Develop Reference

Get selected value from multiple select on change in dynamic form

I'm currently working on a dynamic form which enables the user to add as many variants as they would like. This form which can be added has a price, size and color. The size and color are select2 select boxes which enable the user to select multiple things. The form:
<div class="col-sm-4">
<label>Kleuren</label>
<select name="colors[{{$i}}][]" id='color-options' class="form-control multiple-select" multiple="multiple">
#foreach($colors as $id=>$color)
<option value="{{$id}}">{{$color}}</option>
#endforeach
</select>
</div>
When looking at the HTML code I have multiple of these forms which go by name: colors[0][], colors[1][], colors[2][] etc.
How do I print the value of a selected new color in a new div? The code which I have thus far:
$(document).ready(function() {
$('.multiple-select').select2({
language: 'nl'
});
$('.summernote').summernote();
var addVariantButton = document.getElementById('addVariant[0]');
addVariantButton.addEventListener('click', function(){
addVariant(0);
});
var colorSelected = document.getElementsByName('colors[0][]');
colorSelected.addEventListener("click", displayColorSelected);
});
function displayColorSelected() {
var selected_value = document.getElementById("color-options").value;
console.log(selected_value);
}
But this only works for the first colors input form, but how can I make this into a more dynamical function to get all colors input?

You can get all selected values in array as below:
function displayColorSelected() {
var selected_value = $("[id='color-options']").toArray().map(x => $(x).val());
console.log(selected_value);
}
Note: id selector will always return single element which will be first with that id. So you're getting value for first select only.
You can use attribute selector ([]) instead which will find every element with given id. So here $("[id='color-options']").toArray() will find every element with id equal to color-options and map(x => $(x).val()) will return only value part from the elements array.

Add all the selects a class ("color-select" for example), and run over all the selects -
$('.color-select').each(function() { console.log($(this).val()); })

You may need to delegate your event listener
document.addEventListener('event',function(e){
if(element){//do something}
})
Since you are using jquery its easier
$(document).on('event','element',function());

Doing mutual exclusive checkbox of two buttons with siblings()

I am trying to get two buttons groups with checkboxes mutually exclusive.
Here's my current result on this JS Fiddle
As you can see, there are four divs (with id="UserVsComputer", id="User1VsUser2", id="PlayableHits" and id="button-new-game").
I want the two first <div> ( UserVsComputer and User1VsUser2 ) to be mutually exclusive when we click on the checkbox of concerning <input> (i.e corresponding to the right <div>).
In JavaScript part, I did:
// Select the clicked checkbox for game type
$('input.game').on('click',function(){
setGameType();
});
function setGameType() {
// Get state of the first clicked element
var element = $('#UserVsComputer input.game');
var checkBoxState = element.prop('checked');
// Set !checkBoxState for the sibling checkbox, i.e the other
element.siblings().find('input.game').prop('checked',!checkBoxState);
updateGameType();
}
function updateGameType() {
// Set type of game
if ($('#UserVsComputer input').prop('checked'))
gameType = 'UserVsComputer';
else
gameType = 'User1VsUser2';
}
I don't want the <div id="PlayableHits" class="checkbox"> to be concerned by this mutual exclusion on two first checkboxes.
For example, below a capture showing that I can set the two first checkbox to true without making them exclusive:
What might be wrong here?

Try the following - it uses the target of the click event to ascertain which checkbox was checked:
// Select the clicked checkbox for game type
$('input.game').on('click',function(e){
setGameType(e.target);
});
function setGameType(cb) {
var container = $(cb).parent().parent();
var checkBox = $(cb);
var checkBoxState = checkBox.prop('checked');
// Set !checkBoxState for the sibling checkbox, i.e the other
container.siblings().find('input.game').prop('checked', !checkBoxState);
updateGameType();
}
function updateGameType() {
// Set type of game
if ($('#UserVsComputer input').prop('checked')) {
gameType = 'UserVsComputer';
} else {
gameType = 'User1VsUser2';
}
}
There are other bits which could use some attention (the hardcoded .parent().parent() isn't pretty but works in this case..

Javascript - How to hide a drop down control if it's empty

I have a cascade dropdown on a form. User selects Document Type and most of the document type has Category. However, if a doc type does not have category then I would like to hide the category drop down. Is there a way to see if category dropdown (calculate array or something) and hide category control (by default it always show Select a value even if the drop down does not have any value to select from)
So far I have following and wondering how to evaluate category drop down control based on what user selected in the doc type drop down control.
NWF$(document).ready(function(){
var varDocType= NWF$('#' + jsDocTypes)// gets Doc Type control;
varDocType.change(function(){
if(this.value !== null){
alert(varDocType.val());
var varCategory = NWF$('#' + jsCategory)// gets Category control;
alert(varCategory.val());
if(varCategory == ''){
NWF$('#' + jsCategory).style.visibility = "hidden";
}
}
});
});

Test this:
select:empty {
display: none;
}
Invisible: ||<select></select>--<br>
Visible (whitespace): ||<select> </select>--<br>
Visible (children): ||<select><option>Options!</option></select>--
I do not know what is NWF$ but if you want hide an element by javascript:
TheElement.style.display = "none";

Show multiple textfield based on dropdown's change value

I have four dropdown's value.
Job
Business
Study
Other
If Job is selected than company name and designation textbox should be visible.
If Business is selected than business field is visible
If Study is selected than class and college should be visible and for other just one text box should be visible.
I just know about if other field is selected than how to show it. Dont know what to do in this kind of prob.

I prefer jquery, which this would be easier in, but here is a pure Javascript solution:
//onclick on a select tag it runs a function
document.getElementsByTagName("select")[0].onclick = function () {
//it hides all the input tags. It finds the array of inputs first, change the numbers to change which input tags it hides.
document.getElementsByTagName("input")[0].style.display = 'none';
document.getElementsByTagName("input")[1].style.display = 'none';
document.getElementsByTagName("input")[2].style.display = 'none';
document.getElementsByTagName("input")[3].style.display = 'none';
//shows the input that has an id equal to the value of the select that was clicked.
document.getElementById(this.value).style.display = 'block';
}

First, give all of them the same class ( i went with selection ), and then give all of the related text fields another specific class.
<input class="selection Study" name="class /> and
<input class="selection study" name="college"> and for company,
<input class="selection Business" name="designation">
In jquery, it'd be
$('.dropdown').on('change', function() {
$('.selection').hide();
var val = $(this).val();
$('.' + val).show();
)};

Jquery Chosen plugin. Select multiple of the same option

I'm using the chosen plugin to build multiple select input fields. See an example here: http://harvesthq.github.io/chosen/#multiple-select
The default behavior disables an option if it has already been selected. In the example above, if you were to select "Afghanistan", it would be greyed out in the drop-down menu, thus disallowing you from selecting it a second time.
I need to be able to select the same option more than once. Is there any setting in the plugin or manual override I can add that will allow for this?

I created a version of chosen that allows you to select the same item multiple times, and even sends those multiple entries to the server as POST variables. Here's how you can do it (fairly easily, I think):
(Tip: Use a search function in chosen.jquery.js to find these lines)
Change:
this.is_multiple = this.form_field.multiple;
To:
this.is_multiple = this.form_field.multiple;
this.allows_duplicates = this.options.allow_duplicates;
Change:
classes.push("result-selected");
To:
if (this.allows_duplicates) {
classes.push("active-result");
} else {
classes.push("result-selected");
}
Change:
this.form_field.options[item.options_index].selected = true;
To:
if (this.allows_duplicates && this.form_field.options[item.options_index].selected == true) {
$('<input>').attr({type:'hidden',name:this.form_field.name,value:this.form_field.options[item.options_index].value}).appendTo($(this.form_field).parent());
} else {
this.form_field.options[item.options_index].selected = true;
}
Then, when calling chosen(), make sure to include the allows_duplicates option:
$("mySelect").chosen({allow_duplicates: true})

For a workaround, use the below code on each selection (in select event) or while popup opened:
$(".chosen-results .result-selected").addClass("active-result").removeClass("result-selected");
The above code removes the result-selected class and added the active-result class on the li items. So each selected item is considered as the active result, now you can select that item again.

#adam's Answer is working very well but doesn't cover the situation that someone wants to delete some options.
So to have this functionality, alongside with Adam's tweaks you need to add this code too at:
Chosen.prototype.result_deselect = function (pos) {
var result_data;
result_data = this.results_data[pos];
// If config duplicates is enabled
if (this.allows_duplicates) {
//find fields name
var $nameField = $(this.form_field).attr('name');
// search for hidden input with same name and value of the one we are trying to delete
var $duplicateVals = $('input[type="hidden"][name="' + $nameField + '"][value="' + this.form_field.options[result_data.options_index].value + '"]');
//if we find one. we delete it and stop the rest of the function
if ($duplicateVals.length > 0) {
$duplicateVals[0].remove();
return true;
}
}
....