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Convert Captalize Text to dashed Text (TechnologyStackPage --> technology-stack-page ) and vice Versa (technology-stack-page --> TechnologyStackPage) [closed]

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How to Write a function for converting any Captalize String into small letter dashed String and Vice Versa.
1st Example
TechnologyStackPage --> technology-stack-page
and
technology-stack-page --> TechnologyStackPage
2nd Example
EHSCustomisedSoftwareEstimationForm --> ehs-customised-software-estimation-form
and
ehs-customised-software-estimation-form --> EHSCustomisedSoftwareEstimationForm

const abbr = ['EHS', 'USA']
const kebabCase = new RegExp(`(?=(?<=${abbr.join('|')}|[a-z])[A-Z]+)`, 'g')
const pascalCase = new RegExp(`(^|-)(${abbr.join('|').toLowerCase()}|[a-z])`, 'g')
console.log(``,
'EHSCustomisedSoftwareEstimationForm'.replace(kebabCase, `-`).toLowerCase(),`\n`,
'CustomisedSoftwareEstimationFormUSA'.replace(kebabCase, `-`).toLowerCase(),`\n`,
`\n`,
'ehs-customised-software-estimation-form'.replace(pascalCase, (_, _1, _2) => _2.toUpperCase()),`\n`,
'customised-software-estimation-form-usa'.replace(pascalCase, (_, _1, _2) => _2.toUpperCase())
)

String with character repetition [closed]

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Can someone help me on this one? Given a string, I have to return a string in which each character (case-sensitive) is repeated once.
doubleChar("String") ==> "SSttrriinngg"
doubleChar("Hello World") ==> "HHeelllloo WWoorrlldd"
doubleChar("1234!_ ") ==> "11223344!!__ "
function doubleChar(str) {
}

You can use repeat() method for this like:
function doubleChar(str) {
return [...str].map(s => s.repeat(2)).join('')
}
console.log(doubleChar("String"))
console.log(doubleChar("Hello World"))
console.log(doubleChar("1234!_ "))

Try this:
const str = 'hello'
let arr = str.split('')
const double = arr.map(i => i += i).join('')
console.log(double)

A regex phone reformatting for JS [closed]

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I have phone number like: 89227611508 and i need to reformat this with regex(JS) into +8 922 761-15-08. I'm new in regex and can't get it done. Can anyone provide a simple solution?

Use:
"89227611508".replace(/^(\d{1})(\d{3})(\d{3})(\d{2})(\d{2})$/, "+$1 $2 $3-$4-$5");

You need to use a regular expression to grab the groups of numbers then concatenate the number groups into a formatted string.
let number = '89227611508';
console.log(formatNumber(number));
function formatNumber(number) {
let groups = number.match(/^(\d)(\d{3})(\d{3})(\d{2})(\d{2})$/);
return '+' + groups[1] + ' ' + groups[2] + ' ' + groups[3] + '-' + groups[4] + '-' + groups[5];
}
.as-console-wrapper { top: 0; max-height: 100% !important; }

find all substrings between ${ and } in javascript [closed]

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i have collections of text with some text between ${ and } like "this is ${test} string ${like}". How can I extract all there strings. Output : test,like

try
match(/{[\w\d]+}/g);
example
"{asdas}32323{234}".match(/{[\w\d]+}/g); //outputs ["{asdas}", "{234}"]
It will return with { and } with the matches which you can remove from the resultset by
"{asdas}32323{234}".match(/{[\w\d]+}/g).map(function(value){return value.substring(1, value.length-1)}); //outputs ["asdas", "234"]

you can try:
"this is ${test} string ${like}".match(/\${\w*}/g).map(function(str){return str.slice(2,-1)})
//["test", "like"]

Try this
var str = "this is ${test} string ${like}";
var txt = str.match(/{[\w\d]+}/g);
for(var i=0; i < txt.length; i++) {
txt[i] = txt[i].replace(/[{}]/g, '');
alert(txt[i]);
}

disable 'font-style: italic' if element contains non-latin characters [closed]

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Using JavaScript, how to find every element that have font-style: italic (in addition to <i> and <em>), and switch it to font-style: normal if the element contains one of more characters that are not Latin characters ([a-zA-Z])?

$('selector_for_text_containers').each(function(){
var str = $(this).attr('style').replace('italic', 'normal');
$(this).attr('style', str);
});

You can use the method given from #Loyalty Technology in this function to test if the chars are available.
function validate() {
var chars = 'άλφα';
$.each( $('.text') , function (indx, elm) {
var text = $(elm).text().split('');
text.forEach( function( letter, ind ) {
if ( chars.indexOf(letter) !== -1) {
var str = $(this).attr('style').replace('italic', 'normal');
$(elm).attr('style', str);
}
});
});