disable 'font-style: italic' if element contains non-latin characters [closed] - javascript

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Using JavaScript, how to find every element that have font-style: italic (in addition to <i> and <em>), and switch it to font-style: normal if the element contains one of more characters that are not Latin characters ([a-zA-Z])?

$('selector_for_text_containers').each(function(){
var str = $(this).attr('style').replace('italic', 'normal');
$(this).attr('style', str);
});

You can use the method given from #Loyalty Technology in this function to test if the chars are available.
function validate() {
var chars = 'άλφα';
$.each( $('.text') , function (indx, elm) {
var text = $(elm).text().split('');
text.forEach( function( letter, ind ) {
if ( chars.indexOf(letter) !== -1) {
var str = $(this).attr('style').replace('italic', 'normal');
$(elm).attr('style', str);
}
});
});

Related

String with character repetition [closed]

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Can someone help me on this one? Given a string, I have to return a string in which each character (case-sensitive) is repeated once.
doubleChar("String") ==> "SSttrriinngg"
doubleChar("Hello World") ==> "HHeelllloo WWoorrlldd"
doubleChar("1234!_ ") ==> "11223344!!__ "
function doubleChar(str) {
}
You can use repeat() method for this like:
function doubleChar(str) {
return [...str].map(s => s.repeat(2)).join('')
}
console.log(doubleChar("String"))
console.log(doubleChar("Hello World"))
console.log(doubleChar("1234!_ "))
Try this:
const str = 'hello'
let arr = str.split('')
const double = arr.map(i => i += i).join('')
console.log(double)

find all substrings between ${ and } in javascript [closed]

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i have collections of text with some text between ${ and } like "this is ${test} string ${like}". How can I extract all there strings. Output : test,like
try
match(/{[\w\d]+}/g);
example
"{asdas}32323{234}".match(/{[\w\d]+}/g); //outputs ["{asdas}", "{234}"]
It will return with { and } with the matches which you can remove from the resultset by
"{asdas}32323{234}".match(/{[\w\d]+}/g).map(function(value){return value.substring(1, value.length-1)}); //outputs ["asdas", "234"]
you can try:
"this is ${test} string ${like}".match(/\${\w*}/g).map(function(str){return str.slice(2,-1)})
//["test", "like"]
Try this
var str = "this is ${test} string ${like}";
var txt = str.match(/{[\w\d]+}/g);
for(var i=0; i < txt.length; i++) {
txt[i] = txt[i].replace(/[{}]/g, '');
alert(txt[i]);
}

JavaScript prototypes - technical interview [closed]

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I had a JavaScript interview last wednesday, and I had trouble with one of the questions. Maybe you guys can give me hand with it?
The question was: how would you go about this printing var a and s to the console, in camel case, with the help of a prototype function...
var s = “hello javier”;
var a = “something else”;
String.prototype.toCamelCase = function() {
/* code */
return capitalize(this);
};
...so the result is the same as doing this?
console.log(s.toCamelCase());
console.log(a.toCamelCase());
>HelloJavier
>SomethingElse
Thanks!
var s = 'hello javier';
var a = 'something else';
String.prototype.toCamelCase = function() {
return capitalize(this);
};
function capitalize(string) {
return string.split(' ').map(function(string) {
return string.charAt(0).toUpperCase() + string.slice(1);
}).join('');
}
console.log(a.toCamelCase());
console.log(s.toCamelCase());
Reference
How do I make the first letter of a string uppercase in JavaScript?
I would go with something like this:
var s = "hello javier";
var a = "something else";
String.prototype.toCamelCase = function() {
function capitalize(str){
var strSplit = str.split(' ');
// starting the loop at 1 because we don't want
// to capitalize the first letter
for (var i = 1; i < strSplit.length; i+=1){
var item = strSplit[i];
// we take the substring beginning at character 0 (the first one)
// and having a length of one (so JUST the first one)
// and we set that to uppercase.
// Then we concatenate (add on) the substring beginning at
// character 1 (the second character). We don't give it a length
// so we get the rest.
var capitalized = item.substr(0,1).toUpperCase() + item.substr(1);
// then we set the value back into the array.
strSplit[i] = capitalized;
}
return strSplit.join('');
}
return capitalize(this);
};
// added for testing output
console.log(s.toCamelCase());
console.log(a.toCamelCase());

How to execute if condition based on a value from query string in javascript/jquery? [closed]

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I've a variable called url as follows :
url = "http://56.177.59.250/static/ajax.php?core[ajax]=true&core[call]=prj_name.contactform&width=400&core[security_token]=c7854c13380a26ff009a5cd9e6699840"
Now I want to use if condition only if core[call] is equal to the value it currently has i.e. prj_name.contactform otherwise not.
How should I do this since the parameter from query-string is in array format?
Just use String.indexOf and check if it is present (that is not -1, which means it doesn't exist)
if(url.indexOf("core[call]=prj_name.contactform") > -1){
// valid. Brew some code here
}
You can use location.search :
<script>
function get(name) {
name = name.replace(/[\[]/, "\\[").replace(/[\]]/, "\\]");
var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
results = regex.exec(location.search);
return results === null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));
}
if(get("core[call]") == "prj_name.contactform"){
alert('ok');
}else{
alert('no');
}
</script>

$.trim space using $.trim doesn't work in Jquery [closed]

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$(".p").each(function(i){
len=$(this).text().length;
if(len>80)
{
$(this).text($(this).text().substr(0,80)+'...');
}
});
some of my output is fine like
abc def...
but some of it will be like
1234 45 ...
How to trim the space? I tried $.trim but doesn't work.
This should work:
$(".p").text(function() {
var text = $(this).text();
if (text.length > 80) {
return $.trim(text.substr(0, 80)) + '...';
} else {
return text;
}
});

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