top + height;
return {
top: top,
left: left,
bottom: bottom,
right: right,
}
}
function getOffsetRect(elem) {
var box = elem.getBoundingClientRect();
var body = document.body;
var docElem = document.documentElement;
var scrollTop = window.pageYOffset || docElem.scrollTop || body.scrollTop;
var scrollLeft = window.pageXOffset || docElem.scrollLeft || body.scrollLeft;
var clientTop = docElem.clientTop;
var clientLeft = docElem.clientLeft;
var top = box.top + scrollTop - clientTop;
var left = box.left + scrollLeft - clientLeft;
var bottom = top + (box.bottom - box.top);
var right = left + (box.right - box.left);
return {
top: Math.round(top),
left: Math.round(left),
bottom: Math.round(bottom),
right: Math.round(right),
}
}
function getOffset(elem) {
if (elem) {
if (elem.getBoundingClientRect) {
return getOffsetRect(elem);
} else { // old browser
return getOffsetSum(elem);
}
} else
return null;
}
More about coordinates in JavaScript here: http://javascript.info/tutorial/coordinates
HTML program to show (x, y) of an
element by dragging mouse over it you just copied it and use it on your own
<!DOCTYPE html>
<html>
<head>
<title>
position of an element
</title>
<!-- scropt to get position -->
<script type = "text/javascript">
function getPositionXY(element) {
var rect = element.getBoundingClientRect();
document.getElementById('text').innerHTML
= 'X: ' + rect.x + '<br>' + 'Y: ' + rect.y;
}
</script>
</head>
<body>
<p>Move the mouse over the text</p>
<div onmouseover = "getPositionXY(this)">
Position:
<p id = 'text'></p>
</div>
</body>
</html>
i could just like element.offsetLeft or element.offsetTop. Example :
document.getElementById('profileImg').offsetLeft
I successfully used Andy E's solution to position a bootstrap 2 modal depending on what link in a table row a user clicks on. The page is a Tapestry 5 page and javascript below is imported in the java page class.
javascript:
function setLinkPosition(clientId){
var bodyRect = document.body.getBoundingClientRect(),
elemRect = clientId.getBoundingClientRect(),
offset = elemRect.top - bodyRect.top;
offset = offset + 20;
$('#serviceLineModal').css("top", offset);
}
My modal code:
<div id="serviceLineModal" class="modal hide fade add-absolute-position" data-backdrop="static"
tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true" style="top:50%;">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">x</button>
<h3 id="myModalLabel">Modal header</h3>
</div>
<div class="modal-body">
<t:zone t:id="modalZone" id="modalZone">
<p>You selected service line number: ${serviceLineNumberSelected}</p>
</t:zone>
</div>
<div class="modal-footer">
<button class="btn" data-dismiss="modal" aria-hidden="true">Close</button>
<!-- <button class="btn btn-primary">Save changes</button> -->
</div>
The link in the loop:
<t:loop source="servicesToDisplay" value="service" encoder="encoder">
<tr style="border-right: 1px solid black;">
<td style="white-space:nowrap;" class="add-padding-left-and-right no-border">
<a t:type="eventLink" t:event="serviceLineNumberSelected" t:context="service.serviceLineNumber"
t:zone="pageZone" t:clientId="modalLink${service.serviceLineNumber}"
onmouseover="setLinkPosition(this);">
<i class="icon-chevron-down"></i> <!-- ${service.serviceLineNumber} -->
</a>
</td>
And the java code in the page class:
void onServiceLineNumberSelected(String number){
checkForNullSession();
serviceLineNumberSelected = number;
addOpenServiceLineDialogCommand();
ajaxResponseRenderer.addRender(modalZone);
}
protected void addOpenServiceLineDialogCommand() {
ajaxResponseRenderer.addCallback(new JavaScriptCallback() {
#Override
public void run(JavaScriptSupport javascriptSupport) {
javascriptSupport.addScript("$('#serviceLineModal').modal('show');");
}
});
}
Hope this helps someone, this post helped out.
After much research and testing this seems to work
function getPosition(e) {
var isNotFirefox = (navigator.userAgent.toLowerCase().indexOf('firefox') == -1);
var x = 0, y = 0;
while (e) {
x += e.offsetLeft - e.scrollLeft + (isNotFirefox ? e.clientLeft : 0);
y += e.offsetTop - e.scrollTop + (isNotFirefox ? e.clientTop : 0);
e = e.offsetParent;
}
return { x: x + window.scrollX, y: y + window.scrollY };
}
see http://jsbin.com/xuvovalifo/edit?html,js,output
Just thought I'd throw this out there as well.
I haven't been able to test it in older browsers, but it works in the latest of the top 3. :)
Element.prototype.getOffsetTop = function() {
return ( this.parentElement )? this.offsetTop + this.parentElement.getOffsetTop(): this.offsetTop;
};
Element.prototype.getOffsetLeft = function() {
return ( this.parentElement )? this.offsetLeft + this.parentElement.getOffsetLeft(): this.offsetLeft;
};
Element.prototype.getOffset = function() {
return {'left':this.getOffsetLeft(),'top':this.getOffsetTop()};
};
This is easy as two lines in JS :
var elem = document.getElementById("id");
alert(elem.getBoundingClientRect());
Since different browsers are rendering border, padding, margin and etc in different way. I wrote a little function to retrieve top and left positions of specific element in every root element that you want in precise dimension:
function getTop(root, offset) {
var rootRect = root.getBoundingClientRect();
var offsetRect = offset.getBoundingClientRect();
return offsetRect.top - rootRect.top;
}
For retrieve left position you must return:
return offsetRect.left - rootRect.left;
Get position of div in respect to left and Top
var elm = $('#div_id'); //get the div
var posY_top = elm.offset().top; //get the position from top
var posX_left = elm.offset().left; //get the position from left
I'm making a scheduling calendar. The events are horizontal blocks (Google Cal has vertical ones). And because I have loads of events in one date I want the events to stack onto eachother without wasting any space, like this:
I did find plugins:
http://masonry.desandro.com/
http://isotope.metafizzy.co/
http://packery.metafizzy.co/
But I'm not keen on using a 30kb plugin just to do this simple thing.
To clarify: because this is a timeline, the div-events cannot move left/right, but must fit itself vertically amongst other div-events.
My own solution is a 2.6kb (commented) jQuery script, that uses absolute positioning for events and a div as a container for each row.
This script generates randomly size bars. Each new bar checks for space in each row from top-down. I'm using percentages, because that way calculating bar position against time will be easy (100% / 24h).
http://jsfiddle.net/cj23H/5/
Though works and is efficient enough, it feels bulky. You're welcome to improve.
jQuery code from my jsfiddle:
function rand() {
return Math.floor(Math.random() * 101);
}
function get_target_row(width, left) {
var i = 0;
var target_found = false;
// Loop through all the rows to see if there's space anywhere
while (target_found === false) {
// Define current row selector
var target_i = '.personnel#row' + i;
// Add row if none
if ($(target_i).length === 0) {
$('body').append('<div class="personnel" id="row' + i + '"></div>');
}
// See if there's space
if ($(target_i).children().length === 0) {
target_found = $(target_i);
} else {
var spaceFree = false;
// Check collision for each child
$(target_i).children().each(function () {
// Get left and right coordinates
var thisWidthPx = parseFloat($(this).css('width'), 10);
var thisWidthParentPx = parseFloat($(this).parent().css('width'), 10);
var thisWidth = (thisWidthPx / thisWidthParentPx * 100);
var thisLeftPx = parseFloat($(this).css('left'), 10);
var thisLeftParentPx = parseFloat($(this).parent().css('left'), 10);
var thisLeft = (thisLeftPx / thisWidthParentPx * 100);
var thisRight = thisLeft + thisWidth;
var right = left + width;
// Sexy way for checking collision
if ((right > thisLeft && right < thisRight) || (left < thisRight && left > thisLeft) || (thisLeft > left && thisLeft < right) || (thisRight < right && thisRight > left)) {
spaceFree = false;
return false;
} else {
spaceFree = true;
}
});
// If no children have collided break the loop
if (spaceFree === true) {
target_found = $(target_i);
}
}
i++;
}
// If after all the while loops target is still not found...
if (target_found === false) {
return false;
}
// Else, if target is found, return it.
return target_found;
}
// Generate random bars
for (var i = 0; i < 10; i++) {
var width = rand()/2;
var left = rand()/2;
var right = left + width;
var target = get_target_row(width, left);
target.append('<div class="block" style="width:' + width + '%;position:absolute;left:' + left + '%;background-color:rgba(' + rand() + ',' + rand() + ',' + rand() + ',0.4)" id="bar'+i+'">' + 'b' + i + '</div>');
}
CSS:
.block {
position: absolute;
background-color: rgba(200, 100, 100, 0.4);
height: 32px;
}
.personnel {
position: relative;
float: left;
width: 100%;
height: 33px;
}
How to get an DOM Element [x,y] coordinates in javascript?
Specifically, the coordinates of a button inside a scrollbox.
I found this offsetLeft attribute:
var elements = scroll.children; // with 12 children
if (!elements.item(2)) {
print("no element");
}
else if (!elements.item(2).offsetLeft) {
print("no attribute");
}
else {
print(elements.item(2).offsetLeft);
}
but it's printing "no attribute"...
By the way, it's for Mozilla environment.
Try something like this:
// Based on code from http://www.quirksmode.org/js/findpos.html
function FindElementDocumentPosition(element) {
var left = 0;
var top = 0;
var lastElement = element;
if (element.offsetParent) {
left += element.offsetLeft;
top += element.offsetTop;
element = element.offsetParent;
while (element) {
left += element.offsetLeft;
top += element.offsetTop;
left -= element.scrollLeft;
top -= element.scrollTop;
lastElement = element;
element = element.offsetParent;
}
}
// Adjust for document scroll position
var agent = navigator.userAgent.toLowerCase();
if (!PageInStandardsMode() || (agent.indexOf('firefox') == -1)) {
var leftAdjust = document.body.scrollLeft || document.documentElement.scrollLeft;
var topAdjust = document.body.scrollTop || document.documentElement.scrollTop;
left += leftAdjust;
top += topAdjust;
}
return {
x: left,
y: top
};
}
I want to get the position of an element relative to the browser's viewport (the viewport in which the page is displayed, not the whole page). How can this be done in JavaScript?
Many thanks
The existing answers are now outdated. The native getBoundingClientRect() method has been around for quite a while now, and does exactly what the question asks for. Plus it is supported across all browsers (including IE 5, it seems!)
From MDN page:
The returned value is a TextRectangle object, which contains read-only left, top, right and bottom properties describing the border-box, in pixels, with the top-left relative to the top-left of the viewport.
You use it like so:
var viewportOffset = el.getBoundingClientRect();
// these are relative to the viewport, i.e. the window
var top = viewportOffset.top;
var left = viewportOffset.left;
On my case, just to be safe regarding scrolling, I added the window.scroll to the equation:
var element = document.getElementById('myElement');
var topPos = element.getBoundingClientRect().top + window.scrollY;
var leftPos = element.getBoundingClientRect().left + window.scrollX;
That allows me to get the real relative position of element on document, even if it has been scrolled.
var element = document.querySelector('selector');
var bodyRect = document.body.getBoundingClientRect(),
elemRect = element.getBoundingClientRect(),
offset = elemRect.top - bodyRect.top;
Edit: Add some code to account for the page scrolling.
function findPos(id) {
var node = document.getElementById(id);
var curtop = 0;
var curtopscroll = 0;
if (node.offsetParent) {
do {
curtop += node.offsetTop;
curtopscroll += node.offsetParent ? node.offsetParent.scrollTop : 0;
} while (node = node.offsetParent);
alert(curtop - curtopscroll);
}
}
The id argument is the id of the element whose offset you want. Adapted from a quirksmode post.
jQuery implements this quite elegantly. If you look at the source for jQuery's offset, you'll find this is basically how it's implemented:
var rect = elem.getBoundingClientRect();
var win = elem.ownerDocument.defaultView;
return {
top: rect.top + win.pageYOffset,
left: rect.left + win.pageXOffset
};
function inViewport(element) {
let bounds = element.getBoundingClientRect();
let viewWidth = document.documentElement.clientWidth;
let viewHeight = document.documentElement.clientHeight;
if (bounds['left'] < 0) return false;
if (bounds['top'] < 0) return false;
if (bounds['right'] > viewWidth) return false;
if (bounds['bottom'] > viewHeight) return false;
return true;
}
source
The function on this page will return a rectangle with the top, left, height and width co ordinates of a passed element relative to the browser view port.
localToGlobal: function( _el ) {
var target = _el,
target_width = target.offsetWidth,
target_height = target.offsetHeight,
target_left = target.offsetLeft,
target_top = target.offsetTop,
gleft = 0,
gtop = 0,
rect = {};
var moonwalk = function( _parent ) {
if (!!_parent) {
gleft += _parent.offsetLeft;
gtop += _parent.offsetTop;
moonwalk( _parent.offsetParent );
} else {
return rect = {
top: target.offsetTop + gtop,
left: target.offsetLeft + gleft,
bottom: (target.offsetTop + gtop) + target_height,
right: (target.offsetLeft + gleft) + target_width
};
}
};
moonwalk( target.offsetParent );
return rect;
}
You can try:
node.offsetTop - window.scrollY
It works on Opera with viewport meta tag defined.
I am assuming an element having an id of btn1 exists in the web page, and also that jQuery is included. This has worked across all modern browsers of Chrome, FireFox, IE >=9 and Edge.
jQuery is only being used to determine the position relative to document.
var screenRelativeTop = $("#btn1").offset().top - (window.scrollY ||
window.pageYOffset || document.body.scrollTop);
var screenRelativeLeft = $("#btn1").offset().left - (window.scrollX ||
window.pageXOffset || document.body.scrollLeft);
Thanks for all the answers. It seems Prototype already has a function that does this (the page() function). By viewing the source code of the function, I found that it first calculates the element offset position relative to the page (i.e. the document top), then subtracts the scrollTop from that. See the source code of prototype for more details.
Sometimes getBoundingClientRect() object's property value shows 0 for IE. In that case you have to set display = 'block' for the element. You can use below code for all browser to get offset.
Extend jQuery functionality :
(function($) {
jQuery.fn.weOffset = function () {
var de = document.documentElement;
$(this).css("display", "block");
var box = $(this).get(0).getBoundingClientRect();
var top = box.top + window.pageYOffset - de.clientTop;
var left = box.left + window.pageXOffset - de.clientLeft;
return { top: top, left: left };
};
}(jQuery));
Use :
var elementOffset = $("#" + elementId).weOffset();
Based on Derek's answer.
/**
* Gets element's x position relative to the visible viewport.
*/
function getAbsoluteOffsetLeft(el) {
let offset = 0;
let currentElement = el;
while (currentElement !== null) {
offset += currentElement.offsetLeft;
offset -= currentElement.scrollLeft;
currentElement = currentElement.offsetParent;
}
return offset;
}
/**
* Gets element's y position relative to the visible viewport.
*/
function getAbsoluteOffsetTop(el) {
let offset = 0;
let currentElement = el;
while (currentElement !== null) {
offset += currentElement.offsetTop;
offset -= currentElement.scrollTop;
currentElement = currentElement.offsetParent;
}
return offset;
}
Here is something for Angular2 +. Tested on version 13
event.srcElement.getBoundingClientRect().top;