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Need to have one string from Looped Chars JS [closed]

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need to get the output as 1 string instead of looped string
the output I got each letter on its own
need to have the second output which is one word
Thanks in advance:D
let start = 0;
let swappedName = "elZerO";
for (let i = start; i<swappedName.length; i++){
if (swappedName[i] == swappedName[i].toUpperCase()) {
console.log(swappedName[i].toLowerCase());
}else {
console.log(swappedName[i].toUpperCase());
}
}
//Output
E
L
z
E
R
o
// Need to be
"ELzERo"

Use string = string0+string1 , or keep adding values to an array, then join the array with array.join()
MasteringJs has a great guide on ways to merge characters and strings.
let start = 0;
let swappedName = "elZerO";
var outputString="";
var outputStringArray=[];
var newChar="";
for (let i = start; i<swappedName.length; i++){
if (swappedName[i] == swappedName[i].toUpperCase()) {
newChar = swappedName[i].toLowerCase();
}else {
newChar=swappedName[i].toUpperCase();
}
outputStringArray.push(newChar);
outputString+=newChar;
}
console.log("[Output using string1 + string 2] is "+outputString); // Another example of concating string
console.log("[Output using array.join] is "+outputStringArray.join("")); // Another example of concating string
// Need to be
"ELzERo"

String with character repetition [closed]

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Can someone help me on this one? Given a string, I have to return a string in which each character (case-sensitive) is repeated once.
doubleChar("String") ==> "SSttrriinngg"
doubleChar("Hello World") ==> "HHeelllloo WWoorrlldd"
doubleChar("1234!_ ") ==> "11223344!!__ "
function doubleChar(str) {
}

You can use repeat() method for this like:
function doubleChar(str) {
return [...str].map(s => s.repeat(2)).join('')
}
console.log(doubleChar("String"))
console.log(doubleChar("Hello World"))
console.log(doubleChar("1234!_ "))

Try this:
const str = 'hello'
let arr = str.split('')
const double = arr.map(i => i += i).join('')
console.log(double)

How to execute if condition based on a value from query string in javascript/jquery? [closed]

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I've a variable called url as follows :
url = "http://56.177.59.250/static/ajax.php?core[ajax]=true&core[call]=prj_name.contactform&width=400&core[security_token]=c7854c13380a26ff009a5cd9e6699840"
Now I want to use if condition only if core[call] is equal to the value it currently has i.e. prj_name.contactform otherwise not.
How should I do this since the parameter from query-string is in array format?

Just use String.indexOf and check if it is present (that is not -1, which means it doesn't exist)
if(url.indexOf("core[call]=prj_name.contactform") > -1){
// valid. Brew some code here
}

You can use location.search :
<script>
function get(name) {
name = name.replace(/[\[]/, "\\[").replace(/[\]]/, "\\]");
var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
results = regex.exec(location.search);
return results === null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));
}
if(get("core[call]") == "prj_name.contactform"){
alert('ok');
}else{
alert('no');
}
</script>

$.trim space using $.trim doesn't work in Jquery [closed]

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$(".p").each(function(i){
len=$(this).text().length;
if(len>80)
{
$(this).text($(this).text().substr(0,80)+'...');
}
});
some of my output is fine like
abc def...
but some of it will be like
1234 45 ...
How to trim the space? I tried $.trim but doesn't work.

This should work:
$(".p").text(function() {
var text = $(this).text();
if (text.length > 80) {
return $.trim(text.substr(0, 80)) + '...';
} else {
return text;
}
});

disable 'font-style: italic' if element contains non-latin characters [closed]

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Using JavaScript, how to find every element that have font-style: italic (in addition to <i> and <em>), and switch it to font-style: normal if the element contains one of more characters that are not Latin characters ([a-zA-Z])?

$('selector_for_text_containers').each(function(){
var str = $(this).attr('style').replace('italic', 'normal');
$(this).attr('style', str);
});

You can use the method given from #Loyalty Technology in this function to test if the chars are available.
function validate() {
var chars = 'άλφα';
$.each( $('.text') , function (indx, elm) {
var text = $(elm).text().split('');
text.forEach( function( letter, ind ) {
if ( chars.indexOf(letter) !== -1) {
var str = $(this).attr('style').replace('italic', 'normal');
$(elm).attr('style', str);
}
});
});