I'd like to obtain the effect present on this site's top jQuery slider. You can see the little yellow square shapes indicating current slide position in the list get gradually smaller, shrinking upwards till they're gone and the slider changes image.
Here is a link with what I tried so far.
That is a neat effect :)
You need to combine what you have now with a child element in your LI parent element. When Slider fires, you animate the height of this element from 0 to 100 over 4000 MS and then have a callback which returns the height to 0.
ex:
$('.slider').animate({height: '100%'}, 4000, function() {
$('.slider').css('height','0');
});
Working here: http://codebins.com/bin/4ldqp9c/39
Related
So what I am trying to achieve is to have the SVG element slide into the viewport as the user scrolls within the selected div. The effect is partially working since on the initial load, it doesn't position the element as I defined in CSS, in this case: right: -150px to hide it outside of the viewport, but it immediately sets it to the value assigned in the AnimeJS timeline.
If you scroll slowly, you are going to see the element in the position right: 0 which is the final location, and when it triggers, it pushes the element to -150 and starts the correct animation.
Is there any way to keep the SVG outside before the actual animation is triggered?
This is a codepen:
https://codepen.io/lukagurovic/pen/OJbvKGK
Update:
I just tried to add duration to the animation and it seems like the animation plays as soon as the page loads
Found the answer. The autoplay is not supposed to be set in the animation object, but rather in the timeline itself. const timeline = anime.timeline({autoplay: false});
I'm very new to CSS/HTML/JS so I don't have lots of experience with CSS transitions.
I'm trying to animate a div elements on my page, but I can't achieve a desired result so far.
Here is my problem:
In my HTML I have a div container element that has 5 div elements inside of it. They look like simple boxes positioned in the middle of the screen and aren't visible for now. I also have 5 buttons in the corner of the screen.
What I'm trying to do is:
when I click a button (for example button 3) 3 of the divs on the left should disappear and be moved to the left behind the margin of the screen and 2 of the divs should do the same, but move to the right. After that I want 3 divs that are on the right slide back to the screen and 2 divs on the right should slide back as well. So it looks like they sliding towards each other to the positions they started from initially.
I'm trying to do this effect using CSS transitions (transform: translateX(Npx);). So in my JS file I have something like this:
$(document).ready(function() {
$(".button").click(function(){
// PART 1
// move 3 divs to the left using transform: translateX(Npx) (no animation)
// move 2 divs to the left using transform: translateX(Npx) (no animation)
// PART 2
// slide 3 divs to the left using transform: translateX(Npx) (with animation)
// slide 2 divs to the left using transform: translateX(Npx) (with animation)
});
So the problem is that in this case only the part one works and part two seems to be not working.....if I attach the part on code to a different event...like another click button...it works just fine.
So my question is if these two transitions can be done under one event?!?!
I have done this, and this kind of effect can look great. If I understand your question correctly, your issue is that you run the animation AFTER you moved the divs, so your animation function uses the wrong starting point.
What you need is:
Be sure you have a CSS position:relative; set on your divs so the animation can work.
Run your animation function moving your divs relative to their current position (i.e. top, left), and include a success callback. You may need to first use offset() and some math to figure out the distance traveled.
On the completion of your animation (success callback), change the relative position of your divs back to 0px (or whatever they were before) and simultaneously perform the function where you actually move the divs to their new position in the DOM using insertBefore(). I've never seen a flicker since these functions are near-instant, but if you see an issue you can set visibility to hidden while you reset the position and move the divs, and then reset the visibility afterward
You can even set custom z-indexes for your divs during the animation that you reset on the success callback, allowing you to determine which elements the divs pass over/under or specifying which is on top if they cross each other.
I have a scrolling div with a visible width that's half of the content. (The actual content is double the width.)
I just want a simple javascript utilizing jquery (serialscroll plugin is really too much) to trigger the scroll to slide into view the next half of the content, then click again the slide it back. (the amount of the sliding is a static #)
I've got a jsfiddle with what I have so far. The initial slide left works, but the slide back does not and then it stops working altogether after that.
http://jsfiddle.net/w7Uvj/1/
Use left alone (or right alone) instead of left and right fiddle
Change your second function to:
$('.back').click(function() {
$('#maincol').animate({
'right':'-=400px'},750);
$(this).fadeOut(500);
$('.next').delay(600).fadeIn(500);
});
jsFiddle example.
You can also set the right property to just 0px as well (instead of -=400px).
I am currently learning jQuery. I'd like to know how to make an image slide in when you click on its edge, then click again and it slides away. Similar to this:
http://www.karenmillen.com/
If you see the right hand side and click, there is the effect that i'm looking for. I assume this will involve making a div and giving it a background image then using some jquery to make the div slide into view. Of course the div could have other content such as html. Any ideas?
Would the .slideDown() method work?
if you want a div to slideDown() first it has to hidden.
so use $("#div_Id").hide();
after that use $("#div_Id").slideDown('slow');
this will work
Check out slideToggle
Here's what i have so far:
$(document).ready(function() {
$('.inner').hide();
$("button").click(function() {
$("#static_image").hide();
$('.inner').slideToggle(300);
});
});
So basically the animated div begins hidden. There's another div with a background image that is lined up to look as if the animated div is still sticking out a bit. Then clicking a button makes the static div dissapear and the animated div slide into view. However i'm not sure how to make the timing perfect so it's smooth and people won't know there are two divs. The animated div takes a fraction of a second to move up to where the div with the static image was, however the static images disappears immediately leaving a non-smooth animation.
One other thing, how do i get the static image div to return at the moment that the animated div moves back down after a user click? It can't be at the exact moment the user clicks 'retract' button else it'd definitely appear before it's supposed to.
In order to use the animate() function add a CSS class to the <div> tag that has a height attribute, it can either be in pixels or %, this will be the initial height. After that then you can use the animate().
$('#mydiv').animate({
height: 500px
}, 5000, function() {
// Animation complete.
});
This will slide the div to 500px, which will take 5 seconds.
I have a list of divs, and everytime I want to go to the next div I press a key. I need to check if that div is offscreen, and if so, I need to move the screen to show that div either using anchors or another method.
What is my best option for doing this?
Just to clairify, offscreen in my case means something that can't be seen right now without scrolling down. So if you are on the StackOverflow Home Page at the top, the last question on the entire page is offscreen.
Best option is to scroll your page to the element by getting its y-offset, and checking window height and calculating where to scroll page and then you can animate your page to that point.
//height of your div
var scroll = 250;
//animate from actual position to 250 px lower in 200 miliseconds
$(window).animate({"scrollTop": "+="+scroll+"px"}, 200);
so this is not the complete code but it might give you the idea.
check out jquery scrollTop
hope it helps,
Sinan.