How I can add to my anchor links a class?
My html code looks like this:
<div class="et_pb_blurb_content">
<div class="et_pb_main_blurb_image">
<a href="video.mp4">
<span class="et_pb_image_wrap">
<img loading="lazy" width="128" height="128" src="2021/02/cover.png" alt="" class="et-waypoint et_pb_animation_off wp-image-17" />
</span>
</a>
</div>
<div class="et_pb_blurb_container">
<h4 class="et_pb_module_header">
Watch
</h4>
</div>
</div>
With javascript code I want achieve like this it adds anchor links class:
<div class="et_pb_blurb_content">
<div class="et_pb_main_blurb_image">
<a href="video.mp4" class="vp-a">
<span class="et_pb_image_wrap">
<img loading="lazy" width="128" height="128" src="2021/02/cover.png" alt="" class="et-waypoint et_pb_animation_off wp-image-17" />
</span>
</a>
</div>
<div class="et_pb_blurb_container">
<h4 class="et_pb_module_header">
Watch
</h4>
</div>
</div>
I use wordpress divi theme and there is not possible add class to anchor video links
Could use something like below:
// grab all the parent items by classname
const linkParents = document.querySelectorAll('.et_pb_module_header');
// iterate over parents
[...linkParents].forEach((parent) => {
// grab the anchor tag from the parent
const link = parent.querySelector('a');
// add your classname to the anchor tag
link.classList.add('vp-a');
});
Related
I'm a trainee and actually I'm working on a web shop.
Now I got the problem that I have multiple images placeholders (image_1-6) for our article images. Problem now is, if the article only has 2 images the placeholders for the other 4 are still there. So is there any possibility to hide them if the src is empty or a parameter defined by me?
Here is the code snippet:
<div class="sideimg grid_2">
<div id="image_1" class="lb_thumb">
<a href="javascript:;" onmouseover="swapImage('Bild1','','http://media-11teamsports.de/ArticleBig/[ArtikelOnlinebezeichnungD.Bild1]',1)" onmouseout="swapImgRestore()">
<img class="lb_detailimg" src="http://media-11teamsports.de/ArticleSmall/[ArtikelOnlinebezeichnungD.Bild1]"id=image1 name="Bild1" alt="Bild1" id="Bild2" />
</a>
</div>
<div id="image_2" class="lb_thumb">
<a href="javascript:;" onmouseover="swapImage('Bild1','','http://media-11teamsports.de/ArticleBig/[ArtikelOnlinebezeichnungD.Bild2]',1)" onmouseout="swapImgRestore()">
<img class="lb_detailimg" src="http://media-11teamsports.de/ArticleSmall/[ArtikelOnlinebezeichnungD.Bild2]" id=image2 name="Bild2" alt="Bild2" id="Bild2" />
</a>
</div>
<div id="image_3" class="lb_thumb">
<a href="javascript:;" onmouseover="swapImage('Bild1','','http://media-11teamsports.de/ArticleBig/[ArtikelOnlinebezeichnungD.Bild3]',1)" onmouseout="swapImgRestore()">
<img class="lb_detailimg" src="http://media-11teamsports.de/ArticleSmall/[ArtikelOnlinebezeichnungD.Bild3]" id=image3 name="Bild3" alt="Bild3" id="Bild2" />
</a>
</div>
<div id="image_4" class="lb_thumb">
<a href="javascript:;" onmouseover="swapImage('Bild1','','http://media-11teamsports.de/ArticleBig/[ArtikelOnlinebezeichnungD.Bild4]',1)" onmouseout="swapImgRestore()">
<img class="lb_detailimg" src="http://media-11teamsports.de/ArticleSmall/[ArtikelOnlinebezeichnungD.Bild4]" id=image4 name="Bild4" alt="Bild4" id="Bild2" />
</a>
</div>
<div id="image_5" class="lb_thumb">
<a href="javascript:;" onmouseover="swapImage('Bild1','','http://media-11teamsports.de/ArticleBig/[ArtikelOnlinebezeichnungD.Bild5]',1)" onmouseout="swapImgRestore()">
<img class="lb_detailimg" src="http://media-11teamsports.de/ArticleSmall/[ArtikelOnlinebezeichnungD.Bild5]" id=image5 name="Bild5" alt="Bild5" id="Bild2" />
</a>
</div>
<div id="image_6" class="lb_thumb">
<a href="javascript:;" onmouseover="swapImage('Bild1','','http://media-11teamsports.de/ArticleBig/[ArtikelOnlinebezeichnungD.Bild6]',1)" onmouseout="swapImgRestore()">
<img class="lb_detailimg" src="http://media-11teamsports.de/ArticleSmall/[ArtikelOnlinebezeichnungD.Bild6]" id=image6 name="Bild6" alt="Bild6" id="Bild2" />
</a>
</div>
</div>
Here is the live version(wip): http://www.ebay.de/itm/Jako-Tape-10-Meter-2-5-cm-breit-Rot-F01-/272269970423?
All I know about html css and js I learned by myself so I hope the snippet is fine.
So as you can see I have 6 images with js image swap. The only left problem is that our database don't contains an image for every placeholder, so if there are only 4 pictures there are still 2 empty boxes. So how can i get rid of them?
Thanks all for your help and excuse my english I'm from Germany.
You can try using the CSS selector for html attributes like this:
.lb_detailimg[src]{
(Whatever css u need goes here)
display: block;
}
.lb_detailimg{
display: none;
}
If any <img> of class lb_detailimg does not have a src attribute it will not be displayed.
You could also use a keyword in the src attribute to make this happen, like this:
.lb_detailimg{
(Whatever css u need goes here)
}
.lb_detailimg[src=keyword]{
display: none;
}
EDIT:
As you cannot give style to a parent element in CSS here is a JS snippet that should work fine:
window.onload = function(){
var img_containers = document.getElementsByClassName("lb_thumb");
for(var i=0; i<img_containers.length;i++){
if(img_containers[i].getElementsByTagName("img")[0].src.indexOf("keyword") > -1){
img_containers[i].style.display = "none";
}
}
}
At line 4 in the if ==> .indexOf("yourKeyWordHere")
I am showing a set of products via shortcode in WordPress. The display has an image and button.
Problem: Only the photo contains the link to single product page. The associated button does not have the link to the single product page.
This is the current code:
<div class="display-products">
<div class="wpb_wrapper">
<div class="displayProduct-shortcode displayProduct-Container">
<div class="product_grid dp-section dp-group woocommerce" id="displayProduct">
<div class="dp_product_item dp-col dp-col_1_of_6 firstcol">
<div class="dp_images">
<a class="dp-product-image" title="Custom Made Wedding Cabinet" href="yahoo.com">
<div class="he-wrap tpl1">
<div class="dp-img-wrapper"> <img width="192" height="264" alt="#" class="attachment-display_product_thumbnail size-display_product_thumbnail wp-post-image" src="img_src"> </div>
</div> <span data-id="696" class="dpquickview dp_quickview_button"><img src="img_src"></span> </a>
</div>
<div class="dp-product-information clearfix">
<h2 class="product-name">
<a title="Custom Made Wedding Cabinet" href="#">Custom Made Wedding Cabinet</a>
</h2>
<div class="dp-stock"></div>
<div class="dp-grid-button"> <a class="single_add_to_cart_button button alt db_customButton" href="#">READ MORE</a> </div>
<div style="clear: both;"></div>
</div>
</div>
</div>
</div>
</div>
</div>
Desired Output: I want to somehow iterate over each .single_add_to_cart_button and copy the link of every product-name to each READ MORE button
This is my current jquery code:
j('.display-products .displayProduct-shortcode .dp-product-information .dp-grid-button .single_add_to_cart_button').each(function() {
var getProductLink = j('.display-products .displayProduct-shortcode .dp-product-information .product-name > a').attr('href');
j(this).attr('href', getProductLink);
});
Set the href attribute value using the elements context. Use closest() to traverse up to dp-product-information element then find the desired anchor element the read its attribute and set the value.
Use
j('.display-products .displayProduct-shortcode .dp-product-information .dp-grid-button .single_add_to_cart_button').attr('href', function(){
return j(this).closest('.dp-product-information').find('.product-name>a').attr('href');
});
$(function() {
$('.dp-product-information .dp-grid-button .single_add_to_cart_button').attr('href', function() {
return $(this).closest('.dp-product-information').find('.product-name > a').attr('href');
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="dp-product-information clearfix">
<h2 class="product-name">
<a title="Custom Made Wedding Cabinet" href="#Test">Custom Made Wedding Cabinet</a>
</h2>
<div class="dp-stock"></div>
<div class="dp-grid-button">
<a class="single_add_to_cart_button button alt db_customButton" href="#">READ MORE</a>
</div>
<div style="clear: both;"></div>
</div>
Instead of assigning value for the different buttons with the links I would like to suggest you to use a common class (if you can) then trigger the click event for them:
$('.selector').on('click',function(){
$('.a-selector').trigger('click');
});
When storing DOM elements in a javascript variable prior to appending them to the actual DOM is there a way with jQuery to select elements inside the variable?
For example,
I have a list of tweets on my page. Every time I click a refresh button I append a new tweet to the list below.
I add the new tweet like follows:
new tweet
<li class="tweet normal-tweet" data-user-name="Dorothy">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=Dorothy" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/Dorothy" title="Dorothy">Dorothy</a>
<div class="full-name"></div>
</div>
<div class="text">Once in a lullaby</div>
<div class="time-stamp" data-time="1322631934000">1322631934000</div>
</div>
</li>
Inside each tweet on the page, not the new tweet yet, I use jQuery to append some elements.
I have:
var actionsMarkup =
"<div class='actions'>
<span class='favorite'>Favorite</span>
<span class='retweet'>Retweet</span>
<span class='reply'>Reply</span>
</div>";
and I append it to the element with the .content class
$(actionsMarkup).appendTo('#tweets .tweet .content');
Now, when I make a new tweet I do the following:
$(document).on('click', '.refresh', function() {
newTweet = $(<new tweet code from above>);
actionsMark = $(actionsMarkup);
$(newTweet.appendTo('#tweets');
I need to be able to append the actionsMark contents to the div with class .content. However, I can't just reapply my prior statement of
$(actionsMarkup).appendTo('#tweets .tweet .content');
because that puts the markup on all .content divs again, even if it is already there.
Is there a way for me to use selectors to access the DOM nodes in my newTweet variable before I append it to the document object?
I am thinking something like
$(actionsMarkup).appendTo( newTweet, '.content');
If there is no way with selectors to do this then what are some other quick ways?
List of Tweets and Tweet container
<ul id="tweets" class="normal-tweet show-promoted-tweets">
<li class="tweet promoted-tweet" data-user-name="Dorothy">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=Dorothy" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/Dorothy" title="Dorothy">Dorothy</a>
<div class="full-name">Dorothy</div>
</div>
<div class="text">Somewhere over the rainbow</div>
<div class="time-stamp" data-time="1322631934000">3 minutes ago</div>
</div>
</li>
<li class="tweet promoted-tweet" data-user-name="lion">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=lion" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/lion" title="lion">lion</a>
<div class="full-name">Lion</div>
</div>
<div class="text">Way up high,</div>
<div class="time-stamp" data-time="1322631934000">17 minutes ago</div>
</div>
</li>
<li class="tweet normal-tweet" data-user-name="scarecrow">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=scarecrow" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/scarecrow" title="scarecrow">scarecrow</a>
<div class="full-name">Scarecrow</div>
</div>
<div class="text">And the dreams that you dreamed of,</div>
<div class="time-stamp" data-time="1322631934000">32 minutes ago</div>
</div>
</li>
</ul>
You can use .last(), to select the last element after you append your new tweet, like below:
$(document).on('click', '.refresh', function() {
newTweet = $(<new tweet code from above>);
$(newTweet).appendTo('#tweets');
var actionsMarkup =
"<div class='actions'>
<span class='favorite'>Favorite</span>
<span class='retweet'>Retweet</span>
<span class='reply'>Reply</span>
</div>";
$("#tweets .tweet").last().find(".content").append(actionsMarkup);
});
if you insist to use appendTo(), you can try using :last-child:
$(actionsMarkup).appendTo('#tweets .tweet:last-child .content');
I was looking to see if you can do the same thing, found this question but the existing answer is not useful in my case as i would like to alter the element before adding.
You can create a new dom element in a variable with jQuery and do operations on it as if it is already in the dom before appending it.
Example:
var newTweet = $('<div></div>');
newTweet.addClass('tweet');
newTweet.append('<span class="username"></span>');
newTweet.find('span.username').html('John Doe');
$('body').append(newTweet);
the following will be appended to the body:
<div class="tweet"><span class="username">John Doe</span></div>
Very handy if you are building a reusable interface element (like a dialogue box) with multiple options.
I am new to jQuery and am trying to write a script that will run through a menu list and display the correct background image based on the menu item. The menu list is going to be randomly populated so a script is necessary to load the correct image.
The problem is that the attribute where I am able to see which item the menu belongs to is not on the list item itself but on a div contained inside the list item. My question is is it possible to select a child element of the already selected element ?
E.g (the menuli a segment)
$(document).ready( function() {
$(menuli).each( function(index) {
$itemnumber = $(menuli a).attr("href");
switch($itemnumber) {
case 1:
$(this).css("background-image", "image01.jpg");
break;
}
});
});
This is more or less the script I am trying to get, where each list item is iterated through and depending on the href of the link inside the list item a background image is set to that list item.
EDIT
Here is my html:
<div id="divMenuSportGSXSports">
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=468&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl00_lnkSport" href="/Sport/Groups.aspx?IDSport=468&Antepost=0">
<span title="SOCCER">SOCCER</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=520&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl01_lnkSport" href="/Sport/Groups.aspx?IDSport=520&Antepost=0">
<span title="BASEBALL">BASEBALL</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=544&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl02_lnkSport" href="/Sport/Groups.aspx?IDSport=544&Antepost=0">
<span title="CRICKET">CRICKET</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=525&Antepost=0&Tema=Supabets)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl03_lnkSport" href="/Sport/Groups.aspx?IDSport=525&Antepost=0">
<span title="BASKETBALL">BASKETBALL</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=534&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl04_lnkSport" href="/Sport/Groups.aspx?IDSport=534&Antepost=0">
<span title="ICE HOCKEY">ICE HOCKEY</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=523&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl05_lnkSport" href="/Sport/Groups.aspx?IDSport=523&Antepost=0">
<span title="TENNIS">TENNIS</span>
</a>
</div>
</div>
</div>
Yes you can, use find
var parentElement = $('#someElement');
var childElement = parentElement.find('.child'); //where .child should be your child selector
Where as example code is not clear, I just gave answer to your question.
try to change this:
$(this).css("background-image", "image01.jpg");
to this:
$(this).children("div").css("background-image", "image01.jpg");
If you want to target the direct child of the element, better to use children() than find()
Please refer to this: What is fastest children() or find() in jQuery?
I'm using this code for showing image inside any tag:
var imgs = $(this).find("p").attr("rel");
$('.hLeft img').attr("src", imgs);
Markup:
<div class="hLeft">
<h2></h2>
<a href="" class="mn">
</a>
<img src="" />
</div>
But when I insert <img> inside a, my script not working.
$('.mn img').attr("src", imgs);
Markup:
<div class="hLeft">
<h2></h2>
<a href="" class="mn">
<img src="" />
</a>
</div>
Why the $('.mn img').attr("src", imgs); not working with a tag?
the img is over written by this line:
$("a", $hleft).html(mansetText);
I think it deals with the css properties of class mn. div are displayed as block by default which is not the case for a. Try to add display:block; in the mn class to see the result.